To identify the density of a figurine made using an unknown material, the figurine is dropped into a basin filled with water and found to displace 184.8 mL of water. The figurine is then put on a scale and found to be 3.8 pounds in weight. What is the density of the material that this figurine was made from in pounds/inch^3? (Note: 1 mL = 0.0610237 inch^3
Answers
Step-by-step explanation:
here you go hopw it helps you
Related Questions
Please help me ojn this question
Answers
Answer:
T4 = 162 T5 = 486 T6 = 1458
Explanation:
the pattern is multiply the previous number by 3
so 6 x 3 = 18
18 x 3 = 54
54 x 3 = 162 and so on.
Harry invests $1000 in an investment account that earns 6% interest, compounded annually. How much money will he have in the account after 30 years?
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the answer to that question is 1800
En el sistema, encontrar el doble de y:
2x + y = 5
x + y = 4
a) 6
b) 4
c) 3
d) 2
Answers
Answer:
y=3
x=1
Step-by-step explanation:
1 by substitution method
2x+y=5 (1)
x+y=4 (2)
find x in eq 2
x=4-y
put the value in eq 1
2x+y=5
2(4-y)+y=5
8-2y+y=5
8-y=5
-y=5-8
-y=-3
y = 3
x=4-y
x=4-3
x=3
hope it helps you
please mark it as brainliest
( 100 points + brain ) My dropshipping business makes me 11,000$ - 40,000$ a month, At this rate how much money could I make in a year? how much money could I make in 20 years? how much money could I make in 60 years?
Answers
Answer:
One year: Between $132,000 and $480,000.
20 years: Between $2,640,000 and $9,600,000.
60 years: Between $7,920,000 and $28,800,000.
Step-by-step explanation:
If it makes between 11,000 and 40,000 a month, you should take both values and average them or make an estimate. Since there are 12 months in a year, 11,000*12 = $132,000 minimum, 40,000*12 = $480,000 maximum.
In 20 years, 132,000*20= $2,640,000 minimum, 480,000*20 = $9,600,000 maximum.
In 60 years, 2,640,000*3 = $7,920,000 minimum, 9,600,000*3 = $28,800,000 maximum.
If you want to be more specific, you need to find the average number of times you make certain amounts of money per month to find how likely it is to make a certain amount.
Answer:
taking my points back
Step-by-step explanation:
Use the equation below to find A, if 1 = 6 and w = 3.
A = lw
Answers
Answer:
l=6, w=3
And A is the multiplication of l and w
A=6×3
Please please I need help. What is the value of X
Answers
Answer:
x = 25
Step-by-step explanation:
Solving
∠CAD = 1/2 ∡ CD180° - 90° - (2x)° = 1/2 (80°)2x = 90° - 40° = 50°x = 25What is the value of x in | - 6| = x? O 6 and -6 00 06 -6 HOURME
Answers
Answer:
I believe, 6.
Step-by-step explanation:
Not sure if the rest of the question is the answer choices but the absolute of any number, is it's exact opposite. The reason for this is that an absolute number, or |?| is equal to whatever distance it is from 0. Since adding 1, and subtracting 1, both do such but in opposite directions, the absolute value of both would be 1.
find tan0 please help fast!
Answers
Answer:
Tan(51.06) = 1.24 so the correct answer is A
Step-by-step explanation:
Sin0 = 7/9
0 =Arcsin(7/9)
0 =51.06
So,
Tan(51.06) = 1.24 so the correct answer is A
Answer:
A. [tex]\frac{7\sqrt{2} }{8}[/tex]
Step-by-step explanation:
Finding the missing side :
7² + x² = 9²
x² + 49 = 81
x² = 32
x = 4√2
Taking the tan value :
tanθ = 7/(4√2)
tanθ = 7(4√2)/4√2(4√2)
tanθ = 28√2/32
tanθ = [tex]\frac{7\sqrt{2} }{8}[/tex]
What is the slope of the line passing through the points (2, 5) and (0, -4)?
Show all your work.
Leave your answer as a fraction
Answers
Answer:
slope = 9/2
Step-by-step explanation:
y2 - y1 / x2 - x1
-4 - 5/0- 2 = 9/2
A square has a perimeter of 40 feet. Find the length of the
diagonal of the square.
