Writing Describe another method
for solving the expression in
Exercise 1. Does this method always
work? Explain.

Answer:

parrelel

Step-by-step explanation:

Answer:

-24/25

Step-by-step explanation:

-4/5 ÷ 5/6

To divide fractions, use KFC:

-4/5 ÷ 5/6 would become -4/5 × 6/5 which is -24/25

Hope this helps!

Answer:

-24/25

Step-by-step explanation:

First you keep the first fraction and then you change the division sign to multiplication, then change the second fraction

4/5 time 6/5 and you can’t simplify so -24/25 is your answer.

Answer:

B

Step-by-step explanation:

It seems like the answer would be B since 0.4 x 0.9 = 0.36 and the intersection for answer choice B is 36 grid blocks.

The correct equation of the given grids models the problem is,

⇒ Hundred grid. Four columns shaded vertically and nine rows shaded horizontally. The intersection is 36 grid blocks.

Option B is true.

To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.

We have to given that;

Bailey wants to find the value of 0.4 × 0.9.

Now,

After multiplication, we get;

⇒ 0.4 × 0.9

⇒ 0.36

Hence, By all the options;

The correct equation of the given grids models the problem is,

⇒ Hundred grid. Four columns shaded vertically and nine rows shaded horizontally. The intersection is 36 grid blocks.

Option B is true.

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Answer:

The next number would be 3

Step-by-step explanation:

As you can see its a repeating pattern of "1739"

Answer:

3

Step-by-step explanation:

1 7 3 9 1 7 3 9 1 7 3 9 1 7 3 9 ...

Here we need to Prove that ,

[tex]\bf\implies \sqrt[ab]{ \frac{ {x}^{a} }{ {x}^{b} } } . \sqrt[bc]{ \frac{ {x}^{b} }{ {x}^{c} } } . \sqrt[ca]{ \frac{ {x}^{c} }{ {x}^{a} } } = 1.[/tex]

Lets start with LHS , which is ,

[tex]\bf\implies LHS = \sqrt[ab]{ \dfrac{ {x}^{a} }{ {x}^{b} } } . \sqrt[bc]{ \dfrac{ {x}^{b} }{ {x}^{c} } } . \sqrt[ca]{ \dfrac{ {x}^{c} }{ {x}^{a} } } [/tex]

We know that ,

[tex]\bf\implies \sqrt[n]{k^m }= k^{\frac{m}{n}}[/tex]

• So that ,

[tex]\bf\implies \sqrt[ab]{x^{a-b}} . \sqrt[bc]{x^{b-c}} .\sqrt[ac]{x^{c-a}} \\\\\bf\implies x^{\frac{a-b}{ab}} . x ^{\frac{b-c}{bc}} .x^{\frac{c-a}{ca}} \\\\\bf\implies x^{\frac{ ac - bc + ab - ac + bc - ba }{abc } }\\\\\bf\implies x^{\frac{0}{abc}} \\\\\bf\implies x^0 \\\\\bf\implies 1 = RHS [/tex]

Hence ,

[tex]\implies \boxed{\bf \red{ LHS = RHS }} [/tex]

[tex]\large\underline{\sf{Solution-}}[/tex]

Consider LHS:

[tex]\sf= \sqrt[\sf ab]{\dfrac{\sf x^{a}}{\sf x^{b}}}\cdot \sqrt[\sf bc]{\dfrac{\sf x^{b}}{\sf x^{c}}}\cdot \sqrt[\sf ac]{\dfrac{\sf x^{c}}{\sf x^{a}}}[/tex]

As we know that:

[tex]\sf\red\leadsto\dfrac{x^{a}}{x^{b}}=x^{a-b}[/tex]

We get:

[tex]\sf= \sqrt[\sf ab]{\sf x^{a-b}}\cdot \sqrt[\sf bc]{\sf x^{b-c}}\cdot \sqrt[\sf ac]{\sf x^{c-a}}[/tex]

We can also write it as:

[tex]\sf= x^{\dfrac{a-b}{ab}}\cdot x^{\dfrac{b-c}{bc}}\cdot x^{\dfrac{c-a}{ac}}[/tex]

We know that:

[tex]\sf \red\leadsto x^{a}\cdot x^{b}=x^{a+b}[/tex]

We get:

[tex]\sf= x^{\bigg(\dfrac{a-b}{ab}+\dfrac{b-c}{bc}+\dfrac{c-a}{ac}\bigg)}[/tex]

[tex]\sf= x^{\bigg(\dfrac{c(a-b)+a(b-c)+b(c-a)}{abc}\bigg)}[/tex]

[tex]\sf= x^{\bigg(\dfrac{ac-bc+ab-ac+bc-ab}{abc}\bigg)}[/tex]

[tex]\sf= x^{\bigg(\dfrac{0}{abc}\bigg)}[/tex]

[tex]\sf= x^{0}[/tex]

[tex]\sf=1[/tex]

[tex]\textsf{= RHS}\\[/tex]

Answer:

Step-by-step explanation:

x^2 + 18x + 81 = 0

x^2 + 9x + 9x + 81 = 0

x(x+9) + 9(x+9) = 0

(x + 9)(x + 9) = 0

(x + 9) = 0

x + 9 = 0

x = 0 - 9

Finite approximation method of estimating the area under the curve of the

given function makes use of rectangular approximation of the area.

