Answers
Answer:
i believe it is c
Explanation:
hope this helps and plz mark brainliest
Related Questions
A 60kg woman on skates throws a 3.9kg ball with a velocity of
37m.s west. What is the velocity of the woman?
Answers
Answer:
2.405 m/s
Explanation:
Given that,
Mass of a women, m₁ = 60 kg
Mass of a ball, m₂ = 3.9 kg
Velocity of the ball, v₂ = 37 m/s
We need to find the velocity of the woman. It is a concept based on the conservation of linear momentum. Let v₁ is the velocity of the woman. So,
[tex]m_1v_1=m_2v_2\\\\v_1=\dfrac{m_2v_2}{m_1}\\\\v_1=\dfrac{3.9\times 37}{60}\\\\v_1=2.405\ m/s[/tex]
So, the velocity of the woman is 2.405 m/s.
Mars has two moons, Phobos and Deimos. Phobos orbits Mars at a distance of 9380 km from Mars's center, while Deimos orbits at 23,500 km
from the center.
What is the ratio of the orbital period of Deimos to that of Phobos?
Answers
Answer:
The ratio is [tex]\frac{T_1}{T_2} = 3.965 [/tex]
Explanation:
From the question we are told that
The radius of Phobos orbit is R_2 = 9380 km
The radius of Deimos orbit is [tex]R_1 = 23500 \ km[/tex]
Generally from Kepler's third law
[tex]T^2 = \frac{ 4 * \pi^2 * R^3}{G * M }[/tex]
Here M is the mass of Mars which is constant
G is the gravitational constant
So we see that [tex]\frac{ 4 * \pi^2 }{G * M } = constant[/tex]
[tex]T^2 = R^3 * constant [/tex]
=> [tex][\frac{T_1}{T_2} ]^2 = [\frac{R_1}{R_2} ]^3[/tex]
Here [tex]T_1[/tex] is the period of Deimos
and [tex]T_1[/tex] is the period of Phobos
So
[tex][\frac{T_1}{T_2} ] = [\frac{R_1}{R_2} ]^{\frac{3}{2}}[/tex]
=> [tex]\frac{T_1}{T_2} = [\frac{23500 }{9380} ]^{\frac{3}{2}}][/tex]
=> [tex]\frac{T_1}{T_2} = 3.965 [/tex]
The given values are:
Radius, r = 23500 kmDistance = 9380 kmWe know the formula,
→ [tex]v = \frac{2 \pi r}{T}[/tex]
then,
→ [tex]\sqrt{\frac{GM_{mars}}{r} } =\frac{2 \pi r}{T}[/tex]
or,
→ [tex]T = 2 \pi \sqrt{\frac{r^3}{GM_{mars}} }[/tex]
Now,
The orbital period of Deimos will be:
[tex]= 2 \pi \sqrt{\frac{(23500)^3}{GM_{mars}} }[/tex]
The orbital period of Phobos will be:
[tex]= 2 \pi \sqrt{\frac{(9380)^3}{GM_{mars}} }[/tex]
hence,
The ratio will be:
→ [tex]\frac{T_{deimos}}{T_{Phobos}}[/tex] = [tex]\frac{2 \pi \sqrt{\frac{(23500)^3}{GM_{mars}} } }{2 \pi \sqrt{\frac{(9380)^3}{GM_{mars}} }}[/tex]
= [tex]\sqrt{(\frac{23500}{9380})^3 }[/tex]
= [tex]3.96[/tex]
Thus the above answer is correct.
Learn more about orbital period here:
https://brainly.com/question/14286363
Find the force that must be exerted on the rod to maintain a constant current of 0.173 A in the resistor.
Answers
Complete Question
Find the force that must be exerted on the rod to maintain a constant current of 0.173 A in the resistor.
The figure below shows a zero-resistance rod sliding to the right on two zero-resistance rails separated by the distance L = 0.451 m . The rails are connected by a [tex]12.6 \Omega \ resistor[/tex], and the entire system is in a uniform magnetic field with a magnitude of 0.751 T .
