The isotopes K-37 and K-42 have the same

Answer:

EL Niño  had hurricanes and so many damages in nature. :)

Explanation:

it creates warm weather, there is low pressure towards canada

Numerous health issues, such as disease outbreaks, malnutrition, heat stress, and respiratory illnesses are being brought on by the severe drought and associated food insecurity, flooding, precipitation, and temperature increases brought on by El Nino.

The exceptional warming of surface waters in the eastern tropical Pacific Ocean is referred to as El Nino, a climate pattern. El Nino is a bigger phenomena known as the El Nino-Southern oscillation, and it is its warm phase.

Climate change brought on by El Nino can be severe and extensive. Increased precipitation results from convection over warmer surface waters. In Ecuador and northern Peru, rainfall rises dramatically, causing coastal erosion and flooding.

Homes, businesses, schools, and hospitals may be destroyed by heavy rains and flooding. They hinder transportation and obliterate crops. As reservoirs dry up and rivers carry less water, the droughts pose a threat to the area's water resources. Agriculture is in danger since it depends on water for irrigation.

Find more on El-Nino:

https://brainly.com/question/18307318

#SPJ2

Answer:

Helium has atomic mass  4.002602.

So the answer to yr question is helium.

Answer:

Elements and compounds

Explanation:

Elements and compounds, mixtures are not chemically bonded and can be physically seperated

Answer:

C

Explanation:

its physical change.

Answer:

75 degrees

Explanation:

Answer:

30

Explanation:

25.0 + 5.0  = 30

Answer:

30

Explanation:

Answer:

feel slippery

Explanation:

Bases are certain metallic oxides, metallic hydroxides and aqueous ammonia. They typically have the following characteristics;

From the choices given, the fitting answer is that bases have a slippery feel.

Answer:

B) Feel slippery

Explanation:

Just did the assignment

Complete question

The complete question is shown on the first uploaded image

Answer:

The value is  [tex]K_c  =  2.69 *10^{-5} [/tex]  

Explanation:

From the question we are told that

   The equation is  

           [tex]Fe_20_3_{(s)}+3H_{(g)}\to2Fe_{(s)}+3H_2O_{(g)}[/tex]

Generally the equilibrium is mathematically represented as

        [tex]K_c  =  \frac{[H_2O]^2}{[H_2]^3}[/tex]

Here [tex][H_2O][/tex] is the concentration of water vapor which is mathematically represented as

      [tex][H_2O ] =  \frac{n_w}{V_s }[/tex]

Here [tex]V_s[/tex] is the volume of the solution given as 8.9 L

[tex]n_w[/tex] is the number of moles of water vapor which is mathematically represented as

        [tex]n_w  =  \frac{m_w}{Z_w}[/tex]

Here  [tex]m_w[/tex]  is the mass of water given as 2.00 g

and   [tex]Z_w[/tex]  is the molar mass of water with value  18 g/mol

So  

         [tex]n_w  =  \frac{2}{18}[/tex]

=>     [tex]n_w  = 0.11 \  mol[/tex]

So

     [tex][H_2O ] =  \frac{0.11}{8.9 }[/tex]

=>   [tex][H_2O ] = 0.01236 \  M [/tex]

Also

[tex][H][/tex] is the concentration of hydrogen gas which is mathematically represented as

      [tex][H ] =  \frac{n_v}{V_s }[/tex]

Here [tex]V_s[/tex] is the volume of the solution given as 8.9 L

[tex]n_v[/tex] is the number of moles of  hydrogen gas which is mathematically represented as

        [tex]n_v  =  \frac{m_v}{Z_v}[/tex]

Here  [tex]m_w[/tex]  is the mass of water given as 4.77 g

and   [tex]Z_v[/tex]  is the molar mass of water with value  2 g/mol

So  

         [tex]n_w  =  \frac{4.77}{2}[/tex]

=>     [tex]n_w  = 2.385 \  mol[/tex]

So

     [tex][H_2O ] =  \frac{2.385}{8.9 }[/tex]

=>   [tex][H_2O ] =  0.265 \  M [/tex]

So

     [tex]K_c  =  \frac{( 0.01236 )^3}{ (0.265 )^2}[/tex]

=>   [tex]K_c  =  2.69 *10^{-5} [/tex]  

Answer:

Barium

Explanation:

Answer:

B. 65

Explanation:

arrange your numbers as:

63,64,66,69

add 64 and 66 together to get 130 then divide by 2

-or just think about what number is between 64 and 66

Answer:

Mass of water produced is 22.86 g.

Explanation:

Given data:

Mass of hydrogen = 2.56 g

Mass of oxygen = 20.32 g

Mass of water = ?