Answers
Answer:
14.14
Step-by-step explanation:
Answer:
The length of the diagonal of the square is about 14.142 feet
Step-by-step explanation:
Step 1: Determine the length
[tex]P = 4(l)[/tex]
[tex]40\ ft = 4(l)[/tex]
[tex]\frac{40\ ft}{4}=\frac{4(l)}{4}[/tex]
[tex]10\ ft = l[/tex]
Step 2: Determine the diagonal length
Pythagorean theorem → [tex]a^2 + b^2 = c^2[/tex]
a and b are going to be the sides of the square which are both 10 ft so we just plug those in and solve for c
[tex](10)^2 +(10)^2 =c^2[/tex]
[tex]100+100=c^2[/tex]
[tex]\sqrt{200}=\sqrt{c^2}[/tex]
[tex]14.142=c[/tex]
Answer: The length of the diagonal of the square is about 14.142 feet
Which of the following are always congruent?
Answers
Answer:
B. Vertical angles
Step-by-step explanation:
please help please please help
Answers
Answer:
The answer is the first option because 2÷2=1 and 10÷2=5
4x+3y=6
-4x+2y=14
Solve the system of equations.
A. x= 1/2, y=3
B. x=3, y =1/2
C. x=4, y = -3/2
D. x=-3/2, y = 4
Answers
Answer:
D
Step-by-step explanation:
4x + 3y = 6
-4x + 2y = 14
0 + 5y / 5 = 20/ 5 = 4 = y
4x + 3(4) = 6
4x + 12 - 12 = 6 - 12
4x / 4 = -6 / 4 = -3 / 2 =x
Suppose that you have $14,000 to invest and you are trying to decide between investing in project A or project B. If you invest in
project A, you will receive a payment of $17,000 at the end of 3 years. If you invest in project B, you will receive a payment of $56,000
at the end of 23 years. The annual interest rate is 6 percent and both projects carry no risk.
Instructions: Round your answers to the nearest dollar. Do not round your intermediate calculations.
a. What is the present value of each project? Enter your answers in the table below.
Present Value
Project A =
$
Project B =
$
b. Which project will you choose for your investment?
Project A
Project B
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If our statement was < β is congruent to < α, the reason would be _____.
Answers
Answer:
Step-by-step explanation:
Vertical angles theorem.
It the UK they are called opposite angles,
i want to know this factorization
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32 - (8b^4)^-1 = (1/2)(64 - (4b^4)^-1) = (1/2)(8 + (2b^2)^-1)(8 - (2b^2)^-1)
Or even
32 - (8b^4)^-1 = (1/8)(256 - b^-4) = (1/8)(16 + b^-2)(16 - b^-2)
Both use the difference of two squares ie a^2 - b^2 = (a + b)(a - b)
which prism has the greatest value
Answers
Jeff sells shirts at a store in the mall. Which group should he survey to determine which color of shirt will have the greatest number sold?
Female customers
customers who are wearing blue
200 random customers
10 friends at work
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The 200 random customers is the group in which he surveys to determine which colour of shirt will have the greatest number sold, option third is correct.
What is a survey?A survey is a means of gathering information from a sample of people using pertinent questions with the goal of understanding populations as a whole.
We have:
Jeff sells shirts at a store in the mall.
The selecting the colour of the shirts is subjective.
It also depends on that how many colours that store sell.
Female customers cannot be an option because men also buy shirts and affect the result of the survey.
Customers who are wearing blue data only tells that how many blue shirts sold.
200 random customers. 200 is a sample from a population, so it will give appropriate results about the colour of shirt will have the greatest number sold
Thus, the 200 random customers is the group in which he surveys to determine which colour of shirt will have the greatest number sold, option third is correct.
Learn more about the survey here:
brainly.com/question/17373064
#SPJ1
A midpoint approximation of the area under the curve f(x) = 2x(x-4)(x-8) over the interval [0, 4] with 4 subintervals is 120. 132. 160.
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The midpoint approximation of the area under the curve f(x) = 2x(x-4)(x-8) over the interval [0, 4] with 4 subintervals is 132.
How to calculate the midpoint?The value of f(1/2) will be:
= 2(1/2)(1/2 - 4)(1/2 - 8)
= 105/4
The value of f(3/2) will be:
= 2(3/2)(3/2 - 4)(3/2 - 8)
= 195/4
The value of f(5/2) will be:
= 2(5/2)(5/2 - 4)(5/2 - 8)
= 165/4
The value of f(7/2) will be:
= 2(7/2)(7/2 - 4(7/2 - 8)
= 63/4
Therefore, the midpoint approximation will be:
= 1/4(105 + 195 + 165 + 63)
= 132
Learn more about midpoint on:
brainly.com/question/556641
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PLEASE HELP!!!!!!!!
