What ratio of nitrogen and hydrogen molecules would result in no left-over reactants? Explain your answer.

Answers

Answer 1

Answer:

1:3

Explanation:

nitrogen and hydrogen combine qt high pressure and temperature to form ammonia gas.this method is used to prepare ammonia industrially and the process is called haber's process.

the balanced equation is given as:

N2+3H2=>2NH3

we can see that 1 mole of nitrogen combines with 3 moles of hydrogen to produce 2 moles of ammonia.

hence ratio of nitrogen and hydrogen molecules should be 1:3 for reactants to get used up completely.

I hope it's helpful!


Related Questions

Find the length of time required for the total pressure in a system containing N2O5 at an initial pressure of 0.110 atm to rise to 0.150 atm .

Answers

Answer:

t = 37.1 s

Explanation:

The equation for the reaction is given as;

                  2 N2O5(g)  --> 4 NO2 + O2

Initial:          0.110                  -             -

change:        -2x                  +4x        +x

Final:          0.110 - 2x           +4x        +x

But final = 0.150atm;

0.110 - 2x    +  4x   +  x = 0.150 atm

3x = 0.150 - 0.110

x = 0.0133 atm

Pressure in reactant side;

0.110 - 2x

0.110 - 2 (0.0133) = 0.0834 atm

The integral rate law expression is given as;

ln ( [A] / [Ao] ) = -kt

k =  rate constant = 7.48*10^-3*s-1

ln (0.0834/0.11) = (7.48*10^-3)  t

upon solving, t = 37.1 s

In this exercise we have to use the knowledge of chemistry to calculate the necessary time that the pressure can hold the system, in this way we can say that this time corresponds to:

[tex]t = 37.1 s[/tex]

First we have to use the reaction equation given as:

[tex]2 N_2O_5(g) \rightarrow 4 NO_2 + O_2[/tex]

This equation can be rewritten in terms of pressure, so it will be;              

[tex]0.110 - 2X + 4X + X = 0.150 atm\\3X = 0.150 - 0.110\\X = 0.0133 atm[/tex]

Pressure in reactant side, will be:

[tex]0.110 - 2X \rightarrow 0.110 - 2 (0.0133) = 0.0834 atm[/tex]

The integral rate law expression is given as, knowing that the rate constant is  [tex]7.48*10^{-3}*s^{-1}[/tex]

[tex]\int\limits^{0.0834}_{0.11} {(7.48*10^{-3}) t} \, dt = t = 37.1 s[/tex]

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Why do plant cells need chloroplasts

Answers

In particular, organelles called chloroplasts allow plants to capture the energy of the Sun in energy-rich molecules; cell walls allow plants to have rigid structures as varied as wood trunks and supple leaves; and vacuoles allow plant cells to change size

Answer:

Plants need chloroplasts to capture light energy.

Plant cells use light energy to make food.

The cell uses the energy from food.

Hope it helps ;)

structural formula of 1 methyl butane​

Answers

Answer:

CH(CH3)2C2H5 or C5H12

Explanation:

Methyl butane or isopentane is an hydrocarbon or an alkane hydrocarbon with the formula C5H12. It has five carbons and twelve hydrogens. It is volatile and highly flammable. It has high boiling point and it can boil away at room temperature on a noon day. It is use as refrigerants. It can easily vanishes to the atmosphere when exposed

can u pls help me with this question ​

Answers

Answer:

Explanation:

Answer:

A

Explanation:

2LiClO+KHSO - Li2SO4 + Cl2 + KOOH
1. How many moles of KOOH is produced, if you started the reaction with 5 moles of
LiCIO?

Answers

Answer:

2.5 moles of KOOH are produced.

Explanation:

1)Given data:

Number of moles of KOOH produced = ?

Number of moles of LiClO = 5 mol

Solution:

Chemical equation:

2LiClO +  KHSO₄     →      Li₂SO₄ + Cl₂ + KOOH

now we will compare the moles of KOOH and LiClO.

                 LiClO          :          KOOH

                    2              :              1

                   5               :             1/2×5 = 2.5

2.5 moles of KOOH are produced.

