Answer:
The answer is:
[tex]speed(\frac{m}{s}) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (number)\\\\ 100 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 23 \\\\ 200 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 42 \\\\ 300 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 26 \\\\ 400 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 8 \\\\ 500 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1 \\\\[/tex]
Explanation:
Its total kinetic energy of a gas colloquial atom colloction is equal to absolute temperature alone, according to the programs that directly gas Theory.
Average speed for 1st option:
[tex]= \frac{(200 \times 23)+(400 \times 42)+(600 \times 26)+(800 \times 8) +1000}{100} \\\\= 444\ \frac{m}{s} \ \ \ \ \ \ \ \ \ \text{average speed of gas}[/tex]
Average speed for 2nd option:
[tex]= \frac{(200 \times 11) +(400 \times 21)+ (600 \times 13)+ (800 \times 4)}{11+21+13+4} \\\\= 440 \ \frac{m}{s}[/tex]
Average speed for 3rd option:
[tex]= \frac{(200 \times 43) +(400 \times 50)+ (600 \times 7)}{100} \\\\ =328 \ \frac{m}{s}[/tex]
Average speed for 4th option:
[tex]= \frac{(200 \times 50) +(400 \times 25)+ (600 \times 13)+(800\times 8)+(1000 \times 4)}{100}\\\\ =382\ \frac{m}{s}[/tex]
Average speed for 5th option:
[tex]= \frac{(100 \times 23) +(200 \times 42)+ (300 \times 26)+(400\times 8)+500}{100}\\\\ =222 \ \frac{m}{s}[/tex]
The average speed also increased by half because the temperatures had kinetic energy.[tex]\to 444 \ \frac{m}{s}\ to \ 222 \ \frac{m}{s}[/tex]
During the process of condensation, water vapor:____________.
(1) releases 334 J/g of heat energy
(2) releases 2260 J/g of heat energy
(3) gains 334 J/g of heat energy
(4) gains 2260 J/g of heat energy
Answer: (2) releases 2260 J/g of heat energy
Explanation:
Latent heat of vaporization is the amount of heat required to convert 1 mole of liquid to gas at atmospheric pressure.
Latent heat of condensation is energy released when 1 mole of vapor condenses to form liquid droplets.
The temperature does not change during this process, so heat released goes into changing the state of the substance, thus it is called latent which means hidden. The energy released in this process is same in magnitude as latent heat of vaporization. The heat of condensation of water vapour is about 2,260 J/g.
Phase transition refers to the changes in the states of matter between gas, liquids, and solids.
The correct answer is:
Option 2. releases 2260 J/g of heat energy
The process can be explained as:
1. Condensation is the process of conversion of water vapor into the liquid state.
2. Latent heat of vaporization is defined as the amount of heat required for 1 mole of liquid to convert into a gaseous phase at atmospheric pressure.
3. The change in the temperature does not occur during the condensation, and the heat required for the phase transition is latent heat. The heat of condensation of water vapor is 2,260 J/g.
Thus, the correct answer is Option 2.
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Calculate the following:
1. Mass of 4.3x10^-3 mol of lead
2. Mass of 3.8x10^22 antimony atoms
3. Number of atoms in 15.5 kg of tungsten
Answer:
Explanation:
1) Given data:
Number of moles of lead = 4.3×10⁻³ mol
Mass of lead = ?
Solution:
Mass = number of moles × molar mass
Molar mass of lead = 207.2 g/mol
Mass = 4.3×10⁻³ mol × 207.2 g/mol
Mass = 890.96 g
2) Given data:
Number of atoms of antimony = 3.8×10²² atoms
Mass of antimony = ?
Solution:
1 mole contain 6.022 ×10²³ atoms
3.8×10²² atoms × 1 mol / 6.022 ×10²³ atoms
0.63×10⁻¹ mol
0.063 mol
Mass = number of moles × molar mass
Molar mass of lead = 121.76 g/mol
Mass = 0.063 mol × 121.76 g/mol
Mass = 7.67 g
3) Given data:
Mass of tungsten = 15.5 Kg (15.5 kg × 1000 g/ 1kg = 15500 g)
Number of atoms = ?
