Answer:
1:3
Explanation:
nitrogen and hydrogen combine qt high pressure and temperature to form ammonia gas.this method is used to prepare ammonia industrially and the process is called haber's process.
the balanced equation is given as:
N2+3H2=>2NH3
we can see that 1 mole of nitrogen combines with 3 moles of hydrogen to produce 2 moles of ammonia.
hence ratio of nitrogen and hydrogen molecules should be 1:3 for reactants to get used up completely.
I hope it's helpful!
Find the length of time required for the total pressure in a system containing N2O5 at an initial pressure of 0.110 atm to rise to 0.150 atm .
Answer:
t = 37.1 s
Explanation:
The equation for the reaction is given as;
2 N2O5(g) --> 4 NO2 + O2
Initial: 0.110 - -
change: -2x +4x +x
Final: 0.110 - 2x +4x +x
But final = 0.150atm;
0.110 - 2x + 4x + x = 0.150 atm
3x = 0.150 - 0.110
x = 0.0133 atm
Pressure in reactant side;
0.110 - 2x
0.110 - 2 (0.0133) = 0.0834 atm
The integral rate law expression is given as;
ln ( [A] / [Ao] ) = -kt
k = rate constant = 7.48*10^-3*s-1
ln (0.0834/0.11) = (7.48*10^-3) t
upon solving, t = 37.1 s
In this exercise we have to use the knowledge of chemistry to calculate the necessary time that the pressure can hold the system, in this way we can say that this time corresponds to:
[tex]t = 37.1 s[/tex]
First we have to use the reaction equation given as:
[tex]2 N_2O_5(g) \rightarrow 4 NO_2 + O_2[/tex]
This equation can be rewritten in terms of pressure, so it will be;
[tex]0.110 - 2X + 4X + X = 0.150 atm\\3X = 0.150 - 0.110\\X = 0.0133 atm[/tex]
Pressure in reactant side, will be:
[tex]0.110 - 2X \rightarrow 0.110 - 2 (0.0133) = 0.0834 atm[/tex]
The integral rate law expression is given as, knowing that the rate constant is [tex]7.48*10^{-3}*s^{-1}[/tex]
[tex]\int\limits^{0.0834}_{0.11} {(7.48*10^{-3}) t} \, dt = t = 37.1 s[/tex]
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Why do plant cells need chloroplasts
Answer:
Plants need chloroplasts to capture light energy.
Plant cells use light energy to make food.
The cell uses the energy from food.
Hope it helps ;)
structural formula of 1 methyl butane
Answer:
CH(CH3)2C2H5 or C5H12
Explanation:
Methyl butane or isopentane is an hydrocarbon or an alkane hydrocarbon with the formula C5H12. It has five carbons and twelve hydrogens. It is volatile and highly flammable. It has high boiling point and it can boil away at room temperature on a noon day. It is use as refrigerants. It can easily vanishes to the atmosphere when exposed
can u pls help me with this question
Answer:
Explanation:
Answer:
A
Explanation:
2LiClO+KHSO - Li2SO4 + Cl2 + KOOH
1. How many moles of KOOH is produced, if you started the reaction with 5 moles of
LiCIO?
Answer:
2.5 moles of KOOH are produced.
Explanation:
1)Given data:
Number of moles of KOOH produced = ?
Number of moles of LiClO = 5 mol
Solution:
Chemical equation:
2LiClO + KHSO₄ → Li₂SO₄ + Cl₂ + KOOH
now we will compare the moles of KOOH and LiClO.
LiClO : KOOH
2 : 1
5 : 1/2×5 = 2.5
2.5 moles of KOOH are produced.
What did Aristotle believe?
A. That matter did not exist in the physical world
B. That the scientific method should be used to test ideas
C. That all matter was composed of earth, fire, water, and air
D. That all matter was composed of tiny atoms
Answer:
C.) That all matter was composed of earth, fire, water and air
Explanation:
Just took the test
A gas mixture consists of 60.0% Ar, 30.0% Ne, and 10.0% Kr by volume. If the pressure of this gas mixture is 80.0 kPa, what is the partial pressure of each of the gases
Answer: The partial pressure of Argon , Neon and krypton are 48 kPa , 24 kPa and 8 kPa respectively.