Note: please add the answer next to the number its from so I can know which question was answered
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2)B
1) K < or equal to -5 so smaller than -5 with closed circle
2)K < or equal to 1 so less than 1 with closed circle
What is the area of this figure? Please help
Answers
Answer:
369.5 ft²
Step-by-step explanation:
Area of figure :
Area (rectangle 1) + Area (rectangle 2) + Area (triangle 1) + Area (triangle 2)
5 x 4 + 13 x 8 + 1/2 x 23 x 13 + 1/2 x 24 x 820 + 104 + 149.5 + 96124 + 96 + 149.5220 + 149.5369.5 ft²Answer:
369.5 ft²
Step-by-step explanation:
Separate the figure into 2 rectangles and 2 triangles.
(see attached image)
Area 1
Area of a rectangle = width × length
= 4 × 5
= 20 ft²
Area 2
Area of a rectangle = width × length
= 8 × (4 + 4 + 5)
= 8 × 13
= 104 ft²
Area 3
Area of a triangle = 1/2 × base × height
= 1/2 × (6 + 4 + 5 + 4 - 6) × 23
= 1/2 × 13 × 23
= 149.5 ft²
Area 4
Area of a triangle = 1/2 × base × height
= 1/2 × 8 × (21 + 8 - 5)
= 1/2 × 8 × 24
= 96 ft²
Total Area
Area 1 + Area 2 + Area 3 + Area 2 = 20 + 104 + 149.5 + 96
= 369.5 ft²
hi can anyone solve my math problem
Answers
Answer:
The solutions to this equation are x = -8/9 and x = -16/3.
Step-by-step explanation:
We have this equation here:
[tex]\displaystyle \frac{1}{3}|x-4|=\frac{2}{3} x+2|x+\frac{6}{3} |[/tex]First, let's simplify the right sight of the equation by simplifying 6/3 to 2.
[tex]\displaystyle \frac{1}{3}|x-4|=\frac{2}{3} x+2|x+2 |[/tex]Multiply both sides of the equation by 3 in order to get rid of the fractions.
[tex]|x-4|=2x+6|x+2|[/tex]Move the terms on either side of the equation to set them equal to 0.
[tex]|x-4|-2x-6|x+2|=0[/tex]Now, we can split this equation up into 4 possible cases. In each case, we make the absolute values negative or positive.
Case #1 (first absolute value: positive; second absolute value: positive)[tex](x-4)-2x-6(x+2)=0[/tex]Simplify this equation by distributing -6 inside the parentheses.
[tex]x-4-2x-6x-12=0[/tex]Combine like terms.
[tex]-7x-16=0[/tex]Add 16 to both sides of the equation and divide by -7.
[tex]\displaystyle \boxed{x=-\frac{16}{7}}[/tex]Case #2 (first absolute value: negative; second absolute value: positive)[tex]-(x-4)-2x-6(x+2)=0[/tex]Distribute the negative sign and -6 inside of their respective parentheses.
[tex]-x+4-2x-6x-12=0[/tex]Combine like terms.
[tex]-9x-8=0[/tex]Add 8 to both sides of the equation and divide by -9.
[tex]\displaystyle \boxed{x=-\frac{8}{9}}[/tex]Case #3 (first absolute value: positive; second absolute value: negative)[tex](x-4)-2x-6[-(x+2)]=0[/tex]Distribute the negative sign inside the parentheses first.
[tex]x-4-2x-6(-x-2)=0[/tex]Now, distribute -6 inside the parentheses.
[tex]x-4-2x+6x+12=0[/tex]Combine like terms.
[tex]5x+8=0[/tex]Subtract 8 from both sides of the equation and divide by 5.
[tex]\displaystyle \boxed{ x=-\frac{8}{5}}[/tex]Case #4 (first absolute value: negative; second absolute value: negative)[tex]-(x-4)-2x-6[-(x+2)]=0[/tex]Distribute the negative signs inside the parentheses first.
[tex]-x+4-2x-6(-x-2)=0[/tex]Distribute -6 inside the parentheses.
[tex]-x+4-2x+6x+12=0[/tex]Combine like terms.
[tex]3x+16=0[/tex]Subtract 16 from both sides of the equation and divide by 3.
[tex]\displaystyle \boxed{x=-\frac{16}{3}}[/tex]Extraneous SolutionsWhenever we solve problems with absolute values, we will always need to check for extraneous solutions.
Definition: These are solutions that may come up while solving but do not actually fit in the domain of the original problem.
