Dell Computers receives large shipments of microprocessors (chips) from Intel Corp. It must try to ensure that the proportion of defective chips is small and has contracted to keep the proportion of defective chips at 5% or less. Suppose that Dell tests 25 chips (with replacement) out of a shipment of thousands.
a) What is the probability of obtaining at least three defects in the sample, if the entire shipment has 5% defectives? If a sample results in at least three defects, does it appear that Intel has provided a shipment which is consistent with the contract? Briefly explain, using the calculated probability.
b) For the shipment described in part a, find the expected number of sampled chips that are defective and the standard deviation of the number of sampled chips that are defective.
c) Suppose that 20% of the entire shipment is defective. What is the probability that more than 17 chips in the sample are good (not defective)?​

Answers

Answer 1

Using the binomial distribution, it is found that:

a) 0.1271 = 12.71% probability of obtaining at least three defects in the sample, if the entire shipment has 5% defectives. 5% defective is between 1 and 2 defects, but since this probability is more than the unlikely threshold 5%, more than 2 defects could still mean that Intel has provided a shipment which is consistent with the contract.

b) The mean is of 1.25 defective chips and the standard deviation is of 1.09 defective chips.

c) 0.8908 = 89.08% probability that more than 17 chips in the sample are good.

For each chip, there are only two possible outcomes, either it is defective, or it is not. The probability of a chip being defective is independent of any other chip, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

x is the number of successes. n is the number of trials. p is the probability of a success on a single trial.

In this problem:

25 chips are tested, thus, [tex]n = 25[/tex].

Item a:

Supposing 5% defective, we have that [tex]p = 0.05[/tex].

The probability is:

[tex]P(X \geq 3) = 1 - P(X < 3)[/tex]

In which

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)[/tex]

Then

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{25,0}.(0.05)^{0}.(0.95)^{25} = 0.2774[/tex]

[tex]P(X = 1) = C_{25,1}.(0.05)^{1}.(0.95)^{24} = 0.3650[/tex]

[tex]P(X = 2) = C_{25,2}.(0.05)^{2}.(0.95)^{23} = 0.2305[/tex]

[tex]P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.2774 + 0.3650 + 0.2305 = 0.8729[/tex]

[tex]P(X \geq 3) = 1 - P(X < 3) = 1 - 0.8729 = 0.1271[/tex]

0.1271 = 12.71% probability of obtaining at least three defects in the sample, if the entire shipment has 5% defectives. 5% defective is between 1 and 2 defects, but since this probability is more than the unlikely threshold 5%, more than 2 defects could still mean that Intel has provided a shipment which is consistent with the contract.

Item b:

The mean is:

[tex]E(X) = np = 25(0.05) = 1.25[/tex]

The standard deviation is:

[tex]\sqrt{V(X)} = \sqrt{np(1 - p)} = \sqrt{25(0.05)(0.95)} = 1.09[/tex]

The mean is of 1.25 defective chips and the standard deviation is of 1.09 defective chips.

Item c:

20% are defective, so 80% are good, which means that [tex]p = 0.8[/tex]

The probability is:

[tex]P(X > 17) = P(X = 18) + P(X = 19) + P(X = 20) + P(X = 21) + P(X = 22) + P(X = 23) + P(X = 24) + P(X = 25)[/tex]

Then

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 18) = C_{25,18}.(0.8)^{18}.(0.2)^{7} = 0.1108[/tex]

[tex]P(X = 19) = C_{25,19}.(0.8)^{19}.(0.2)^{6} = 0.1633[/tex]

[tex]P(X = 20) = C_{25,20}.(0.8)^{20}.(0.2)^{5} = 0.1960[/tex]

[tex]P(X = 21) = C_{25,21}.(0.8)^{21}.(0.2)^{4} = 0.1867[/tex]

[tex]P(X = 22) = C_{25,22}.(0.8)^{22}.(0.2)^{3} = 0.1358[/tex]

[tex]P(X = 23) = C_{25,23}.(0.8)^{23}.(0.2)^{2} = 0.0708[/tex]

[tex]P(X = 24) = C_{25,24}.(0.8)^{24}.(0.2)^{1} = 0.0236[/tex]

[tex]P(X = 25) = C_{25,25}.(0.8)^{25}.(0.2)^{0} = 0.0038[/tex]

Then:

[tex]P(X > 17) = P(X = 18) + P(X = 19) + P(X = 20) + P(X = 21) + P(X = 22) + P(X = 23) + P(X = 24) + P(X = 25) = 0.1108 + 0.1633 + 0.1960 + 0.1867 + 0.1358 + 0.0708 + 0.0236 + 0.0038 = 0.8908[/tex]

0.8908 = 89.08% probability that more than 17 chips in the sample are good.

