A baseball is hit straight up in the air with an initial velocity of 38 m/s
How long does it stay in the air?
How high does it go?

Answers

Answer 1

The time of motion or time spent in air by the baseball is 7.76 seconds.

The maximum height attained by the baseball is 73.67 m.

The given parameters;

initial velocity of the baseball, u = 38 m/s

The time of motion of the baseball is calculated using the first kinematic equation as follows;

v = u - gt

where;

t is the time to reach maximum heightv is the final velocity of the ball at the maximum height = 0

0 = u -gt

gt = u

[tex]t = \frac{u}{g} \\\\\t = \frac{38}{9.8} \\\\t = 3.88 \ s[/tex]

The time spent in the air = time of entire motion = 2(3.88 s) = 7.76 seconds

The maximum height attained by the ball is calculated using the second kinematic equation as shown below;

[tex]h = ut -\frac{1}{2} gt^2\\\\h = (38\times 3.88)\ - \ (0.5 \times 9.8 \times 3.88^2)\\\\h = 73.67 \ m[/tex]

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Related Questions

Fossils show that some animals _____.

are extinct
had not seen rain
liked the cold
made noise

Answers

Answer:I think Fossils show that some animals are extinct

Explanation:

Please mark as brainliest for me.Thanks

Are extinct is the answer

Does bouncing or sticking produce more impulse?

Answers

Answer:

yes

Explanation:

Bouncing is a way to increase impulse. Because an object that bounces changes directions the force of impulse must be absorbed then generated by the target object. (Impulse is nearly doubled.)

HELPPP


Which of the following statements about friction is FALSE .
1 ) Friction involves objects that are in physical contact .
2) Friction is less if surfaces are very smooth .
3 ) Friction is always in the direction of the motion .
4) Friction is caused by the uneven surfaces of touching objects

Answers

Friction is caused by the uneven surfaces of touching objects

helphelphelp due in 5 minutes answer the question below

Answers

The correct answer is B

Explain what occurs to satellites when they travel too fast and too slow to keep in orbit​

Answers

If the satellite goes too slow:

It will crash into it's surrounding things it's orbiting.It would not go forward enough due to pull of gravity.Gravity will pull it back to Earth.The satellite could be knocked or moved closer or farther from the object it is orbiting.

If the satellite goes too fast:

It will eventually fly away.It can go forward soo fast.It would go too fastly that gravity can't retain in an orbit.The satellite's inertia would carry it off into space.

Why potential energy is remian constant when solid body is heated?

Answers

the temperature remains constant because the given heat is used to increase only the potential energy of the molecules of the given substance (which results in the change of its state) and not the kinetic energy as temperature of a body is actually the measure of the average kinetic energy of its molecules.

A 940-g rock is whirled in a horizontal circle at the end of a 1.30-m-long string. (a) If the breaking strength of the string is 120 N, what’s the minimum angle the string can make with the horizontal? (b) At this minimum angle, what’s the rock’s speed?

Answers

(a) The minimum angle the string can make with the horizontal is 4.4 ⁰.

(b) The rocks speed at the minimum angle is 165.7 m/s.

The given parameters;

mass of the rock, m = 940 g = 0.94 kglength of the string, L = 1.3 mTension on the string, T = 120 N

The net force on the string is calculated as follows;

[tex]Tsin(\theta) = mg\\\\Tcos(\theta) = \frac{mv^2}{r} \\\\\frac{Tsin(\theta)}{Tcos(\theta)} = \frac{mg r}{mv^2} \\\\tan(\theta) = \frac{rg}{v^2} \\\\v^2 = \frac{rg}{tan (\theta)} \\\\v = \sqrt{\frac{rg}{tan (\theta)}}[/tex]

The minimum angle the string can make with the horizontal is calculated as follows;

[tex]Tsin(\theta) = mg\\\\sin(\theta) = \frac{mg}{T} \\\\sin(\theta) = \frac{0.94 \times 9.8}{120} \\\\sin(\theta) = 0.0767\\\\\theta = sin^{-1} (0.0767)\\\\\theta = 4.4 \ ^o[/tex]