Checking for these is tedious, but it will help eliminate wrong answers, so let's plug every "solution" for x that we found back into the original equation.
1) x = -16/7Substitute this value back into the original equation.
[tex]\displaystyle \frac{1}{3}|(-\frac{16}{7}) -4|=\frac{2}{3} (-\frac{16}{7}) +2|(-\frac{16}{7}) +\frac{6}{3} |[/tex]If we do all the calculations correctly, we will get:
[tex]\displaystyle \frac{44}{21} =-\frac{20}{21}[/tex]Since this equation is NOT true, this means that x = -16/7 is NOT A SOLUTION.
2) x = -8/9Substitute this value back into the original equation.
[tex]\displaystyle \frac{1}{3}|(-\frac{8}{9}) -4|=\frac{2}{3} (-\frac{8}{9}) +2|(-\frac{8}{9}) +\frac{6}{3} |[/tex]If we do all the calculations correctly, we will get:
[tex]\displaystyle \frac{44}{27} =\frac{44}{27}[/tex]Since this equation IS true, this means that x = -8/9 IS A SOLUTION.
3) x = -8/5Substitute this value back into the original equation.
[tex]\displaystyle \frac{1}{3}|(-\frac{8}{5}) -4|=\frac{2}{3} (-\frac{8}{5}) +2|(-\frac{8}{5}) +\frac{6}{3} |[/tex]If we do all the calculations correctly, we will get:
[tex]\displaystyle \frac{28}{15} =-\frac{4}{15}[/tex]Since this equation is NOT true, this means that x = -8/5 is NOT A SOLUTION.
4) x = -16/3Substitute this value back into the original equation.
[tex]\displaystyle \frac{1}{3}|(-\frac{16}{3}) -4|=\frac{2}{3} (-\frac{16}{3}) +2|(-\frac{16}{3}) +\frac{6}{3} |[/tex]If we do all the calculations correctly, we will get:
[tex]\displaystyle \frac{28}{9} =\frac{28}{9}[/tex]Since this equation IS true, this means that x = -16/3 IS A SOLUTION.
Final AnswerThe two true solutions of the double absolute value equation, shown above, are:
[tex]\displaystyle \boxed{-\frac{8}{9} } \ \ \& \ \ \boxed{-\frac{16}{3}}[/tex]Answer:
x = -16/3 or -8/9
Step-by-step explanation:
The equation can be rewritten as a piecewise linear function with two breakpoints, or three domain regions. Each breakpoint is at the value of x where the argument of the absolute value function is zero: at x=4 and x=-2.
For each absolute value, we have ...
|q| = -q for q < 0
|q| = q for q ≥ 0
Then the three parts of the domain are ...
x < -2 . . . . . . . . where |x +2| has its vertex-2 ≤ x < 4 . . . . . between the vertices4 ≤ x . . . . . . . . . where |x -4| has its vertex__
Subtracting the right side, the equation becomes ...
1/3|x -4| -2/3x -2|x +2| = 0
Then the three piecewise functions are ...
x < -2Both absolute value arguments are negated.
1/3(-(x -4)) -2/3x -2(-(x +2)) = 0
x(-1/3 -2/3 +2) +4/3 +4 = 0 . . . . . collect terms
x +5 1/3 = 0 . . . . . . . simplify
x = -5 1/3 . . . . . . . . . subtract 5 1/3. This result is in the domain
__
-2 ≤ x < 4Only the argument of |x -4| is negated.
1/3(-(x -4)) -2/3x -2(x +2) = 0
x(-1/3 -2/3 -2) +4/3 -4 = 0 . . . . collect terms
-3x -8/3 = 0 . . . . . . . simplify
-3x = 8/3 . . . . . . . add 8/3
x = -8/9 . . . . . divide by -3. This result is in the domain
__
4 ≤ xNeither absolute value function argument is negated.
1/3(x -4) -2/3x -2(x +2) = 0
x(1/3 -2/3 -2) -4/3 -4 = 0 . . . . . collect terms
-7/3x -8/3 = 0 . . . . . . . . . simplify
-7/3x = 8/3 . . . . . . . . add 8/3
x = -8/7 . . . . . . . . . divide by -7/3. This result is not in the domain.
There is no solution in this region.
__
The solutions are ...
x = -5 1/3x = -8/9Suppose you have a photograph that
has a height of 8 in and a width of 5
in. If you want to enlarge the
photograph so that it has a height of
32 in, how wide will it need to be?