The diagram illustrating this question is shown on the first uploaded image
Answer:
The value is [tex]F = 0.0586 \ N [/tex]
Explanation:
From the question we are told that
The current is [tex]I = 0.173 \ A[/tex]
The length of separation is [tex]L= 0.451 \ m[/tex]
The resistance is [tex]12.6 \Omega[/tex]
The magnetic field is [tex]B = 0.751\ T[/tex]
Generally the force is mathematically represented as
[tex]F = BIL sin (\theta )[/tex]
Given that the velocity is perpendicular to magnetic field then [tex]\theta = 90[/tex]
=> [tex]sin(90) = 1[/tex]
So
[tex]F = 0.751 *0.173 * 0.451 sin (\theta )[/tex]
[tex]F = 0.751 *0.173 * 0.451 * 1[/tex]
[tex]F = 0.0586 \ N [/tex]
The derivative of a position function is a velocity function. The derivative of a velocity function is an acceleration function. A particle moves along a straight line. The distance of the particle from the starting point at time t is given by the function: s=t5−6t4 Find the value of t (other than 0 ) at which the acceleration is equal to zero. 6
Answers
Answer:
3.6secsExplanation:
Given the distance of the particle from the starting point at time t is given by the function: s=t⁵−6t⁴
velocity v(t) = ds/dt
[tex]v(t) = 5t^{5-1}-4(6)t^{4-1}\\v(t) = 5t^4-24t^3\\[/tex]
Next is to get the acceleration function:
[tex]a(t) = 4(5)t^{4-1}-3(24)t^{3-1}\\a(t) = 20t^3-72t^2[/tex]
Next is to get the value of t at which the acceleration is equal to zero
[tex]a(t) = 20t^3-72t^2\\0 = 20t^3-72t^2\\20t^3-72t^2 = 0\\t^2(20t-72) = 0\\t^2 =0 \ and \ 20t-72 = 0[/tex]
Since t ≠ 0, hence;
20t -72 = 0
20t = 72
t = 72/20
t = 3.6secs
Hence the value of t (other than 0 ) at which the acceleration is equal to zero is 3.6secs
Suppose you take a trip that covers 180 km and takes 3 hours to make.
Your average speed is
8. 33 m/s
b. 16.66 m/s
c. 27.78 m/s
d. 41.67 m/s
Answers
Answer:
v = 16,66 m/s
Explanation:
To obtain the velocity of the train we must use the velocity formula for a uniform line movement:
v = x/t
Where x is the space and t is time.
replacing given values:
v = 180 km / 3 h
v = 60 km/h
to pass this value to international units:
v = 60 / 3,6 m/s
v = 16,66 m/s
1- Write Gauss’ Law.
2- Consider an electric field line passing through a closed surface. What is the sign of the flux if:
a) The line passes from inside to outside?
b)The line passes from outside to inside?
Think of a conductor as having both positive and negative mobile charges. Consider a conductor in electrostatic equilibrium – that is, whose charges are stationary.
3- Given that all of the charges are stationary, what must the E-field be at any point inside of the conductor?
Answers
1)The total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux through an area is defined as the electric field multiplied by the area of the surface projected in a plane perpendicular to the field.