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Related Questions

solve pls brainliest

Answers

Answer: (a.) -19  (b.) 78

Step-by-step explanation:

(a.) -33+14= -19       (b.) 75 - x = 78

(b.) 75 to zero = 75     Zero to -3

is 3 points behind zero, this make more distance from 75 so…

(b.) 75+3 = 78

Factor.

2xy+5x−12y−30



Enter your answer in the box.

Answers

(2y+5)(x−6)

not rlly sure tho

elect the correct answer from each drop-down menu.
Triangle XYZ, with vertices X(-2, 0), Y(-2, -1), and Z(-5, -2), undergoes a transformation to form triangle X′Y′Z′, with vertices X′(4, -2), Y′(4, -3), and Z′(1, -4). The type of transformation that triangle XYZ undergoes is a
.

Triangle X′Y′Z′ then undergoes a transformation to form triangle X′′Y′′Z′′, with vertices X″(4, 2), Y″(4, 3), and Z″(1, 4). The type of transformation that triangle X′Y′Z′ undergoes is a
.

Answers

Answer:

1. Triangle XYZ undergoes a translation.

2. Triangle X'Y'Z' undergoes a reflection across the x-axis

Moon Company produces baseball bats and cricket paddles. It has two departments that process all products – Cutting Department and Finishing Department.

In Finishing Department, direct materials (DM) are added at the start of the process and conversion costs (CC) are added evenly during the process. Company is using Weighted Average method for the Finishing Department.

During July, beginning work in process in the Finishing Department was 80% complete as to conversion. Beginning inventories included $30,800 for transferred-in costs, $13,200 for direct materials, and $27,500 for conversion costs. Ending inventory was 30% complete as to CC. Additional information about the Finishing Department follows:



Finishing

Beginning work-in-process units

26,400

Units transferred in this period

74,800

Units completed & transferred out

79,200

Ending work-in-process units

22,000





Material costs added

$37,400

Conversion costs

$75,460

Transferred-in costs

$141,240



What is equivalent units for transferred-in cost, direct materials, and conversion cost, respectively? Separate with slash /.
Moon Company produces baseball bats and cricket paddles. It has two departments that process all products – Cutting Department and Finishing Department.

In Finishing Department, direct materials (DM) are added at the start of the process and conversion costs (CC) are added evenly during the process. Company is using Weighted Average method for the Finishing Department.

During July, beginning work in process in the Finishing Department was 80% complete as to conversion. Beginning inventories included $30,800 for transferred-in costs, $13,200 for direct materials, and $27,500 for conversion costs. Ending inventory was 30% complete as to CC. Additional information about the Finishing Department follows:



Finishing

Beginning work-in-process units

26,400

Units transferred in this period

74,800

Units completed & transferred out

79,200

Ending work-in-process units

22,000





Material costs added

$37,400

Conversion costs

$75,460

Transferred-in costs

$141,240



What is equivalent units for transferred-in cost, direct materials, and conversion cost, respectively? Separate with slash /.
Moon Company produces baseball bats and cricket paddles. It has two departments that process all products – Cutting Department and Finishing Department.

In Finishing Department, direct materials (DM) are added at the start of the process and conversion costs (CC) are added evenly during the process. Company is using Weighted Average method for the Finishing Department.

During July, beginning work in process in the Finishing Department was 80% complete as to conversion. Beginning inventories included $30,800 for transferred-in costs, $13,200 for direct materials, and $27,500 for conversion costs. Ending inventory was 30% complete as to CC. Additional information about the Finishing Department follows:



Finishing

Beginning work-in-process units

26,400

Units transferred in this period

74,800

Units completed & transferred out

79,200

Ending work-in-process units

22,000





Material costs added

$37,400

Conversion costs

$75,460

Transferred-in costs

$141,240



What is equivalent units for transferred-in cost, direct materials, and conversion cost, respectively? Separate with slash /.
Moon Company produces baseball bats and cricket paddles. It has two departments that process all products – Cutting Department and Finishing Department.

In Finishing Department, direct materials (DM) are added at the start of the process and conversion costs (CC) are added evenly during the process. Company is using Weighted Average method for the Finishing Department.

