50 mL of 2.2 M HCl is combined with 50 mL of 2.0 M NaOH in a coffee-cup
calorimeter. The temperature of the solution increases 13.4°C. Assume the
calorimeter is a perfect insulator and the mixture has a specific heat capacity identical
to pure water (4.184 wc)
.
Calculate the heat change from the chemical reaction (in units of kJ). (Pay attention to
sign conventions and do not write the units in your typed answer.)

Answers

Answer 1

Answer:

-56.1kJ/mol

Explanation:

The reaction between HCl and NaOH is:

NaOH + HCl → NaCl + H₂O + ΔH

Where ΔH is heat change in  the reaction.

As the temperature of the solution increases, the heat is released and ΔH < 0

The heat released in the reaction is obtained using coffe-cup calorimeter equation:

Q = C×m×ΔT

Where Q is heat

C is specific heat of the solution (4.184J/g°C)

m is mass of solution: Assuming density = 1g/mL, 100mL of solution = 100g

And ΔT is change in temperature (13.4°C)

Replacing:

Q = C×m×ΔT

Q = -4.184J/g°C×100g×13.4

Q = -5606.6J

Now, in the reaction you have:

Moles HCl:

0.050L * (2.2mol/L) = 0.11 moles

Moles NaOH:

0.050L * (2.0mol/L) = 0.1 moles

That means the moles of reaction are 0.1 moles, and heat change in the chemical reaction is:

5606.6J / 0.1 mol = 56066J =

-56.1kJ/mol


Related Questions

Select the correct responses to the questions from the drop-down menus.

Which type of precipitation freezes when it comes into contact with a cold surface?

Which type of precipitation is round pellets of ice more than 5 millimeters in diameter?

Which type of precipitation is water vapor that condenses into ice crystals in clouds?

Answers

Answer:

Which type of precipitation freezes when it comes into contact with a cold surface?  

✔ freezing rain

Which type of precipitation is round pellets of ice more than 5 millimeters in diameter?  

✔ hail

Which type of precipitation is water vapor that condenses into ice crystals in clouds?  

✔ snow

Explanation:

The type of precipitation that freezes when it comes into contact with a cold surface is freezing rain.

The type of precipitation that is round pellets of ice more than 5 millimeters in diameter is hail.

The type of precipitation where water vapor condenses into ice crystals in clouds is snow.

Freezing rain is the rain that is maintained at a temperature that's below freezing by ambient air mass. It's made entirely of liquid droplets.

Read related link on:

https://brainly.com/question/16381514

Based on what you observed on the link above,
describe how ice in a teapot is turned into steam.
Liquid
lid


Answers

Answer: the particles in the water heats up and the hotter to gets the faster it moves. When there is no where for the heat to go it builds up and pushes its way out and turns to steam when it hits cool air

Explanation:

Help!!!

A. A halogen
B. An alkaline earth metal
C. An alkali metal
D. A transition element

Answers

Answer:

B?

Explanation:

Enter the symbol of a sodium ion, Na+
N
a
+
, followed by the formula of a sulfate ion, SO42−
S
O
4
2

. Separate the ions with a comma only—spaces are not allowed.
Express your answers as ions separated by a comma.

Answers

Answer:

Na⁺,SO₄²⁻

Explanation:

Sodium sulfate is formed by the sodium and sulfate ion.

Sodium is present in group one thus it has only one valence electron. Sodium lose its one valence electron to get complete octet and thus form cation with +1 charge.

On other hand sulfate ion is an anion it carries -2 charge so when it react with sodium there are two sodium atom combine with one sulfate ion inorder to make the compound neutral.

2Na + SO₄²⁻  →  Na₂SO₄

Sodium sulfate is actually form when sodium react with sulfuric acid and hydrogen gas is liberated.

Chemical equation:

Na + H₂SO₄  →  Na₂SO₄ + H₂

Balance chemical equation:

2Na + H₂SO₄  →  Na₂SO₄ + H₂

PLEASEEEEEEEEEEEEEEEEEEEE im slow i'll give you brainliest if you answer idkk what to do

Answers

Answer:Molecule:

a group of atoms bonded together, representing the smallest fundamental unit of a chemical compound that can take part in a chemical reaction.