15) A 1720 kg car accelerates at a rate of 3.0 m/s2. How much force is the car's engine producing? (use the formula F=ma
Answers
Answer:
The answer is 5160 NExplanation:
To find the force acting on an object given it's mass and acceleration we use the formula
Force = mass × accelerationFrom the question
mass = 1720 kg
acceleration = 3.0 m/s²
We have
Force = 1720 × 3
We have the final answer as
5160 NHope this helps you
In a mass spectrometer chlorine ions of mass 35u and charge 5e are emitted from a source and accelerated through a potential difference of 250 kV. They then enter a region with a magnetic field that is perpendicular to their original direction of motion. The chlorine ions exit the spectrometer after being bent along a path with radius of curvature 3.5 m. What is the speed of the chlorine ions as they enter the magnetic field region
Answers
Answer:
Explanation:
From the question we are told that
The mass of chlorine ion is [tex]m_c = 35u = 35 * 1.66*10^{-27} = 5.81*10^{-26}\ kg[/tex]
The charge is [tex]q = 5e = 5 * 1.60 *10^{-19} = 8.0*10^{-19}\ C[/tex]
The potential difference is [tex]V = 250 kV = 250*10^{3} \ V[/tex]
The radius of curvature of the path is [tex]r = 3.5 \ m[/tex]
Gnerally the magnetic force will cause the speed of the chlorine ions to change from 0 m/s to [tex]v_y[/tex] m/s along the y -axis but will not affect the velocity along the x-axis
Generally according the law of energy conservation
[tex]K = PE[/tex]
Here K is the kinetic energy of the of the chlorine ions which is mathematically represented as
[tex]K = \frac{1}{2} mv^2[/tex]
And PE is electric potential energy which is mathematically represented as
[tex]PE = Q * V[/tex]
So
[tex] \frac{1}{2} mv^2 = Q * V [/tex]
=> [tex] \frac{1}{2} * 5.81*10^{-26} * v^2 = 8.0*10^{-19} * 250*10^{3} [/tex]
=> [tex] v = sqrt{6.8847 *10^{12}} [/tex]
=> [tex] v = 2.634 *10^{6} \ m/s [/tex]
1) The equilibrium constant Kc for the reaction N 2(g) + O 2(g) 2NO(g) at 1200 C is 1.00x 10^-5. Calculate the molar concentration of NO, N2 and O2 in equilibrium at 1200 C in a 1.00L container that initially had 0.114 mol of N2 and 0.114 mol of O2
2) A 2.0 mmol sample of Cl2 was closed inside a 2.0 L reaction vessel and heated to 1000k to study its dissociation into Cl atoms, Kc= 1.2x10^- 7 (a) Calculate the composition of the mixture in equilibrium. What is the percentage of decomposition of Cl2? (b) If 2.0 mmol of F2, Kc= 1.2x10^-4, is placed inside the container instead of chlorine, what will be its equilibrium composition at 1000k? Use your results from (a) and (b) to determine which is the most stable with respect to your atoms, Cl2 or F2, at 1000k
Answers
Explanation:
1) N₂ + O₂ → 2 NO
Kc = [NO]² / ([N₂] [O₂])
Set up an ICE table:
[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\N_{2}&0.114&-x&0.114-x\\O_{2}&0.114&-x&0.114-x\\NO&0&+2x&2x\end{array}\right][/tex]
Plug into the equilibrium equation and solve for x.
1.00×10⁻⁵ = (2x)² / ((0.114 − x) (0.114 − x))
1.00×10⁻⁵ = (2x)² / (0.114 − x)²
√(1.00×10⁻⁵) = 2x / (0.114 − x)
0.00316 = 2x / (0.114 − x)
0.00361 − 0.00316x = 2x
0.00361 = 2.00316x
x = 0.00018
The volume is 1.00 L, so the concentrations at equilibrium are:
[N₂] = 0.114 − x = 0.11382
[O₂] = 0.114 − x = 0.11382
[NO] = 2x = 0.00036
2(a) Cl₂ → 2 Cl
Kc = [Cl]² / [Cl₂]
[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\Cl_{2}&2.0&-x&2.0-x\\Cl&0&+2x&2x\end{array}\right][/tex]
1.2×10⁻⁷ = (2x)² / (2 − x)
1.2×10⁻⁷ (2 − x) = 4x²
2.4×10⁻⁷ − 1.2×10⁻⁷ x = 4x²
2.4×10⁻⁷ ≈ 4x²
x² ≈ 6×10⁻⁸
x ≈ 0.000245
2x ≈ 0.00049
2(b) F₂ → 2 F
Kc = [F]² / [F₂]
[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\F_{2}&2.0&-x&2.0-x\\F&0&+2x&2x\end{array}\right][/tex]
1.2×10⁻⁴ = (2x)² / (2 − x)
1.2×10⁻⁴ (2 − x) = 4x²
2.4×10⁻⁴ − 1.2×10⁻⁴ x = 4x²
2.4×10⁻⁴ ≈ 4x²
x² ≈ 6×10⁻⁵
x ≈ 0.00775
2x ≈ 0.0155
F₂ dissociates more, so Cl₂ is more stable at 1000 K.