Solution:

Chemical equation:

2H₂ + O₂   →  2H₂O

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 20.32 g/ 32 g/mol

Number of moles = 0.635 mol

Number of moles of hydrogen:

Number of moles = mass/ molar mass

Number of moles = 2.56 g/ 2 g/mol

Number of moles = 1.28 mol

Now we will compare the moles of water with oxygen and hydrogen.

                    O₂            :            H₂O

                     1              :             2

                  0.635        ;            2×0.635 =  1.27

                   H₂             :              H₂O

                    2              :              2

                 1.28            :           1.28

The number of  moles of water produced by oxygen are less thus it will be limiting reactant.

Mass of water produced:

Mass = number of moles × molar mass

Mass = 1.27 × 18 g/mol

Mass = 22.86 g

Answer:

22.88

Explanation:

correct have a g'day mate

Please do mark me as Brainiest. I would be so happy!!! Here's your answer....

Answer:

D.)

Explanation:

Compact fluorescent lamps, or CFLs, use 75 percent less energy than a traditional incandescent bulb, but they never quite caught on for home use.

Have a great rest of your day!

Answer:

The mass of object is 0.5 Kg.

Explanation:

Given data:

Acceleration of object = 12.0 m/s²

Force on object = 6.0 N

Mass of object = ?

Solution:

Formula:

F = m×a

F = force

m = mass

a = acceleration

Now we will put the values in formula.

6.0 N = m  × 12.0 m/s²

m =  6.0 N / 12.0 m/s²  

   ( N = kg.m/s²)

m = 0.5 kg

The mass of object is 0.5 Kg.

Answer:

its b.

Explanation:

Answer:

Time = 8.12 h = 0.34 day

Explanation:

First we find speed of water flow:

Speed = u = (3160 tons/s)(907.185 kg/1 ton)

u = 2866704.6 kg/s

also,

Density = (1 g/mL)(1 mL/1 x 10⁻⁶ m³)(1 x 10⁻³ kg/1 g)

Density = 1000 kg/m³

Now,

Volume Flow Rate = Speed/Density

Volume Flow Rate = (2866704.6 kg/s)/(1000 kg/m³)

Volume Flow Rate = 2866.7 m³/s

Now, we find volume of cylinder:

Volume = (Area)(Length)

Volume = (πd²/4)(L)

Volume = [(π)(0.53 m)²/4][236000 mi][1609.36 m/1 mi]

Volume = 83,792,823.82 m³

Now,

Time = Volume/Volume Flow Rate

Time = (83,792,823.82 m³)/(2866.7 m³/s)

Time = (29299.71 s)(1 h/3600 s)

Time = 8.12 h = 0.34 day

Answer:convection

Explanation:

Answer: B. Convection

Explanation: I hope this helps! :)

Answer:

The sample which would contain more oxygen atoms is a glass stirring rod.

Explanation:

According to the periodic table ,

the glass stirring rod is Silicon dioxide and the cotton ball is cellulose

Here , the molar mass of the glass stirring rod [tex]SiO_{2}[/tex] = 60.08 Grams/mole

Molar mass  of the cotton ball  [tex]C_{6} H_{10}O_{5}[/tex] = 162.09 gram/mole .

since ,total number of molecules present in oxygen is 32 ,

therefore ,

In glass stirring rod ,

number of oxygen atoms present in 5g = [tex]\frac{32}{60.07} \times 5[/tex]

                                                                 = 2.66 g of oxygen

                                                              [tex]\frac{1}{16} \times 2.66[/tex]

                                                           =  0.16625 moles

                                                      = 0.16625 x [tex]6.023\times 10^{23}[/tex]

                                                   =[tex]1.001 \times10^{23}[/tex] atoms

In cotton ball ,

number of oxygen atoms present in 5g = [tex]\frac{80}{162.09} \times 5[/tex]

                                                                = 2.467 g of oxygen

                                                              [tex]\frac{1}{16} \times 2.467[/tex]

                                                           = 0.15418 moles

                                                            = 0.15418 [tex]\times 6.023 \times 10^{23}[/tex]

                                                           = 0.928 [tex]\\ \times10^{23}[/tex]

Hence , the glass stirring rod contains more number of oxygen atoms .

