Answer:
v = 16,66 m/s
Explanation:
To obtain the velocity of the train we must use the velocity formula for a uniform line movement:
v = x/t
Where x is the space and t is time.
replacing given values:
v = 180 km / 3 h
v = 60 km/h
to pass this value to international units:
v = 60 / 3,6 m/s
v = 16,66 m/s
Which action could a student take to show a transverse wave
A:blow up a balloon
B:shake a rope from side to side
C:shout across a soccer field
D:Knock on a door
Answer:
B is the correct answer
Explanation:
I just did this question
A small truck has a mass of 2145 kg. How much work is required to decrease the speed of the vehicle from 25.0 m/s to 12.0 m/s on a level road?
Answer:
The work required is -515,872.5 J
Explanation:
Work is defined in physics as the force that is applied to a body to move it from one point to another.
The total work W done on an object to move from one position A to another B is equal to the change in the kinetic energy of the object. That is, work is also defined as the change in the kinetic energy of an object.
Kinetic energy (Ec) depends on the mass and speed of the body. This energy is calculated by the expression:
[tex]Ec=\frac{1}{2} *m*v^{2}[/tex]
where kinetic energy is measured in Joules (J), mass in kilograms (kg), and velocity in meters per second (m/s).
The work (W) of this force is equal to the difference between the final value and the initial value of the kinetic energy of the particle:
[tex]W=\frac{1}{2} *m*v2^{2}-\frac{1}{2} *m*v1^{2}[/tex]
[tex]W=\frac{1}{2} *m*(v2^{2}-v1^{2})[/tex]
In this case:
W=?m= 2,145 kgv2= 12 [tex]\frac{m}{s}[/tex]v1= 25 [tex]\frac{m}{s}[/tex]Replacing:
[tex]W=\frac{1}{2} *2145 kg*((12\frac{m}{s} )^{2}-(25\frac{m}{s} )^{2})[/tex]
W= -515,872.5 J
The work required is -515,872.5 J
The amount of work needed by the vehicle to decrease its speed from 25 m/s to 12 m/s is 515872.5 J.
The amount of work required by the truck to decrease its speed can be calculated using the formula below.
Formula:
W = m(u²-v²)/2............. Equation 1Where:
W = amount of work required to decrease the speed of the vehicle.m = mass of the truckv = Final speedu = initial speed.From the question,
Given:
m = 2145 kgv = 12 m/su = 25 m/s.Substitute these values into equation 1
W = 2145(25²-12²)²/2W = 2145(481)/2W = 515872.5 J.Hence, The amount of work needed by the vehicle to decrease its speed from 25 m/s to 12 m/s is 515872.5 J.
Learn more about work here: brainly.com/question/18762601
1. A baseball, 0.314 kg, is accelerated at a rate of 153 m/s2 when hit by a professional baseball player. What force does the player's bat exert on the ball? (use the formula F=ma)
Answer:
The answer is 48.0 NExplanation:
To find the force acting on an object given it's mass and acceleration we use the formula
Force = mass × accelerationFrom the question
mass = 0.314 kg
acceleration = 153 m/s²
We have
force = 0.314 × 153 = 48.042
We have the final answer as
48.0 NHope this helps you
Nervous tissue makes up most of the
Brain
Lungs
Kidneys
Stomach
Answer:
, Nervous tissue is composed of two types of cells, neurons and glial cells. Neurons are the primary type of cell that most anyone associates with the nervous system. They are responsible for the computation and communication that the nervous system provides.