Compound:

A compound is a material formed by chemically bonding two or more chemical elements. The type of bond keeping elements in a compound together may vary: covalent bonds and ionic bonds are two common types. The elements are always present in fixed ratios in any compound.

Element:

Chemical element, also called element, any substance that cannot be decomposed into simpler substances by ordinary chemical processes. Elements are the fundamental materials of which all matter is composed.

Mixture:

is a material made up of two or more different substances which are physically combined.

Chemical Formula:

A chemical formula identifies each constituent element by its chemical symbol and indicates the proportionate number of atoms of each element. I

Pure substance:

A substance that has a fixed chemical composition throughout is called a pure substance such as water, air, and nitrogen.

hope this help!

Answer:

Here are the definitions of all of them.

Explanation:

Molecule:

a group of atoms bonded together, representing the smallest fundamental unit of a chemical compound that can take part in a chemical reaction.

Compound:

A compound is a material formed by chemically bonding two or more chemical elements. The type of bond keeping elements in a compound together may vary: covalent bonds and ionic bonds are two common types. The elements are always present in fixed ratios in any compound.

Element:

Chemical element, also called element, any substance that cannot be decomposed into simpler substances by ordinary chemical processes. Elements are the fundamental materials of which all matter is composed.

Mixture:

is a material made up of two or more different substances which are physically combined.

Chemical Formula:

A chemical formula identifies each constituent element by its chemical symbol and indicates the proportionate number of atoms of each element. I

Pure substance:

A substance that has a fixed chemical composition throughout is called a pure substance such as water, air, and nitrogen.

It takes 15.0 seconds to run 100.0 meters if you run .0500 how many meters will you run

Answers

Answer:

150 seconds

Explanation:

Which process squeezes layers of sediment together?

compaction
deposition
erosion
weathering

Answers

The answer is compaction.

Answer:

The answer is compaction.

Explanation:

A 4.534 g sample of a solid mixture was analyzed for barium ion. First the rock was crushed in a mortar and pestle. 100% of the sample was transferred to a beaker, where it was dissolved in 150.0 mL of d.i. water. to give 152 mL of solution. The aqueous sample was then analyzed by adding a small excess of sulfuric acid. The resultant reaction produced a precipitate of barium sulfate, which was collected by filtration, rinsed, dried and weighed. If 0.5376 g of barium sulfate was obtained, what was the mass percent of barium in the original sample? What was the molar concentration barium in the 152 mL of solution prior to adding sulfuric acid? Show work clearly; include a balanced net ionic chemical equation, units and sig. figs.

Answers

Answer:

6.976%

0.0152 M

Explanation:

Step 1: Write the balanced chemical equation

Ba²⁺(aq) + H₂SO₄(aq) ⇒ BaSO₄(s) + 2 H⁺(aq)

The balanced net ionic chemical equation is:

Ba²⁺(aq) + SO₄²⁻(aq) ⇒ BaSO₄(s)

Step 2: Calculate the moles corresponding to 0.5376 g of BaSO₄

The molar mass of BaSO₄ is 233.39 g/mol.

0.5376 g × (1 mol/233.39 g) = 2.303 × 10⁻³ mol

Step 3: Calculate the moles of Ba²⁺ that produced 2.303 × 10⁻³ moles of BaSO₄

The molar ratio of Ba²⁺ to BaSO₄ is 1:1. The moles of Ba²⁺ are 1/1 × 2.303 × 10⁻³ mol = 2.303 × 10⁻³ mol.

Step 4: Calculate the mass corresponding to 2.303 × 10⁻³ moles of Ba²⁺

The molar mass of Ba²⁺ is 137.33 g/mol.

