Tom volunteered 1 out of the last 12 days at the school store. Which shows the decimal form of this ratio?

Answer:

4.1 units

Step-by-step explanation:

A( -2,3)

B( 2,5)

C( 8.6)

Answer: number of kids(k)=200

sand the number of adults(a)=300, visited the carnival.

The tool I used is called simultaneous equation and I used elimation method as the method.

The values of x given the following expression are ∛243/7 and 7^1/4

Given the following expression

7x³ =243
x³ = 243/7

x = ∛243/7

For the expression

5x⁴ + 7 = 42
5x⁴  = 42 - 7

5x⁴ = 35

x⁴ = 7

x = 7^1/4

Hence the values of x given the following expression are ∛243/7 and 7^1/4

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Answer:

49.12 ft squared

Step-by-step explanation:

1/2(6*8) = 24

1/2(16)pi = 8pi = 25.12

total: 49.12

Answer:

volume = 14,137

Step-by-step explanation:

radius is the diameter divided by 2

30÷2=15

radius = 15 then square

15^2 = 225

formula of volume of a cone is 1/3*pi*raduis^2*the height

1/3(3.14)(225)(60)= 14,137

The volume of a cone with a diameter of 30 feet and a height of 60 feet is 14130.

The volume of the cone is given by;

[tex]\rm Volume \ of \ cone=\dfrac{1}{3}\pi r^2h\\\\Where;\ r = radius \ and \ h = height[/tex]

The volume of a cone with a diameter of 30 feet and a height of 60 feet.

The radius of the cone is;

[tex]\rm Radius =\dfrac{Diameter}{2}\\\\Radius=\dfrac{30}{2}\\\\Radius=15[/tex]

Substitute all the values in the formula

[tex]\rm Volume \ of \ cone=\dfrac{1}{3}\pi r^2h\\\\ Volume \ of \ cone=\dfrac{1}{3}\times 3.14 \times 15^2 \times 60\\\\Volume \ of \ cone=14130[/tex]

Hence, the volume of a cone with a diameter of 30 feet and height of 60 feet is 14130.

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Answer:

The rule is "add 5, add 10, add 20" and the rule keeps doubling.

Answer:

radius = 72.00 in (nearest hundredth)

Step-by-step explanation:

[tex]\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}[/tex]

Given:

Substituting the given values into the formula and solving for r:

[tex]\implies \sf 1481276.16=3.14 \cdot r^2 \cdot 91[/tex]

[tex]\implies \sf 1481276.16=285.74r^2[/tex]

[tex]\implies \sf r^2=\dfrac{1481276.16}{285.74}[/tex]

[tex]\implies \sf r^2=5184[/tex]

[tex]\implies \sf r=\sqrt{5184}[/tex]

[tex]\implies \sf r=72\:in[/tex]

Answer: radius : 72.00 inch

The following is a cylinder.

Volume of Cylinder: πr²h

Given following:

Solve for radius:

[tex]\rightarrow \sf \pi r^2h =V[/tex]

[tex]\rightarrow \sf (3.14) r^2(91) =1,481,276.16[/tex]

[tex]\rightarrow \sf r^2 =\dfrac{1,481,276.16 }{91(3.14)}[/tex]

[tex]\rightarrow \sf r^2 =5184[/tex]

[tex]\rightarrow \sf r=\sqrt{5184}[/tex]

[tex]\rightarrow \sf r=72[/tex]

Answer:

multiplication

Step-by-step explanation:

the () means to multipy

Answer:

273

Step-by-step explanation:

Answer: 273

Step-by-step explanation: when you divide 16.38 by 0.06 you get 273.

The answers to the problem are:

a) The value of x is : 8

b) ∠ZRB and ∠BTS are not supplementary angles.

c) ∠BST and ∠RSB are complementary angles.

d) ∠ABT is  an acute angle

e) SA is not the bisector of the angle ∠ZSY.

Angles are formed when two lines meet and they are of different types.

acute: this is an angle less than 90°

obtuse: this angle is greater than 90° but less than 180°

reflex: this angle is greater than 180° but less than 360°

Analysis:

∠BRS = 180 - (20X - 22) = 202 - 20X

a) To find x, sum of angles in the triangle = 202-20x + 2x+32 + 5x+10 + 120-10x = 180

364 -23x = 180

23x = 364-180

23x = 184

x = 8

b) ∠ZRB = 20x-22 = 20(8) - 22 = 138°

   ∠BTS = 2x+32 = 2(8)+32 = 48°

    138°+48° = 186° [tex]\neq[/tex] 180°

     They are not supplementary

c)  ∠BST = 120-10X = 120 - 10(8) = 40°

     ∠RSB = 5x+10 = 5(8)+10 = 50°

      50+40 = 90°. They are complementary

d)   ∠ABT = 180 - ∠ABR = 180 - 100 - x = 88°

      It is acute since it is less than 90°

e)   SA is not an angle bisector, since it dived the angles as 40° and 50° and not equal.

