Do 2. A cyclist starts from rest and accelerates along a straight path to a speed of
12.15 m/s in a time of 4.5 seconds.
What is the cyclist's acceleration to the nearest tenth?
O
54.7 m/s2
o
24.3 m/s?
2.7 m/s2
De
3.4 m/s?
The cyclist's acceleration to the nearest tenth is: C. 2.7 [tex]m/s^2[/tex].
Given the following data:
Initial velocity = 0 m/s (since the cyclist starts from rest).Final velocity = 12.5 m/s.Time = 4.5 seconds.To find the cyclist's acceleration to the nearest tenth:
Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.
Mathematically, acceleration is given by the formula;
[tex]A = \frac{V - U}{t}[/tex]
Where:
A is the acceleration.V is the final velocity.U is the initial velocity.t is the time measured in seconds.Substituting the given parameters into the formula, we have;
[tex]A = \frac{12.5\; - \;0}{4.5} \\\\A = \frac{12.5}{4.5}[/tex]
Acceleration, A = 2.7 [tex]m/s^2[/tex]
Therefore, the cyclist's acceleration to the nearest tenth is 2.7 [tex]m/s^2[/tex].
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Types of muscle tissue includes
Skeletal muscle
Cardiac muscle
Smooth muscle
All of the above
Answer:
D. all of the above
Explanation:
hope it helps
I don't quite understand. Can you help please?
If the forces on an object are balanced, the object will do what?
An object is traveling with a velocity of 3.05 m/s. The object then accelerates at 2.82 m/s-over a
displacement of 18.4 m. What is its final velocity?
Answer:
Final velocity (v) = 5.148 m/s (Approx)
Explanation:
Given:
Initial velocity (u) = 3.05 m/s
Acceleration (a) = 2.82 m/s²
Displacement (s) = 18.4 m
Find:
Final velocity (v)
Computation:
v² = u² + 2as
v² = (3.05)² + 2(2.82)(3.05)
v² = 9.3025 + 17.202
v² = 26.5045
v = 5.148 m/s (Approx)
Stokes’ law describes sedimentation of particles in liquids and can be used to measure viscosity. Particles in liquids achieve terminal velocity quickly. One can measure the time it takes for a particle to fall a certain distance and then use Stokes’ law to calculate the viscosity of the liquid. Suppose a steel ball bearing (density 7.8 \times 10^3~\text{kg/m}^37.8×10 3 kg/m 3 and diameter 3.0~\text{mm}3.0 mm) is dropped in a container of motor oil. It takes 12 s to fall a distance of 0.60 m. Calculate the viscosity of the oil.
Answer:
The viscosity is [tex]\eta = 0.76243 \ kg/ m \cdot s [/tex]
Explanation:
From the question we are told that
The density is [tex]\rho = 7.80 *10^{3} \ kg/m^3[/tex]
The diameter is [tex]d = 3.0 \ mm =0.003 \ m[/tex]
The time taken is [tex]t = 12 \ s[/tex]
The distance covered is [tex]d = 0.60 \ m[/tex]
Generally the velocity of the ball is
[tex]v = \frac{d}{t}[/tex]
=> [tex]v = \frac{0.60}{12}[/tex]
=> [tex]v = 0.05 \ m/s [/tex]
Generally the mass of the steel ball is
[tex]m = \rho * V[/tex]
Here V is the volume and this is mathematically represented as
[tex]V = \frac{4}{3} * \pi * [\frac{d}{2} ]^3[/tex]
=> [tex]V = \frac{4}{3} * 3.142 * [\frac{0.003}{2} ]^3[/tex]
=> [tex]V = 1.414 *10^{-8} \ m^3[/tex]
So
[tex]m = 7.80 *10^{3} * 1.414 *10^{-8}[/tex]
[tex]m = 0.00011 \ kg [/tex]
Generally the viscosity is mathematically represented as
[tex]\eta = \frac{m * g}{6\pi * r * v }[/tex]
Here r is the radius represented as
[tex]r = \frac{d}{2}[/tex]
=> [tex]r = \frac{0.003}{2}[/tex]
[tex]r = 0.0015 \ m [/tex]
So
[tex]\eta = \frac{0.00011 * 9.8}{6 * 3.142 * 0.0015 * 0.05 }[/tex]
=> [tex]\eta = 0.76243 \ kg/ m \cdot s [/tex]
mechanical energy defintion
Answer: Mechanical energy is the energy that is possessed by an object due to its motion or due to its position.
