Why is the r.a.m. value used?
A. The r.a.m. value is used to determine how many isotopes an element has.
B. None of these
C. Atoms are too small for their masses to be measured directly.
D. A single atom cannot be isolated, so only the average size of a group of atoms can be measured.

Answer:

temperature, or true. I don't know which you want.

Explanation:

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Answer:

Explanation:

Observation. Observational skills are the starting point for critical thinking. People who are observant can quickly sense and identify a new problem.

Analysis. Once a problem has been identified, analysis skills become essential. ...

Answer:

d) I, III, and IV

Explanation:

rust, copper oxidation, and percipitate from a chemical reaction are all, well, chemical reactions.

Answer:

See below

Explanation:

From periodic chart

Mg = 24.305 gm per mole

24.305 * 3 = 72.915 gm

Na = 22.989

Cl = 35.45            summed = 58.439 gm per mole

   58.439 * 4.2 = 245.4438 gm

Answer:

They contain and control nuclear chain reactions that produce heat through a physical process called fission. That heat is used to make steam that spins a turbine to create electricity

Explanation:

Answer:

2H+(aq) + 2Br-(aq) + Mg2+(aq) + S2–(aq) = Mg2+(aq) + 2Br-(aq) + H+(aq) + HS-(aq)

Answer:

hydrocarbon

Explanation:

it reacts with oxygen to produce water and carbon dioxide.

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Explanation:

Zn + Sn3(PO4)4 = Zn3(PO4)2 + Sn - Balanced Chemical Equation

4.3 is limiting

is the answer

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Answer: Smelling salts and oxygen are introduced into a metal catalyst-containing tube (platinum). Typically warmed to get the reaction started. The alkali is then oxidized to produce nitric oxide.

Answer:

The Ostwald process is a chemical process used for making nitric acid. Wilhelm Ostwald developed the process, and he patented it in 1902. The Ostwald process is a mainstay of the modern chemical industry, and it provides the main raw material for the most common type of fertilizer production

Explanation:

The first stage of the Ostwald process involves the catalytic oxidation of ammonia into nitric oxide, using platinum as the catalyst. The nitric oxide is then transferred to a different oxidizing tower, where it is oxidized into nitrogen dioxide

Answer:

0.109

Explanation:

0.4-0.291=0.109

The mass of the acid produced is 0.252 g from the information in the question.

The term neutralization refers to the reaction between an acid and a base that yileds salt and water only.

The equation of this reaction is; 2HCl + CaCO3 ----->CaCl2 + CO2 + H2O

Number of moles of CaCO3 =   0.350 g/100 g = 0.0035 moles

Since 2 moles of acid reacts with 1 mole of CaCO3

x moles acid reacts with 0.0035 moles of CaCO3

x = 0.007 moles

Mass of acid = 0.007 moles * 36 g/mol = 0.252 g

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Answer:

[tex]\displaystyle K_a = 4.24\times 10^{-10}[/tex]

Explanation:

Write the base reaction of NaA with water:

[tex]\displaystyle \text{A}^-_\text{(aq)}+\text{H$_2$O}_\text{($\ell$)}\rightleftharpoons \text{HA}_\text{(aq)} + \text{OH}^-_\text{(aq)}[/tex]

Hence, the equilibrium constant expression for the reaction is:
[tex]\displaystyle K_b = \frac{[\text{OH}^-][\text{HA}]}{[\text{A}^-]}[/tex]

Thus, to find Ka, we can find Kb and use the fact that Ka × Kb = Kw.

From the reaction and initial concentration of NaA, create an ICE chart:

[tex]\begin{tabular}{llllll} & A^- &\text{H$_2$O} & \rightleftharpoons & HA & OH^- \\I & 0.563 M & \---- & & 0 M & 0 M \\C & -\text{ $ x$} & \---- & & +\text{ $x$ M} & + \text{$x$ M} \\E & \text{(0.563 - $x$) M} & \---- & & \text{$x$ M} & \text{$x$ M} \end{tabular}[/tex]

Find [OH⁻] from the given pH:
[tex]\displaystyle \begin{aligned} \text{pH} +\text{pOH} & = 14.00 \\ \\ \text{pOH} & = 14.00 - \text{pH} \\ \\ & = 14.00 - (11.56) \\ \\ & = 2.44 \\ \\ -\log[\text{OH}^-] & = 2.44 \\ \\ [\text{OH}^-] &= 10^{-2.44} \\ \\ & =0.00363 \text{ M}= 3.63\times 10^{-3} \text{ M} = x\text{ M}\end{aligned}[/tex]