Calculate the acceleration of a student riding his bicycle in a straight line that speeds up from 4 m/s to 6 m/s in 5 seconds.
this is the movie i have never watched(interesting) adjective
Dillon wants to go to the park to play basketball. To get to the park, he must travel 9 km East, and then 6 km South, then 9 Km West. Calculate the distance
Answer:
24 km
Explanation:
9 + 9 + 6 = 24
A child (mass Me) pulls a sled (mass Ms) holding a baby (mass m) across the snow (assume the snow is frictionless). When the child starts the sled moving the baby brother slips off the sled instead of moving with the sled. The child tries again with a slightly smaller force and the baby stays on the sled due to the friction between the baby and the sled. Write a symbolic solution for the coefficient offriction between the baby and the sled if the maximum acceleration ofthe sled for the baby to stay on the sled is a. The solution may include the variables MC: Ms, m: a and g but does not need to have all ofthem_ The computer Ivill not recognize any other variables. Do not include any numbers (or the in your answer). Fill in the blank
Answer:
symbolic solution for the coefficient of friction between the baby and the sled is
[tex] \mu = \frac{m + M_s}{m} * \frac{a}{g}[/tex]
Explanation:
From the question we are told that
The mass of the boy is [tex]M_e =[/tex]
The mass of the shed is [tex]M_s[/tex]
The mass of the baby is [tex]m[/tex]
The maximum acceleration for the baby to stay is a
Generally the frictional force between the baby and the shed is mathematically represented as
[tex]F_f = \mu N[/tex]
Here N is the normal force acting on the baby which is mathematically represented as
[tex]N = m * g[/tex]
=> [tex]F_f = \mu * m * g[/tex]
Now for the baby not the slip off the shed the frictional force between the baby and the shed must be equal to the the force applied by the child
The force applied by the child is mathematically represented as
[tex]F = [M_s+m] * a[/tex]
So
[tex] \mu * m * g = [M_s+m] * a[/tex]
=> [tex] \mu = \frac{m + M_s}{m} * \frac{a}{g}[/tex]
-5 1/3 - 2 1/3 in math
Answer:
3
Explanation:
5 1/3 - 2 1/3 = 3
Broken down: 1/3 - 1/3 = 0 5 - 2 = 2
How does energy from the sun travel to earth .
Answer:
through uv light
A reversible power cycle operates with a thermal efficiency of 75%. The cycle receives energy input by heat from a thermal reservoir at 1200K. What is the temperature, in K, of the low temperature thermal reservoir
Answer:
The temperature of the low temperature thermal reservoir is 300 K.
Explanation:
All reversible power cycles are equivalent to the Carnot's cycle, whose equation for efficiency is:
[tex]\eta_{th} =1-\frac{T_{L}}{T_{H}}[/tex] (Eq. 1)
Where:
[tex]\eta_{th}[/tex] - Thermal efficiency, dimensionless.
[tex]T_{H}[/tex] - High temperature reservoir, measured in Kelvin.
[tex]T_{L}[/tex] - Low temperature reservoir, measured in Kelvin.
Now we proceed to clear the low temperature reservoir within:
[tex]\frac{T_{L}}{T_{H}} = 1-\eta_{th}[/tex]
[tex]T_{L} = (1-\eta_{th})\cdot T_{H}[/tex]
If [tex]\eta_{th} = 0.75[/tex] and [tex]T_{H} = 1200\,K[/tex], then:
[tex]T_{L} = (1-0.75)\cdot (1200\,K)[/tex]
[tex]T_{L} = 300\,K[/tex]
The temperature of the low temperature thermal reservoir is 300 K.
Convert 56,340,040 meters into scientific notation?
Answer:
5.634004 × 10^7
Explanation:
the number 7 is for the numbers before the number 5
I WILL MARK YOU AS BRAINLIEST IF RIGHT
A 1250 kg car was traveling at 10 m/s toward a traffic signal when the light suddenly turned red. The driver slammed on his brakes, stopping the car in 3.3 seconds. What was the acceleration of the car ?
