Can anyone help with these? I appreciate and I will award 5 stars and brainliest

Answer:

Turn the negative fraction into a decimal

Step-by-step explanation:

example:

-1/2=-0.5

Answer:

Subtract the absolute value of the decimal.

Add the negative number to the positive number.

Add the opposite of the negative number to the positive number.

Step-by-step explanation:

hope this helped </3

Answer:

it's ASA because you have 2 angles congruent and a side congruent.

Answer: 673.98

Step-by-step explanation: The 8 is the hundredth place, and anything less than five you don't round up

Answer:

[tex]y=\frac{1}{4}(x)+2[/tex]

you can write this as

[tex]f(x)=\frac{1}{4}x+2[/tex]

Step-by-step explanation:

2 points

(-4,1)(0,2)

[tex]y=\frac{1}{4}x+2[/tex] is the equaction of the line thats in the grapj

Why and How I got it?

you had 2 points, so you can using the slope equaction

Rise over run

why is slope important?

using the y incept equactions

y=mx+b, where slope is m

so you get slope you got m

Solve

rise over run

[tex]\frac{2-1}{0-(-4)}[/tex]

so you get

[tex]y=\frac{1}{4}x+b[/tex]

How do you get B?

you plug 1 points in

[tex]-4=\frac{1}{4}(1)+b[/tex]

Hoped this helped ya

<3

Answer:240 seconds

Step-by-step explanation:

Answer:

A=43

B=32

C=105

Answer:

3i-1

Step-by-step explanation:

2+3i-3

3i-1

Answer:

-1 + 3i.

Step-by-step explanation:

Hope this helps!

Answer:

a

[tex]E[(3X+1)^2]= 8.5  [/tex]

b

[tex]P(1 <  X < 2)=0.1170 [/tex]

Step-by-step explanation:

From the question we are told that

   The parameter of  X  is  [tex]\lambda  =  2[/tex]

Generally the expected value of  X is  

    [tex]E(X) =  \frac{1}{\lambda }[/tex]

     [tex]E(X) =  \frac{1}{2}[/tex]

=>  [tex]E(X) =  0.50 [/tex]

Generally we have that

     [tex]E(X^2) =  E(X)^2 + E(X)^2[/tex]

=>  [tex]E(X^2) =  [\frac{1}{2}] ^2 + [\frac{1}{2} ]^2[/tex]

=>  [tex]E(X^2) =  0.5 [/tex]

Generally

    [tex]E[(3X+1)^2]= E(9x^2 + 1 + 6x)[/tex]

=>  [tex]E[(3X+1)^2]= 9E[X^2] + 1 + 6 E[X])[/tex]

=>    [tex]E[(3X+1)^2]= 9* 0.5  + 1 + 6 * 0.5 [/tex]

=>   [tex]E[(3X+1)^2]= 8.5  [/tex]

Generally  

   [tex]P(1 <  X < 2)=  P(X < 2) - P(X < 1)[/tex]

Here  [tex]P(X <  2 ) =  e^{- 2 * \lambda }[/tex]

=>      [tex]P(X <  2 ) =   e^{- 2 * 2 }[/tex]

=>       [tex]P(X <  2 ) =   e^{- 4}[/tex]

and  

    [tex]P(X <  1 ) =   e^{- 1 * \lambda }[/tex]

    [tex]P(X <  1 ) =   e^{- 1 * 2 }[/tex]

    [tex]P(X <  1 ) =   e^{-2 }[/tex]

So

   [tex]P(1 <  X < 2)= e^{-2 } -  e^{- 4} [/tex]

  [tex]P(1 <  X < 2)=0.1170 [/tex]

Answer:

$200

Step-by-step explanation:

%15 = 0.15

0.15 • 200 = 30

200 - 30 = 170

Problem 5

Domain = [tex]-4 \le x \le 3[/tex]

This is because the smallest x value allowed is x = -4 as shown by the left-most point. The right most point has x coordinate x = 3, so this is the largest value in the domain.

The domain in interval notation is [-4, 3]. The square brackets include the endpoint.

--------------

Range = [tex]-4 \le y \le 5[/tex]

We're now looking at the possible y values. The lowest point happens when y = -4 and the highest point is when y = 5. We can have any y value between those endpoints.

