Where would sound NOT be
able to travel?

A. through the ground
B. through the ocean
C. through the air
D. through outer space

Answer:

maybe the answer is solid state

By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is [tex]\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}[/tex] meters.

Let suppose that the entire construction has a uniform mass, then the coordinates of the center of mass can be determined by definition of weighted average:

[tex]\bar x = \frac{\sum \limits_{i = 1}^{n}x_{i}\cdot m_{i}}{\sum \limits_{i=1}^{n}m_{i}}[/tex]     (1)

[tex]\bar y = \frac{\sum \limits_{i = 1}^{n}y_{i}\cdot m_{i}}{\sum \limits_{i=1}^{n}m_{i}}[/tex]     (2)

If we know that a = 2.20 m and b = 1.63 m, then the x-coordinates of the center of mass of the compound figure is:

[tex]\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}[/tex]

By weighted average method, the x-coordinates of the center of mass of the compound figure, the uniform thin L-shaped construction brace is [tex]\bar x = \frac{1.10\cdot m_{A}+2.10\cdot m_{B}}{m_{A}+m_{B}}[/tex] meters.

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If the masses of the objects are both doubled to 600 kg each, the force between them will be 40N.

The Newton's law of universal gravitation states that, force of gravity between two objects is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.

As such;

F = Km1m2/r^2

If the masses of the objects are doubled but the distance of separation remains the same, it follows that the force between the masses will also be doubled.  Hence, if the masses of the objects are both doubled to 600 kg each, the force between them will be 40N.

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Answer:

Explanation:

Voltage and Current relation is given by V=IR
I=9A

R=4Ohm

V=IR
V=9x4=36Volts

Resistance = 4 Ohm

Current = 9 Ampere

Voltage = 36 Volts

Answer:

4 mph

Explanation:

velocity =   miles divided by time =  miles/time

             =   1 mile / .25 hr   = 4 mph

Answer:

1600 joules

Explanation:

Potential Energy = m * g * h

                           = 20 kg  *  10 m/s^2  * 8 m = 1600 J

Answer:

The answer is Less.

Explanation:

The further you are away from a light source, the less intense the light appears.

A 95 kg fullback was running downfield at 8 m/s. A defensive player (110 kg) was running upfield at 6 m/s straight at the fullback. The momentum of each player before they impacted Fullback 760 kgm/s, Defender: 660 kgm/s.

In classical mechanics, the integral of a force, F, over the time period over which it acts, t, is referred to as the "impulse." Impulse is a vector quantity because force is one as well. When an item receives an impulse, it experiences an equivalent vector change in its linear momentum and also in the direction that results.

momentum = mass *velocity

momentum = 95*8 = 760 kg-m/sec Fullback

momentum = 110*6 = 660 kg-m/sec Defender

A 95 kg fullback was running downfield at 8 m/s. A defensive player (110 kg) was running upfield at 6 m/s straight at the fullback. The momentum of each player before they impacted Fullback 760 kgm/s, Defender: 660 kgm/s.

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[tex]\huge{\color{red}{\fbox{\textsf{\textbf{Answer}}}}} [/tex]

94.6J

Explanation:

Force (F) = 22N

mass (m) = 12kg

distance (S) = 4.3m

While

[tex] \sf Work \: done = Force \times distance[/tex]

This means

W = FS

while mass has no role in equation

Now substituting the required values

[tex] \sf W = 4.3 \times 22 \\ \\ \sf W = 94.6J[/tex]

λ = c : f

λ = 3 x 10⁸ : 1.05 x 10⁸

λ = 2.86 m

E = hf

h = Planck's constant (6.626.10⁻³⁴ Js)

E = 6.626.10⁻³⁴ x 2.86

E = 1.896 x 10⁻³³ J

λ = 3 x 10⁸ : 1.011 x 10⁸

λ = 2.97 m

E = hf

h = Planck's constant (6.626.10⁻³⁴ Js)

E = 6.626.10⁻³⁴ x 2.97

E = 1.97 x 10⁻³³ J

λ = 3 x 10⁸ : 1.05 x 10⁸

λ = 2.96 m

E = hf

h = Planck's constant (6.626.10⁻³⁴ Js)

E = 6.626.10⁻³⁴ x 2.96

E = 1.96 x 10⁻³³ J

Answer:

electron in the outermost

Explanation:

These are the electrons available for bonding or transfer

  protons do are not involved in actual bonding

Answer:

b

Explanation:

Atoms form chemical bonds using electrons in the outermost energy level, otherwise known as valence electrons.