The rocks speed at the minimum angle is calculated as follows;

[tex]v = \sqrt{\frac{rg}{tan(\theta)} } \\\\v = \sqrt{\frac{1.3 \times 9.8}{tan(4.4)} } \\\\v = 165.7 \ m/s[/tex]

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I NEED A 100% ACCURATE ANSWER FOR THIS QUESTION ASAP NO LINKS !!!
What is defined by force per unit area?
1: gravity
2: force
3: temperature
4: pressure

Answers

Answer:

4. pressure is defined as force per unit area

Pressure is defined by force per unit area.

WHAT IS PRESSURE:Pressure refers to the force applied to a substance per unit area.

Force is measured in Newtons (N) while area is measured in m², hence, the unit of pressure is N/m² also called pascal.

Therefore, according to this question, it can be said that pressure is defined by force per unit area

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Which of the following happens when a substance melts?

Answers

Answer:

hola como estas hablas español

Explanation:

Is my answer correct

Answers

Answer:

it right congratulations

Answer:

A

Explanation:

Simply option A is correct

It's a bit of a common sense question

At the highest point it's velocity will be automatically 0 since it is in rest and so is the acceleration

How much heat must be added to 160 g of ice at 0°C to melt the ice completely? The latent heat of fusion of ice is 80 cal/g.



The amount of heat required is
cal

Answers

To melt the ice you will need 33.4 cal

Which is the largest number? O A. 9.9 x 106 O B. 4.5 x 107 O c. 5.5 x 105 O D. 5.8 x 108​

Answers

Answer:

107

Explanation:

It's the biggest number

What is the mass of an object that is experiencing a net force of 225 N and an acceleration of 3.0 m/s^2?​

Answers

Answer:

Mass of a object 75 Kilograms

Explanation:

Net force acting on an object, [tex]Fnet = 225N[/tex]

Acceleration produced, [tex]a = 3.0m/s^2[/tex]

According to Newton's second law :

F = m a

[tex]M =\frac{F}{a}[/tex]

[tex]m =\frac{225N}{300m/s^2}[/tex]

[tex]m= 75 Kg[/tex]

So, the mass of an object is 75kg.

Hence, this is the required solution.

Answer:

75 kg.

Explanation:

Net Force

[tex]\sf \longmapsto F_{net} = 225N[/tex]

Acceleration produced

[tex]\sf \longmapsto \: a = 3 .0 m / {s}^{2}[/tex]

According to Newton's 2nd Law –

F = m•a

[tex]\sf \longmapsto \: M = \frac{F}{A} [/tex]

[tex]\sf \longmapsto \: M = \frac{225N}{300m/s ^{2} } [/tex]

[tex]\sf \longmapsto \: M = \: 75 \: kg[/tex]

Therefore, the mass of an object is 75 kg.

I WILL MARK BRAINLIEST !! PLEASE HELP!

Answers

Answer:

b

Explanation:

Which requires more work, lifting a 20 kg box vertically 2 meters OR lifting a 10 kg box 4 meters? Explain.​

Answers

Answer:

I'm not sure in which direction 10kg is lifted but assuming 10kg is lifted (or dragged) horizontally then

the 20kg vertically requires more work because gravity pushing down on it will require a somewhat large output of Energy.

But if they are both lifted vertically (or horizontally)then they are equal in work.

Hope this helps

A 12.0-g bullet is fired horizontally into a 112-g wooden block that is initially at rest on a frictionless horizontal surface and connected to a spring having spring constant 149 N/m. The bullet becomes embedded in the block. If the bullet-block system compresses the spring by a maximum of 83.5 cm, what was the speed of the bullet at impact with the block

Answers

The speed would be in a decimal? Or do you want it in a fraction?