Answers
Answer:
20
Step-by-step explanation:
You need to times 8*4 to get 32 therefore u times 5*4 to get 20
please solve the given problem
Answers
Answer:
x = -47.1
x = -3.35454... (2-digit repeat)
Step-by-step explanation:
Each of the absolute value functions causes the overall behavior of the equation to change where that absolute value function's argument is zero. Those values of x are -7, -5/2, -2/5.
These breakpoints cause the domain of the equation to be divided into 4 parts. A graphing calculator shows us that solutions exist only in the two regions ...
x < -7-7 ≤ x < -5/2In those regions, the equation simplifies to ...
x < -72(-(x +2/5)) -2(-(x +7)) = 2/3x +(-(x +5/2))
x(-2 +2) -4/5 +14 = x(2/3 -1) -5/2 . . . . collect terms
15.7 = -1/3x . . . . . . add 5/2
x = -47.1 . . . . . . . multiply by -3
__
-7 ≤ x < -5/22(-(x +2/5)) -2(x +7) = 2/3x +(-(x +5/2))
x(-2 -2) -4/5 -14 = x(2/3 -1) -5/2 . . . . collect terms
(-3 2/3)x = 12.3 . . . . . . . . add 1/3x +14.8
x = -36.9/11 = -369/110
x = -3 39/110 ≈ -3.35454... (2-digit repeat)
Which graph represents the function f(x) = –x2 + 5? On a coordinate plane, a parabola opens down. It goes through (negative 3, negative 4), has a vertex at (0, 5), and goes through (3, negative 4). On a coordinate plane, a parabola opens up. It goes through (negative 2, 9), has a vertex at (0, 5), and goes through (2, 9). On a coordinate plane, a parabola opens down. It goes through (negative 6, negative 9), has a vertex at (negative 5, 0), and goes through (negative 2, negative 9). On a coordinate plane, a parabola opens up. It goes through (negative 8, 9), has a vertex at (negative 5, 0), and goes through (negative 2, 10).
Answers
Answer:
The graph in the attached figure
Step-by-step explanation:
we have the quadratic function
[tex]f(x)=-x^2+5[/tex]
This is a vertical parabola open downward
The vertex is a maximum
Remember that
The equation of a vertical parabola in vertex form is equal to
[tex]y=a(x-h)^2+k[/tex]
where
a is a coefficient
(h,k) is the vertex
In this problem
a=-1
(h,k)=(0,5) ----> vertex
The y-intercept is the point (0,5) ---> value of y when the value of x is equal to zero (is the same point that the vertex)
The x-intercepts are the points --->values of x when the value of y is equal to zero
using a graphing tool
The graph in the attached figure
Answer:
A on edge
Step-by-step explanation:
i took the test
Convert 85° to degrees Fahrenheit.
If necessary, round your answer to the nearest tenth of a degree.
Here are the formulas.
Answers
answer :
[tex]C=\frac{265}{9}[/tex]
work:
[tex]F=85[/tex] °[tex]C[/tex]
[tex]F= 85[/tex] into [tex]C=\frac{5}{9}(F-32)[/tex]
[tex]C=\frac{5}{9}[/tex] x [tex](85-32)[/tex]
[tex]C=\frac{265}{9}[/tex]
Which expression is equivalent to -36-8
Answers
. Estimate the sum of 277 and 854 and write them in Roman numerals.
Answers
Answer:
The answer is MC = 1100. The real answer is 1131 but I have estimated the answer to the nearest hundred.
Step-by-step explanation:
I just added them up to get the real answer. The real answer is 1131 but I have estimated the answer to the nearest hundred.
The sum of 277 and 854 is 1131.
M = 1000
C = 100
X = 10
I = 1
x-3<9 this is a inequalite question
Answers
- - - - - - - - - - - - - - - - - - - - - - - - - - - -
[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond[/tex]
x-3<9
[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to solve:-}}}}\diamond[/tex]
✩ First, add 3 on both sides:-
[tex]\it{x < 9+3}[/tex]
Which results in
[tex]\it{x < 12}[/tex]
So the values of x less than 12 will make this inequality true.
Good luck.- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
2x+ 5y = 15
5x+10y = 35
O A. (5.-1)
O B. (5,1)
(
O C. (10,-1)
O D. (10,1)
Answers
Answer:
B.
Step-by-step explanation:
Plug in those x and y values into your equations.
(x, y) = (5, 1)
2x + 5y = 15
2(5) + 5(1) = 15
10 + 5 = 15
5x + 10y = 35
5(5) + 10(1) = 35
25 + 10 = 35
This proves those values are true. So the answer is B.