What did Aristotle believe?
A. That matter did not exist in the physical world
B. That the scientific method should be used to test ideas
C. That all matter was composed of earth, fire, water, and air
D. That all matter was composed of tiny atoms

Answers

Answer:

C.) That all matter was composed of earth, fire, water and air

Explanation:

Just took the test

A gas mixture consists of 60.0% Ar, 30.0% Ne, and 10.0% Kr by volume. If the pressure of this gas mixture is 80.0 kPa, what is the partial pressure of each of the gases

Answers

Answer: The partial pressure of Argon , Neon and krypton are 48 kPa , 24 kPa and 8 kPa respectively.

Explanation:

According to Raoult's Law , the partial pressure of each component in the solution is equal to the total pressure multiplied by its mole fraction. It is mathematically expressed as

[tex]p_A=x_A\times P_{total}[/tex]

where, [tex]p_A[/tex] = partial pressure of component A

[tex]x_A[/tex] = mole fraction of A

[tex]P_{total}[/tex] = total pressure

mole fraction of Ar = [tex]\frac{\text {Moles of Ar}}{\text {total moles}}=\frac{60.0}{60.0+30.0+10.0}=0.6[/tex]

[tex]p_{Ar}=0.60\times 80.0kPa=48kPa[/tex]

mole fraction of Ne = [tex]\frac{\text {Moles of Ne}}{\text {total moles}}=\frac{30.0}{60.0+30.0+10.0}=0.30[/tex]

[tex]p_{Ne}=0.30\times 80.0kPa=24kPa[/tex]

mole fraction of Kr = [tex]\frac{\text {Moles of Kr}}{\text {total moles}}=\frac{10.0}{60.0+30.0+10.0}=0.10[/tex]

[tex]p_{Kr}=0.10\times 80.0kPa=8kPa[/tex]

Hydrogen has 2 naturally occurring isotopes hydrogen -1 and hydrogen-2. what is the symbol for each of these isotopes?

Answers

Answer:

Their nuclear symbols are therefore 1H, 2H, and 3H.

Explanation:

A habit is:
pls help me ty​

Answers

what class is this? (Subject)
I think it would be A?

iv. If only 174.6 g of Cu(OH)2 precipitate were actually collected from the reaction, what would the percent yield be? SHOW ALL WORK!

Answers

Answer:

59.4%

Explanation:

CuSO4(aq) + 2NaOH(aq) -----> Cu(OH)2(aq) + Na2SO4 (aq)

Ratio of molesCuSO4 to NaOH is 1:2

To determine the limiting reagent;

For CuSO4

Number of moles= 638.44g/160 = 4 moles

1 mole of CuSO4 yields 1 mole of Cu(OH)2

4 moles of CuSO4 also yields 4 moles of Cu(OH)2

For NaOH

Number of moles= 240g/40g/mol= 6 moles

2 moles of NaOH yields 1 mole of Cu(OH)2

6 moles of NaOH yields 6× 1/2 = 3 moles of Cu(OH)2

Hence NaOH is the limiting reactant.

Hence mass of Cu(OH)2 = 3 × 98 g/mol

= 294 g

% yield = actual yield/ theoretical yield × 100

% yield= 174.6 /294 × 100/1

% yield = 59.4%

The percent yield is   59.4%

Firstly write the balanced chemical equation:

CuSO₄(aq) + 2NaOH(aq) → Cu(OH)₂(aq) + Na₂SO₄ (aq)

Ratio of moles for CuSO₄ to NaOH is 1:2

To determine the limiting reagent:

For CuSO₄:

[tex]\text{Number of moles}= \frac{ 638.44g}{160}= 4 \text{moles}[/tex]

1 mole of CuSO₄ produces 1 mole of Cu(OH)₂

4 moles of CuSO₄ will produce 4 moles of Cu(OH)₂

For NaOH:

[tex]\text{Number of moles}= \frac{240g}{40g/mol} = 6 \text{moles}[/tex]

2 moles of NaOH yields 1 mole of Cu(OH)₂

6 moles of NaOH yields [tex]6*\frac{1}{2} = 3[/tex] moles of Cu(OH)₂

Hence, NaOH is the limiting reactant.

Therefore, mass of Cu(OH)₂ = [tex]3 * 98 g/mol= 294 g[/tex]

% yield = actual yield/ theoretical yield × 100

% yield= [tex]\frac{174.6}{294}* 100[/tex]

% yield = 59.4%

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Why burning gasoline in a lawnmower is not physical change

Answers

Answer:

Burning gasoline in a lawnmower is a chemical change.