2.303 × 10⁻³ mol × 137.33 g/mol = 0.3163 g

Step 5: Calculate the mass percent of barium in the original sample

0.3163 g of barium ion were in a 4.534 g-sample. The mass percent of barium ion is:

0.3163 g/4.534 g × 100% = 6.976%

Step 6: Calculate the molar concentration barium in the 152 mL of solution

2.303 × 10⁻³ moles of barium ion were in 152 mL (0.152 L) of solution. The molarity of barium ion is:

M = 2.303 × 10⁻³ mol/0.152 L = 0.0152 M

Using Beer's Law determine the concentration of a dye dissolved in water that has an absorptivity of 1 x 102 cm-1M-1 and produces an absorbance reading 1.0. The length of the cuvette is 1 cm.

Answers

Answer:

1 × 10⁻² M

Explanation:

Step 1: Given data

Absorptivity of a dye (ε): 1 × 10² cm⁻¹M⁻¹

Absorbance (A): 1.0

Length of the cuvette (l): 1 cm

Concentration of a dye (C): ?

Step 2: Calculate the concentration of the dye

We will use Beer's Law.

A = ε × l × C

C = A / ε × l

C = 1.0 / 1 × 10² cm⁻¹M⁻¹ × 1 cm

C = 1 × 10⁻² M

The concentration of the dye is 1 × 10⁻² M.

* 20 POINTS

A ________ is made of two or more elements chemically combined.


a.

alloy


b.

mixture


c.

element


d.

compound

Answers

Answer:

Compound is the answer

Match the term with the definition. (4 points)

Column A
1.
Liquid

:
Liquid

2.
Plasma

:
Plasma

3.
Solid

:
Solid

4.
Gas

:
Gas

Column B
a.
has lots of space between the charged particles

b.
has lots of space between particles and is easily compressible

c.
flows easily but is difficult to compress

d.
does not flow easily and is difficult to compress

Answers

Answer:

1 - does not flow easily and is difficult to compress

2 -does not flow easily and is difficult to compress.

3 -has lots of space between the charged particles.

4-flows easily but is difficult to compress.

Explanation:

what is the formula for sodium hydrogen phosphate

Answers

Answer: Na2HPO4

Explanation: this is the formula

Answer:

Na3PO4

Explanation:.

The salt copper(II) sulfate dissolves in water according to the reaction: CuSO4(s) Cu2+(aq) + SO42-(aq) (a) Calculate the standard enthalpy change ΔH° for this reaction, using the following data: CuSO4(s) = -771.4 kJ mol-1 Cu2+(aq) = 64.8 kJ mol-1 SO42-(aq) = -909.3 kJ mol-1 kJ (b) Calculate the temperature reached by the solution formed when 13.0 g of CuSO4 is dissolved in 0.109 L of water at 25.0 °C. Approximate the heat capacity of the solution by the heat capacity of 109 g of pure water (specific heat capacity = 4.18 J g-1 °C-1), ignoring the mass of the salt. °C (c) Heats of reaction find practical application in hot packs or cold packs. Would this dissolution reaction be appropriate for the preparation of a hot pack or a cold pack?

Answers

Answer:

(a) [tex]\Delta H=-73.1\frac{kJ}{mol}[/tex]

(b) [tex]T_2=38.1\°C[/tex]

(c) Yes, it is appropriated.

Explanation:

Hello.

(a) In this case, given the formation enthalpies for copper (II) sulfate, copper (II) ion and sulfate ion, we can compute the enthalpy change for such process as follows:

[tex]\Delta H=\Delta H_{Cu^{2+}}+\Delta H_{SO_4^{-2}}-\Delta H_{CuSO_4}\\\\\Delta H=64.8-909.3-(-771.4)\\\\\Delta H=-73.1\frac{kJ}{mol}[/tex]

(b) In this case, since 13.0 g of copper (II) sulfate (molar mass: 159.55 g/mol) we can compute the gained heat by water via:

[tex]Q_{water}=-n_{CuSO_4}\Delta H=-13.0g*\frac{1mol}{159.55g}* -73.1\frac{kJ}{mol}\\ \\Q_{water}=5.96kJ=5960J[/tex]

