Answer:
Explanation:
10.00 5
If the length of an ax is 20 cm and the width is 5 cm what is the MA of a knife?
O 2
0 4
O 10
O6
Answer:
4
Explanation:
From the question given above, the following data were obtained from:
Length of an axe = 20 cm
Width = 5 cm
Mechanical advantage (MA) =.?
The mechanica advantage is simply defined as the ratio of the length to the width of the axe. Mathematically, it is expressed as:
Mechanical advantage = length /width
With the above formula, we can obtain the mechanical advantage of the axe as follow:
Length of an axe = 20 cm
Width = 5 cm
Mechanical advantage (MA) =.?
MA = 20/5
MA = 4
Therefore, the mechanical advantage (MA) of the axe is 4
please please please please please please
9514 1404 393
Answer:
Mona
Explanation:
Speed is the slope of the position vs. time curve. The higher speed will have the greater slope.
Mona's curve has a greater slope, so Mona is fastest.
Doctors were furious. Their patients didn't care about regular medicine anymore. All they wanted was a wave of Dr. Mesmer's wand. The doctors griped — and groused — and fussed — and fumed. What is most likely the meaning of the word furious?
A quietly curious B quite thrilled C mildly annoyed D extremely angry
Answer:
am pretty sure the answer is d
Phoebe wants to measure the volume of a small, irregularly
shaped rock. Which of the following instruments would be best
for Phoebe to use?
Answer:
A graduated cylinder
Explanation:
A man is pulling a box with the force of 10N. There is nobody else on the other side of the box. What is the total amount of force on the box? *
A metric unit of volume equal to a milliliter
Which of the following is the primary force that shapes the Earth's landscape?
A coil is wrapped with 206 turns of wire on the perimeter of a circular frame (of radius 31 cm). Each turn has the same area, equal to that of the frame. A uniform magnetic field is directed perpendicular to the plane of the coil. This field changes at a constant rate from 23 mT to 54 mT in 24 ms. What is the magnitude of the induced average E in the coil, over the time interval 24 ms during which the field changes? Answer in units of V.
Answer:
E = -80.33 V
Explanation:
For this exercise we use Faraday's law of induction
E = - N d[tex]\phi _{B}[/tex] / dt
where the magnetic flux is
\phi _{B} = B A cos θ
In the exercise they indicate that the magnetic field is perpendicular to the coil, therefore the normal of the coil area and the field has the same direction, consequently the angle is zero. Since the area is constant
E = - N A dB / dt
let's look for each term
a =π r²
they tell us that the variation in the field is linear
dB / dT = (B_f-B₀) / t
we substitute
E = - N (π r²) (B_f -B₀) / t
let's calculate
E = - 206 π 0.31² (54 - 23) 10⁻³ / 24 10⁻³
E = -80.33 V
You move 6 meters east and move 8 meters south what’s the distance and displacement
The distance travelled in total is 14 m. But the resultant displacement is the square root of the sum of squares of each distances covered in different directions, that is 10 m.
What is displacement ?Displacement is a physical quantity that, that measures how far we travelled from a mean position. The change in position is dependent on the magnitude and direction as well. Hence, displacement is a vector quantity.
The distance covered by an object is total length or sum magnitudes of the length it covered. It is a scalar quantity. Here, the distance covered is 6 + 8 = 14 m.
The resultant displacement here, is calculated as follows:
ds = √(6² + 8²) = √100 = 10 m
Therefore, the displacement of us will be 10 m.
Find more on displacement :
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Why does a sound come out when you blow into a bottle?
When does the jet of air convert to vibrations?
Which undergoes greater acceleration: an airplane that goes from 1000 km/h to 1005 km/h in 10 seconds or a skateboard that
goes from zero to 5 km/h in 1 second?
Answer:
Skateboard
Explanation:
Acceleration is change in velocity over time.
a = Δv / Δt
The airplane's acceleration is:
a = (1005 km/h − 1000 km/h) / 10 s
a = 0.5 km/h/s
The skateboard's acceleration is:
a = (5 km/h − 0 km/h) / 1 s
a = 5 km/h/s
A wind tunnel draws atmospheric air at 20°C and 101.3 kPa by a large fan located near the exit of the tunnel. If the air velocity in the tunnel is 80 m/s, determine the pressure in the tunnel.
Answer:
The pressure in the tunnel is 97.45 kPa
Explanation:
Given;
atmospheric pressure, P₁ = 101.3 kPa
air velocity in the tunnel, v₂ = 80 m/s
density of air at 20°C, ρ = 1.204 kg/m³
pressure in the tunnel, P₂ = ?
