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A 1125 kg car was traveling at 20 m/s toward a traffic signal when the light suddenly turned red. The driver stomped on her accelerator, clearing the intersection in 1.7 seconds and coming to a speed of 24.6 m/s . What was the acceleration of the car?
Answer:
a = 3.88 m/s^2 (3.88 meters per second squared)
Explanation:
The acceleration of the car can be obtained based of the change of velocities (from initial velocity "vi" to final velocity "vf") in the given amount of time:
In our case:
a = (26.6 - 20) / 1.7 = 3.88 m/s^2
An Object is thrown straight up into the air with an initial velocity of 15m/s. What is its velocity at the peak of its flight?
Answer:
0
Explanation:
The initial velocity of an object is 15 m/s when it was thrown straight up into the air.
At maximum height, the velocity of the object is equal to 0. It starts coming downward after that and falls ground. Height attained by the object is given by :
[tex]h=\dfrac{v^2}{2g}[/tex]
Hence, its velocity at the peak of its flight is equal to 0.
Which action could a student take to show a transverse wave
A:blow up a balloon
B:shake a rope from side to side
C:shout across a soccer field
D:Knock on a door
Answer:
B is the correct answer
Explanation:
I just did this question
BLANK charges repel each other.
Answer:
like
Explanation:
Have a good day!!
Answer: negitive
Explanation:
A target lies flat on the ground 4 m from the side of a building that is 10 m tall, as shown below.
The acceleration of gravity is 10 m/s^2.
Air resistance is negligible.
A student rolls a 4 kg ball off the horizontal
the roof of the building in the direction of the
target.
The horizontal speed v with which the ball
must leave the roof if it is to strike the target
is most nearly
1. v =√3 /4 m/s.
2. v =4√3 /3 m/s.
3. v = 4 m/s.
4. v = 2√2 m/s.
5. v =√2 / 4 m/s.
6. v =√5 / 4 m/s.
7. v = 4√3 m/s.
8. v = 4√5 m/s.
9. v = 6 m/s.
10. v = 4√2 m/s.
Answer:
v = 2√2 m/s
Explanation:
The following data were obtained from the question:
Height (h) = 10 m
Acceleration due to gravity (g) = 10 m/s²
Horizontal distance (s) = 4 m
Horizontal velocity (v) =.?
Next, we shall determine the time taken for the ball to get to the target.
This can be obtained as shown below:
Height (h) = 10 m
Acceleration due to gravity (g) = 10 m/s²
Time (t) =?
h = ½gt²
10 = ½ × 10 × t²
10 = 5 × t²
Divide both side by 5
t² = 10/5
t² = 2
Take the square root of both side.
t = √2 s
Finally, we shall determine the horizontal velocity as shown below:
Horizontal distance (s) = 4 m
Time (t) = √2 s
Horizontal velocity (v) =.?
s = vt
4 = v × √2
Divide both side by √2
v = 4 /√2
Rationalise the denominator
v = (4 /√2) × √2/√2
v = 4 × √2 / √2 × √2
v = 4 × √2 / 2
v = 2√2 m/s
If an object starts out at rest and accelerates to 100 m/s what is its initial speed?
Answer:0m/s
Explanation.
The initial velocity is 0 because when the object starts moving its speed is zero
A child (mass Me) pulls a sled (mass Ms) holding a baby (mass m) across the snow (assume the snow is frictionless). When the child starts the sled moving the baby brother slips off the sled instead of moving with the sled. The child tries again with a slightly smaller force and the baby stays on the sled due to the friction between the baby and the sled. Write a symbolic solution for the coefficient offriction between the baby and the sled if the maximum acceleration ofthe sled for the baby to stay on the sled is a. The solution may include the variables MC: Ms, m: a and g but does not need to have all ofthem_ The computer Ivill not recognize any other variables. Do not include any numbers (or the in your answer). Fill in the blank
Answer:
symbolic solution for the coefficient of friction between the baby and the sled is
[tex] \mu = \frac{m + M_s}{m} * \frac{a}{g}[/tex]
Explanation:
From the question we are told that
The mass of the boy is [tex]M_e =[/tex]
The mass of the shed is [tex]M_s[/tex]
The mass of the baby is [tex]m[/tex]
The maximum acceleration for the baby to stay is a
Generally the frictional force between the baby and the shed is mathematically represented as
[tex]F_f = \mu N[/tex]
Here N is the normal force acting on the baby which is mathematically represented as
[tex]N = m * g[/tex]
=> [tex]F_f = \mu * m * g[/tex]
Now for the baby not the slip off the shed the frictional force between the baby and the shed must be equal to the the force applied by the child
The force applied by the child is mathematically represented as
[tex]F = [M_s+m] * a[/tex]
So
[tex] \mu * m * g = [M_s+m] * a[/tex]
=> [tex] \mu = \frac{m + M_s}{m} * \frac{a}{g}[/tex]
Nervous tissue makes up most of the
Brain
Lungs
Kidneys
Stomach
Answer:
, Nervous tissue is composed of two types of cells, neurons and glial cells. Neurons are the primary type of cell that most anyone associates with the nervous system. They are responsible for the computation and communication that the nervous system provides.