As the heat lost by the reaction is gained by the water, therefore, the final temperature is:

[tex]Q_{water}=m_{water}Cp_{water}(T_2-T_1)\\\\T_2=T_1+\frac{Q_{water}}{m_{water}Cp_{water}}\\ \\T_2=25.0\°C+\frac{5960J}{0.109L*\frac{1000g}{1L}*4.18\frac{J}{g\°C} } \\\\T_2=38.1\°C[/tex]

(c) In this case, since this dissolution reaction is exothermic as it increases the temperature when undergone, we can infer that yes, this dissolution would be appropriate for the preparation of a hot pack, because a cold pack would be with an endothermic dissolution reaction.

Best regards.

HELP ASAP!!!........

Answers

Bleach, Carbon dioxide, Baking soda and table salt
Iron, Carbon Dioxide, Copper, Baking Soda, Oxygen, and Salt.

Looked them up, so not super sure but these are what they gave me!

Which of the following describes a chemical change?
A. a suspension of corn starch and water
B. formation of a precipitate
C. formation of a solution
D. filtration of a solid from a liquid

Answers

Answer:

C

Explanation:

Have a nice day

Classify the sugars as either aldoses or ketoses. A Fischer projection with a six carbon backbone. Carbon one is an aldehyde and carbon six is part of the group C H 2 O H. Carbons two and three have an hydroxide group on the left, and carbons four and five have an hydroxide group on the right. A Fischer projection of a six carbon backbone. Carbons one and six are part of a C H 2 O H group. Carbon two is attached to a ketone, carbons three and four have a hydroxide group on the left, and carbon five has a hydroxide group on the right. A Fischer projection with a five carbon backbone. Carbon one is an aldehyde, carbon five is part of the group C H 2 O H, and carbons two through four have an hydroxide group on the right. A Fischer projection with a three carbon backbone. Carbon one is an aldehyde, carbon three contains the group C H 2 O H, and carbon two has a hydroxide group on the right. A Fischer projection with a five carbon backbone. Carbons one and five are part of a C H 2 O H group. Carbon two is attached to a ketone and carbons three and four have a hydroxide group on the right. A Fischer projection of a four carbon backbone. Carbons one and four are part of a C H 2 O H group. Carbon two is attached to a ketone and carbon three has a hydroxide group on the right. Answer Bank

Answers

Answer AND Explanation: Carbohydrates or sugars have three classes:

Monossaccharides: made from a single polyhydroxy aldehyde or ketone unit;Oligosaccharides: formed by short chains of monossacharides united by glycosidic linkage;Polysaccharides: consist of a long chain of monossaccharides;

Monossaccharides are formed by a chain of unbranched carbon, all bonded  by single bonds, except for a carbon that is double-bonded by an oxygen. This bond form a carbonyl group.

If the carbonyl is at an end of the chain, the carbon is aldehyde and the molecule is called aldose. If the group is in any other position, it is a ketone and is called ketose

So analysing each projection:

1) Carbon one is a aldehyde, which means is a carbonyl and there are no other carbons forming that bond, so it's a ALDOSE

2) Carbon two is attached to a ketone and other carbons aren't, so it's a KETOSE.

3) Carbon one is aldehyde, so it's ALDOSE

4) Carbon one is aldehyde, so ALDOSE

5) Carbon two is attached to ketone, so KETOSE

6) Carbon two attached to a ketone, so KETOSE

Which properties makes a metal a good material to use for electrical wires?
A. Malleability and reactivity
B. Conductivity and ductility
C. Ductility and malleability
D. Reactivity and conductivity

Answers

Answer:

D

Explanation:

Because a metal must reactive and able to conduct

Answer:

B.Conductivity and ductility

Explanation.

Some metals are conductive and are ductile

Conductivity is the ability to have an electric flow

Ductility is the ability to bend

Determine the milliliters of paint in a 5.0 gallon bucket
Ans: 18950 ML

Answers

18,927.06 I believe that is the exact answer

Answer:

the answer is 18,927,06.