Apply Bernoulli's equation;
P₁ + ¹/₂ρv₁² + ρgz₁ = P₂ + ¹/₂ρv₂² + ρgz₂
v₁ = 0
z₁ = z₂ = 0
P₁ = P₂ + ¹/₂ρv₂²
P₂ = P₁ - ¹/₂ρv₂²
P₂ = 101.3 kPa - (0.5 x 1.204 x 80²)
P₂ = 101.3 kPa - 3.8528 kPa
P₂ = 97.45 kPa
Therefore, the pressure in the tunnel is 97.45 kPa
Which of the following represents an example of thermal energy?
O a
Saxophone
Ob
Oven
с
Powerlines
Od
Windmill
Answer:
The answer of this question is windmill
A father fashions a swing for his kids out of a long rope that he fastens to the limb of a tall tree. As one of the kids swings from this rope that is 7.00 m long his tangential speed at the bottom of the swing is 8.65 m/s. What is his angular speed in rad/s
Answer:
1.236 rad/s
Explanation:
From the question above,
v = ωr................ Equation 1
Where v = tangental speed, ω = angular speed, r = radius = length of the rope.
Make ω the subject of the equation
ω = v/r.............. Equation 2
Given: v = 8.65 m/s, r = 7.00 m
Substitute these values into equation 2
ω = 8.65/7
ω = 1.236 rad/s
Hence the angular speed is 1.236 rad/s
To a stationary observer, a man jogs east at 2 m/s and a woman jogs west at
3 m/s. From the woman's frame of reference, what is the man's velocity?
Answer:
5 m/s east
Explanation:
i just took the test and it was correct
Answer:
Just took the test. 5 m/s east.
Explanation:
15. An astronaut on the moon has a 110 kg crate and a 230 kg crate. How do the forces required to liftyihe crates straight up on the moon compare with the forces required to lift them on Earth?
Explanation:
Mass of carte 1 is 110 kg and that of crate 2 is 230 kg
Force required to lift crates is equal to its crate i.e. W = mg
On Moon, a = 1.625 m/s²
Weight of crate 1, W = 110 kg × 1.625 m/s² = 178.75 N
Weight of crate 2, W = 230 kg × 1.625 m/s² = 373.75 N
On Earth, g = 9.8 m/s²
Weight of crate 1, W = 110 kg × 9.8 m/s² = 1078 N
Weight of crate 2, W = 230 kg × 9.8 m/s² = 2254 N
Hence, this is the required solution.
The forces required to lift the crates straight up on the Moon is lesser than the forces required to lift them on Earth.
Given the following data:
Mass A = 110 kgMass B = 230 kgScientific data:
Acceleration due to gravity on Earth = 9.8 [tex]m/s^2[/tex]Acceleration due to gravity on Moon = 1.6 [tex]m/s^2[/tex]The formula for weight.Mathematically, the weight of an object is given by the formula;
[tex]Weight = mg[/tex]
Where;
m is the mass of the object.g is the acceleration due to gravity.For the weight on Moon:[tex]Weight \;A= 110 \times 1.6[/tex]
Weight A = 176 Newton.
[tex]Weight \;B=230 \times 1.6[/tex]
Weight B = 368 Newton.
For the weight on Earth:[tex]Weight \;A= 110 \times 9.8[/tex]
Weight A = 1,078 Newton.
[tex]Weight \;B=230 \times 9.8[/tex]
Weight B = 2,254 Newton.
In conclusion, the forces required to lift the crates straight up on the Moon is lesser than the forces required to lift them on Earth.
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A 30.0 g object fell from a height y = 2.94 m. It’s velocity when y is zero is approximately equal to (in m/s) (a) 0 (b) 19.6 (c) 29.4 (d) 8.64
Analysing the question:
We are given:
mass of object (m) = 0.03 kg
height of object (h) = 2.94 m
acceleration due to gravity (a) = 10 m/s²
initial velocity (u) = 0 m/s [the object fell, we are NOT given any initial velocity]
final velocity (v) = v m/s
Solving for Final velocity:
from the third equation of motion:
v² - u² = 2ah
replacing the variables
(v)² - (0)² = 2(10)(2.94)
v² = 58.8
v = 7.67 m/s
In the early 1900s, Robert Millikan used small charged droplets of oil, suspended in an electric field, to make the first quantitative measurements of the electron’s charge. A 0.71-um-diameter droplet of oil, having a charge of , is suspended in midair between two horizontal plates of a parallel-plate capacitor. The upward electric force on the droplet is exactly balanced by the downward force of gravity. The oil has a density of 860 kg/m^3 , and the capacitor plates are 4.5 mm apart.