A machine gun fires 50gm bullets at a speed of 1000m/s. the Gunner, holding the machine gun in his hand,can exert an average force of 180N against the gun. determine the maximum number of bullets he can fire per minute.
Answers
Answer:
We are given:
m = 50g OR 0.05 kg
v = 1000 m/s
Force applied by the gunner in a second = 180 N
Momentum(p) of the bullet:
p = mv
p = 0.05 * 1000
p = 50 kg m/s
Finding the recoil force:
The units kg m/s are also known as 'N' (newtons)
So, we can say that the force exerted on every bullet is 50 N
According to the law of conservation of momentum, every bullet fired applies a force of 50N towards the gunner
Hence, we can say that the recoil force of every bullet is 50N
Finding the number of bullets fired in a minute:
We are given that the gunner applied an average force of 180N on the gun
we know that that can also be written as 180 kg m/s. Notice the 's' in the units of the momentum, it tells us that this force is applied every second
So, to find the amount of force applied in a minute, we can multiply it by 60
Force applied by the gunner in a minute = (60 * 180) = 10800 N
Let n be the number of bullets fired in a minute
We can say that the force applied by the gunner is equal to the force applied by a bullet times the number of bullets fired
F(gunner) = n * F(bullet)
10800 = n * 50
n = 10800/50
n = 216 bullets / minute
The gunner shoots 216 bullets in a minute
In 2.5 s, a car increases its speed from 60 km/h to 65 km/h while a bicycle goes from rest to 5 km/h. Which undergoes the
greater acceleration?
What is the acceleration of each? (Don't forget your units when reporting answers).
Answers
Answer:
Same, 2 km/h/s
Explanation:
Acceleration is change in velocity over time.
a = Δv / Δt
The car's acceleration is:
a = (65 km/h − 60 km/h) / 2.5 s
a = 2 km/h/s
The bicycle's acceleration is:
a = (5 km/h − 0 km/h) / 2.5 s
a = 2 km/h/s
Can someone who knows how to do physics please answer this
Answers
Answer:
about 3.17647 hours
Explanation:
The appropriate relation is ...
time = distance/speed
time = (270 km)/(85 km/h) = 3 3/17 h ≈ 3.17647 h
It will take Derek about 3.17647 hours to drive the distance.
I WILL MARK YOU AS BRAINLIEST IF RIGHT
If you know that your average speed on road trips in 47 mph, how much time should you plan for a road trip to Atlanta, which is 715 miles away?
Answers
Answer:
about 15 hours and 13 minutes
Explanation:
If the average speed on road trips is 47 mph, then we use the formula for speed to estimate the time it would take to cover a distance of 715 miles:
speed = distance / time
solve for "time" by cross-multiplication:
time = distance / speed
time = 715 / 47 = 15.212 hours
Which is about 15 hours and 13 minutes
What's the equation with gravity that involves acceleration and time?
Answers
Answer:
g = G*M/R^2, where g is the acceleration due to gravity, G is the universal gravitational constant, M is mass, and R is distance.
