When the weight moves, it has kinetic energy. Is this energy the result of a transfer or a transformation of energy from the spring? A transfer of energy means that the energy does not change form but is shifted from one object to another.

Explanation: a reduction in genetic diversity and discomfort for animals that have very exaggerated characteristics.

Answer:

1 / f = 1 / i + 1 / o             1 / f = (o + i) / i o

f = i o / (o + i)

f = -26.5 * 8.25 / (8.25 - 26.8)

f = -221 / -.308 = 11.8 cm

Answer:

B. has the greatest mass

Explanation:

mass & distance affect pull

grativy affects speed & shape of orbit of the planet

quiziz

Answer:

5 Oxygen , 3 Carbon dioxide and 3 water

Answer: the answer is 5

Blood travels through the body in tubes called arteries and veins.

Blood vessels are tubes through which the blood circulates in the body. Blood vessels include the following;

Thus, we can conclude that blood travels through the body in tubes called arteries and veins.

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(1) The thermal energy absorbed by the Carnot engine is 7.15 x 10⁸ J.

(2) The thermal energy lost per hour by the Carnot engine is 2.75 x 10⁸ J.

The thermal energy absorbed by the heat engine is calculated as follows;

[tex]Q_h = \frac{P\Delta t}{1 - T_c/T_h}[/tex]

where;

[tex]Q_h = \frac{(122,000) \times (3600)}{1 - \frac{282}{731} } \\\\Q_h = 7.15\times 10^8 \ J[/tex]

The thermal energy lost per hour by the heat engine is calculated as follows;

[tex]Q_c = Q_h - P\Delta t\\\\Q_c = (7.15 \times 10^8 )\ - \ (122,000 \times 3600)\\\\Q_c = 2.75 \times 10^8 \ J[/tex]

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Answer:

The correct answer is C

Explanation:

Hope this helped :)

if im wrong pls tell me.

Answer:

W = 1/2 x P x E

Explanation:

Let :

Formula

Solving

Let's see

[tex]\\ \rm\rightarrowtail W=P\vec{E}(cos\theta_i-cos\theta_f)[/tex][tex]\\ \rm\rightarrowtail W=P\vec{E}(cos0-cos60)[/tex]

[tex]\\ \rm\rightarrowtail W=P\vec{E}(1-1/2)[/tex]

[tex]\\ \rm\rightarrowtail W=\dfrac{P\vec{E}}{2}[/tex]

Answer:

Explanation:

Los keyloggers son software o hardware que tienen la función de guardar la información que se escribe en el teclado de una computadora.

Un keylogger es un término para referirse a un software o hardware que tiene la función de seguir y registrar todas y cada una de las pulsaciones que se hacen en el teclado de una computadora.

Generalmente, los keyloggers son formar ilícitas de obtener información confidencial del usuario de un computador sin su consentimiento. En los últimos años, se ha relacionado a los keyloggers con actividad digital delictiva debido a que es una de las formas que utilizan los criminales para robar información confidencial como cuentas bancarias.

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Answer:

It is called Motion Energy

Explanation:

The sound intensity level of 100 physics professors talking simultaneously is equal to 72 decibel.

Given the following data:

Sound intensity can be defined as a measure of the power of a sound wave per unit area. Thus, sound intensity is a quantity that can be used to measure the energy of sound and its unit of measurement is Watts per square meter.

Mathematically, sound intensity level is given by this formula:

[tex]\beta = 10 log(\frac{I}{I_{ref}} )[/tex]

Note: The reference value of sound intensity is equal to [tex]1.0 \times 10^{-12}\;W/m^2[/tex]

Thus, the sound intensity for one (1) professor is given by:

[tex]I_1 = 1.0 \times 10^{-12} \times 10^{5.2}\\\\I_1=1.585 \times 10^{-7}\;W/m^2[/tex]

For 100 professors, the sound intensity is:

[tex]I_{100} = 1.585 \times 10^{-7} \times 100\\\\I_{100}=1.585 \times 10^{-5}\;W/m^2[/tex]

Substituting the parameters into the formula, we have;

[tex]\beta = 10 log(\frac{1.585 \times 10^{-5}}{1.0 \times 10^{-12}})\\\\\beta = 10 log(15.58 \times 10^{6})\\\\\beta = 10 \times 7.2\\\\\beta =72\;dB[/tex]

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Complete Question:

One physics professor talking produces a sound intensity level of 52 dB. It's a frightening idea, but what would be the sound intensity level of 100 physics professors talking simultaneously?

Answer:

72dB

Explanation:

The sound intensity level of one prof is given, that's your β1 (which is equal to 52dB).

Using the sound intensity level formula:

β1= 10log ([tex]\frac{I}{I_{o} }[/tex]) = 52 dB

*This will be useful later on [even if β1 is known]

Set up the formula for β2 (β2 is going to be the new sound intensity, the one for the 100 profs):

β2 = 10 log( [tex]\frac{ 100 I}{I_{o} }[/tex] )

*You need to multiply the intensity of one professor by 100 (because now there's more)

*do some algebra- pull out the 100

β2  = 10 log (100 [tex]\frac{I}{I_{o} }[/tex])

*use log laws

β2 = 10 ( log(100) + log ([tex]\frac{I}{I_{o} }[/tex]) )

*Now, isn't there a familiar part? Well, yes! The expression for β1!

β2 = 10log(100) + β1

β2 = 10log(100) + 52dB

*use your calculator

β2 = 73dB

^^^ that's your new sound intensity level

Answer:

B) sublimation

Explanation:

An example is the vaporization of frozen carbon dioxide (dry ice) at ordinary atmospheric pressure and temperature.