Solution:
Number of moles of tungsten:
Number of moles = mass/molar mass
Number of moles = 15500 g / 183.84 g/mol
Number of moles = 84.3 mol
1 mole contain 6.022 ×10²³ atoms
84.3 mol × 6.022 ×10²³ atoms / 1mol
507.65 ×10²³ atoms
photo attached
if anyone from my class sees this no you didn't
Answer:
I think its b or c
Explanation:
hope this helps I mainly think b
wich of these does the sun provide in large amounts 1.carbon dioxide 2.energy 3.glucose 4.oxygen
Answer:
2. Energy
Explanation:
Consider the following intermediate chemical equations.
2 equations. First: upper C (s) plus one half upper O subscript 2 (g) right arrow upper C upper O (g). Second: upper C upper O (g) plus one half upper O subscript 2 (g) right arrow upper C upper O subscript 2 (g).
How will oxygen appear in the final chemical equation?
Upper O subscript 2 (g). as a product
Upper O subscript 2 (g). as a reactant
O(g) as a product
2O(g) as a reactant
Answer:
c
Explanation:
got it right on test
Oxygen will appear in the final equation as O2 reactant.
What are chemical equation?A chemical equations shows the interplay between reactants and products. The reactants are on the left hand side while the products are at the right hand side.
Looking at the two equations, we know that oxygen will appear in the final equation as O2 reactant.
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Find the length of time required for the total pressure in a system containing N2O5 at an initial pressure of 0.110 atm to rise to 0.150 atm .
Answer:
t = 37.1 s
Explanation:
The equation for the reaction is given as;
2 N2O5(g) --> 4 NO2 + O2
Initial: 0.110 - -
change: -2x +4x +x
Final: 0.110 - 2x +4x +x
But final = 0.150atm;
0.110 - 2x + 4x + x = 0.150 atm
3x = 0.150 - 0.110
x = 0.0133 atm
Pressure in reactant side;
0.110 - 2x
0.110 - 2 (0.0133) = 0.0834 atm
The integral rate law expression is given as;
ln ( [A] / [Ao] ) = -kt
k = rate constant = 7.48*10^-3*s-1
ln (0.0834/0.11) = (7.48*10^-3) t
upon solving, t = 37.1 s
In this exercise we have to use the knowledge of chemistry to calculate the necessary time that the pressure can hold the system, in this way we can say that this time corresponds to:
[tex]t = 37.1 s[/tex]
First we have to use the reaction equation given as:
[tex]2 N_2O_5(g) \rightarrow 4 NO_2 + O_2[/tex]
This equation can be rewritten in terms of pressure, so it will be;
[tex]0.110 - 2X + 4X + X = 0.150 atm\\3X = 0.150 - 0.110\\X = 0.0133 atm[/tex]
Pressure in reactant side, will be:
[tex]0.110 - 2X \rightarrow 0.110 - 2 (0.0133) = 0.0834 atm[/tex]
The integral rate law expression is given as, knowing that the rate constant is [tex]7.48*10^{-3}*s^{-1}[/tex]
[tex]\int\limits^{0.0834}_{0.11} {(7.48*10^{-3}) t} \, dt = t = 37.1 s[/tex]
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Which of these is a harmful interaction
Answer:The five major types of species interactions, summarized in Figure 10, are competition, predation, parasitism, mutualism, and commensalism.
Explanation:
What ratio of nitrogen and hydrogen molecules would result in no left-over reactants? Explain your answer.
Answer:
1:3
Explanation:
nitrogen and hydrogen combine qt high pressure and temperature to form ammonia gas.this method is used to prepare ammonia industrially and the process is called haber's process.
the balanced equation is given as:
N2+3H2=>2NH3
we can see that 1 mole of nitrogen combines with 3 moles of hydrogen to produce 2 moles of ammonia.
hence ratio of nitrogen and hydrogen molecules should be 1:3 for reactants to get used up completely.
I hope it's helpful!