Explanation:
These two laws lead to the most useful form of the formula for calculating acceleration due to gravity
explain which one would have a larger momentum a charging elephant or a buzzing bee
Answers
Plz mark me brainliest
A certain amusement park ride consists of a large rotating cylinder of radius R=3.05 m.R=3.05 m. As the cylinder spins, riders inside feel themselves pressed against the wall. If the cylinder rotates fast enough, the frictional force between the riders and the wall can be great enough to hold the riders in place as the floor drops out from under them. If the cylinder makes f=0.450 rotations/s,f=0.450 rotations/s, what is the magnitude of the normal force FNFN between a rider and the wall, expressed in terms of the rider's weight W?W? FN=FN= WW What is the minimum coefficient of static friction µsμs required between the rider and the wall in order for the rider to be held in place without sliding down?
Answers
Answer:
a. N = 2.49W b. 0.40
Explanation:
a. What is the magnitude of the normal force FNFN between a rider and the wall, expressed in terms of the rider's weight W?
Since the normal force equals the centripetal force on the rider, N = mrω² where r = radius of cylinder = 3.05 m and ω = angular speed of cylinder = 0.450 rotations/s = 0.450 × 2π rad/s = 2.83 rad/s
Now N = mrω² = m(3.05 m) × (2.83 rad/s)² = 24.43m
The rider's weight W = mg = 9.8m
The ratio of the normal force to the rider's weight is
N/W = 24.43m/9.8m = 2.49
So the normal force expressed in term's of the rider's weight is
N = 2.49W
b. What is the minimum coefficient of static friction µsμs required between the rider and the wall in order for the rider to be held in place without sliding down?
The frictional force, F on the rider by the wall of the cylinder equals the weight, W of the rider. F = W.
Since the frictional force F = μN, where μ = coefficient of static friction between rider and wall of cylinder and N = normal force between rider and wall of cylinder.
So, the normal force equals
N = F/μ = W/μ = mg/μ = mrω²
μ = mg/mrω²
= W/N
= 9.8m/24.43m
= 0.40
What is the most dangerous electromagnetic wave?
Answers
Answer:
Gamma Rays
Explanation:
Because it has the most energetic radiation and could penetrate through six feet of concrete. It is so strong it can damage your dna.
What is an antibody and what does it do?
Answers
an antibody is a blood protein produced in response to and counteracting a specific antigen. Antibodies combine chemically with substances which the body recognizes as alien, such as bacteria, viruses, and foreign substances in the blood.
Antibodies are proteins that help fight off infections and can provide protection against getting that disease again (immunity). Antibodies are disease specific.
The word photokinetic means “moving in response to light”. Why does this make sense based on the two main parts (morphemes) in this word?
Answers
Explanation:
photo means light in latin
kinetic means to move
if you double the period of a pendulum. what happens to its length?
Answers
The only way you COULD double the period would be to make the string 4 times as long as it is now.
Who? What? Where? When? Why?
Answers
Why does Chelsea see sparks as she removes her clothes from the clothes dryer?
conduction
induction
static discharge
static electricity
Answers
Answer:
Your answer is static discharge
Explanation:
Your negatively charged hand repels electrons in the metal, so the electrons move to the other side of the knocker. ... This allows electrons to suddenly flow from your hand to the knocker. The sudden flow of electrons is static discharge. The discharge of electrons is the spark you see and the shock you feel. I hope this helps, ( the other answer said static electricity which is wrong.) :)
Answer:
C
Explanation:
Why can concave mirror is used in cosmetic mirror
Answers
On his fishing trip Justin takes the boat 4 km south. The fish aren’t biting so he goes 4 km back east. He follows a school of fish 4 km further north and then 3 km west. What distance did he cover? What was his displacement?
Answers
Answer:
Distance = 15km
Displacement = 1km
Explanation:
the total distance covered is how far Justin has travelled = 4km + 4km + 4km + 3km
Total distance covered = 15km
To get the displacement, we will use the Pythagoras theorem. Find the diagram attached.