Because mass is determined from protons
and neutrons, what conclusion can you
make?
Answer:
Electrons have virtually no mass
Explanation:
I had a test an this was the right answer^
Answer: Electrons have virtually no mass
Explanation: on edpuzzle that was the answer
Convert 56,340,040 meters into scientific notation?
Answer:
5.634004 × 10^7
Explanation:
the number 7 is for the numbers before the number 5
A
A penny is dropped from the top of a 200 m building and is in free fall. How long will it take
the penny to hit the ground?
Answer:
The penny will hit the ground at 6.39 seconds
Explanation:
Free Fall
The penny is dropped from a height of y=200 m. The equation of the height on a free-fall motion is given by:
[tex]\displaystyle y=\frac{gt^2}{2}[/tex]
Where [tex]g=9.8\ m/s^2[/tex], and t is the time.
Solving for t:
[tex]\displaystyle t=\sqrt{\frac{2y}{g}}[/tex]
Using the value y=200:
[tex]\displaystyle t=\sqrt{\frac{2*200}{9.8}}[/tex]
t=6.39 sec
The penny will hit the ground at 6.39 seconds
Calculate the acceleration of a student riding his bicycle in a straight line that speeds up from 4 m/s to 6 m/s in 5 seconds.
A disc with moment of inertia 1.5 kg m2 is rotating with an angular speed of 800 rev/min on a shaft. A second disc, initially at rest and with moment of inertia 5.0 kg m2,is suddenly clamped together to the same shaft.
(a) Determine magnitude of angular momentum of the first disc.
(b) Determine the common angular speed of the combination of the two discs.
Answer:
Explanation:
Angular momentum p = Iw
I is the moment of inertia
w is the angular velocity
a) Angular momentum of the first disc
p1 = I1w1
Given
I1 = 1.5kg/m²
w1 = 800rev/min
Convert to rad/s
1 rev = 6.283rad
1 min = 60secs
800rev/min = 800(6.283)/60
= 83.77rad/s
p1 = 1.5×83.77
p1 = 125.66kgrad/s
Hence the magnitude of angular momentum of the first disc is 125.66kgrad/s
b) according to law of conservation of momentum
I1w1+I2w2 = (I1+I2)w
w is the common angular speed
Given
11w1 = 125.66
w2 = 0rad/s
I1 = 1.5kgm²
I2 = 5kgm²
Substitute
125.66+0 = (1.5+5)w
125.66 = 6.6w
w = 125.66/6.5
w = 19.33rad/s
Since 1rad/s = 9.549tev/min
19.33rad/s = 184.6rev/min
Hence the common angular speed of the combination of the two discs is 184.6rev/min
What is meant by the term straight line motion?
A. An object can turn, but after each turn, it moves in a straight line, not curves
B. A path taking between two points, without turning left or right
C. An object is moving at a constant speed
D. Motion where the object faces forward, regardless of the path taken
Answer:
A
Explanation:
Answer: B
Explanation: I got it right
Question # 40
A body falls freely under gravity. If speeds is v when it has lost an amount x of the gravitational P.E, then its mass is:
2x / v2
2x / v3
2x / v4
none
please give me its solution
Answer:
Potential Energy = x = m g h
Kinetic energy = 1/2 m v^2
Assuming the mass fall from rest
1/2 m v^2 = m g h
v^2 = 2 g h
So the speed attained is independent of the mass
Also, x / v does not have the units of mass
So the solution is none of the above.