The range in interval notation is [-4, 5]

=============================================================

Problem 6

Domain = [tex]-2 \le x < 2[/tex]

Same idea as the previous problem. This time the left most point has x = -2 and the right most point has x coordinate x = 2.

The big difference here is that the open hole says to not include the endpoint. The domain in interval notation is [-2, 2) where we use a parenthesis to not include the endpoint.

-------------

Range = [tex]-4 \le y < 4[/tex]

The smallest possible y value is y = -4. The ceiling for the y values is y = 4, but we can't actually reach this value due to the open hole.

The range in interval notation is [-4, 4)

=============================================================

Problem 7

Domain = [tex]-4 < x \le 2[/tex]

Same idea as earlier. Now the open hole is at the left endpoint. The right most point occurs not at an endpoint this time.

The domain in interval notation is (-4, 2]

-------------

Range: [tex]-4 < y < 4[/tex]

Both endpoints are open holes, so we exclude both endpoints.

The range in interval notation is (-4, 4). Unfortunately in this case, interval notation looks identical to ordered pair notation.

=============================================================

Problem 8

Domain = [tex]-5 < x < 3[/tex]

Domain in interval notation = (-5, 3)

The graph is too blurry to be able to determine the range.

Step-by-step explanation:

Hey there!

Given; 3y - 5(y+2).

Multiply 5 and (y+2)

3y - 5y - 10

Simplify to get answer.

-2y -10

Take 2 and (-) common.

-2(y+5)

Therefore, the simplified form is -2(y+5).

Hope it helps...

Answer:

Step-by-step explanation:

3y - 5 ( y + 2)

= 3y - 5y - 2

= -2y -2

Answer:

2/5 is bigger

Step-by-step explanation:

2/5 is 0.40

Answer:

x=40

Step-by-step explanation:

Answer:

The price that maximizes the revenue is $63.75

Step-by-step explanation:

Analyzing the statement one after the other.

[tex]Initial\ Quantity = 550[/tex]  ---- When ----- [tex]Initial\ Price = \$100[/tex]

When there's a reduction of $1, we have:

[tex]Quantity = 550 + 20x[/tex] and [tex]Price = 100 - x[/tex]

Where x represents the maximum reduction

At this point, we need to calculate the revenue (R)

[tex]R = Quantity * Price.[/tex]

[tex]R = (550 + 20x) * (100 - x)[/tex]

Open Brackets

[tex]R = 55000 - 550x + 2000x - 20x^2[/tex]

[tex]R = 55000 +1450x - 20x^2[/tex]

Differentiate both sides with respect to x

[tex]\frac{dR}{dx} = 0 + 1450 - 40x[/tex]

[tex]\frac{dR}{dx} = 1450 - 40x[/tex]

To maximize revenue;

[tex]\frac{dR}{dx} = 0[/tex]

So:

[tex]1450 - 40x = 0[/tex]

[tex]1450 =40x[/tex]

Solve for x

[tex]x = 1450/40[/tex]

[tex]x = 36.25[/tex]

Recall that:

[tex]Price = 100 - x[/tex]

Substitute [tex]x = 36.25[/tex]

[tex]Price = 100 - 36.25[/tex]

[tex]Price = 63.75[/tex]

Hence:

The price that maximizes the revenue is $63.75

Answer:

Nine and six hundred two thousandths

Step-by-step explanation:

Hope this helped.

Answer: nine and sixty-two thousandths nine and six hundred two hundredths nine and sixty-two hundredths nine and six hundred two thousandths.

Step-by-step explanation:

Answer:

the answer is                                                 b

Step-by-step explanation:

Answer:

this answer will be in your book

Answer:

Step-by-step explanation:

bro im out n can come scoop

Answer:

300,000

Step-by-step explanation:

Answer:

The last two are the right ones

Step-by-step explanation:

Answer:

the direction of the road

Step-by-step explanation:

To calculate the net force, we need to know the direction through which the forces are acting.

Are the forces directed towards one another or against each other?

  Net force is a vector sum of forces that acts on a body. It is that single force that can replace two or more forces acting on a body.