(The energy acquired by the objects upon which work is done)
Which best illustrates the electromagnetic force in action?
-a football being kicked
-leaves falling from tree
-flashlight
-neutron beta particle and proton
Answer:
neutron beta particle and proton (last option in the list)
Explanation:
The neutron beta particle and proton inside a neutron is a clear example of a negative particle (beta particle) and a positive particle (proton) experiencing electromagnetic force (attraction between positive and negative charges) at a very short distance.
Answer:
I'm pretty sure it's the flashlight because electromagnetic force produces electricity.
PLS URGENT!!
A radio station sending out a radio wave of frequency 100.5MHz at velocity of 3×10⁸ms⁻¹. At what wavelength is the radio station broadcasting
If this piece of abductin is 3.1 mm thick and has a cross-sectional area of 0.49 cm2 , how much potential energy does it store when compressed 1.5 mm ?
Complete question:
A scallop forces open its shell with an elastic material called abductin, whose Young's modulus is about 2.0×10⁶ N/m2 .
If this piece of abductin is 3.1 mm thick and has a cross-sectional area of 0.49 cm2 , how much potential energy does it store when compressed 1.5 mm ?
Answer:
The elastic potential energy of the material is 0.036 J
Explanation:
Given;
Young's modulus, E = 2.0×10⁶ N/m²
Thickness of the abductin, l = 3.1 mm = 0.0031 m
compression of the abductin, x = 1.5 mm = 0.0015 m
area, A = 0.49 cm² = 0.49 x 10⁻⁴ m²
Young's modulus for elastic material is given by;
[tex]E = \frac{stress}{strain} = \frac{Fl}{Ax} \\\\ E = \frac{F}{x}*\frac{l}{A}\\\\ E = k*\frac{l}{A}\\\\k = \frac{AE}{l}\\\\k = \frac{(0.49 x10^{-4})(2*10^6)}{0.0031}\\\\ k = 31,612.9 \ N/m[/tex]
The elastic potential energy of the material is given by;
U = ¹/₂kx²
U = ¹/₂(31,612.9)(0.0015)²
U = 0.036 J
Therefore, the elastic potential energy of the material is 0.036 J
leaves uses_,_and_to make food for the plant
light, water, carbon dioxide
Explanation:
c02 , h20 and light
Where is the magnetic south pole compared to the geographical north pole?
Currently, the magnetic south pole lies about ten degrees distant from the geographic north pole, and sits in the Arctic Ocean north of Alaska. The north end on a compass therefore currently points roughly towards Alaska and not exactly towards geographic north.
Find the required angular speed, ω, of an ultracentrifuge for the radial acceleration of a point 2.10 cm from the axis to equal 5.00×105 g (where g is the free-fall acceleration)
Answer:
ω = 15275.25 rad/s
Explanation:
Given that,
Radial acceleration of an ultracentrifuge is, [tex]a=5\times 10^5g[/tex]
Distance from the axis, r = 2.1 cm = 0.021 m
g is the free-fall acceleration such that g = 9.8 m/s²
We need to find the angular speed of an ultracentrifuge. The formula that is used to find the angular speed is given by formula as follows :
[tex]a=r\omega^2[/tex]
Putting all the values,
[tex]\omega=\sqrt{\dfrac{a}{r}} \\\\\omega=\sqrt{\dfrac{5\times 10^5\times 9.8}{0.021}} \\\\\omega=15275.25\ rad/s[/tex]
So, the required angular speed, ω, of an ultracentrifuge is 15275.25 rad/s.
A .25 kilogram baseball is thrown upwards with a speed of 30 meters per second. Neglecting friction the maximum height reached by the baseball is approximately
Answer: 46 meters
Explanation:
The maximum height reached by the base ball is 45.9 meters.
To find the maximum height the given values are,
Mass = 25 Kg
speed v = 30 meters per second.
What is the height of baseball reached?As the ball goes up, it acts due to the gravity.
The gravity slows an upward-moving object,
Acceleration due to gravity = 9.8 m/s every second,
the baseball reaches its greatest height in (30/9.8) = 3.06 seconds.
At that instant, its speed is zero.
The baseball's average speed from toss to peak is
(1/2) (30 + 0) = 15 m/s .
The baseball average speed = 15 m/s
And the time for greatest height = 3.06 seconds.
Substituting the given values,
The ball rises can be calculated as
(15 x 3.06) = 45.9 meters.
Thus, the baseball reached the maximum height approximately is 45.9 meters.