Explanation:
According to Raoult's Law , the partial pressure of each component in the solution is equal to the total pressure multiplied by its mole fraction. It is mathematically expressed as
[tex]p_A=x_A\times P_{total}[/tex]
where, [tex]p_A[/tex] = partial pressure of component A
[tex]x_A[/tex] = mole fraction of A
[tex]P_{total}[/tex] = total pressure
mole fraction of Ar = [tex]\frac{\text {Moles of Ar}}{\text {total moles}}=\frac{60.0}{60.0+30.0+10.0}=0.6[/tex]
[tex]p_{Ar}=0.60\times 80.0kPa=48kPa[/tex]
mole fraction of Ne = [tex]\frac{\text {Moles of Ne}}{\text {total moles}}=\frac{30.0}{60.0+30.0+10.0}=0.30[/tex]
[tex]p_{Ne}=0.30\times 80.0kPa=24kPa[/tex]
mole fraction of Kr = [tex]\frac{\text {Moles of Kr}}{\text {total moles}}=\frac{10.0}{60.0+30.0+10.0}=0.10[/tex]
[tex]p_{Kr}=0.10\times 80.0kPa=8kPa[/tex]
Hydrogen has 2 naturally occurring isotopes hydrogen -1 and hydrogen-2. what is the symbol for each of these isotopes?
Answer:
Their nuclear symbols are therefore 1H, 2H, and 3H.
Explanation:
A habit is:
pls help me ty
iv. If only 174.6 g of Cu(OH)2 precipitate were actually collected from the reaction, what would the percent yield be? SHOW ALL WORK!
Answer:
59.4%
Explanation:
CuSO4(aq) + 2NaOH(aq) -----> Cu(OH)2(aq) + Na2SO4 (aq)
Ratio of molesCuSO4 to NaOH is 1:2
To determine the limiting reagent;
For CuSO4
Number of moles= 638.44g/160 = 4 moles
1 mole of CuSO4 yields 1 mole of Cu(OH)2
4 moles of CuSO4 also yields 4 moles of Cu(OH)2
For NaOH
Number of moles= 240g/40g/mol= 6 moles
2 moles of NaOH yields 1 mole of Cu(OH)2
6 moles of NaOH yields 6× 1/2 = 3 moles of Cu(OH)2
Hence NaOH is the limiting reactant.
Hence mass of Cu(OH)2 = 3 × 98 g/mol
= 294 g
% yield = actual yield/ theoretical yield × 100
% yield= 174.6 /294 × 100/1
% yield = 59.4%
The percent yield is 59.4%
Firstly write the balanced chemical equation:
CuSO₄(aq) + 2NaOH(aq) → Cu(OH)₂(aq) + Na₂SO₄ (aq)
Ratio of moles for CuSO₄ to NaOH is 1:2
To determine the limiting reagent:
For CuSO₄:
[tex]\text{Number of moles}= \frac{ 638.44g}{160}= 4 \text{moles}[/tex]
1 mole of CuSO₄ produces 1 mole of Cu(OH)₂
4 moles of CuSO₄ will produce 4 moles of Cu(OH)₂
For NaOH:
[tex]\text{Number of moles}= \frac{240g}{40g/mol} = 6 \text{moles}[/tex]
2 moles of NaOH yields 1 mole of Cu(OH)₂
6 moles of NaOH yields [tex]6*\frac{1}{2} = 3[/tex] moles of Cu(OH)₂
Hence, NaOH is the limiting reactant.
Therefore, mass of Cu(OH)₂ = [tex]3 * 98 g/mol= 294 g[/tex]
% yield = actual yield/ theoretical yield × 100
% yield= [tex]\frac{174.6}{294}* 100[/tex]
% yield = 59.4%
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Why burning gasoline in a lawnmower is not physical change
Answer:
Burning gasoline in a lawnmower is a chemical change.
Explanation:
Here, a combustion reaction takes place. Freezing water to make ice cubes, melting gold to make jewellery and boiling water for soup are examples of physical change since, only a change in physical state takes place.
A 5.00-cm cube of magnesium has a mass of 217.501 g. What is the density of magnesiummetal?
Answer:
d = 43.5 g/cm³
Explanation:
Given data:
Mass of magnesium cube = 217.501 g
Volume of magnesium cube = 5.00 cm³
Density of magnesium cube = ?