Part A
What must the potential difference between the plates be to hold the droplet in equilibrium?
Express your answer to two significant figures and include the appropriate units
ΔV=
Answer:
The potential difference is [tex]\Delta V = 44.40 \ V [/tex]
Explanation:
From the question we are told that
The diameter of the droplet of oil is [tex]d = 0.71 \mu m = 0.71 *10^{-6} \ m[/tex]
The density of the oil is [tex]\rho = 860 kg/m^3[/tex]
The distance of separation of the capacitor plate is [tex]l = 4.5 \ mm = 0.0045 \ m[/tex]
Generally the radius of the droplet is mathematically represented as
[tex]r = \frac{d}{2}[/tex]
=> [tex]r = \frac{0.71 *10^{-6} }{2}[/tex]
=> [tex]r = 3.55 *0^{-7} \ m[/tex]
Generally the mass of the oil droplet is mathematically represented as
[tex]m = \rho * V[/tex]
Here V is the volume of the oil droplet which is mathematically represented as
[tex]V = \frac{4}{3} * 3.142 * (3.55 *0^{-7} )^3[/tex]
[tex]V = 1.874 *10^{-19} \ m^3[/tex]
So
[tex]m = 860 * 1.874 *10^{-19} [/tex]
=> [tex]m = 1.611 *10^{-16} \ kg [/tex]
Generally the electric force acting on the droplet is mathematically represented as
[tex]F = E * q[/tex]
Here q is the charge on an electron with value [tex]q = 1.60*10^{-19}\ C[/tex]
This force is equivalent to the weight of the droplet which is mathematically represented as
[tex]W = mg[/tex]
So
[tex]E * q = m * g[/tex]
Here E is the electric field which is mathematically represented as
[tex]E = \frac{\Delta V}{l}[/tex]
[tex]\frac{\Delta V}{l} * q = m * g[/tex]
=> [tex]\Delta V = \frac{m * g * l }{q}[/tex]
=> [tex]\Delta V = \frac{1.611 *10^{-16} * 9.8 * 0.0045 }{1.60*10^{-19}}[/tex]
=> [tex]\Delta V = 44.40 \ V [/tex]
If you walk North for 40 feet and then walk East for 30 feet, what is your total distance
travelled? What is your displacement?
Answer:
The person travelled a total distance of (40+30) feet = 70 feet
Displacement= 50feet (im not positive on the displancement)
displacemeny is the shortest distance between two pionts
Explanation:
Two charged objects, A and B, are exerting an electric force on each other. What will happen if the charge on A is increased?
А. The charge on B will decrease.
В. The charge on B will increase.
C. The electric force between A and B will decrease.
D. The electric force between A and B will increase.
Answer: The forces acting on both of them will increase in magnitude.
Explanation:
According to Coulomb's law, the electrostatic force between two bodies is proportional to the product of their two charges. If the charge on A is increased this product increases in size (it must have been non-zero to begin with, since there was a force between them at first). Thus, the force between them rises.
Answer:
d. seems like the right answer.
Explanation:
how does a fly function in a energy pyramid
Answer:
A pyramid of energy shows the relative amount of energy available at each trophic level of a food chain or web. On average, about 10 percent of the energy available within one trophic level is transferred to the next level.
Explanation:
A roller coaster at the Six Flags Great America amusement park in Gurnee, Illinois, incorporates some clever design technology and some basic physics. Each vertical loop, instead of being circular, is shaped like a teardrop. The cars ride on the inside of the loop at the top, and the speeds are fast enough to ensure that the cars remain on the track. The biggest loop is 40.0 m high. Suppose the speed at the top is 10.8 m/s and the corresponding centripetal acceleration is 2g. (a) What is the radius of the arc of the teardrop at the top
Answer:
5.95 m
Explanation:
Given that the biggest loop is 40.0 m high. Suppose the speed at the top is 10.8 m/s and the corresponding centripetal acceleration is 2g
For the car to stick to the loop without falling down, at the top of the ride, the centripetal force must be equal to the weight of the car. That is,
(MV^2) / r = mg
V^2/ r = centripetal acceleration which is equal to 2g
2 × 9.8 = 10.8^2 / r
r = 116.64 /19.6
r = 5.95 m
My bill at Office Depot came to $92.35 before my teacher discount. Once the clerk applies
my 15% teacher discount, how much will I have to pay?