Learn more about the height due to gravity,
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How much is the weight of a 1 kg mass at the pole and the equator of the earth
Given parameters:
Mass given = 1kg
Unknown:
Weight of the body at pole and equator = ?
Solution:
Both locations are on the surface of the earth. Generally, we take 9.8m/s² as the acceleration due to gravity on the earth.
Weight = mass x acceleration due to gravity
But little disparity occurs in the value of acceleration due to gravity from the pole to equator. This is due to equatorial bulge.
At the equator , 9.780 m/s²
pole 9.832 m/s²
Weight at equator = 1 x 9.780 = 9.78N
Weight at the pole = 1 x 9.832 = 9.832N
What happens to the temperature of a substance while it is changing state?
Answer:
its temperature stays constant
Explanation:
explain what happent to the pressure exerted by an object when the area over which it is exerted:
a) increase
b) decrease
the rotational speed of earth is similar to?
An electromagnet crane is carrying the electromagnet with the help of the three cables. But the electromagnet is not stable because of the wind. What is the reason behind the cause
Answer:
The reason behind the given instance is summarized below.
Explanation:
When another electromagnet shifts because of the wind, it induces a simulated area that acts on either the electromagnet as an effect or force, considered as the Lorentz force. This force thus renders the resultant force equivalent to a non-zero value mostly on the electromagnet. The balance is not protected by this power. When there is no breeze, just the three connectors sustain equilibrium.Two cars traveling in the same direction pass you at exactly the same time . The car that is going faster
moves farther in the same amount of time.
Explanation:
based on my answer......
we supposed to assume that both cars are equal except for speed. So they would have the same mass.....
Anyway, the question doesn't tell you anything about weight or size, so you can't tell from the information given which has more mass.
But the very definition of 'faster' is 'moves farther in the same amount of time'.
Hope this helps
Answer:
They both moves at the same speed
Explanation:
hope it works
A device for acclimating military pilots to the high accelerations they must experience consists of a horizontal beam that rotates horizontally about one end while the pilot is seated at the other end. In order to achieve a radial acceleration of 29.9 m/s2 with a beam of length 5.33 m , what rotation frequency is required
Answer:
Rotation frequency is 0.377 hertz.
Explanation:
After a careful reading of statement, we need to apply the concept of radial acceleration due to uniform circular motion, whose formula is:
[tex]a_{r} = \omega^{2}\cdot L[/tex] (Eq. 1)
Where:
[tex]a_{r}[/tex] - Radial acceleration, measured in meters per square second.
[tex]\omega[/tex] - Angular velocity, measured in radians per second.
[tex]L[/tex] - Length of the beam, measured in meters.
Now we clear the angular velocity within:
[tex]\omega = \sqrt{\frac{a_{r}}{L} }[/tex]
If [tex]a_{r} = 29.9\,\frac{m}{s^{2}}[/tex] and [tex]L = 5.33\,m[/tex], the angular velocity is:
[tex]\omega = \sqrt{\frac{29.9\,\frac{m}{s^{2}} }{5.33\,m} }[/tex]
[tex]\omega \approx 2.368\,\frac{rad}{s}[/tex]
The frequency is the number of revolutions done by device per second and can be found by using this expression:
[tex]f = \frac{\omega}{2\pi}[/tex] (Eq. 2)
Where [tex]f[/tex] is the frequency, measured in hertz.
If we know that [tex]\omega \approx 2.368\,\frac{rad}{s}[/tex], then rotation frequency is:
[tex]f = \frac{2.368\,\frac{rad}{s} }{2\pi}[/tex]
[tex]f = 0.377\,hz[/tex]
Rotation frequency is 0.377 hertz.
Explain why a golf ball that is hit on the moon travels much farther than a golf ball that is hit with the same force on Earth.
Answer:
the reason why is that if it is hit with the same force the moon has a lot less gravity than the earth dose so the golf ball will hit the ground on earth first before the golf ball on moon dose
Sedimentary rock turns into magnum through which process
HELP PLSSSSSSSSSjjdndnsnsj
Answer:
i feel like 3 not too sure tho
A parallel plate capacitor contains a positively charged plate on the left, and a negatively charged plate on the right. An electron in between the plates is moving to the right. Which statement is true? Group of answer choices The potential energy of the electron is decreasing and it is moving to a region having a higher potential The potential energy of the electron is decreasing and it is moving to a region having a lower potential. The potential energy of the electron is increasing and it is moving to a region having a lower potential The potential energy of the electron is increasing and it is moving to a region having a higher potential.