8. Explain how Elianto oil is obtained from maize seeds.
Answer:
Almost all corn oil is expeller-pressed
Explanation:
then solvent-extracted using hexane or 2-methylpentane (isohexane). The solvent is evaporated from the corn oil, recovered, and re-used. After extraction, the corn oil is then refined by degumming and/or alkali treatment, both of which remove phosphatides.Oct 16, 2020
Suppose you have 2.50 L of a substance with a density of 8.00 g/mL and you want to determine the mass of the substance. The calculation can be broken down into three steps. First, convert the volume from liters to milliliters. Then, determine the mass of the sample in grams. Finally, convert the mass from grams to kilograms. Show the unit analysis by placing the correct components into the unit‑factor slots. The question marks (?) represent the answer to the previous step.
Answer:
20 kg
Explanation:
From the question given above, the following data were obtained:
Volume (V) of substance = 2.50 L
Density (D) of substance = 8.00 g/mL
Mass (m) of substance =?
Next, we shall convert 2.50 L to millilitres (mL). This can be obtained as follow:
1 L = 1000 mL
Therefore,
2.50 L = 2.50 L × 1000 mL / 1 L
2.50 L = 2500 mL
Thus, 2.50 L is equivalent to 2500 mL.
Next, we shall determine the mass of the substance. This can be obtained as follow:
Volume (V) of substance = 2500 mL
Density (D) of substance = 8.00 g/mL
Mass (m) of substance =?
D = m / V
8 = m / 2500
Cross multiply
m = 8 × 2500
m = 20000 g
The mass of the substance is 20000 g.
Finally, we shall convert 20000 g to Kg
This can be obtained as follow:
1000 g = 1 kg
Therefore,
20000 g = 20000 g × 1 kg / 1000 g
20000 g = 20 kg
Therefore, the mass of the substance is 20 Kg
iv. If only 174.6 g of Cu(OH)2 precipitate were actually collected from the reaction, what would the percent yield be? SHOW ALL WORK!
Answer:
59.4%
Explanation:
CuSO4(aq) + 2NaOH(aq) -----> Cu(OH)2(aq) + Na2SO4 (aq)
Ratio of molesCuSO4 to NaOH is 1:2
To determine the limiting reagent;
For CuSO4
Number of moles= 638.44g/160 = 4 moles
1 mole of CuSO4 yields 1 mole of Cu(OH)2
4 moles of CuSO4 also yields 4 moles of Cu(OH)2
For NaOH
Number of moles= 240g/40g/mol= 6 moles
2 moles of NaOH yields 1 mole of Cu(OH)2
6 moles of NaOH yields 6× 1/2 = 3 moles of Cu(OH)2
Hence NaOH is the limiting reactant.
Hence mass of Cu(OH)2 = 3 × 98 g/mol
= 294 g
% yield = actual yield/ theoretical yield × 100
% yield= 174.6 /294 × 100/1
% yield = 59.4%
The percent yield is 59.4%
Firstly write the balanced chemical equation:
CuSO₄(aq) + 2NaOH(aq) → Cu(OH)₂(aq) + Na₂SO₄ (aq)
Ratio of moles for CuSO₄ to NaOH is 1:2
To determine the limiting reagent:
For CuSO₄:
[tex]\text{Number of moles}= \frac{ 638.44g}{160}= 4 \text{moles}[/tex]
1 mole of CuSO₄ produces 1 mole of Cu(OH)₂
4 moles of CuSO₄ will produce 4 moles of Cu(OH)₂
For NaOH:
[tex]\text{Number of moles}= \frac{240g}{40g/mol} = 6 \text{moles}[/tex]
2 moles of NaOH yields 1 mole of Cu(OH)₂
6 moles of NaOH yields [tex]6*\frac{1}{2} = 3[/tex] moles of Cu(OH)₂
Hence, NaOH is the limiting reactant.