So, without knowing the direction, we cannot calculate the net force.

Answer:

Step-by-step explanation:

Given

N(t) = 29t²-115t+52

T(t) = 6t+1.5

To get the composite function N(T(t)), we will follow the steps

N(T(t)) = N(6t+1.5)

To get N(6t+1.5), we will replace t in N(t) with 6t+1.5 as shown:

N(6t+1.5) = 29(6t+1.5)²-115(6t+1.5)+52

N(6t+1.5) = 29(36t²+18t+2.25)-690t-172.5+52

N(6t+1.5) = 1044t²+522t+65.25-690t-172.5+52

N(6t+1.5) = 1044t²+522t-690t+65.25-172.5+52

N(6t+1.5) = 1044t²-168t-55.35

Hence;

N(T(t)) = 1044t²-168t-55.35

To determine the time when the bacteria count reaches 500, we will equate the expression to 500 and find t

500 = 1044t²-168t-55.35

1044t²-168t-55.35-500= 0

1044t²-168t-555.35 = 0

Factorize

t =140±√1630115/1740

t = 0.81

Hence the time reached when the bacteria was 500 hours is 0.81hours

Answer:

he put it on one brownie so 1/7

Answer: 325

Step-by-step explanation:

All your doing is multiplying

Answer:

The answer is 325

Step-by-step explanation:

the problem directly tells me that c(x)= 50x is how many words i can type in x minutes. then proceeds to ask me how many words i can type in 6.5 minutes.

in this case, x=6.5.

substitute and solve!

c(6.5)= 50(6.5)

c(6.5)= 325

according to this function, i can type 325 words in 6.5 minutes.

hope this helps!!

Answer:

$26.05

Step-by-step explanation:

$8.99(2) + $19.99 + $11.99(3) = $73.95 - $100

Hope this helped :)

Answer:

9 < x < 0

Step-by-step explanation:

from 0 to 9 i think

Step-by-step explanation:

David earns $8 per hour. He works 40 hours each week. How much does he earn in 6 weeks? . After 6 weeks, who earned more money? How much more money?

he would earn 1,680 because if he works 40 hours per week when you divide by 7 cuz there a 7 days in a week he works 5 hours each day. then we multiply 5 with 8 and it's 40 so he earns 40 dollars per day then if week multiply 40 with 7 we get 280 and that's what he earns per week. then I came and tried to figure out how many days are in 6 weeks and I got 42 so then i came and multiplied the hours(5) which then gave me 210 then I multiped that (210) and 8 together and got 1,680

1.Michael earns $9 per hour. He works 28 hours each week. How much does he earn in 6 weeks?

so what i did was divide 28 by 7 the 7 was for the days and the 28 was for the hours so per day he works 4 hours and he earns 36 dollars per day .and then i came to know what the final answer was I came a figured out how many days are in 6 weeks and it's 42 so then I came and multiped the hours with the days which gave me 168  then I multiped that by the amount of money he earns per hour and it gave me 1,512 per 6 weeks

Answer:

[tex] f(-2) = 13 [/tex]

[tex] f(0) = 9 [/tex]

[tex] f(5) = -1 [/tex]

Step-by-step explanation:

Given:

[tex] f(x) = -2x + 9 [/tex]

Required:

Find,

h(-2); h(0), and h(5)

SOLUTION:

Plug in the value of x into [tex] f(x) = -2x + 9 [/tex] in each case as follows:

[tex] f(-2) = -2(-2) + 9 [/tex]

[tex] f(-2) = 4 + 9 [/tex]

[tex] f(-2) = 13 [/tex]

[tex] f(0) = -2(0) + 9 [/tex]

[tex] f(0) = 0 + 9 [/tex]

[tex] f(0) = 9 [/tex]

[tex] f(5) = -2(5) + 9 [/tex]

[tex] f(5) = -10 + 9 [/tex]

[tex] f(5) = -1 [/tex]

The value of h(x) when x= -2,0, and 5 is; 13, 9 and -1 respectively.

The function, h(x) given is; h(x) = -2x +9 .

As such, evaluation of h(x) when x = 2,0, and 5 is as follows;

For x = -2

For x = 0

For x = 5

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