-5 1/3 - 2 1/3 in math
Answer:
3
Explanation:
5 1/3 - 2 1/3 = 3
Broken down: 1/3 - 1/3 = 0 5 - 2 = 2
A reversible power cycle operates with a thermal efficiency of 75%. The cycle receives energy input by heat from a thermal reservoir at 1200K. What is the temperature, in K, of the low temperature thermal reservoir
Answer:
The temperature of the low temperature thermal reservoir is 300 K.
Explanation:
All reversible power cycles are equivalent to the Carnot's cycle, whose equation for efficiency is:
[tex]\eta_{th} =1-\frac{T_{L}}{T_{H}}[/tex] (Eq. 1)
Where:
[tex]\eta_{th}[/tex] - Thermal efficiency, dimensionless.
[tex]T_{H}[/tex] - High temperature reservoir, measured in Kelvin.
[tex]T_{L}[/tex] - Low temperature reservoir, measured in Kelvin.
Now we proceed to clear the low temperature reservoir within:
[tex]\frac{T_{L}}{T_{H}} = 1-\eta_{th}[/tex]
[tex]T_{L} = (1-\eta_{th})\cdot T_{H}[/tex]
If [tex]\eta_{th} = 0.75[/tex] and [tex]T_{H} = 1200\,K[/tex], then:
[tex]T_{L} = (1-0.75)\cdot (1200\,K)[/tex]
[tex]T_{L} = 300\,K[/tex]
The temperature of the low temperature thermal reservoir is 300 K.
A 10-cm-thick aluminum plate (α = 97.1 × 10−6 m2/s) is being heated in liquid with temperature of 550°C. The aluminum plate has a uniform initial temperature of 25°C. If the surface temperature of the aluminum plate is approximately the liquid temperature, determine the temperature at the center plane of the aluminum plate after 15 s of heating. Solve this problem using the analytical one-term approximation method. The temperature at the center plane after 15 s of heating is
Answer:
356°C.
Explanation:
(1). The first step to the solution to this particular Question/problem is to determine the Biot number, and after that to check the equivalent value of the Biot number with plate constants.
That is, Biot number = (length × ∞)÷ thermal conductivity. Which gives us the answer as ∞. Therefore, the equivalent value of the ∞ on the plates constant = 1.2732 for A and 1.5708 for λ.
(2). The next thing to do is to determine the fourier number.
fourier number = [α = 97.1 × 10−6 m2/s × 15 s] ÷ (.05m)^2 = 0.5826.
(3). The next thing is to determine the temperature at the center plane after 15 s of heating.
The temperature at the center plane after 15 s of heating = 500°C [ 25°C - 500°C ] [1.2732] × e^(-1.5708)^2 ( 0.5826).
The temperature at the center plane after 15 s of heating = 356°C.
1. A baseball, 0.314 kg, is accelerated at a rate of 153 m/s2 when hit by a professional baseball player. What force does the player's bat exert on the ball? (use the formula F=ma)
Answer:
The answer is 48.0 NExplanation:
To find the force acting on an object given it's mass and acceleration we use the formula
Force = mass × accelerationFrom the question
mass = 0.314 kg
acceleration = 153 m/s²
We have
force = 0.314 × 153 = 48.042
We have the final answer as
48.0 NHope this helps you
Which object has the greatest
inertia?
F- a falling leaf
G- a softball in flight
H-a seated high school student
J-a rising helium-filled toy balloon
Answer:
H-a seated high school student
Explanation:
"Inertia" is an important word in Physics. It is the resistance of an object to any change in motion. Measuring the amount of inertia largely relies on the "mass of an object." The heavier the object, the more likely it is able to resist any change in motion.
Among the choices above, the high school student is the heaviest and has greater mass than the leaf, softball or balloon. This means, it has the greatest inertia.
Thus, this explains the answer.
A freight train consists of two 8.00 \times 10^5~\text{kg}8.00×10 5 kg engines and 45 cars with average masses of 5.50 \times 10^5~\text{kg}5.50×10 5 kg. What force must each engine exert backward on the track to accelerate the train at a rate of 5.00 \times 10^{-2}~\text{m/s}^25.00×10 −2 m/s 2 if the force of friction is 7.50 \times 10^5 ~\text{N}7.50×10 5 N, assuming the engines exert identical forces? This is not a large frictional force for such a massive system. Rolling friction for trains is small, and consequently trains are very energy-efficient transportation systems.