Solve for all species concentrations at equilibrium from the found x value:

[tex]\displaystyle [\text{HA}] = [\text{OH}^-] = 3.63\times 10^{-3} \text{ M}[/tex]

And:

[tex]\displaystyle \begin{aligned} \ [\text{A}^-] & = 0.563 - 3.63\times 10^{-3} \text{ M}\\ \\ & = 0.559\text{ M}\end{aligned}[/tex]

Find Kb:

[tex]\displaystyle \begin{aligned} \displaystyle K_b &= \frac{[\text{OH}^-][\text{HA}]}{[\text{A}^-]} \\ \\ & = \frac{(3.63\times 10^{-3})(3.63\times 10^{-3})}{(0.559)}\\ \\ & = 2.36\times 10^{-5}\end{aligned}[/tex]

Find Ka:

[tex]\displaystyle \begin{aligned} K_a\cdot K_b & = K_w \\ \\ K_a & = \frac{K_w}{K_b} \\ \\ & = \frac{(1.00 \times 10^{-14})}{(2.36\times 10^{-5})} \\ \\ &= 4.24\times 10^{-10} \end{aligned}[/tex]

In conclusion:
[tex]\displaystyle K_a = 4.24\times 10^{-10}[/tex]

Answer:

Explanation:

General Remarks

The balance numbers are the same. (The balance numbers are 2 and 2)

The balance number in front of the O2 is 1.

So for every mole of O2 needed 2 moles of NO2 should be produced.

If 10.0 moles of oxygen is used, then you should get 20 mols of NO2 should be produced.

Formula

% yield = (what was produced / what should have been produced) *100

Givens

What was produced = 7 moles

What should have been produced = 20 moles

Solution

Substitute the givens into the equation

% yield = 8/20 * 100

% yield = 0.40 * 100

Answer: 40%

Answer:

Aerosol cans are pressurized, High temperatures increase the pressure in an aerosol can, potentially to the point of explosion.

Answer:

H30,+ion is known as Hydroniom Ion

Explanation:

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Answer:

Coal

Explanation:

Since the molecule is able to immediately absorb the red color of the bromine, the molecule would be cycloheptene.

Unsaturation in organic compounds refers to the presence of double or triple bonds in the compounds.

One way to test for unsaturation is to use bromine water. A saturated compound will not be able to absorb bromine because it is already saturated.

An unsaturated compound, on the other hand, will be able to absorb bromine due to the unsaturation. Therefore, the red color of bromine will disappear due to absorption.

Cycloheptane is saturated while cycloheptene is unsaturated. Thus, the latter will absorb the red color of bromine.

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Decay of Uranium-238 produces gamma radiaton whereas decay of thorium-234 releases beta radiation.

In the decay of U-238, two gamma rays of different energies are emitted in addition to the alpha particle while on the other hand, in the decay of thorium-234 , beta rays are emitted.

So we can conclude that decay of Uranium-238 produces gamma radiaton whereas decay of thorium-234 releases beta radiation.

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Answer:

2g is the answer

Explanation:

based on google

Answer:

the answer has been given below have a good day

Explanation:

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The species are present at 10-6 mole/L or greater when dissolved in water is when in solutions, weak acids and bases partially ionize.

Ionization is defined as anything that causes electrically neutral atoms or molecules to gain or lose electrons in order to become electrically charged atoms or molecules (ions).  One of the main mechanisms by which radiation, including charged particles and X-rays, transmits their energy to matter is ionization. An anion is created when an atom or molecule picks up an electron; a cation is created when they lose an electron.

Weak Acids and Weak Bases Ionizing. Numerous acids and bases are weak, meaning they do not completely ionize in aqueous solution. The nonionized acid, hydronium ion, and conjugate base of a weak acid are all mixed together to form a solution in water, with the nonionized acid being present in the highest concentration.

Thus, the species are present at 10-6 mole/L or greater when dissolved in water is when in solutions, weak acids and bases partially ionize.