Explanation:

Here, a combustion reaction takes place. Freezing water to make ice cubes, melting gold to make jewellery and boiling water for soup are examples of physical change since, only a change in physical state takes place.

A 5.00-cm cube of magnesium has a mass of 217.501 g. What is the density of magnesiummetal?

Answers

Answer:

d = 43.5 g/cm³

Explanation:

Given data:

Mass of magnesium cube = 217.501 g

Volume of magnesium cube = 5.00 cm³

Density of magnesium cube = ?

Solution:

Formula:

d = m/v

d = density

m = mass

v = volume

by putting values,

d = 217.501 g/ 5.00 cm³

d = 43.5 g/cm³

Is 4 grams of oxygen bigger than 1 mole of oxygen

Answers

Answer:

No, a mole of oxygen is about 16 grams

Explanation:

5. If two gases are present in a contain the total pressure in the container is equal to ​

Answers

Answer:

Sum of their partial pressures

Explanation:

If two gases are present in a container, the total pressure in the container is equal to the sum of their partial pressures.

This solution is based on the Dalton's Law of Partial Pressures.

Dalton's Law of Partial Pressure states that "the total pressure of a mixture of gases is equal to the sum of the partial pressures of the constituent gases".

A partial pressure is the pressure a gas would exert if it alone occupied the volume of the gas mixture.

Consider the following intermediate chemical equations.


2 equations. First: upper C (s) plus one half upper O subscript 2 (g) right arrow upper C upper O (g). Second: upper C upper O (g) plus one half upper O subscript 2 (g) right arrow upper C upper O subscript 2 (g).


How will oxygen appear in the final chemical equation?

Upper O subscript 2 (g). as a product

Upper O subscript 2 (g). as a reactant

O(g) as a product

2O(g) as a reactant

Answers

Answer:

c

Explanation:

got it right on test

Oxygen will appear in the final equation as O2 reactant.

What are chemical equation?

A chemical equations shows the interplay between reactants and products. The reactants are on the left hand side while the products are at the right  hand side.

Looking at the two equations, we know that oxygen will appear in the final equation as O2 reactant.

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What is the electron shielding effect? What is the trend for it? How and why does it happen?

Answers

Answer:

See explanation

Explanation:

In an atom, the inner electrons may shield the outer electrons from the attractive force of the nucleus. We, refer to this phenomenon as the shielding effect, It is defined as a decrease in the magnitude of attraction between an electron and the nucleus of an atom having more than one electron shell (energy level).

Shielding effect increases down the group due to addition of more shells but decreases across the period due to the increase in the size of the nuclear charge.

As the magnitude of shielding increases down the group, ionization of electrons becomes easier and the first ionization energies of elements decreases as we move down the group. Since shielding effect decreases across the period, the first ionization energies of elements increases across the period.

Methanol, or wood alcohol, is the combustible material used in sterno. Write a balanced equation for the complete oxidation reaction that occurs when methanol (CH3OH) burns in air. Use the smallest possible integer coefficients.

Answers

Answer:

2CH₃OH + 3O₂ → 2CO₂ + 4H₂O

Explanation:

A complete reaction for when any organic compound burns in air, produces only water and carbon dioxide. It does so by reacting with the oxygen gas (O₂) present in air.

In the case of methanol (CH₃OH) combustion, the balanced reaction is:

2CH₃OH + 3O₂ → 2CO₂ + 4H₂O

100. mL of 0.100 M HCl aqueous solution is mixed with 200. mL of 0.100 M CaCl2 solution to make a 300.mL solution. Find the molarity of the Cl- and pOH in the mixed solution Question 7 options:

Answers

Answer:

Explanation:

HCl    ⇄    H⁺    +   Cl⁻

HCl is a strong electrolyte so it will ionize completely .

moles of Cl⁻ in 100 mL of .1 HCl = .1 x .1 = .01 gram - ion .

CaCl₂ = Ca⁺² + 2 Cl⁻

1 mole                2 mole

moles of CaCl₂ in 200 mL of .1 M CaCl₂ = .2 x .1 = .02 gram mole  .

.02 gram mole of CaCl₂ will give 2 x .02 = .04 gram-ion of Cl⁻ ion .

Total gram - ion of Cl⁻ = .01 + .04 = .05 gram-ion .

Total volume = 300mL = .3 L

molarity of Cl⁻ = .05 / .3 = .167 M .