Answer:
F₁ = 4.29 x 10⁵ N
Explanation:
The total force required to move the freight train with the given acceleration is given by the following formula:
F = ma + f
where,
F = Total Force Required from both engines = ?
m = equivalent mass of system = 2(8 x 10⁵ kg) + 5.5 x 10⁵ kg = 21.5 x 10⁵ kg
a = required acceleration = 5 x 10⁻² m/s²
f = force of friction = 7.5 x 10⁵ N
Therefore,
F = (21.5 x 10⁵ kg)(0.05 m/s²) + 7.5 x 10⁵ N
F = 8.575 x 10⁵ N
Now, for identical forces in each engine can be given as:
Force exerted by each engine = F₁ = F/2
F₁ = 8.575 x 10⁵ N/2
F₁ = 4.29 x 10⁵ N
North America and South America are on the same Tectonic Plate.
True
False
Answer:True
Explanation:
What volume is represented by each small tick mark ? Help !!!
Answer:
In the taller, skinnier cylinder, each tick mark represents 2, while in the larger one, each tick mark represents 50.
Explanation:
If you count the tick marks between each big number, then you can divide, and figure out what amount each tick mark represents.
A car travels 90 km/h. How long does it take for the car to travel
400 km?
b. 1.5x103 s
C. 1.5x104 s
a. 4x104 s.
d. 1.6x104s
Answer:
4.44 hr
Explanation:
distance= rate*time
400km/(90 km/hr)=time
time=4.44 hr
A net force F accelerates a mass 'm' with an acceleration 'a'. what acceleration results if force 13F acts on mass 15m in terms of 'a'
Answer:
13a/15
Explanation:
According to newton's second law
F = ma
F is the force
m is the mass
a is the acceleration
From the formula:
a = F/m
Given
F = 13F
m = 15m
Substitute the given parameters into the formula:
a' = 13F/15m
a' = 13/15 * F/m
a' = 13/15 * a
a' = 13a/15
Hence the new acceleration a' that results in terms of a is 13a/15
PLEASE HELP ASAP
A 744N object falling in the air experiences 434N of air resistance. what is the amount if net force of the falling objec
Answer:
The amount of net force of the falling object is -310 N, or 310 N downwards
Explanation:
Net Force
Being the force a vector, the net force is the sum of all the force vectors acting on an object at a given time:
[tex]\vec F_n=\vec F_1+\vec F_2+\vec F_3+.....\vec F_m[/tex]
When the forces are acting in one axis, say the y-axis, the direction of the forces can be considered by the sign of the magnitude of the force.
For example, the weight of the object is usually assigned a negative direction. In our problem:
W=-744 N
The air resistance always opposes the direction of motion. Since the object is falling, the air resistance is positive:
Fa = +434 N
The net force is the sum of both, including their signs:
Fn = -744 N + 434 N = -310 N
The amount of net force of the falling object is -310 N, or 310 N downwards
give reasons with examples why houses are made up of bricks and cement instead of metal
Answer:
The most important is that the thermal conductivity of the armadillas several orders of magnitude lower than the thermal conductivity of the metal, therefore it is easier to maintain the temperature in winter
Explanation:
Cement and bricks are used in the construction of houses instead of metal, for several reasons
* The most important is that the thermal conductivity of the armadillas several orders of magnitude lower than the thermal conductivity of the metal, therefore it is easier to maintain the temperature in winter
* Metal has more oxidation problems than brick
* The cost of sheet metal is higher than the cost of cement brick.
A source of sound produce waves in air of wavelength 3.42m . If the speed of sound in air is 330m/s, What is the period of vibration?
Explanation:
wavelength=3.42m
velocity=330m/s
T=?
v=f×wavelength
f=330÷3.42
f=96.5Hz
T=1/f
=1/96.5
T=0.01s
why did you test the resistance of the wire
Answer:
What????
Explanation:
is there more to the problem???
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In order to climb up a mountainside, a train needs to start at a speed of 40 mph. The speed limit on the track, however, is 25 mph. How much time does the train need to get up to 40 mph if it can accelerate 4 mph per minute ?