The correct responses are;

i) The estimated area using a lower sum with two rectangles of equal width is 1,715 square units.

ii) The estimated area using a lower sum with four rectangles of equal width is 3,001.25 square units.

iii) The estimated area using an upper sum with two rectangles of equal width is 8,575 square units.

iv) The estimated area using a upper sum with four rectangles of equal width is 6,431.25 square units.

Reasons:

The given function is f(x) = 5·x²

The given domain is x₀ to x₁₄

i) Estimate using lower sum with two rectangles of equal width;

[tex]Let \ \Delta x = \dfrac{14}{2} = 7 \ we \ get;[/tex]

f(0) = 0

f(7) = 5 × 7² = 245

A = 0 × 7 + 245 × 7 = 1,715

The estimated area using a lower sum with two rectangles of equal width

is 1,715 square units.

ii) Estimate using lower sum with four rectangles of equal width;

[tex]Let \ \Delta x = \dfrac{14}{4} = 3.5 \ we \ get;[/tex]

f(0) = 0

f(3.5) = 5 × 3.5² = 61.25

f(7) = 5 × 7² = 245

f(10.5) = 5 × 10.5² = 551.25

A = 0 × 3.5 + 61.25 × 3.5 + 245 × 3.5 + 551.25 × 3.5 = 3,001.25

The estimated area using a lower sum with four rectangles of equal width is 3,001.25 square units.

iii) Estimate using an upper sum with two rectangles of equal width;

[tex]Let \ \Delta x = \dfrac{14}{2} = 7 \ we \ get;[/tex]

f(7) = 5 × 7² = 245

f(14) = 5 × 14² = 980

A = 245 × 7 + 980 × 7 = 8575

The estimated area using an upper sum with two rectangles of equal width

is 8,575 square units.

iv) Estimate using an upper sum with four rectangles of equal width;

[tex]Let \ \Delta x = \dfrac{14}{4} = 3.5 \ we \ get;[/tex]

f(3.5) = 5 × 3.5² = 61.25

f(7) = 5 × 7² = 245

f(10.5) = 5 × 10.5² = 551.25

f(14) = 5 × 14² = 980

A = 61.25 × 3.5 + 245 × 3.5 + 551.25 × 3.5 + 980 × 3.5 = 6,431.25

The estimated area using a upper sum with four rectangles of equal width

is 6,431.25 square units.

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[tex] = \: \: \: \sqrt[4]{ {x}^{3} + 15 \sqrt{x} + 75 \sqrt[4]{x} + 125 } [/tex]

hope it helps

see the attachment

Answer:

4000

Step-by-step explanation:

Therefore, the answer is 4000.

Answer:

$300

Step-by-step explanation:

Diane's interest rate on the loan is approximately 8.43%.

Let's determine Diane's interest rate step by step.

1. First, we need to understand the formula for simple interest:

  Simple Interest (SI) = Principal (P) × Rate (R) × Time (T)

  where:

  P = Principal amount (initial loan amount)

  R = Interest rate (unknown, what we want to find)

  T = Time period in years

2. We have the following information from the problem:

  P = $3000 (Principal amount)

  SI = $253 (Total interest paid)

  T = 11 months

3. However, to use the formula, we need to convert the time from months to years. Since 1 year has 12 months, we can write:

  T = 11 months ÷ 12 months/year

     ≈ 0.917 years

4. Now, let's rearrange the formula to solve for the interest rate (R):

  R = SI / (P × T)

  Substituting the given values:

  R = $253 / ($3000 × 0.917) ≈ 0.0925

5. Finally, we need to convert the interest rate from a decimal to a percentage:

  R = 0.0925 × 100 ≈ 8.43%

So, Diane's interest rate on the loan is approximately 8.43%.

In summary, to find the interest rate, we used the simple interest formula and rearranged it to solve for the rate. We converted the time from months to years before calculating the interest rate. The result is approximately 8.43% interest rate, indicating the percentage of the principal that Diane had to pay as interest over 11 months.

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Answer:

4,287 x 6 = 25,722

.......

Usando un sistema de ecuaciones, hay que se elaboraron 6 títulos y 16 actas.

Para el sistema, hay que:

Total de 22 operaciones, o sea:

[tex]x + y = 22[/tex]

$3500 por elaborar un título de propiedad y $2000 por el acta constitutiva de una empresa. Ingreso total de $53000, o sea:

[tex]3500x + 2000y = 53000[/tex]

De el primer ecuación:

[tex]y = 22 - x[/tex]

Reemplazando en la segunda:

[tex]3500x + 2000y = 53000[/tex]

[tex]3500x + 2000(22 - x) = 53000[/tex]

[tex]1500x = 9000[/tex]

[tex]x = \frac{9000}{1500}[/tex]

[tex]x = 6[/tex]

[tex]y = 22 - x = 22 - 6 = 16[/tex]

Se elaboraron 6 títulos y 16 actas.