During July, beginning work in process in the Finishing Department was 80% complete as to conversion. Beginning inventories included $30,800 for transferred-in costs, $13,200 for direct materials, and $27,500 for conversion costs. Ending inventory was 30% complete as to CC. Additional information about the Finishing Department follows:



Finishing

Beginning work-in-process units

26,400

Units transferred in this period

74,800

Units completed & transferred out

79,200

Ending work-in-process units

22,000





Material costs added

$37,400

Conversion costs

$75,460

Transferred-in costs

$141,240



What is equivalent units for transferred-in cost, direct materials, and conversion cost, respectively? Separate with slash /.

Answers

The Moon Company's equivalents units for transferred-in cost, direct materials, and conversion cost are 74,800 / 101,200 / 86,800 respectively.

Data and Calculations:

Percentage of completion:

Beginning work in process = 80%

Ending work in process = 30%

Beginning inventories:

Transferred-in costs = $30,800

Direct materials costs = $13,200

Conversion costs = $27,500

Physical Flows of Units:

Beginning WIP = 26,400

Units transferred in from Cutting Department = 74,800

Total production units available = 101,200 (26,400 + 74,800)

Units completed and transferred out = 79,200

Ending WIP = 22,000

                                 Transferred-in   Direct Materials   Conversion

Units transferred out                                   79,200             79,200

(79,200 x 100%)

Units transferred-in         74,800                          0                      0

(74,800 x 100%)

Ending WIP                                0               22,000 (100%)   6,600 (22,000 x 30%)

Total equivalent units    74,800              101,200             86,800

Thus, the equivalent units for the Finishing Department are determined based on the percentage of completion under the Weighted Average Method.

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13+ 6.4+ 2.78 awnser ?

Answers

Answer:

22.28

Step-by-step explanation:

first add the decimals then the other number.

A 98% confidence interval for a proportion is found to be (0.62, 0.68).

What is
the sample proportion?

O A. 0.66

OB. 0.64

O C. 0.65

O D. 0.68

Answers

Answer:

I think the answer is C ,The sample proportion is the fraction of samples which were successes, so. (1) For large , has an approximately normal distribution.

Step-by-step explanation:

If the queston true please votes 5 stars and mark as brainliest for me.Thank you so much

Given that a 98% confidence interval for a proportion is found to be (0.62, 0.68). The sample proportion will be 0.65.

What is confidence interval for population proportion?

Formula to calculate the confidence interval for population proportion p :-

[tex]p' - Z_{\alpha }\sqrt{\frac{p'q'}{n} } < p < p' + Z_{\alpha }\sqrt{\frac{p'q'}{n} }[/tex]

Where,

p is the population proportion.

p' is the sample proportion.

n is the size of the sample.

[tex]Z_{\alpha }[/tex] is the desired degree of confidence.

Given that a 98% confidence interval for a proportion p is found to be (0.62, 0.68).

[tex]p' - Z_{\alpha }\sqrt{\frac{p'q'}{n} } = 0.62\\\\p' + Z_{\alpha }\sqrt{\frac{p'q'}{n} } = 0.68[/tex]

Adding the two equations,

2p' = 1.3

p' = 0.65

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Pls help

||x-5|+2|<=3

Answers

Answer:

1,1 + 1oope k1 5l+<=3 is the 109199

Write the converse inverse and contrapositive of the statement below

Answers

The statement to be converted is "If Snoopy did not dance a jig, then Charles Schultz wrote a Sonata.

The converse is: If Charles Schultz did not write a Sonata, then Snoopy did dance a jig.

What is the Converse of a Statement?

A converse statement is arrived at when you have swapped the hypothesis and the conclusion.

Another example that helps buttress this is given below:

Original Statement: If the car braked, then the driver was sleeping.

Converse Statement: The driver was not sleeping therefore the car did not brake.

See the link below for more about Converse Statements:

https://brainly.com/question/2751386

20.99 for a 42 lb-bag of dog food (im pretty sure your supposed to divide the last number to the first number example: 18.5÷11.99)

Answers

Answer:

18.5÷11.99 is correct the answer is most likly option B

What is the measure of <1

Answers

Answer:

43

Step-by-step explanation:

274 would be absurd and 83 would be close to a right angle which that angle is no where near. It looks like half a right angle meaning 45 and 43 is the closest to that so I think its 43

A principal of $2200 is invested at 6.25% interest, compounded annually. How much will the investment be worth after 13 years

Answers

Answer:

Let S = Sum after 13 years

So = amount invested

t = time in years

i = annual interest rate = .0325

The S = So(1+i)t = $2,200(1.0325)13 = $3,334.21

After 13 years, the investment will be worth approximately $4365.67. To calculate the future value of the investment after 13 years with annual compounding interest, we can use the formula for compound interest.