From the diagram, the displacement D is expressed as:
D = AC - BC
From the diagram
AC = 4km
BC = 3km
D = 4km - 3km
D = 1km
Hence his displacement is 1km
PHYSICS HELP URGENT!!! While standing at the edge of the roof of a building, a man throws a stone upward with an initial speed of 7.59 m/s. The stone subsequently falls to the ground, which is 18.9 m below the point where the stone leaves his hand. At what speed does the stone impact the ground? Ignore air resistance and use =9.81 m/s2 for the acceleration due to gravity. I need help finding out the impact speed, please.
Answers
Answer:
v = 20.69 m/s
Explanation:
Given that,
Initial speed of a stone, u = 7.59 m/s
he stone subsequently falls to the ground, which is 18.9 m below the point where the stone leaves his hand, h = 18.9 m
We need to find the speed of the stone impact the ground. Let the speed be v. Using the equation of kinematics to find v. So,
[tex]v^2-u^2=2as[/tex]
Here, a = g
So,
[tex]v^2=2gs+u^2\\\\v=\sqrt{2gs+u^2} \\\\v=\sqrt{2\times 9.81\times 18.9+(7.59)^2} \\\\v=20.69\ m/s[/tex]
So, the speed of the stone impact the ground is 20.69 m/s.
Newton's Law of Gravitation says that the magnitude F of the force exerted by a body of mass m on a body of mass M isF = GmMr2where G is the gravitational constant and r is the distance between the bodies.(a) Find dF/dr.dFdr = What is the meaning of dF/dr?dF/dr represents the rate of change of the distance between the bodies with respect to the force.dF/dr represents the rate of change of the mass with respect to the force. dF/dr represents the rate of change of the force with respect to the distance between the bodies.dF/dr represents the amount of force per distance.dF/dr represents the rate of change of the mass with respect to the distance between the bodies.What does the minus sign indicate?The minus sign indicates that the force between the bodies is decreasing.The minus sign indicates that the bodies are being forced in the negative direction. The minus sign indicates that as the distance between the bodies increases, the magnitude of the force decreases.The minus sign indicates that as the distance between the bodies decreases, the magnitude of the force remains constant.The minus sign indicates that as the distance between the bodies increases, the magnitude of the force increases.
Answers
Answer:
Explanation:
I forgot how to breath
Answers
Answer:
1-steal an inhaler 2-use it 3-your good
orrrr
1-swallow air(preferably air from space)
Answer:
then breath
Explanation:
A 10 kg object has a 40 N force applied to it. What is the acceleration of the object ? *
Answers
Answer:
a = 4 [m/s^2]
Explanation:
To solve this problem we must use Newton's second law, which tells us that force is equal to the product of mass by acceleration.
F = m*a
where:
F = force = 40 [N]
m = mass = 10 [kg]
a = 40/10
a = 4 [m/s^2]
Explain how to find the angle between two nonzero vectors. Choose the correct answer below. A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the twoâ vectors' magnitudes. Then taking the inverse cosine of the result. B. The angle between two nonzero vectors can be found by first dividing the product of the twoâ vectors' magnitudes by the dot product of the two vectors. Then taking the inverse cosine of the result. C. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the twoâ vectors' magnitudes. Then taking the inverse sine of the result. D. The angle between two nonzero vectors can be found by first dividing the product of the twoâ vectors' magnitudes by the dot product of the two vectors. Then taking the inverse sine of the result.
Answers
Answer:
θ = Cos⁻¹[A.B/|A||B|]
A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result
Explanation:
We can use the formula of the dot product, in order to find the angle between two non-zero vectors. The formula of dot product between two non-zero vectors is written a follows:
A.B = |A||B| Cosθ
where,
A = 1st Non-Zero Vector
B = 2nd Non-Zero Vector
|A| = Magnitude of Vector A
|B| = Magnitude of Vector B
θ = Angle between vector A and B
Therefore,
Cos θ = A.B/|A||B|
θ = Cos⁻¹[A.B/|A||B|]
Hence, the correct answer will be:
A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result
When jumping straight down, you can be seriously injured if you land stiff-legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 60.0-kg man just before contact with the ground has a speed of 4.18 m/s. (a) In a stiff-legged landing he comes to a halt in 1.00 ms. Find the magnitude of the average net force that acts on him during this time. (b) When he bends his knees, he comes to a halt in 0.245 s. Find the magnitude of the average net force now. (c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of the forces, find the magnitude of the force applied by the ground on the man in part (b).