Explanation:

I just took the test ; )

How many total atoms are in one molecule of maltose?

Answers

Answer:

The total number of atoms is 12 + 22 + 11 = 45, so carbon atoms are 12/45 of the total.

Explanation:

Some dog foods contains corn and wheat that provide the dog with carbohydrates. Which claim explains why carbohydrates are important to cell processes?

A) They are a source of energy.

B) They make amino acids.

C) They form cell membranes.

D) They help chemical processes happen.

(Science 7th grade)

Answers

Hello!

The answer is that they are a source of energy!

Hope this helps!

C is the correct answer.

In a chemical reaction, what happens to the total number of each type of atom?

Answers

Answer:

In a chemical reaction the total mass of all the substances taking part in the reaction remains the same. Also, the number of atoms in a reaction remains the same. Mass cannot be created or destroyed in a chemical reaction.

Stoichiometry must be multiplied by the number that is printed on the element's foot in order to determine how many atoms of a certain element there are in a given molecule.  Therefore, the quantity of atoms inside a reaction doesn't change.

What is atom?

Atom is the smallest particle of any element, molecule or compound. Atom can not be further divided. Atoms have a central nucleus and electrons that move in a fixed orbit around it. Protons and neutrons are found in the nucleus. Electron has -1 charge while proton has +1 charge.

The combined mass of all of the components involved in a chemical process stays constant. Additionally, the quantity of atoms inside a reaction doesn't change. Chemical reactions cannot produce or destroy mass.

Therefore, the quantity of atoms inside a reaction doesn't change.

To know more about atom, here:

https://brainly.com/question/13518322

#SPJ6

How many moles of carbon are produced When 1745g of sugar react according to the equation C6H12O6+ H2SO4 to 6C +6H2O

Answers

Answer:

Number of moles of C produced =  58.08 mol

Explanation:

Given data:

Mass of sugar = 1745 g

Moles of C produced = ?

Solution:

Chemical equation:

C₆H₁₂O₆  +   6H₂SO₄    →     6C + 6(H₂SO₄.H₂O)

Number of moles of sugar:

Number of moles = mass/molar mass

Number of moles = 1745 g/180.16 g/mol

Number of moles = 9.68 mol

Now we will compare the moles of C and sugar.

                 C₆H₁₂O₆          :           C

                      1                  :           6

                    9.68              :          6×9.68 = 58.08 mol

Number of moles of C produced =  58.08 mol

How many oxygen atoms are in 8.20 g Na 2SO 4?

Answers

Answer:

No. of atom =

no.of moles x avagardro's number xatomicity

= weight /molar mass x No x atomicity

=8.2/142 x6.02x10^23 x 4

=0.346 x 10^23(approximately)


You were tasked to check if the liquid sample you have is a substance or a
mixture. Which among these tests is the BEST way to do so?l.color comparizon
lltaste comparizon
III. Boiling Test
IV. Melting Test
a.I, II, III and IV. b.l,II, and III only
c. I and Ill only
d. I, II, and IV only

Answers

Answer:

The correct answer is - option C.  I and Ill only.

Explanation:

One never tastes a unknown chemical in chemistry lab especialy a liquid that can be hazardous. Melting test is for solid as a solution is already a liquid state so melting test can not be perform on it.

The two test can be perform on given sample that are color comparison and boiling test to check if it is substance or a mixture. A misture is prepared from mixing different kind of compounds that can give different kind of color  while a particular substance give a uniform color always or remain colorless.

Boiling test can be helpful in distinguish a mixture from a substance as a particular sybstance always give a particular boiling point but mixture can be varry and depend of the coponents mixed together

What would be the formal charge of N in NO2?

Answers

Answer:

What would be the formal charge of N in NO2?

Explanation:

The nitrogen gets two electrons for the double bond, one from the single bond and one from the half-filled orbital associated with it. That's a total of 4 and gives N a +1 formal charge since itneeds 5 to be neutral. The Rules for Writing Lewis Structures has some discussion of formal charge in it.