HCl    ⇄    H⁺    +   Cl⁻

moles of H⁺ = moles of Cl⁻ = .01 gram-ion .

volume of solution = .3 L

molarity of H⁺ = .01 / .3 = 33.33 x 10⁻³ M .

[ H⁺] [ OH⁻] = 10⁻¹⁴

33.33 x 10⁻³  [ OH⁻] = 10⁻¹⁴

[ OH⁻] = 3 x 10⁻¹³

pOH = - log[OH⁻] = - log3 x 10⁻¹³

13-log3

= 13 - .477

12.52

or ,

pH = - log[H⁺] = - log33.33 x 10⁻³

3 - log 33.33

= 3 - 1.52

= 1.48

pOH = 14 - 1.48 = 12.52

Element X has two naturally occurring isotopes, 65X (isotopic mass 65.0457 amu, abundance 20.53%) and 67X (isotopic mass 66.9704 amu, abundance 79.47%). Calculate the atomic mass of element X.

Answers

Answer:

66.5753 amu

Explanation:

From the question given above, the following data were obtained:

Isotope A (⁶⁵X):

Mass of A = 65.0457 amu

Abundance of A = 20.53%

Isotope B (⁶⁷X):

Mass of B = 66.9704 amu

Abundance of B = 79.47%

Atomic mass of X =?

The atomic mass of X can be obtained as follow:

Atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100]

= [(65.0457 × 20.53)/100] + [(66.9704 × 79.47)/100]

= 13.3539 + 53.2214

= 66.5753 amu

Therefore, the atomic mass of X is 66.5753 amu.

Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu,  79.47%).

What is the average atomic mass?

The average atomic mass (atomic mass) of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance.

Element X has 2 isotopes:

⁶⁵X with an isotopic mass of 65.0457 amu and an abundance of 20.53% (0.2053).⁶⁷X with an isotopic mass of 66.9704 amu and an abundance of 79.47% (0.7947).

We can calculate the average atomic mass of X using the following expression.

mX = m⁶⁵X × ab⁶⁵X + m⁶⁷X × ab⁶⁷X

mX = 65.0457 amu × 0.2053 + 66.9704 amu × 0.7947

mX = 66.58 amu

Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu,  79.47%).

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what are examples of actinides

Answers

Answer:

Neptunium, Protactinium, plutonium and more

Explanation:

What is the answer to this?

Answers


I think C is the correct answer

A 25.00 mL sample of H 2SO 4 requires 31.43 mL of 0.110 M NaOH to reach the equivalence point. What is the molarity of the H 2SO 4

Answers

Answer:

0.069 M

Explanation:

Equation of the reaction:

H₂SO₄(aq) + 2NaOH(aq) ⇒ Na₂SO₄(aq)+2H₂O(l)

From the equation above, 2 mole of NaOH is required to  reach equivalent point with 1 mole of H₂SO₄.

n'CV = nC'V' ........................ Equation 1

Where n and n' = are number of moles of acid and base respectively, C and C' = are molarities of acid and base respectively, V and V' are volumes of acid and base respectively.

make C the subject of the equation

C = nC'V'/n'V.............................. Equation 2

Given: n = 1, n' = 2, C' = 0.11 M, V = 25 mL, V' = 31.43 mL

Substitute into equation 2

C = (1×0.11×31.43)/(25×2)

C = 0.069 M.

Hence the molarity of H₂SO₄ is 0.069 M

photo attached

if anyone from my class sees this no you didn't

Answers

Answer:

I think its b or c

Explanation:

hope this helps I mainly think b

what kind of structure do the cations and anions in table salt form

Answers

Answer:

ionic solids

Explanation:

Ionic solids are a regular pattern of cations and anions that arrange themselves into a continuous solid network.

NaCl is composed of sodium ions and chloride ions that are held together by Coulumbic attractive forces to form a large crystal structure.

Such ionic solids have a very high melting point and do not conduct electricity in the sold state. However, the molten substance or a solution of the substance conducts electricity.

Convert this measurement, 3.2x10-3 mm, from scientific notation to standard notation

Answers

Answer:

0.0032mm

Explanation:

Given dimension:

Measurement  = 3.2 x 10⁻³mm

Unknown:

Write in standard notation from scientific notation = ?

Solution:

The standard notation is the way we normally write.