Solution:
Formula:
d = m/v
d = density
m = mass
v = volume
by putting values,
d = 217.501 g/ 5.00 cm³
d = 43.5 g/cm³
Is 4 grams of oxygen bigger than 1 mole of oxygen
Answer:
No, a mole of oxygen is about 16 grams
Explanation:
5. If two gases are present in a contain the total pressure in the container is equal to
Answer:
Sum of their partial pressures
Explanation:
If two gases are present in a container, the total pressure in the container is equal to the sum of their partial pressures.
This solution is based on the Dalton's Law of Partial Pressures.
Dalton's Law of Partial Pressure states that "the total pressure of a mixture of gases is equal to the sum of the partial pressures of the constituent gases".
A partial pressure is the pressure a gas would exert if it alone occupied the volume of the gas mixture.
Consider the following intermediate chemical equations.
2 equations. First: upper C (s) plus one half upper O subscript 2 (g) right arrow upper C upper O (g). Second: upper C upper O (g) plus one half upper O subscript 2 (g) right arrow upper C upper O subscript 2 (g).
How will oxygen appear in the final chemical equation?
Upper O subscript 2 (g). as a product
Upper O subscript 2 (g). as a reactant
O(g) as a product
2O(g) as a reactant
Answer:
c
Explanation:
got it right on test
Oxygen will appear in the final equation as O2 reactant.
What are chemical equation?A chemical equations shows the interplay between reactants and products. The reactants are on the left hand side while the products are at the right hand side.
Looking at the two equations, we know that oxygen will appear in the final equation as O2 reactant.
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What is the electron shielding effect? What is the trend for it? How and why does it happen?
Answer:
See explanation
Explanation:
In an atom, the inner electrons may shield the outer electrons from the attractive force of the nucleus. We, refer to this phenomenon as the shielding effect, It is defined as a decrease in the magnitude of attraction between an electron and the nucleus of an atom having more than one electron shell (energy level).
Shielding effect increases down the group due to addition of more shells but decreases across the period due to the increase in the size of the nuclear charge.
As the magnitude of shielding increases down the group, ionization of electrons becomes easier and the first ionization energies of elements decreases as we move down the group. Since shielding effect decreases across the period, the first ionization energies of elements increases across the period.
Methanol, or wood alcohol, is the combustible material used in sterno. Write a balanced equation for the complete oxidation reaction that occurs when methanol (CH3OH) burns in air. Use the smallest possible integer coefficients.
Answer:
2CH₃OH + 3O₂ → 2CO₂ + 4H₂O
Explanation:
A complete reaction for when any organic compound burns in air, produces only water and carbon dioxide. It does so by reacting with the oxygen gas (O₂) present in air.
In the case of methanol (CH₃OH) combustion, the balanced reaction is:
2CH₃OH + 3O₂ → 2CO₂ + 4H₂O
100. mL of 0.100 M HCl aqueous solution is mixed with 200. mL of 0.100 M CaCl2 solution to make a 300.mL solution. Find the molarity of the Cl- and pOH in the mixed solution Question 7 options:
Answer:
Explanation:
HCl ⇄ H⁺ + Cl⁻
HCl is a strong electrolyte so it will ionize completely .
moles of Cl⁻ in 100 mL of .1 HCl = .1 x .1 = .01 gram - ion .
CaCl₂ = Ca⁺² + 2 Cl⁻
1 mole 2 mole
moles of CaCl₂ in 200 mL of .1 M CaCl₂ = .2 x .1 = .02 gram mole .
.02 gram mole of CaCl₂ will give 2 x .02 = .04 gram-ion of Cl⁻ ion .
Total gram - ion of Cl⁻ = .01 + .04 = .05 gram-ion .
Total volume = 300mL = .3 L
molarity of Cl⁻ = .05 / .3 = .167 M .
HCl ⇄ H⁺ + Cl⁻
moles of H⁺ = moles of Cl⁻ = .01 gram-ion .
volume of solution = .3 L
molarity of H⁺ = .01 / .3 = 33.33 x 10⁻³ M .