In conclusion, the solution to the questions are:

a) The value of x is : 8

b) ∠ZRB and ∠BTS are not supplementary angles

c) ∠BST and ∠RSB are complementary angles

d) ∠ABT is  an acute angle

e) SA is not the bisector of the angle ∠ZSY

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The quotient of the fraction n³ / (2n - 6) ÷ n³ / (3n - 9) is 2/3

n³ / (2n - 6) ÷ n³ / (3n - 9)

= n³ / (2n - 6) × 1 / n³ / (3n - 9)

= 2n - 6 / 3n - 9

= 2(n - 3) / 3(n - 3)

= 2/3

Therefore, quotient of the fraction n³ / (2n - 6) ÷ n³ / (3n - 9) is 2/3

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Answer:

2/3

Step-by-step explanation:

Answer:

  16.6°

Step-by-step explanation:

The triangle can be solved using the Law of Cosines to find the side opposite the given angle, then the Law of Sines to find the missing angle from the given sides.

__

We choose to use a=10, b=4, C=29°.

  c² = a² +b² -2ab·cos(C) . . . . . law of cosines

  c² = 10² +4² -2·10·4·cos(29°) ≈ 46.0304

  c ≈ √46.0304 ≈ 6.78457

Then angle B (opposite side b) is ...

  sin(B)/b = sin(C)/c . . . . . . . . . law of sines

  sin(B)/4 = sin(29°)/6.78457

  B = arcsin(4/6.78457×sin(29°)) ≈ 16.6085°

The missing acute angle is about 16.6°.

Answer:

108

Step-by-step explanation:

Volume of a Square Pyramid :

Solving :

Answer: Volume = 108 cm ³

Explanation:

For a square pyramid, the volume can be calculated as follows:

Volume =  * area of base * height

Volume =  * side² * height

We have:

side length = 6 cm

height = 9 cm

Therefore:

Volume =  * 36 * 9 = 108 cm ³

Hope this helps :)

Answer:

200 feet of the ground at a thirty degrees angle does not make a difference .

u need to know whether it is the top or bottom of it, the kite

Answer:

Jorge needs 1/2 apple to make the snack.

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve for x and y ~

Since the given triangle is a right angled triangle, we can use Trigonometric ratios here to get the required values

[tex]\qquad \sf  \dashrightarrow \: \tan(45 \degree) = \dfrac{y}{2 \sqrt{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: 1= \dfrac{y}{2 \sqrt{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \:y = 2 \sqrt{2} \: \: units[/tex]

Now, let's get to x ~

[tex]\qquad \sf  \dashrightarrow \: \sin(45 \degree) = \dfrac{y}{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \dfrac{1}{ \sqrt{2} } = \dfrac{2 \sqrt{2} }{x} [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 2 \sqrt{2}{} \times \sqrt{2} [/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 2 \times 2[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 4 \: \: units[/tex]

I hope you understood the whole procedure ~

Answer:

15t

Step-by-step explanation:

if you do the sqrt of 25 you get five than multiply that by 3 to get 15 then do the sqrt of t to get t

Hope this helps! ;-)

The solution of the liner equation 6k + 10.5 = 3k + 12 is k = 1/2.

Here, 6k + 10.5 = 3k + 12

         6k - 3k = 12 - 10.5

         3k = 1.5

          k = 1.5/3

          k = 1/2

Thus, The solution of the liner equation 6k + 10.5 = 3k + 12 is k = 1/2.

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Answer: y=108

Step-by-step explanation:

Answer:

k = 4.5

y = 4.5x

Step-by-step explanation:

Finding the variation constant, k :

Equation of variation :

Part A

y-intercept: 3

It represents that after 0 months practice, the number of matches won is 3.

Part B

slope intercept form: y = mx + b

Here to find slope,

take two points: (5, 12), (0, 3)

[tex]\sf slope: \dfrac{y_2-y_1}{x_2-x_1} = \dfrac{rise}{run}[/tex]

[tex]\rightarrow \sf slope = \dfrac{3-12}{0-5} = 1.8[/tex]

Equation:

y - y1 = m(x- x1)

y - 12 = 1.8(x - 5)

y = 1.8x - 9 + 12

y = 1.8x + 3

To find Matches won after 13 months

insert x = 13

y = 1.8(13) + 3

y = 26.4 ≈ 26 matches

The team could have won 26 matches after 13 months practice.

Answer:

See below ~

Step-by-step explanation:

Part A :

Part B :

Forming the equation :

Predicting how many matches can be won with 13 months of practice :

Let's solve this problem step by step:

 ⇒ on one side, I solve the equaiton

    ⇒ on the other side, I give you the property that I use to solve the

        equation

         ⇒ you don't need to write down those properties if your teachers

             didn't ask you for it

  [tex]4(5x-2)=2(9x+3)\\[/tex]      |   Given equation

  [tex]20x-8=19x+6[/tex]           |    Distributive Multiplication over subtract/add

  [tex]x=14[/tex]                             |    Subtraction Property of Equality

Answer: x = 14

Definition of Properties:

Answer:

See below ~

Step-by-step explanation:

1. The average grade of Brenda :

2. During the second quarter, Brenda scored her lowest grade, which was an 82.

To find the point of symmetry:

  ⇒ must find where the distance between the original point and the

   line of symmetry and reflected point and the line of symmetry are

   equally distant from each other

Based on that knowledge:

 ⇒ the image appears to be entirely reflected horizontally

    ⇒ when the line of symmetry is the y-axis

        ⇒ A, A' equal distant from line of symmetry

        ⇒ B, B' equal distant from line of symmetry

        ⇒ C, C' equal distant from line of symmetry

Answer: y- axis

Hope that helps!

Answer:

[tex]a^{4}-2a^{2} -24[/tex]

Step-by-step explanation:

We do FOIL to solve this

Answer:

[tex] d = sin(39) \times 30[/tex]