Which of the following equations have no solution? Check all that apply.
6x + 1 = 3(2x – 4)
2 – 5x = 7x – 12
4(3 – x) = 2(6 – 2x)
5(x + 2) = 2(x – 4)
–4(x + 3) = 4(–x – 1)

Answers

Answer 1

Answer:

–4(x + 3) = 4(–x – 1) and 6x + 1 = 3(2x – 4)

Step-by-step explanation:

Answer 2

Answer:

1 ans 5

Step-by-step explanation:

no solution              –––

6x + 1 = 3(2x - 4)

6x + 1 = 6x - 4

6x - 6x + 1 = 6x - 6x - 4

1 ≠ -4

one solution

2 - 5x = 7x - 12

2 -5x + 5x = 7x + 5x - 12

2 = 12x - 12

2 + 12 = 12x - 12 + 12

14 = 12x

x = 14/12

infinite solutions

4(3 - x) = 2(6 - 2x)

12 - 4x = 12 - 4x

12 - 12 - 4x + 4x = 12 - 12 - 4x + 4x

0 + 0 = 0 + 0

0 = 0

one solution

5(x + 2) = 2(x - 4)

5x + 10 = 2x - 8

5x - 5x + 10 + 8 = 2x - 5x - 8 + 8

18 = -3x

x = -6

no solution                            –––

-4(x + 3) = 4(-x - 1)

-4x + 4x - 12 = -4x + 4x - 4

-12 ≠ -4


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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Answers

Answer:c because the angle to the left and right are equal

Step-by-step explanation:

Answer:

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Step-by-step explanation:

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Answers

Answer:

C. 5, 12 and 13

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Step-by-step explanation:

To see if three side lengths would give you a right triangle, you have to use the Pythagoras Theorem which is a² + b² = c², where c is the hypotenuse (longest side) and a and b are adjacent to the right angle.

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Two lines are perpendicular if . Another way of saying this is the slopes of the two lines must be negative reciprocals of each other

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Answers

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Please be more specific

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Answers

Answer:

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Step-by-step explanation:

increased is another word for add

Answer:

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Find (x+y)^2 when (x-y)=5 and xy=24
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Answers

Answer:

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Answers

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Step-by-step explanation:

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Answers

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A

Step-by-step explanation:

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Answer:

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Answers

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Step-by-step explanation:

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Answer:

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Answers

Answer:

NO

Step-by-step explanation:

Pairs of alternate interior angles remain congruent, pairs of alternate exterior angles remain congruent, and pairs of same-side interior angles remain supplementary when the transversal is changed.

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An angle measures 38° less than its complement. Find the measures of the two angles.​

Answers

Let c represent the complement.

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equation :

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The measures of the angles are: 64°  and 26°.

Recall: Two angles are complement of each other if they add up to the sum of 90° .

Thus,

Let [tex]x[/tex] represent the first angle

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Therefore:

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Solve for x

[tex]x + x - 38 = 90\\2x - 38 = 90\\2x - 38 + 38 = 90 + 38\\2x = 128\\x = 64[/tex]

The first angle, x, is 64°

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Plug in the value of x

[tex]= 64 - 38\\= 26[/tex]

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