Answer:
a = - 3 m/s^2 (negative 3 meters per second squared)
Explanation:
We use the formula for acceleration as the change in velocities (from initial velocity "vi" to final velocity "vf") divided the time "t" it took. In our case:
a = (vf - vi) / t = (0 - 10) / 3.3 = -10 /3.33 = -3 m/s^2
A 10-cm-thick aluminum plate (α = 97.1 × 10−6 m2/s) is being heated in liquid with temperature of 550°C. The aluminum plate has a uniform initial temperature of 25°C. If the surface temperature of the aluminum plate is approximately the liquid temperature, determine the temperature at the center plane of the aluminum plate after 15 s of heating. Solve this problem using the analytical one-term approximation method. The temperature at the center plane after 15 s of heating is
Answer:
356°C.
Explanation:
(1). The first step to the solution to this particular Question/problem is to determine the Biot number, and after that to check the equivalent value of the Biot number with plate constants.
That is, Biot number = (length × ∞)÷ thermal conductivity. Which gives us the answer as ∞. Therefore, the equivalent value of the ∞ on the plates constant = 1.2732 for A and 1.5708 for λ.
(2). The next thing to do is to determine the fourier number.
fourier number = [α = 97.1 × 10−6 m2/s × 15 s] ÷ (.05m)^2 = 0.5826.
(3). The next thing is to determine the temperature at the center plane after 15 s of heating.
The temperature at the center plane after 15 s of heating = 500°C [ 25°C - 500°C ] [1.2732] × e^(-1.5708)^2 ( 0.5826).
The temperature at the center plane after 15 s of heating = 356°C.
A train travels from Boston to New York. It travels at a speed of 180 km/h for two hours, speeds up to 200 km/h for the next four hours and then slows down to 120 km/h for the next six hours. What is the average speed of the train for this trip?
Answer:
156 2/3 km/hr
Explanation:
Average speed is found by dividing total distance by total time.
180 km/hr in 2 hrs is 360 miles
200 km/hr in 4 hrs is 800 miles
120 km/hr in 6 hrs is 720 miles
Total time is 12 hrs; Total distance 1880 hrs
Divide distance by time and you have 156 2/3 km/hr. This is your average speed.
Because mass is determined from protons
and neutrons, what conclusion can you
make?
Answer:
Electrons have virtually no mass
Explanation:
I had a test an this was the right answer^
Answer: Electrons have virtually no mass
Explanation: on edpuzzle that was the answer
HELP! IDENTIFY AND DRAW A CONCLUSION FOR THIS PROBLEM PLS! ASAP.
Answer:
the conclusion is that the plant that had been given fertilizer B grew more than the plant with fertilizer A and the plant without fertilizer. so in conclusion fertilizer B is better for growing plants fastly.
the problem is that you noticed your tomatoes were not growing properly.
Hope this helps!❤
List the 4 materials that would light up this light bulb when dropped onto the crocodile clips. In 1 -2 sentences describe why it caused the light to turn on using these 4 key terms Conductors, circuit, electrons and flow.
Answer:
Ok I might be wrong but I think its the screwdriver, screw, key and the fork
Explanation:
Why because they all have metal in them if am wrong am sorry buddy i was struggling on the same thing
Question # 40
A body falls freely under gravity. If speeds is v when it has lost an amount x of the gravitational P.E, then its mass is:
2x / v2
2x / v3
2x / v4
none
please give me its solution
Answer:
Potential Energy = x = m g h
Kinetic energy = 1/2 m v^2
Assuming the mass fall from rest
1/2 m v^2 = m g h
v^2 = 2 g h
So the speed attained is independent of the mass
Also, x / v does not have the units of mass
So the solution is none of the above.
North America and South America are on the same Tectonic Plate.
True
False
Answer:True
Explanation:
a dump truck slowly tilts its bed upward to dispose of a 95 kg steel cabinet. For small angle of tilt the crate stay put,but when the tilt angle exceeds 23.2° the steel cabinet begins to slide.What is the coefficient of static friction between the bed of the truck and the steel cabinet?