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Answer:

there's no questions haha, ty sa points

Answer:can you plz give us the question

Step-by-step explanation:

plz mark brainliest i need 5 of them

Answer:

estimating it's 548/9

Step-by-step explanation:

Answer:

1.1

Step-by-step explanation:

slope = (-4-7)/(-6-4)= -11/-10 = 1.1

The intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²

Decibel level, dB = 10log₁₀(I/I₀) where dB = decibel level = 156, I = intensity at 156 dB and I₀ = 10⁻¹² W/m².

Since we require I, making I subject of the formula, we have

dB/10 = log₁₀(I/I₀)

[tex]\frac{I}{I_{0} } = 10^{\frac{dB}{10} } \\I = I_{0} 10^{\frac{dB}{10} }[/tex]

Substituting the values of the variables into the equation, we have

[tex]I = I_{0} 10^{\frac{dB}{10} }\\I = 10^{-12} 10^{\frac{156}{10} }\\I = 10^{-12} 10^{15.6}\\I = 10^{15.6-12} \\I = 10^{3.6} W/m^{2}[/tex]

I = 3981.072W/m²

I = 3.981 × 10³ W/m²

So, the intensity of sound which the decibel level of the sound measures 156 is 3.981 × 10³ W/m²

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Answer:

........................

Answer:

Cost of each pendant = $2.80

Step-by-step explanation:

Since we're given information regarding the total cost of beads, $13.20, and the total cost of beads and pendants for all 4 necklaces, $24.40:

Let b = beads

p = pendants

C = total cost of beads and pendants for all 4 necklaces.

b + p = C

$13.20 + p  = $24.40

$13.20 - $13.20 + p  = $24.40 - $13.20

p = $11.20 (This represents the total cost of 4 pendants).

To find out the cost of each pendant, divide $11.20 by 4:

$11.20 ÷ 4 = $2.80

Therefore, the cost of each pendant is $2.80.

Answer:

I'm 50% sure it's $7.52 though I may be wrong

Answer:

$166.66

Step-by-step explanation:

if 6 items =$1000

1 item= ?

1item×$1000/6items

=$166.66

Answer:

29in

pls give brainliest tq

have a great day

Testing the conditions, we get that [tex]np = 58 \geq 10[/tex] and [tex]n(1 - p) = 42 \geq 10[/tex], thus, this binomial experiment can be approximated using a normal distribution.

For each person sampled, there are only two possible outcomes. Either they believe in Hell, or they do not. The probability of a person believing in hell is independent of any other person, which means that the binomial distribution is used to solve this question.

Binomial distribution:

Probability of x successes on n trials, with p probability.

If [tex]np \geq 10[/tex] and [tex]n(1 - p) \geq 10[/tex], it can be approximated to the normal distribution.

In this problem:

Then

[tex]np = 100(0.58) = 58 \geq 10[/tex]

[tex]n(1 - p) = 100(0.42) = 42 \geq 10[/tex]

[tex]np = 58 \geq 10[/tex] and [tex]n(1 - p) = 42 \geq 10[/tex], thus, this binomial experiment can be approximated using a normal distribution.

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Answer:

x= 45°

y= 95°

z= 85°

hope this helps <3

Answer:

Step-by-step explanation:

x= 50

y+25=180(because it is on a straight line)

y+25=180

y+25=180

y+25-25= 180-25

y+0= 155

y= 155

z+ y=180

z+ 155= 180

z+ 155- 155 =180-155

z+ 0 =  25

z = 25

x = 50

y = 155

z = 25

Using the compound interest formula, the amount of money in the man's bank account in the second year is $100352

The compound interest relationship is computed using the relation :

Plugging the values into the formula :

Final amount = 80000(1 + 12%)²

Final amount = 80000(1 + 0.12)²

Final amount = 80000(1.12)²

Final amount = $100352

Therefore, the final amount in the second year is $100352

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Answer:

7w

Step-by-step explanation:

Simplify the parenthesis first

(13-6)=7

Then multiply by the w

7*w=7w

(13-6)*w=7w

* Can be rewritten as (13-6)w or w(13-6) or w*(13-6).

Answer:

52

Step-by-step explanation:

All of these are odd numbers 52 isn't not a odd number so it doesn't belong...

Answer:

D 36

Step-by-step explanation:

Write the information algebraically

c = 3a

c + a = 48

c = children, a = adults

In the second sentence (in bold), we can replace c with 3a

c + a = 48 → 3a + a = 48

Simplify

3a + a = 48 → 4a = 48 → a = 12 (divide both sides by 4)

We can then substitute or plug in a = 12 into the original equation:

c + a = 48 → c + 12 = 48 → c = 36 (subtract 12 from both sides)