Answer:

Empirical formula = [tex]\mathbf{C_{10}H_{12}N_{2}}[/tex]

Molecular formula = [tex]\mathbf{C_{20}H_{24}N_{4}}[/tex]

Explanation:

From the given information:

we need to estimate the mass of carbon C in 1.321 g of [tex]CO_2[/tex]

before that, the number of moles of C is:

[tex]C = 1.321 \ g \times \dfrac{1 \ mol \ CO_2}{44/010 \ g \ of \ CO_2}[/tex]

c = 0.03002 mol

we know that:

number of moles = mass/ molar mass

mass = number of moles × molar mass

mass = 0.03002  × 12.011g of C

mass of C = 0.3606 g

Similarly; for hydrogen

the number of moles of H = [tex]0.325 g \ of \ H_2O \times \dfrac{ 1\ mol \ H_2O}{18.02g \ of \ H_2O}\times \dfrac{2 \ mole \ of H }{1 \ mol \ H_2O }[/tex]

the number of moles of H = [tex]0.325 g \ of \ H_2O \times \dfrac{2 \ mole \ of H}{18.02g \ of \ H_2O}[/tex]

the number of moles of H = 0.0361 mol of H

mass of H = [tex]0.0361 \ mol \ of \ H \times \dfrac{1.008 g \ of \ H}{ 1 \ mol \ of \ H}[/tex]

mass of H  = 0.0364 g

The mass of N will therefore be the difference the sample burnt with the mass of carbon and hydrogen.

i.e

mass of N = 0.487 g - 0.3606 of C - 0.0364 g of H

mass of N = 0.0900 g

however, the number of moles of nitrogen  = mass/ molar mass

the number of moles = 0.0900 g /14.007 g

the number of moles of nitrogen = 0.00643 mol

Thus, the formula is:  [tex]\mathsf{C_{0.03002}H_{0.0361}N_{0.00643}}[/tex]

If we divide by the smallest number (0.00643); we have:

[tex]\mathsf{C_{\dfrac{0.03002}{0.006432}}H_{\dfrac{0.0361}{0.00643}}N_{\dfrac{0.00643}{0.00643}}}[/tex]

= [tex]\mathsf{C_{4.7}H_{5.7}N}[/tex]

Thus, multiplying the subscript by 2.1,  we have:

 [tex]\mathsf{C_{4.7 \times 2.1}H_{5.7 \times 2.1}N_{1\times 2.1}}[/tex]

Thus, the empirical formula = [tex]\mathbf{C_{10}H_{12}N_{2}}[/tex]

The mass of the empirical formula is:

= (10 × 12.010 u) + (12 × 1.008 u) + ( 2 × 14.007 u)

= 160.21 u

Thus, because the molecular mass 324 g/mol is double the value of the empirical formula, the molecular mass is definitely double the empirical formula;

i.e

Molecular formula = [tex]\mathbf{C_{10\times 2}H_{12\times 2}N_{2\times 2}}[/tex]

Molecular formula = [tex]\mathbf{C_{20}H_{24}N_{4}}[/tex]

Answer:

Kinetic theory of gases is a description of gas as a large number of non-stop random moving particles (atoms or molecules, generally without distinction in physics, are called molecules). Fast-moving molecules continuously collide with other molecules or the walls of the container. Molecular motion theory is to explain the macroscopic properties of gas, such as pressure, temperature, volume, etc., through the composition and motion of molecules. The theory of molecular motion believes that pressure does not come from static repulsion between molecules, as Newton’s conjecture, but from collisions between molecules that move thermally at different speeds.

The molecule is too small to be seen directly. The random movement of pollen particles or dust particles under the microscope-Brownian motion, is a direct result of molecular collisions. This can be used as evidence of the existence of the molecule.

Temperature is a measure of the average kinetic energy of the particles in a substance. Temperature of a volume of air represents the average kinetic energy of its molecules. Temperature is a measure of the average kinetic energy of a substance.

According to Kinetic Molecular Theory, the average kinetic energy of gas molecules is a function only of temperature. where T is the Kelvin temperature and k is Boltzmann's constant.

Answer:

Atom

Explanation:

Its the smallest unit into which matter can be divided without the release of electrically charged particles.

Answer:

True

Explanation:

A homogeneous mixture is simply any mixture that is uniform in composition throughout. As long as each substance is mixed in enough to be indistinguishable from the others, it is a homogeneous mixture.

Answer:

[tex]m_{H_2O}=6.84gH_2O[/tex]

Explanation:

Hello.