   For example;   standard notation of 1 million is 1000000

Now;

        3.2 x 10⁻³  =   [tex]\frac{3.2}{1000}[/tex]    = 0.0032mm

3.2x10⁻³ mm in standard notation is 0.0032 mm. The normal or generally accepted manner of representing or expressing anything is referred to as standard notation.

Standard notation refers to the conventional or widely accepted way of representing or expressing something. In mathematics, for example, standard notation refers to the commonly used symbols and formats for writing mathematical expressions, equations, or numbers. The use of standard notation ensures uniformity, ease of understanding, and communication among mathematicians and students. Powers of 10 are used in scientific notation to express extremely large or extremely small quantities. 3.2x10⁻³ mm in standard notation is 0.0032 mm.

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Suppose you have two identical 1.0 L sealed containers. Both containers are kept at exactly 25oC. One vessel contains only neon gas at 1.5 atm, and the other contains only xenon gas at 2.5 atm.


A) Is the average kinetic energy possessed by the neon atoms greater than, equal to, or less than that of the xenon atoms? Explain.



B) What variable must be changed in order to decrease the average kinetic energy of the xenon atoms?



C) Does the vessel with the xenon gas contain more, fewer, or the same number of gas particles as the vessel of neon gas? Explain.

Answers

Answer:

See explanation

Explanation:

a)  The average kinetic energy of the molecules of a gas depends on the temperature and the molar mass of the gas. However, at the same temperature, all gases have the same average kinetic energy. Hence Xe and Ne atoms have the same average kinetic energy.

b) To decrease the kinetic energy of Xe atoms the temperature must be changed. When the temperature is changed, Xe a lower average kinetic energy due to its larger molar mass.

c) All gases occupying the same volume have equal number of particles at the same temperature and pressure according to Avogadro's law. Therefore, since Xe and Ne occupy the same volume at the same temperature but different pressures they do not contain the same number of particles. Xe gas contains more particles because there are more moles of Xe gas present than moles of Ne gas. The greater the number of moles of gas present, the more the number of gas particles present.

Which of the following substances would form when aluminum and sulfur undergo a combination/synthesis reaction?

Answers

Aluminum and Sulfur react to produce Aluminum sulfide(Al₂S₃)

Further explanation

Given

The reaction of Aluminium and Sulfur

Required

The products of the reaction

Solution

There are several types of reactions that can occur

Synthesis/combination reaction : 2 elements combine to form a single product

The general formula :

A + B ⇒ AB

For reaction above :

2Al + 3S ⇒ Al₂S₃

The chemical equation below shows the combustion of propane (C3H8).

C3H8 + 5O2 Right arrow. 3CO2 + 4H2O

The molar mass of oxygen gas (O2) is 32.00 g/mol. The molar mass of C3H8 is 44.1 g/mol. What mass of O2, in grams, is required to completely react with 0.025 g C3H8?
0.018
0.034
0.045
0.091

Answers

Answer:

0.091

Explanation:

just took test on edg

Answer:

0.091

Explanation:

correct on edge 2021 unit test

What does the last line of the poem suggest

Answers

Answer:

that the poem needs to be finished heh pog

Explanation:

Answer:

Where is the poem?

Explanation:

Object A has a density of 2.0 and a mass of 100 g. Object B a density of 0.8 and a mass of 240 g. Object Ca
density of 5.0
and a mass of 100 g. Which of the objects above (A, B, or C) has the least volume?
cm

Answers

I beleve its B if not im sorry

To determine which object has the least volume, we can calculate the volume of each object using the formula of density. From this, Object C has the smallest volume of 20 cm³ among Objects A, B, and C.

The formulae of volume:

Volume = Mass / Density

Let's calculate the volumes of objects A, B, and C:

For Object A:

Density = 2.0 g/cm³

Mass = 100 g

Volume of A = Mass / Density

Volume of A = 100 g / 2.0 g/cm³

Volume of A = 50 cm³

For Object B:

Density = 0.8 g/cm³

Mass = 240 g

Volume of B = Mass / Density

Volume of B = 240 g / 0.8 g/cm³

Volume of B = 300 cm³

For Object C:

Density = 5.0 g/cm³

Mass = 100 g

Volume of C = Mass / Density

Volume of C = 100 g / 5.0 g/cm³

Volume of C= 20 cm³

Comparing the volumes, we find that Object C has the least volume, with 20 cm³.

Therefore, Object C has the smallest volume among Objects A, B, and C.

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