Future Value (FV) = Principal (P) * (1 + (Interest Rate (r) / 100))^Time (n)

Where:

P = Principal (initial investment)

r = Annual interest rate (as a decimal)

n = Number of years

Given:

Principal (P) = $2200

Annual interest rate (r) = 6.25% = 6.25/100 = 0.0625 (as a decimal)

Number of years (n) = 13

Now, let's calculate the future value:

FV = $2200 * (1 + 0.0625)^13

FV = $2200 * (1.0625)^13

FV ≈ $2200 * 1.984396861  (rounded to 9 decimal places)

FV ≈ $4365.672097  (rounded to 2 decimal places)

After 13 years, the investment will be worth approximately $4365.67.

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please help me with this question

Answers

Answer:

1.4

Step-by-step explanation:

hope it helped

1. Scale 1 cm = 250 km
25
Using the scale above, calculate to find how
many km are in the following map distances:
a.) 2 cm =
km
b.) 5 cm
km
c.) 3 cm=
km

Answers

Answer:

a= 500km b= 1,250 c= 750

Step-by-step explanation:

a= 250x2=500km

b= 250x5=1,250km

c= 250x3=750km

PLEASE HELP ITS MATH THANK YOUUUU

Answers

Answer:

8 millimeters 4x where x is 2 millimeters

good luck homie you got this

Wesley willed his estate to Margaret,
no b Betty Jo, and Johnny. He gave Margaret
$20,000. Betty Jo got 22 times as much as
Margaret. Johnny got 32 times as much
as Margaret. What was the total value of
the estate?

Answers

Answer:

1,100,000

Step-by-step explanation:

20000 + 22(20000) + 32 (20000)= 55 (20000)= 1,100,000

Answer:

1,100,000

Step-by-step explanation:

Help please thank you

Answers

Mistake is both the numbers were added. After multiplication, it becomes 3.3 * 10^8

. . .Factor 2x2 + x - 1

Answers

Answer:

(2−1)(+1)

Step-by-step explanation:

22+−12x^{2}+{\color{#c92786}{x}}-12x2+x−122+2−−1

A painter has 7/8 gallon of stain. An interior door requires 1/4 gallon of stain to finish. How many doors can be finished?

Answers

Answer:

Three and a half doors can be painted with 7/8 gallons

Step-by-step explanation:

It takes 2/8 to be 1/4 so divide each side of the 7/8 by 2 and you get 3.5/4

Answer:

3 and 1/2 doors can be painted with 7/8 gallons of stain

help plz for brainliest

Answers

0.95

Explanation: divide 19 by 20, and you will get .95! Hope this helps!

Hansen and his good buddy Xavier are both mechanics at a shop that does oil changes. They are in a friendly competition to see who can complete the most oil changes in one day. Hansen has already finished 7 oil changes today, and can complete more at a rate of 2 oil changes per hour. Xavier just came on shift, and can finish 3 oil changes every hour. Sometime during the day, the friends will be tied, with the same number of oil changes completed. How many oil changes will Hansen and Xavier each have done? How long will that take?

Answers

Least Common Multiple (LCM)
2: ( already starts at 7)
9, 11, 13, 15, 17, 19, 21
3: 7th hour
3, 6, 9, 12, 15, 18, 21
7th hour

At the 7th hour, they both have done 21 oil changes.

work out the value of 5(x-y)

Answers

Answer:

5x - 5y

Step-by-step explanation:

Answer:

5x-5y or x=y.

Step-by-step explanation:

If 5(x-y) then we can distribute that, right?

then that turns into 5x-5y, lets say that equals zero, since there is no other information. Then 5x-5y=0 and wecould add 5y to both sides, getting 5x=5y

dividing 5x=5y/5 we get x=y.

Please include step by step instruction, so I can learn how to solve the problem. Thank you

Answers

9514 1404 393

Answer:

  A, C

Step-by-step explanation:

First of all, recognize that any basic arithmetic operation between a rational number and an irrational number will have an irrational result. That means, you can eliminate any answer choices that involve an irrational number.