Answer:
The value is [tex]\mu =0.4286[/tex]
Explanation:
From the question we are told that
The mass of the steel cabinet is [tex]m = 95 \ kg[/tex]
The threshold angle is [tex]\theta = 23.2^o[/tex]
Generally at the point just before the steel cabinet starts to slide
The horizontal force on the steel cabinet is equal to the frictional force that is
[tex]F_f = F_h[/tex]
Here [tex]F_h[/tex] is the horizontal force which is mathematically represented as
[tex]F_h = m * g cos (theta )[/tex]
and [tex]F_f = \mu N[/tex]
Here N is the normal force acting on the steel cabinet and this is mathematically represented as
[tex]N = mg sin (\theta )[/tex]
=> [tex] m * g cos (theta )= mg sin (\theta ) * \mu [/tex]
=> [tex]\mu = tan (\theta )[/tex]
=> [tex]\mu = tan (23.2)[/tex]
=> [tex]\mu =0.4286[/tex]
The coefficient of static friction between the bed of the truck and steel cabinet is 0.43.
The given parameters;
mass of the steel, m = 95 kgangle of inclination, θ = 23.2⁰The coefficient of static friction between the bed of the truck and steel cabinet is calculated as follows;
[tex]\Sigma F = 0\\\\mg sin(\theta) - \mu mg cos(\theta) = 0\\\\\mu mg cos(\theta ) = mg sin(\theta)\\\\\mu cos(\theta) = sin(\theta)\\\\\mu = \frac{sin(\theta)}{cos(\theta)} \\\\\mu = tan (\theta)\\\\\mu = tan \ (23.2)\\\\\mu = 0.43[/tex]
Thus, the coefficient of static friction between the bed of the truck and steel cabinet is 0.43.
Learn more about coefficient of static friction: https://brainly.com/question/16902584
I WILL MARK YOU AS BRAINLIEST IF RIGHT
A 1125 kg car was traveling at 20 m/s toward a traffic signal when the light suddenly turned red. The driver stomped on her accelerator, clearing the intersection in 1.7 seconds and coming to a speed of 24.6 m/s . What was the acceleration of the car?
Answer:
a = 3.88 m/s^2 (3.88 meters per second squared)
Explanation:
The acceleration of the car can be obtained based of the change of velocities (from initial velocity "vi" to final velocity "vf") in the given amount of time:
In our case:
a = (26.6 - 20) / 1.7 = 3.88 m/s^2
Suggest one reason why the bricklayer needs a higher energy diet than the computer operator
Answer:
he needs more because he is doing more exercise this means he is working his body more and he needs more energy than someone he is sitting in an office. The computer operator would not need as much energy as the brick layer.
What is meant by the term straight line motion?
A. An object can turn, but after each turn, it moves in a straight line, not curves
B. A path taking between two points, without turning left or right
C. An object is moving at a constant speed
D. Motion where the object faces forward, regardless of the path taken
Answer:
A
Explanation:
Answer: B
Explanation: I got it right
If a drag racing car accelerated at 69 miles per second in 0.25 s, what is the acceleration of the car
Answer:
acceleration is : 276 mi/s^2
(276 miles per second squared)
Explanation:
We use the formula for acceleration (a) which is the change in velocity divided by the time it took to change it:
a = (vf - vi) / t
where "vf" stands for final velocity, "vi" for initial velocity, and "t" for the time it took for the velocity to change.
In our case:
a = (69 - 0) / 0.25 = 276 mi/s^2
(276 miles per second squared)
A car travels 90 km/h. How long does it take for the car to travel
400 km?
b. 1.5x103 s
C. 1.5x104 s
a. 4x104 s.
d. 1.6x104s
Answer:
4.44 hr
Explanation:
distance= rate*time
400km/(90 km/hr)=time
time=4.44 hr
PLEASE HELP ASAP
A 744N object falling in the air experiences 434N of air resistance. what is the amount if net force of the falling objec
Answer:
The amount of net force of the falling object is -310 N, or 310 N downwards
Explanation:
Net Force
Being the force a vector, the net force is the sum of all the force vectors acting on an object at a given time:
[tex]\vec F_n=\vec F_1+\vec F_2+\vec F_3+.....\vec F_m[/tex]
When the forces are acting in one axis, say the y-axis, the direction of the forces can be considered by the sign of the magnitude of the force.