A Wheatstone Bridge type circuit is shown (10marks) R1=20ohms, R2=10ohms, R3=8ohms, R4=5ohms, and R5=2ohms and also has 10V battery. Determine A. the p.d. between terminals B and D, and (5 marks) B. The value to which R4 must be adjusted in order to reduce the current through R3 to zero (balance the bridge). (5marks)​

Answers

Answer:

Dunno

Explanation:

Dunno

What provides the centripetal force for the moon's orbit around Earth?​

Answers

Answer:

Gravitational attraction provides the centripetal force needed to keep planets in orbit around the Sun and all types of satellite in orbit around the Earth. This centripetal force is supplied by gravity. The Earth's gravity keeps the Moon orbiting us. Centripetal force is perpendicular to velocity and causes uniform circular motion. The gravitational attraction of the Sun is an inward force acting on Earth. This force produces the centripetal acceleration of the orbital motion. Centripetal forces are always directed toward the center of the circular path.

Explanation:

Answer: C.

the gravitational pull of the Sun

Explanation: plato :3

Hope this helps!

hola buen día por favor alguien me puede ayudar por favor1. Dos cargas puntuales q1=+4μC y q2=+ 6μC están separadas por 10 cm. Una carga


puntual
q3=+2μC se coloca a medio camino entre q1 y q2. Encuentra la magnitud y la dirección de la
fuerza resultante sobre q3. Asuma que q1 está a la izquierda de q3 y q2 a la derecha de q3.
Revisa el ejemplo de la clase del tema 6. Además, recuerda que las fuerzas no siempre actúan
en la misma dirección.

2. Se coloca una carga puntual de 4 μC en un punto P (x = 0.2 m, y = 0.4 m). ¿Cuál es el campo
eléctrico E debido a esta carga en el origen del plano cartesiano? Hint: asume un plano
cartesiano y dibuja el campo eléctrico que se busca. Además, recuerda el teorema de
Pitágoras.

3. Una carga puntual q = 25μC está ubicada en el centro de una esfera de radio R = 25 cm, el
campo eléctrico generado a esta distancia debido a esa carga es E=3.6 x 10^6 N/C. Se quita de
la superficie una sección circular con radio r = 5 cm. Encuentre el flujo eléctrico que pasa por
esta sección. Hint: solo quieres saber el flujo eléctrico sobre el área de la superficie que se
aisló, por lo que es importante recordar cómo se obtiene el área de un círculo.

4. En cierta región al norte del planeta tierra, existe un campo eléctrico uniforme, la dirección
del campo eléctrico es hacía el centro del planeta y según se sabe, tiene un valor de 1000 N/C.
Encuentra el cambio de la energía potencia eléctrica de una partícula que tiene una carga de
-1.6 x10 -19 C. Considera que la partícula se suelta en un punto A y llega hasta un punto B que
está a 50 m del punto A.

5. Dos cargas q1 = −2 μC y q2 = + 2 μC se fijan en sus posiciones y se separan por una distancia d
= 10 cm. ¿Cuál es el potencial eléctrico en el origen debido a estas dos cargas?

Answers

Answer:

vfyugpuvfhvjvfhuvihfiurj

Explanation:

vfehgwfljhgiurnjfkfjhk

A closed, uninsulated system fitted with movable piston, so no matter is exchanged with the surroundings, was assembled. Introduction of 430 J of heat caused the system to expand, doing 238 J of work against a constant pressure of 101 kPa. What is the value of for this process

Answers

Answer: You do not specify what is being asked for. ∆E? ∆H?

∆E = (430 - 238) J = 192 J

∆H = 430 J

Explanation:

If asked for the value of ∆H the answer is simply the change in heat, and in the question, it states introduction of 430 J of heat is causing the system to expand.