For atoms to bond, they must either gain or lose electrons.

By gaining electrons, the atom attains a negative charge.

By losing electrons, the atom attains a positive charge.

Answer:

4000Ns

Explanation:

I=F×T=400N×10ms

Answer:

12.65 Meters / Second (m/s)

Explanation:

the problem is really easy to solve, we begin by stating the kinetic energy formula which is:

KE = (1/2)(mass)(velocity)^2

We equate 1200 J to the formula, substitute the mass, and solve for velocity either using a CAS, app, or by hand

1200J = (0.5)(15kg)v^2

v = 12.65 m/s

Answer:

[tex]2 \times 10^{-5}\ m[/tex]

Explanation:

[tex]v = f \lambda[/tex]

velocity of wave = frequency x wavelength

I'll assume we're talking about EM radiation here, which is any kind of light (microwave, ultraviolet, visible, etc.).

Every type of EM radiation has the same velocity — the speed of light.

Speed of light, known as [tex]c[/tex] — 300 000 000 = [tex]3 \times 10^8[/tex]

velocity: [tex]c = 3 \times 10^8[/tex] [tex]ms^{-1}[/tex]

frequency: [tex]f = 1.5 \times 10^{13}[/tex] [tex]\text{Hz}[/tex]

wavelength: [tex]\lambda =\ ?[/tex] [tex]m[/tex]

[tex]v = f \lambda\\3 \times 10^8 = 1.5 \times^{13}\ \times \ \lambda\\\text{rearrange for}\ \lambda\\\lambda = \frac{3 \times 10^8}{1.5 \times 10^{13}} = 2 \times 10^{-5}[/tex] [tex]m[/tex]

Answer:

thermometer A

Explanation:

The range of a thermometer is the difference between the minimum and maximum temperatures that the thermometer can read.

             ∴ Range of thermometer A = 110° - (-10)° = 120°

                Range of thermometer B = 50° - (-10)° = 60°

∴ Range of thermometer A is greatest.

Hope this helps!

A limitation of this model is that it can't be tested practically in order to check its validity.

Models are representations of scientific data that can help in defining, analyzing, and communicating many concepts. These models are developed in order to do analysis, specification, design, verification, and validation of a system.

So we can conclude that a limitation of this model is that it can't be tested practically in order to check its validity.

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That states that the blackhole ends are working like bridges between one space to another.

This may be possible

rxcuobudbbgvd CT I ng a ubjnr. hbgvw

Explanation:

Acceleration is a vector quantity which is defined as the rate at which an object changes its velocity

The block moving at instant the spring is compressed 15cm is  √[(25m - 45)/m]

When there is no external force acting on the system, the total mechanical energy remains conserved.

K.E i = K.E f + SPE

1/2 mu² =1/2 mv² + 1/2 kx²

Substitute u = 5m/s, k =2000N.m and x =0.15m, we get the final velocity

1/2 mu² =1/2 mv² + 1/2 kx²

v =√[(25m - 45)/m]

Thus, the block moving at the instant the spring has been compressed 15 cm is √[(25m - 45)/m]

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Answer:

a

0.57g

b

20.52

c

28.5

Explanation:

a

The bottle weighs 80g with tablets

If the bottle alone weighs 23g, the tablets weigh 57g

100 tablets weigh 57g, 1 tablet weighs 0.57g

b

0.57g is one tablet, so to achieve 36 tablets we must multiply by 36

0.57 multiplied by 36 is 20.52

c

To find 50 tablets we can use the same method we used before or a slightly faster method

100 tablets is 57g, so all we have to do is halve to find 50

57 divided by 2 is 28.5

the car take to catch up to the truck =  same distance

d truck = d car

vt = vot+1/2 at² (vo=0, from rest)

vt = 1/2at²

15t=1.5t²

1.5t²-15t=0

t(1.5t-15)=0

t = 0 or

1.5t=15⇒ t=10 s

Answer:

False

Explanation:

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[tex] \large \sf \underline{Question:}[/tex]

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[tex] \large \sf \underline{Answer:}[/tex]

Impulse and momentum are important in sports like cricket because from the word "momentum" it describe itself like you're getting used of it or you know what to do like there's no stopping you.

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How are impulse and momentum related?

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