$106.20
$13.85
$78.50
$92.35
Answer: $78.50 or C.
Explanation:
$92.35 x 15% or .15 is $78.50
What happens to the acceleration of a ball if the force increases while the mass remains the same?
Answer:
if the force increases while the mass of the ball remains the same, the acceleration increases.
Explanation:
According to Newton's second law of motion, the acceleration of an object produced by a net force is directly proportional to the magnitude of the net force Fn and inversely proportional to the mass of the object m.
[tex]\displaystyle a=\frac{Fn}{m}[/tex]
Suppose the net force doubles to 2Fn. The new acceleration will be:
[tex]\displaystyle a'=\frac{2Fn}{m}=2\frac{Fn}{m}=2a[/tex]
The acceleration doubles too. Thus, if the force increases while the mass of the ball remains the same, the acceleration increases.
Which of the following graphs shows the motion of an object that starts to travel forward, stops for several seconds, then returns to its original position?
Answer:
Pls can you send the following graphs
which can occur in a physical change
Answer:
A physical change involves a change in physical properties. Examples of physical properties include melting, transition to a gas, change of strength, change of durability, changes to crystal form, textural change, shape, size, color, volume and density.
Explanation:
How do waves transfer energy? Be detailed.
Answer:
Electromagnetic waves transfer energy through vibrations of electric and in magnetic fields. For sound waves the energy is transferred through the vibration of air particles or particles of a solid. Waves also carry energy, the amount of energy they carry depends on their frequency and their amplitude. The more energy and the higher frequency amplitude, the more energy waves are ^‿^
What is the equivalent temperature in kelvin if you have a metal at 50°F?
A.
50 K
B.
150 K
C.
283 K
D.
300 K
Answer:
The answer is C 283 kelvin
Answer: C.
283 K
Explanation: edmentum
State and explain Gauss's law in
electrostatics and use it to determine the electric field
intensity due to a line charge.
To find:-
To find the electric field due to a point charge using Gauss's Law .Answer:-
Gauss's law in electrostatics states that the electric flux through a closed surface is equal to 1/ε0 times the charge enclosed by that surface, that is,
[tex]\implies \displaystyle \phi_E = \oint \vec{E} .\vec{ds} \\[/tex]
Also ,
[tex]\implies\displaystyle \oint \vec{E}.\vec{ds} =\dfrac{q}{\epsilon_0} \\[/tex]
Linear density of charge:-
It ise defined as charge per unit length. Mathematically,
[tex]\implies\displaystyle \lambda =\dfrac{q}{\ell} \\[/tex]
where ,
[tex] q[/tex] is the charge .[tex]\ell[/tex] is the length of the conductor.For figure see attachment.
Now let us assume that the linear density of charge is [tex]\lambda[/tex] . There is a point P near the wire at a distance of " r " from it , where we are interested in calculating the electrical field. Imagine a coaxial Gaussian cylinder of length [tex]\ell[/tex] , and radius " r " such that the point P lines on its surface.
Calculating Electrical flux through the cylinder:-
[tex]\implies\displaystyle \phi_E = 0 + 0 + \oint E.ds \\[/tex]
[tex]\implies\displaystyle\phi_E = \oint E.ds \ \cos0^o \\[/tex]
[tex]\implies\displaystyle \phi_E = \oint Eds \\[/tex]
[tex]\implies\displaystyle \phi_E = E\oint ds \\[/tex]
[tex]\implies\displaystyle \phi_E = E (2\pi r\ell) \ \ dots (1) \\[/tex]
From Gauss's law:-
[tex]\implies\displaystyle \phi_E =\dfrac{q}{\epsilon_0} \\[/tex]
[tex]\implies\displaystyle \phi_E = \dfrac{\lambda \ell}{\epsilon_0}\ \dots (2) \\[/tex]
Therefore , from equation (1) and (2) , we have;
[tex]\implies\displaystyle E \times 2\pi r \ell =\dfrac{\lambda\ell}{\epsilon_0}\\[/tex]
[tex]\implies\displaystyle \underline{\underline{\green{ E =\dfrac{1}{4\pi \epsilon_0}\dfrac{2\lambda}{r}}}}\\[/tex]
And we are done!
An airplane flying at 119 m/s is accelerated uniformly at the rate of 0.5 m/s2 for 10
seconds. What is its final speed?
Answer:
124m/s
Explanation:
v=u+at
v=119+(0.5×10)
v=119+5
v=124m/s