Element Rand Element Q have the same number of valence
electrons. These elements both have similar chemical behavior, but
Element R has fewer energy levels than Element Q. Which statement best
describes the positions of the two elements in the periodic table?

Answers

I know I'm answering super late, but I just want to help others who don't know the answer

Answer:

H. The two elements are in the same group, with Element R just above Element Q.

Explanation:

When answering a question like this, I would highly recommended using a periodic table. I used a periodic table to find the answer to the question.

What is the smallest particle of matter called?

Answers

Answer:

an atom and inside the atom are protons electrons and nuetrons

Explanation:

Answer:

An Atom

Explanation:

An atom is the most smallest particle of matter, you can't see with the most powerful telescopes or microscopes

Suppose 4.0 g of hydrogen reacts completely with 32.0 g of oxygen to form one product what is the mass of the product?

Answers

Answer: The mass of product, [tex]H_2O[/tex] is, 36.0 grams.

Explanation : Given,

Mass of [tex]H_2[/tex] = 4.0 g

Mass of [tex]O_2[/tex] = 32.0 g

Molar mass of [tex]H_2[/tex] = 2 g/mol

Molar mass of [tex]O_2[/tex] = 32 g/mol

First we have to calculate the moles of [tex]H_2[/tex] and [tex]O_2[/tex].

[tex]\text{Moles of }H_2=\frac{\text{Given mass }H_2}{\text{Molar mass }H_2}[/tex]

[tex]\text{Moles of }H_2=\frac{4.0g}{2g/mol}=2.0mol[/tex]

and,

[tex]\text{Moles of }O_2=\frac{\text{Given mass }O_2}{\text{Molar mass }O_2}[/tex]

[tex]\text{Moles of }O_2=\frac{32.0g}{32g/mol}=1.0mol[/tex]

Now we have to calculate the limiting and excess reagent.

The balanced chemical equation is:

[tex]2H_2+O_2\rightarrow 2H_2O[/tex]

From the balanced reaction we conclude that

2 mole of [tex]H_2[/tex] react with 1 mole of [tex]O_2[/tex]

From this we conclude that, there is no limiting and excess reagent.

Now we have to calculate the moles of [tex]H_2O[/tex]

From the reaction, we conclude that

2 moles of [tex]H_2[/tex] react to give 2 moles of [tex]H_2O[/tex]

Now we have to calculate the mass of [tex]H_2O[/tex]

[tex]\text{ Mass of }H_2O=\text{ Moles of }H_2O\times \text{ Molar mass of }H_2O[/tex]

Molar mass of [tex]H_2O[/tex] = 18 g/mole

[tex]\text{ Mass of }H_2O=(2.0moles)\times (18g/mole)=36.0g[/tex]

Therefore, the mass of product, [tex]H_2O[/tex] is, 36.0 grams.

12. What is the frequency of a photon with an energy of 3.03 x 10-19 J?
(Planck's constant: h=6.63x 10-34 J·s) (E =hu)
a. 1.98x10^-18 Hz
b. 4.58x10^14 Hz
c. 2.16x10^14 Hz
d. 4.39x10^-19 Hz

Answers

Answer:

[tex]u=4.57x10^5GHz[/tex]

Explanation:

Hello.

In this case, given the formula:

[tex]E=h*u[/tex]

Whereas E is the energy, h the Planck's constant and u the frequency of the photon. Thus, solving for it, we obtain:

[tex]u=\frac{E}{h}=\frac{3.03x10^{-19}J}{6.63x10^{-34}J*s}\\ \\u=4.57x10^{14}s^{-1}[/tex]

Or also:

[tex]u=4.57x10^{14}Hz*\frac{1GHz}{1x10^9Hz}\\ \\u=4.57x10^5GHz[/tex]

Best regards.

Which of the following is least like the others on the list?

a. Glucose
b. Glycogen
c. Sucrose
d. Catalase

Answers

Answer:

catalase

Explanation:

catalase is enzime the rest are glucides

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