Answer:

sublimation

Explanation:

sublimation, in physics, conversion of a substance from the solid to the gaseous state without its becoming liquid. An example is the vaporization of frozen carbon dioxide or dry ice(CO2)

or Solid Chlorine (Cl2) at ordinary atmospheric pressure and temperature. The phenomenon is the result of vapour pressure and

temperature relationships.

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Answer:

Thermal Energy

Explanation:

When friction acts between two surfaces that are moving over each other, some kinetic energy is transformed into heat energy. Otherwise known as thermal energy.

Answer:

D -- 12

Explanation:

Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Also remember to rate answers to help other students, While leaving thanks to answers that help you. Have a great day!

Answer:

[tex]40h[/tex]

Explanation:

Use the velocity formula to solve

[tex]v = \frac{d}{t}[/tex]

In this question, you are given velocity [tex]v = 45km/h[/tex], and you are given a distance, [tex]d = 1800km[/tex].  Time in this question is what you'll need to find.

Start by rearranging the velocity formula, to isolate for t.

[tex]v = \frac{d}{t}[/tex]

Start by multiplying both sides by t

[tex]v(t) = \frac{d}{t}(t)\\\\vt = d[/tex]

Then divide both sides by v.

[tex]vt\frac{1}{v} = d/v\\ \\t = \frac{d}{v}[/tex]

Now that you've isolated for time, sub in your values and calculate.

[tex]t = \frac{d}{v} = \frac{1800km}{45km/h} = 40 h[/tex]

Answer:

W=Fd

This is the equation for it

Answer: i would say true uwu

Explanation:hope this helps!

  ....Max-

Answer:

yes

Explanation:

as speed is a scalar quantity and velocity is a vector quantity. Which means speed only depends on the magnitude at which it travels but velocity depends on the speed at which travel and also the direction to where the object travels.

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Answer:

See below

Explanation:

KE = 1/2 m v ^2

    = 1/2 (250/1000) 300^2   j         the bullet is 250/1000  kg  ( assuming g is grams and not GRAINS - in which bullet weight is usually measured)

force to stop it is the same number

PE = mgh = .5 *9.81  *  .75 =

     doubling height will double PE

2 x 10^6  =  40 * 9.81  *  h      sove for 'h' in meters  

Initial kinetic energy is 11250 J and magnitude of force to stop bullet is 75 N.

The GPE for 0.75m height floor is 3.75J.

The GPE for double of 0.75m height is 7.5J.

The high on which 40 kg mass is lifted is 5000m.

The kinetic energy of an object is the energy that it possesses due to its motion.

[tex]KE = 1/2 m v ^2[/tex]

      [tex]=1/2 (250/1000) 300^2 J\\= 11250 J[/tex]

Work done,

[tex]W= fs\\\\f=\frac{W}{s}\\\\f=\frac{11250}{150}[/tex]

[tex]f=75 N[/tex]

Gravitational potential energy is the potential energy a massive object has in relation to another massive object due to gravity.

PE = mgh

    = .5 *9.81  *  .75

    = 3.75 J

Potential energy when height doubles = 7.5J

The potential energy is given by

[tex]PE = mgh\\\\h = PE/ mg\\\\h = 2*10^6 J /40*9.8\\\\h = 5000 m[/tex]

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 The work done on the car due to friction is -125 J.

Work is said to be done when a force moves an object through a certain distance.

To calculate the workdone on the car by friction, we use the formula below

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, The work done on the car due to friction is -125 J.

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Answer:

S = v0 t + 1/2 a t^2       a = 0 seems given in the problem

Vp  t = Vr t + 16

both travel for time t but the police car is going faster and travels 16 km farther

t (Vp - Vr) = 16

t = 16 km / (100 - 80) km/hr

t = 16 / 20 hr = 4/5 hr = 48 min

Answer:

weight = 30000 Newton

Given:

========================

[tex]\sf pressure \ (Pa)=\dfrac{force \ (N)}{area \ (m^2)}[/tex]

[tex]\dashrightarrow \sf \ 60 000 = \dfrac{force}{0.5}[/tex]

[tex]\dashrightarrow \sf \ force =60 000 *0.5[/tex]

[tex]\dashrightarrow \sf \ force =30000 \ N[/tex]

========================

Weight is the force due to gravity.

Thus, force = gravity = 30000 N

Answer:

it way the most on jupiter and the least on mars

Explanation:

Answer:

Speed Formula:

[tex]s = \frac{d}{t} [/tex]

Answer:

amount and speed of traffic on the acceleration lane and expressway.

Answer:

36.04N

Explanation:

accelerating force: mass × acceleration

F=ma

m=212/10= 21.2kg

a=1.7m/s2

F=21.2×1.7

=36.04N

Answer:

200 Nm

Explanation:

Work Done by Particular Force = Particular Force × Distance

Answer:

D.

Explanation:

The answer should be D. because if it increases by a factor of 2 then it will decrease at a factor of 4.

I hope it helps! Have a great day!

Anygays-

Answer:

5N

Explanation:

Work done by a constant force is given by the following equation:

W=F⋅d⋅cos(θ)

where F is the applied force, d is the distance over which the force is applied, and θ is the angle between the force and displacement vectors.

In this case, the work is done by gravity, and as the object is assumed to fall straight down, θ=0^o.

We know that the force of gravity acting on an object can be expressed by FG=mg, and for an object which is not accelerating (e.g. a stationary object), this is equal to the object's weight.

We know d=10m,θ=0^o and W=50J, so we can solve for F to find the object's weight. ⇒F=Wdcos (θ) But cos (0^o)=1, so: F=Wd=50J10m=5N