Fractions and mixed numbers involving integers are always rational, so you only need to look at the radicals. You know 9 is 3×3, so is a perfect square, and √9 = 3 is rational. You know 5 is not a perfect square, so √5 is irrational.

Considering the above, any expression involving √5 will have an irrational result. That means you can eliminate choices B and D.

  choices A and C will result in a rational number

_____

Additional comment

  A = 6.8 +0.75 = 7.55 (rational)

  C = 6.8 × 0.75 = 5.100 (rational)

Sue's paycheck is $1,040 for 40 hours of work. If she works 30 hours next week, what will her paycheck be?

Answers

Answer: 780

Step-by-step explanation:

1040/40 = 26

If Sue's paycheck contains $1,040 for 40 hours then she gets pay $26 for a hour.

26(30) = 780

To find what her paycheck consist of within 30 hours, you'll multiply 26, the amount she make an hour by 30, hours and you'll get 780.

Simplify the following:

[tex]\sqrt{50} x^{2} y^{3}[/tex]

Answers

Answer:

5xy[tex]\sqrt{2y}[/tex]

Step-by-step explanation:

Answer: simplify

5√2x² y²

NO LINKS!!! Part 1: y = x^3

Shape:
Domain:
Range:
Locater point:​

Answers

Answer:

Shape: Not sure what to put

Domain: ( -oo, oo )

Range: ( -oo, oo )

Locater point: ( 0, 0 )

Step-by-step explanation:

Shape - You have the shape on the graph

Domain and Range - Both go on forever since there is no hole/interruption

Locater Point: I would say origin because it is the closest thing to a vertex, which is an example of a locater point.

Hopefully this helps!

Brainliest please?

7+ За = 12 + 2а

Can anyone give the answer quick!

Answers

Answer:

A=5

Step-by-step explanation:

Answer:

A=5

Step-by-step explanation:

7+3a=12+2a

-2a -2a

7+a=12

-7 -7

a=5

give the quadratic sequence 2,3,10,23,........
write down the next term of the sequence.​

Answers

Answer:

The next term of the sequence is 42

Helppppppp plzzzzzzz

Answers

Answer:

102°

Step-by-step explanation:

Angles in a straight line is added up to 180°

So,

Angle 1 + Angle 2 = 180°

Given that,

Angle 2 = 78°

We can find angle 1

Let us find,

Let the angle 1 be x

[tex]x+78=180\\x=180-78\\x=102[/tex]

As a and b lines are parallel,

Angle 1 = Angle 5 (Corresponding angles)

Also we already found the angle 1

So,

Angle 5 = 102°

Hope this helps you.

Let me know if you have any other questions :-)

what is the greatest common factor of 42, 12, and 6?​

Answers

Answer:

The greatest common factor is surprisingly 6.

All three numbers can be divided by 6 and it is the highest value that can be taken from all three numbers.

Step-by-step explanation:

Hope this helps.

<3

Answer:

the GCF of those numbers is 6.

Step-by-step explanation:

One way to solve this is to list the factors of them, then find the greatest one that they share.

42: 1, 2, 3, 6, 7, 14, 21, 42

12: 1, 2, 3, 4, 6, 12

6: 1, 2, 3, 6

If we look at them, notice that six is in all of them. All of them have factors of six. Can we go any higher than that? No because six is the greatest factor of six, so we can't go any higher and still have all of them share a GCF. So your answer is 6.

CE TASK
V.
3
The carpenter spent 7/8 of his money on bags of sand for the sandbox. He spent 1/2 of the rest
of his money on some packs of bunting flags to decorate thesandbox and had $19.90 left How much money did the carpenter start with? Draw a bar model to show your work

Answers

Determine how much money did the carpenter start with

The total money with the carpenter is $318.4

Given:

let

x = total money with the carpenter

Bags of sand = 7/8 of x

= 7/8x

Money remaining = x - 7/8x

= (8x-7x) / 8

= 1/8x

Bags of bunting bags = 1/2 of 1/8x

= 1/2 × 1/8x

= 1/16x

Money left = $19.90

Total money = bags of sand + bag of bunting flag + money left

x = 7/8x + 1/16x + 19.90

x = (14x + x) / 16 + 19.90

x = 15/16x + 19.90

x - 15/16x = 19.90

16x - 15x / 16 = 19.90

x/16 = 19.90

divide both sides by 1/16

x = 19.90 ÷ 1/16

= 19.90 × 16/1

= 318.4

Therefore, the total money with the carpenter is $318.4

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