Complete Question
A parallel plate capacitor contains a positively charged plate on the left, and a negatively charged plate on the right. An electron in between the plates is moving to the right. Which statement is true?
Group of answer choices
a The potential energy of the electron is decreasing and it is moving to a region having a higher potential
b The potential energy of the electron is decreasing and it is moving to a region having a lower potential.
c The potential energy of the electron is increasing and it is moving to a region having a lower potential
d The potential energy of the electron is increasing and it is moving to a region having a higher potential.
Answer:
The correct option is C
Explanation:
From the question we are told that
An electron in between the plates is moving to the right
Generally the potential energy of the electron is mathematically represented as
[tex]PE = e * V[/tex]
Here e is the charge on the electron and V is the electric potential of the electron
Generally the left side with the positive charge has a higher potential than the right side with the negative charge
Now when the potential energy of the electron increases it will move toward the plate with the lower potential which is the left plate
If you hold a piece of copper wire in an open flame, which of the following will most likely happen?
The heat will travel through the wire to your hand.
The light will change into electricity.
The flame will absorb heat from the wire.
The ſame will get brighter.
Answer:
The heat will travel through the wire to your hand.
Explanation:
Thats the one that makes the most sense.
derive ideal gas equation for n mole of gas.
Answer:
Explanation:
Ideal gas equation- The volume (V) occupied by the n moles of any gas has pressure(P) and temperature (T) Kelvin,
the relationship for these variables PV=nRT where R gas constant is called the ideal gas law
Derivation of the Ideal Gas Equation
Let us consider the pressure exerted by the gas to be ‘p,’
The volume of the gas be – ‘v’
Temperature be – T
n – be the number of moles of gas
Universal gas constant – R
According to Boyle’s Law,
it constant n & T, the volume bears an inverse relation with the pressure exerted by a gas.
i.e. v∝1p ………………………………(i)
According to Charles’ Law,
When p & n are constant, the volume of a gas bears a direct relation with the Temperature.
i.e. v∝T ………………………………(ii)
According to Avogadro’s Law,
When p & T are constant, then the volume of a gas bears a direct relation with the number of moles of gas.
i.e. v∝n ………………………………(iii)
Combining all the three equations, we have-
v∝nTp
or pv=nRT
where R is the Universal gas constant, which has a value of 8.314 J/mol-K
Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B.
Answer:
[tex]B=1.61\times 10^{-4}\ T[/tex]
Explanation:
The attached figure shows the path followed by an electron in the semicircular path from A to B.
Velocity of the electron is, [tex]v=1.42\times 10^6\ m/s[/tex]
It can be seen from the figure that the radius of thenpath, r = 5 cm or 0.05 m
The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,
[tex]Bqv=\dfrac{mv^2}{r}[/tex]
B is the magnitude of the magnetic field
[tex]B=\dfrac{mv}{rq}\\\\\text{Putting all the values}\\\\B=\dfrac{9.1\times 10^{-31}\times 1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}\\\\B=1.61\times 10^{-4}\ T[/tex]
So, the magnitude of the magnetic field is [tex]1.61\times 10^{-4}\ T[/tex].
The magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B will be [tex]B=1.61\times 10^-{4]\ T[/tex]
What is magnetic field?The magnetic field is defined as when the current passes through the wire, then the magnetic field is generated around the wire in a circular pattern.
The attached figure shows the path followed by an electron in the semicircular path from A to B.
The velocity of the electron is, [tex]v=1.42\times 10^6\ \frac{m}{s}[/tex]
It can be seen from the figure that the radius of then path, r = 5 cm or 0.05 m
The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,
[tex]Bqv=\dfrac{mv^2}{r}[/tex]
B is the magnitude of the magnetic field
[tex]B=\dfrac{mv}{rq}[/tex]
[tex]B=\dfrac{9.1\times 10^{-31}\times1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}[/tex]
[tex]B=1.61\times 10^{-4}\ T[/tex]
So, the magnitude of the magnetic field is [tex]B=1.61\times 10^-{4]\ T[/tex]
To know more about the magnetic field, follow
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Please help I don’t know how to do this
Answer:
3.176 hoursExplanation:
given:
distance = 270 km
speed = 85 km/h
find:
how long does it take to get into his audition in hours?
solution:
velocity = distance / time
85 km/h = 270 km
t
85 (t) = 270
t = 270 / 85
t = 3.176 hours
A Coolie raises a box of mass 20 kg to a height of 1.5m. If the force of gravity on 1 kg is 10N. The work done by the Coolie is