[ H⁺] [ OH⁻] = 10⁻¹⁴
33.33 x 10⁻³ [ OH⁻] = 10⁻¹⁴
[ OH⁻] = 3 x 10⁻¹³
pOH = - log[OH⁻] = - log3 x 10⁻¹³
13-log3
= 13 - .477
12.52
or ,
pH = - log[H⁺] = - log33.33 x 10⁻³
3 - log 33.33
= 3 - 1.52
= 1.48
pOH = 14 - 1.48 = 12.52
Element X has two naturally occurring isotopes, 65X (isotopic mass 65.0457 amu, abundance 20.53%) and 67X (isotopic mass 66.9704 amu, abundance 79.47%). Calculate the atomic mass of element X.
Answer:
66.5753 amu
Explanation:
From the question given above, the following data were obtained:
Isotope A (⁶⁵X):
Mass of A = 65.0457 amu
Abundance of A = 20.53%
Isotope B (⁶⁷X):
Mass of B = 66.9704 amu
Abundance of B = 79.47%
Atomic mass of X =?
The atomic mass of X can be obtained as follow:
Atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100]
= [(65.0457 × 20.53)/100] + [(66.9704 × 79.47)/100]
= 13.3539 + 53.2214
= 66.5753 amu
Therefore, the atomic mass of X is 66.5753 amu.
Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu, 79.47%).
What is the average atomic mass?The average atomic mass (atomic mass) of an element is the sum of the masses of its isotopes, each multiplied by its natural abundance.
Element X has 2 isotopes:
⁶⁵X with an isotopic mass of 65.0457 amu and an abundance of 20.53% (0.2053).⁶⁷X with an isotopic mass of 66.9704 amu and an abundance of 79.47% (0.7947).We can calculate the average atomic mass of X using the following expression.
mX = m⁶⁵X × ab⁶⁵X + m⁶⁷X × ab⁶⁷X
mX = 65.0457 amu × 0.2053 + 66.9704 amu × 0.7947
mX = 66.58 amu
Element X, with an atomic mass of 66.58 amu, has 2 naturally occurring isotopes, ⁶⁵X (65.0457 amu, 20.53%) and ⁶⁷X (66.9704 amu, 79.47%).
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what are examples of actinides
Answer:
Neptunium, Protactinium, plutonium and more
Explanation:
What is the answer to this?
A 25.00 mL sample of H 2SO 4 requires 31.43 mL of 0.110 M NaOH to reach the equivalence point. What is the molarity of the H 2SO 4
Answer:
0.069 M
Explanation:
Equation of the reaction:
H₂SO₄(aq) + 2NaOH(aq) ⇒ Na₂SO₄(aq)+2H₂O(l)
From the equation above, 2 mole of NaOH is required to reach equivalent point with 1 mole of H₂SO₄.
n'CV = nC'V' ........................ Equation 1
Where n and n' = are number of moles of acid and base respectively, C and C' = are molarities of acid and base respectively, V and V' are volumes of acid and base respectively.
make C the subject of the equation
C = nC'V'/n'V.............................. Equation 2
Given: n = 1, n' = 2, C' = 0.11 M, V = 25 mL, V' = 31.43 mL
Substitute into equation 2
C = (1×0.11×31.43)/(25×2)
C = 0.069 M.
Hence the molarity of H₂SO₄ is 0.069 M
photo attached
if anyone from my class sees this no you didn't
Answer:
I think its b or c
Explanation:
hope this helps I mainly think b
what kind of structure do the cations and anions in table salt form
Answer:
ionic solids
Explanation:
Ionic solids are a regular pattern of cations and anions that arrange themselves into a continuous solid network.
NaCl is composed of sodium ions and chloride ions that are held together by Coulumbic attractive forces to form a large crystal structure.
Such ionic solids have a very high melting point and do not conduct electricity in the sold state. However, the molten substance or a solution of the substance conducts electricity.
Convert this measurement, 3.2x10-3 mm, from scientific notation to standard notation
Answer:
0.0032mm
Explanation:
Given dimension:
Measurement = 3.2 x 10⁻³mm
Unknown:
Write in standard notation from scientific notation = ?
Solution:
The standard notation is the way we normally write.