For example, the weight of the object is usually assigned a negative direction. In our problem:
W=-744 N
The air resistance always opposes the direction of motion. Since the object is falling, the air resistance is positive:
Fa = +434 N
The net force is the sum of both, including their signs:
Fn = -744 N + 434 N = -310 N
The amount of net force of the falling object is -310 N, or 310 N downwards
A source of sound produce waves in air of wavelength 3.42m . If the speed of sound in air is 330m/s, What is the period of vibration?
Explanation:
wavelength=3.42m
velocity=330m/s
T=?
v=f×wavelength
f=330÷3.42
f=96.5Hz
T=1/f
=1/96.5
T=0.01s
A target lies flat on the ground 4 m from the side of a building that is 10 m tall, as shown below.
The acceleration of gravity is 10 m/s^2.
Air resistance is negligible.
A student rolls a 4 kg ball off the horizontal
the roof of the building in the direction of the
target.
The horizontal speed v with which the ball
must leave the roof if it is to strike the target
is most nearly
1. v =√3 /4 m/s.
2. v =4√3 /3 m/s.
3. v = 4 m/s.
4. v = 2√2 m/s.
5. v =√2 / 4 m/s.
6. v =√5 / 4 m/s.
7. v = 4√3 m/s.
8. v = 4√5 m/s.
9. v = 6 m/s.
10. v = 4√2 m/s.
Answer:
v = 2√2 m/s
Explanation:
The following data were obtained from the question:
Height (h) = 10 m
Acceleration due to gravity (g) = 10 m/s²
Horizontal distance (s) = 4 m
Horizontal velocity (v) =.?
Next, we shall determine the time taken for the ball to get to the target.
This can be obtained as shown below:
Height (h) = 10 m
Acceleration due to gravity (g) = 10 m/s²
Time (t) =?
h = ½gt²
10 = ½ × 10 × t²
10 = 5 × t²
Divide both side by 5
t² = 10/5
t² = 2
Take the square root of both side.
t = √2 s
Finally, we shall determine the horizontal velocity as shown below:
Horizontal distance (s) = 4 m
Time (t) = √2 s
Horizontal velocity (v) =.?
s = vt
4 = v × √2
Divide both side by √2
v = 4 /√2
Rationalise the denominator
v = (4 /√2) × √2/√2
v = 4 × √2 / √2 × √2
v = 4 × √2 / 2
v = 2√2 m/s
A freight train consists of two 8.00 \times 10^5~\text{kg}8.00×10 5 kg engines and 45 cars with average masses of 5.50 \times 10^5~\text{kg}5.50×10 5 kg. What force must each engine exert backward on the track to accelerate the train at a rate of 5.00 \times 10^{-2}~\text{m/s}^25.00×10 −2 m/s 2 if the force of friction is 7.50 \times 10^5 ~\text{N}7.50×10 5 N, assuming the engines exert identical forces? This is not a large frictional force for such a massive system. Rolling friction for trains is small, and consequently trains are very energy-efficient transportation systems.
Answer:
F₁ = 4.29 x 10⁵ N
Explanation:
The total force required to move the freight train with the given acceleration is given by the following formula:
F = ma + f
where,
F = Total Force Required from both engines = ?
m = equivalent mass of system = 2(8 x 10⁵ kg) + 5.5 x 10⁵ kg = 21.5 x 10⁵ kg
a = required acceleration = 5 x 10⁻² m/s²
f = force of friction = 7.5 x 10⁵ N
Therefore,
F = (21.5 x 10⁵ kg)(0.05 m/s²) + 7.5 x 10⁵ N
F = 8.575 x 10⁵ N
Now, for identical forces in each engine can be given as:
Force exerted by each engine = F₁ = F/2
F₁ = 8.575 x 10⁵ N/2
F₁ = 4.29 x 10⁵ N