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Answer:

The Relationship between Pressure and Volume: Boyle's Law

As the pressure on a gas increases, the volume of the gas decreases because the gas particles are forced closer together. Conversely, as the pressure on a gas decreases, the gas volume increases because the gas particles can now move farther apart

For the first ionization energy of mercury is 1006 kJ/mol. The energy change for the reaction  is mathematically given as

dH = 1006KJ/mol

The amount of energy required to remove an electron from a neutral atom is called ionization energy. from the question, the electron is removed from the neutral atom Hg to give the first ionization energy

Hg→Hg +e

therefore the energy change for the reaction is

dH = 1006KJ/mol

In conclusion, the energy change for the reaction is

dH = 1006KJ/mol

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Explanation:

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Answer: D. Fusion reactions in the sun convert small amounts of mayter into large amounts of energy.

Explanation:

N2 (g) + H2 (g) gives out NH3 (g)

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.(If you balance the hydrogen reactant with a whole number first, I can guarantee you that you will have to give NH3 a new stoichiometric coefficient.)

N2 (g) + 3H2 (g) gives out 2NH3 (g)

The stoichiometric coefficients tell you that if we can somehow treat every component in the reaction as the same (like on a per-mol basis, hinthint), then one "[molar] equivalent" of nitrogen yields two [molar] equivalents of ammonia.

Luckily, one mol of anything is equal in quantity to one mol of anything else because the comparison is made in the units of mols.

So what do we do? Convert to

mols (remember the hint?).

28g N2 × 1 mol N2/ 2 × 14.007) g N2

= 0.9995 mol N2

At this point you don't even need to calculate the number of mols of H2 . Why? Because H2 is about 2 g/mol, which means we have over 10 mols of H2. We have 1 mol N2, and we need three times as many mols of H2 as we have

N2.

After doing the actual calculation you should realize that we have about 4 times as much H2 as we need. Therefore the limiting reagent is clearly N2.

Thus, we should yield 2×0.9995=1.9990 mols of NH3 (refer back to the reaction). So this is the second and last calculation we need to do:

1.9990 mol NH3 × 17.0307 g NH3/ 1 mol NH3

= 34.0444 g NH3

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34grams of NH₃ can be produced from the reaction of 28g of N₂ and 25g of H₂ and 19g of the excess reagent is left over.

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.

A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.

Given,

Mass of N₂ = 28g

Mass of H₂ = 25g

Moles of N₂ = mass / molar mass

                    = 28 / 28

                   = 1 mole

Moles of H₂ = 25 / 2

                     = 12.5 moles

Since the number of moles of N₂ is lesser, the amount of products formed depends on the moles of N₂.

From the reaction,

1 mole of N₂ gives 2 moles of NH₃

So, Mass of NH₃ in 2 moles = 2 × 17

                                              = 34g

B) From the reaction,

1 mole of N₂ reacts with 3 moles of H₂.

The number of Moles of H₂ left = 12.5 - 3

                                                    = 9.5 moles

Mass of excess reagent left = moles left × molar mass of H₂

                                             = 9.5 × 2

                                             = 19g

Therefore, 34grams of NH₃ can be produced from the reaction of 28g of N₂ and 25g of H₂ and 19g of the excess reagent is left over.

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A precipiatate of mass 0.013 g is formed when you mix 75.0 mL of a NaOH solution with pOH of 2.58 and  125.0 mL of a 0.0018 M MgCl2 solution

In stoichiometry, calculations are made based on mass - mole or mole - volume relationships. First we must put down the balanced reaction equation; 2NaOH(aq) + MgCl2(aq) -----> Mg(OH)2(s) + 2NaCl(aq)

Now Ionically;

2OH^-(aq) + Mg^2+(aq)  -----> Mg(OH)2(s)

Concentration of OH^- = Antilog (-2.58) = 2.6 * 10^-3 M

Number of moles of OH^- = 2.6 * 10^-3 M * 75/1000 = 0.000195 moles

Concentration of Mg^2+ = 0.0018 M

Number of moles of Mg^2+ =0.0018 M * 125/1000 = 0.000225 moles

Since;

1 mole of Mg^2+ reacts with 2 moles of  OH^-

x moles of Mg^2+ reacts with 0.000195 moles of  OH^-

x = 0.0000975 moles

Mg^2+  is the limiting reactant.

1 mole of Mg^2+ yields 1 mole of the precipitate

0.000225 moles of Mg^2+ yields 0.000225 moles of precipitate.

Hence, a precipitate is formed.

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Answer:

The kinetic energy decreases

Explanation:

When water freezes, it is losing heat. Heat and energy are interchangeable, meaning it loses energy.

Answer:

The kinetic energy of the molecules decreases.

Explanation:

because when temperature decreases the average kinetic energy of the gas molecules decreases as well.