Answers
Answer:
a) The average force that acts on the man is [tex]2.508\times 10^{8}[/tex] newtons.
b) The average force that acts on the man is 1023.673 newtons.
c) The force of the ground on the man is 1612.093 newtons upwards.
Explanation:
a) After a careful reading of the statement we construct the following model by applying Impact Theorem, that is:
[tex]m\cdot \vec v_{A} + \vec F \cdot \Delta t = m\cdot \vec v_{B}[/tex] (Eq. 1)
Where:
[tex]m[/tex] - Mass of the man, measured in kilograms.
[tex]\vec v_{A}[/tex] - Initial velocity of the man, measured in meters per second.
[tex]\vec v_{B}[/tex] - Final velocity of the man, measured in meters per second.
[tex]\Delta t[/tex] - Impact time, measured in seconds.
[tex]\vec F[/tex] - Average net force, measured in newtons.
Now we proceed to clear average net force within expression:
[tex]\vec F \cdot \Delta t = m\cdot (\vec v_{B}-\vec v_{A})[/tex]
[tex]\vec F = \frac{m}{\Delta t}\cdot (\vec v_{B}-\vec v_{A})[/tex] (Eq. 2)
If we know that [tex]m = 60\,kg[/tex], [tex]\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex], [tex]\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex] and [tex]\Delta t = 1\times 10^{-6}\,s[/tex], we obtain the following vector:
[tex]\vec F = \frac{60\,kg}{1\times 10^{-6}\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right][/tex]
[tex]\vec F = 2.508\times 10^{8}\,\hat{j}\,\,\,[N][/tex]
The average force that acts on the man is [tex]2.508\times 10^{8}[/tex] newtons.
(b) If we know that [tex]m = 60\,kg[/tex], [tex]\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex], [tex]\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex] and [tex]\Delta t = 0.245\,s[/tex], we obtain the following vector:
[tex]\vec F = \frac{60\,kg}{0.245\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right][/tex]
[tex]\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right][/tex]
The average force that acts on the man is 1023.673 newtons.
(c) From Second Newton's Law we find the following equation of equilibrium:
[tex]\vec F = \vec N -\vec W[/tex] (Eq. 3)
Where:
[tex]\vec F[/tex] - Average force that acts on the man, measured in newtons.
[tex]\vec N[/tex] - Force of the ground on the man, measured in newtons.
[tex]\vec W[/tex] - Weight of the man, measured in newtons.
By applying the concept of weight, we expand the previous equation:
[tex]\vec F = \vec N -m\cdot \vec g[/tex] (Eq. 3b)
Where [tex]\vec g[/tex] is the gravitational acceleration, measured in meters per square second.
And then we clear the force of the ground on the man:
[tex]\vec N = \vec F +m\cdot \vec g[/tex] (Eq. 4)
If we get that [tex]\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right][/tex], [tex]m = 60\,kg[/tex] and [tex]\vec g = 9.807\,\hat{j}\,\,\,\left[\frac{m}{s^{2}} \right][/tex], the average force is:
[tex]\vec N = 1023.673\,\hat{j}\,\,\,[N]+(60\,kg)\cdot (9.807\,\hat{j})\,\,\,\left[\frac{m}{s^{2}} \right][/tex]
[tex]\vec N = 1612.093\,\hat{j}\,\,\,\left[N\right][/tex]
The force of the ground on the man is 1612.093 newtons upwards.