For example; standard notation of 1 million is 1000000
Now;
3.2 x 10⁻³ = [tex]\frac{3.2}{1000}[/tex] = 0.0032mm
3.2x10⁻³ mm in standard notation is 0.0032 mm. The normal or generally accepted manner of representing or expressing anything is referred to as standard notation.
Standard notation refers to the conventional or widely accepted way of representing or expressing something. In mathematics, for example, standard notation refers to the commonly used symbols and formats for writing mathematical expressions, equations, or numbers. The use of standard notation ensures uniformity, ease of understanding, and communication among mathematicians and students. Powers of 10 are used in scientific notation to express extremely large or extremely small quantities. 3.2x10⁻³ mm in standard notation is 0.0032 mm.
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Suppose you have two identical 1.0 L sealed containers. Both containers are kept at exactly 25oC. One vessel contains only neon gas at 1.5 atm, and the other contains only xenon gas at 2.5 atm.
A) Is the average kinetic energy possessed by the neon atoms greater than, equal to, or less than that of the xenon atoms? Explain.
B) What variable must be changed in order to decrease the average kinetic energy of the xenon atoms?
C) Does the vessel with the xenon gas contain more, fewer, or the same number of gas particles as the vessel of neon gas? Explain.
Answer:
See explanation
Explanation:
a) The average kinetic energy of the molecules of a gas depends on the temperature and the molar mass of the gas. However, at the same temperature, all gases have the same average kinetic energy. Hence Xe and Ne atoms have the same average kinetic energy.
b) To decrease the kinetic energy of Xe atoms the temperature must be changed. When the temperature is changed, Xe a lower average kinetic energy due to its larger molar mass.
c) All gases occupying the same volume have equal number of particles at the same temperature and pressure according to Avogadro's law. Therefore, since Xe and Ne occupy the same volume at the same temperature but different pressures they do not contain the same number of particles. Xe gas contains more particles because there are more moles of Xe gas present than moles of Ne gas. The greater the number of moles of gas present, the more the number of gas particles present.
Which of the following substances would form when aluminum and sulfur undergo a combination/synthesis reaction?
Aluminum and Sulfur react to produce Aluminum sulfide(Al₂S₃)
Further explanationGiven
The reaction of Aluminium and Sulfur
Required
The products of the reaction
Solution
There are several types of reactions that can occur
Synthesis/combination reaction : 2 elements combine to form a single product
The general formula :
A + B ⇒ AB
For reaction above :
2Al + 3S ⇒ Al₂S₃
The chemical equation below shows the combustion of propane (C3H8).
C3H8 + 5O2 Right arrow. 3CO2 + 4H2O
The molar mass of oxygen gas (O2) is 32.00 g/mol. The molar mass of C3H8 is 44.1 g/mol. What mass of O2, in grams, is required to completely react with 0.025 g C3H8?
0.018
0.034
0.045
0.091
Answer:
0.091
Explanation:
just took test on edg
Answer:
0.091
Explanation:
correct on edge 2021 unit test
What does the last line of the poem suggest
Answer:
that the poem needs to be finished heh pog
Explanation:
Answer:
Where is the poem?
Explanation:
Object A has a density of 2.0 and a mass of 100 g. Object B a density of 0.8 and a mass of 240 g. Object Ca
density of 5.0
and a mass of 100 g. Which of the objects above (A, B, or C) has the least volume?
cm
To determine which object has the least volume, we can calculate the volume of each object using the formula of density. From this, Object C has the smallest volume of 20 cm³ among Objects A, B, and C.
The formulae of volume:
Volume = Mass / Density
Let's calculate the volumes of objects A, B, and C:
For Object A:
Density = 2.0 g/cm³
Mass = 100 g
Volume of A = Mass / Density
Volume of A = 100 g / 2.0 g/cm³
Volume of A = 50 cm³
For Object B:
Density = 0.8 g/cm³
Mass = 240 g
Volume of B = Mass / Density
Volume of B = 240 g / 0.8 g/cm³
Volume of B = 300 cm³
For Object C:
Density = 5.0 g/cm³
Mass = 100 g
Volume of C = Mass / Density
Volume of C = 100 g / 5.0 g/cm³
Volume of C= 20 cm³
Comparing the volumes, we find that Object C has the least volume, with 20 cm³.
Therefore, Object C has the smallest volume among Objects A, B, and C.
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