In this case, for 5.17 g of hexane (molar mass = 86 g/mol) and 16.5 g of oxygen (molar mass =32 g/mol), we have the reaction:

[tex]C_6H_{14}+\frac{19}{2} O_2\rightarrow 6CO_2+7H_2O[/tex]

Next, via the 1:7 mole ratio of hexane to carbon dioxide and 19/2:7 mole ratio of oxygen to carbon dioxide, we compute the yielded mass of water (molar mass = 18 g/mol) as its theoretical yield by the two masses of reactants and we infer that the limiting reactant is that yielding the fewest moles of product:

[tex]m_{H_2O}^{by\ Hexane}=5.17gC_6H_{12}*\frac{1molC_6H_{12}}{86 gC_6H_{12}} *\frac{7molH_2O}{1molC_6H_{12}}*\frac{18gH_2O}{1molH_2O} =7.57gH_2O\\\\m_{H_2O}^{by\ Oxygen}=16.5gO_2*\frac{1molO_2}{32gO_2} *\frac{7molH_2O}{\frac{19}{2}molO_2 }*\frac{18gH_2O}{1molH_2O} =6.84gH_2O[/tex]

Whereas it is evidenced that oxygen yields the fewest grams of water, therefore, it is the limiting reactant and the theoretical yield of water is:

[tex]m_{H_2O}=6.84gH_2O[/tex]

Best regards!

Answer:

Follows are the solution to this question:

Explanation:

The creation of four fragments,  

(n endpoint) MNQSYGR (c endpoint)  

Weight of the molecular = 854.92

Load = 2

[tex]\to \frac{mass}{Load}[/tex] = 427.46

(n endpoint)RLVSR (c endpoint)

Weight of the molecular = 629.76

Load = 3

[tex]\to \frac{mass}{Load}[/tex]= 209.92

(n endpoint) AATAMASLIK (c endpoint)

Weight of the molecular = 976.20

Load at pH(2). = 2

[tex]\to \frac{mass}{Load}[/tex]= 442.50

(n endpoint) IFAWWY (c endpoint)

Weight of the molecular = 885.03

Load= 1

[tex]\to \frac{mass}{Load}[/tex]= 885.03

It is apparent that RLVSR is the smallest mass ration for this peptide that is detected in the first place.

Answer:

40.32 grams of solute required for the preparation of 1.5L of 0.32M NaHCO₃

Explanation:

Molar concentration or molarity is a measure of the concentration of a solute in a solution. Molarity is defined as the number of moles of solute present in one liter of solution.

Molarity is calculated by the expression:

[tex]Molarity=\frac{number of moles of solute}{volume}[/tex]

Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].

In this case:

Replacing:

[tex]0.32 M=\frac{number of moles of solute}{1.5 L}[/tex]

Solving:

number of moles of solute= 0.32 M* 1.5 L

number of moles of solute= 0.48 moles

Being the molar weight of NaHCO₃ equal to 84 g / mole, the following rule of three can be applied: if there are 84 grams in 1 mole, how much mass is there in 0.48 moles?

[tex]mass=\frac{0.48 moles*84 grams}{1 mole}[/tex]

mass= 40.32 grams

40.32 grams of solute required for the preparation of 1.5L of 0.32M NaHCO₃

Answer:

a. evaporation .

Explanation:

In this case, given the described situation, we should take into account that there are two types of liquid-gas phase transitions, evaporation and vaporization, which occur in totally different way.

Firstly, evaporation is a superficial phenomena, it means that it occurs at the surface of the liquid only whereas the vaporization is a bulk phenomena, which means that it occurs along the whole volume of liquid.

In such a way, we can infer that cold steam stream flowing over the pond has the capacity to strip or remove liquid water molecules in the pond and take them to the vapor phase, which means that the answer is a. evaporation .

Best regards.

Answer:

Theoretical yield of CaCO₃ is 2.002 g.

Explanation:

Given data:

Mass of K₂CO₃ = 2.5 g

Mass of CaCl₂ = 2 g

Theoretical yield of CaCO₃ = ?

Solution:

Chemical equation:

K₂CO₃ +  CaCl₂      →     CaCO₃ + 2KCl

Number of moles of K₂CO₃:

Number of moles = mass/molar mass

Number of moles = 2.5 g/ 138.205 g/mol

Number of moles = 0.02 mol

Number of moles of CaCl₂:

Number of moles = mass/molar mass

Number of moles = 2 g/ 110.98 g/mol

Number of moles = 0.02 mol

Now we will compare the moles of CaCO₃ with K₂CO₃ and CaCl₂.

                CaCl₂             :              CaCO₃

                    1                  :                  1

                  0.02              :              0.02

                 K₂CO₃            :               CaCO₃

                     1                 :                   1

                   0.02             :               0.02

Theoretical yield of CaCO₃:

Mass = number of moles × molar mass

Mass = 0.02 mol × 100.1 g/mol

Mass =  2.002 g

Theoretical yield of CaCO₃ is 2.002 g.

Answer: c

Explanation:

Answer: C - Centuries

Explanation:

Explanation:

Mass, is amout of matter contained in body

it value remain constant

it cannot be zero

weight is gravitational force which attract body towards centre of earth

it value changes

it can be zero