Therefore ∆H = 430 J

If asked for ∆E, we know that ∆E = ±q (heat) + work (-P∆V) = ±q + w

The question states that 238 J of work are done AND the system expanded

(work is negative because expansion means work is done BY the system, releasing energy/heat... Conversely, if the system were compressed, work is done ON the system, absorbing heat/energy)

Therefore, ∆E = (430 - 238) J = 192 J

Which theory of emotion explains the startle response

Answers

Answer:

In the present study, the startle blink reflex is used as a measure of emotion regulation to effective picture stimuli. Based on the aphasic theory of emotion, it is hypothesized that the startle response will be largest in magnitude in the presence of negative emotional stimuli (Varanasi, Spence, & Lang, 1988).

the hanging
mass would need to be

Answers

Answer:

what do you need help with I can try to help you

What is the initial velocity (in m/s) of a car if it takes 10 seconds to travel a kilometer
while accelerating at 2 m/s??

Answers

B bd eneemkelelele elelel wlelle

What is the magnitude of the electric field at a point 0.0075 m from a 0.0035
C charge?
Use E-
kq
and k - 9.00 x 10° N.m²/C2.
A. 1.9 x 1010 N
B. 4.2 x 10' N
O c. 5.6 x 1011 N
D. 5.5 x 1012 N

Answers

Explanation:

E = 9×10^9 × 0.0035 /(0.0075)²

= 9×10^9 × 3.5×10`³/(7.5×10`³)²

= 31.5×10^6 /(56.25 ×10^-6)

= 0.56 × 10^12

= 5.6 × 10^11 N/C (option C)

Heat rash is caused by chemical exposure Truth or false

Answers

Answer:

This is false.

Explanation:

Heat rash develops when some of your sweat ducts clog. Instead of evaporating, perspiration gets trapped beneath the skin, causing inflammation and rash. Heat rash is usually self-limited, meaning it resolves on its own without treatment. Over-the-counter treatments such as calamine, hydrocortisone cream, itch preparations (such as Benadryl spray), or sunburn lotions can be used as skincare to treat the itching and burning symptoms. Heat rash usually goes away on its own within three or four days so long as you don't irritate the site further. Heat rash happens when the sweat glands get blocked. The trapped sweat irritates the skin and leads to small bumps.

Answer:

FALSE

Explanation:

Heat rash develops when blocked pores or sweat ducts trap perspiration under your skin. Symptoms range from superficial blisters to deep, red lumps. Some forms of heat rash feel tingly  or intensely itchy.

10 basic rules of badminton?​

Answers

Explanation:

Rules

A match consists of the best of three games of 21 points.

The player/pair winning a rally adds a point to its score.

At 20-all, the player/pair which first gains a 2-point lead wins that game.

At 29-all, the side scoring the 30th point wins that game.

The player/pair winning a game serves first in the next game.

A badminton match can be played by two opposing players (singles) or four opposing players (doubles).

A competitive match must be played indoors utilising the official court dimensions.

A point is scored when the shuttlecock lands inside the opponent's court or if a returned shuttlecock hits the net or lands outside of the court the player will lose the point.

At the start of the rally, the server and receiver stand in diagonally opposite service courts.

A legal serve must be hit diagonally over the net and across the court.

A badminton serve must be hit underarm and below the server's waist height with the racquet shaft pointing downwards, the shuttlecock is not allowed to bounce. After a point is won, the players will move to the opposite serving stations for the next point.

The rules do not allow second serves.

During a point a player can return the shuttlecock from inside and outside of the court.

A player is not able to touch the net with any part of their body or racket.

A player must not deliberately distract their opponent.

A player is not able to hit the shuttlecock twice.

A 'let' may be called by the referee if an unforeseen or accidental issue arises.

A game must include two rest periods. These are a 90-second rest after the first game and a 5-minute rest after the second game.

Pls help and thank u need asap!

Answers

Answer:

ill help if u help me?its 4am

The term that is used to quantity the amount of heat in the evaporator is

Answers

Answer:

Enthalpy

The quantity of heat contained in a material as measured from a particular base or point.

giúp em toàn bộ nhé ............

Answers

Explanation:

nnnnkgcbchg of bbjbjk oh jjzjjzkedkkdkfjjsjdsjfkjfdkkdowkronqfojofj see j FC

A__________ shows how velocity changes over time

Answers

Velocity time graph goes into the blank hope it helps please mark me brainliest
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