Therefore, mass of Cu(OH)₂ = [tex]3 * 98 g/mol= 294 g[/tex]
% yield = actual yield/ theoretical yield × 100
% yield= [tex]\frac{174.6}{294}* 100[/tex]
% yield = 59.4%
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Which of the processes is exothermic?
a) evaporation of alcohol
b) sublimation of iodine
c) solidification of volcanic lava
d) burning of paper
Answer:
Choice C as my opinion
Explanation:
solidification of volcanic lava has to do with changes in earth and the thermal structure that's just a point not sure though
hope I was helpful though thank you
Answer:
c) solidification of volcanic lava
Explanation:
heat is being lost to the outside surroundings "exo" thermic
The most common source of copper (CuCu) is the mineral chalcopyrite (CuFeS2CuFeS2). How many kilograms of chalcopyrite must be mined to obtain 395 gg of pure CuCu
Answer:
1.14kg of chalcopyrite
Explanation:
In 1 mole of chalcopyrite, CuFeS₂, there is 1 mole of Cu. Thus, to solve this question we need to convert the mass of pure Cu to moles using molar mass (Cu = 63.546g/mol). Then, the moles of Cu are equal to moles of chalcopyrite that must be converted to grams and then to kg (CuFeS₂: 183.54g/mol)
Moles Cu:
395g Cu * (1mol / 63.546g) = 6.216 moles Cu = 6.216 moles CuFeS₂
Mass chalcopyirite:
6.216 moles CuFeS₂ * (183.54g/mol) = 1140.9g
In kilograms:
1140.9g * (1kg / 1000g) =
1.14kg of chalcopyriteA habit is:
pls help me ty
Li2SO4 _____ an electrolyte in solution.
A. Is
B. Is not
Answer:
a
Explanation:
it is an electrolyte because of its strong polar chemical bond
Questions 4-6: Use the following Molar Masses:
H2: 2.02 g/mol Oz: 32.00 g/mol H2O: 18.02 g/mol
5) What mass of oxygen is needed to completely react
with 32.0 g of hydrogen?
2 Hz O2 → 2 H2O
+
32 g H2
х
x
x
= 329 H2
= 1g 42
= 2.02 g H2
= 1 mol H2
* 2.02 mol H2
- 2 mol H2
# 1 mol O2
- 2 mol O2
# 32 mol Oz
3 32 mol O2
=> 32 g 02
- 1 g 02
= 1013 g 02
: 0.248 g 02
253.4 g 02
Answer:
Mass = 253.4 g
Explanation:
Given data:
Mass of oxygen required = ?
Mass of hydrogen available = 32.0 g
Solution:
Chemical equation:
2H₂ + O₂ → 2H₂O
Number of moles of hydrogen:
Number of moles = mass/molar mass
Number of moles = 32.0 g/ 2.02 g/mol
Number of moles = 15.84 mol
Now we will compare the moles of hydrogen and oxygen:
H₂ : O₂
2 : 1
15.84 : 1/2×15.8 = 7.92 mol
Mass of oxygen required:
Mass = number of moles × molar mass
Mass = 7.92 mol × 32.00 g/mol
Mass = 253.4 g
I just need the balanced redox equation for the cell using the oxidation and reduction half reactions. PLEASE AND ILL MARK BRAINLIEST!
Answer: For the balanced redox equation, you should add the half reactions.
Like this.
Explanation:
Was it helpful? Or do you need different answer?
A 5.00-cm cube of magnesium has a mass of 217.501 g. What is the density of magnesiummetal?
Answer:
d = 43.5 g/cm³
Explanation:
Given data:
Mass of magnesium cube = 217.501 g
Volume of magnesium cube = 5.00 cm³
Density of magnesium cube = ?
Solution:
Formula:
d = m/v
d = density
m = mass
v = volume
by putting values,
d = 217.501 g/ 5.00 cm³
d = 43.5 g/cm³
When heating a sample to extreme heat over a flame, you will often use a crucible. Before starting the heating, you should locate the correct labware for the experiment, including the equipment to safely handle and support the crucible. What equipment should you have ready to start your crucible experiment
Answer:
The equipments you should have ready to start the crucible experiment includes: safety goggles, crucible with lid, crucible tong, ring support with clay triangle, Bunsen burner and heat resistant tile.
Explanation:
Crucible is an equipment in the laboratory which is suitable for heating a sample to extreme heat over a flame, Modern laboratory crucible are made up of graphite- based composite materials for achievement of higher performance. Because extreme heat is involved, you should locate the correct labware for the experiment, including the equipment to safely handle and support the crucible. These equipments includes:
--> Safety goggles: Because you will work with chemical it is advisable to use a safety goggles which protects the eyes from dangerous floating chemical aerosol.
--> crucible with lid: This is the main apparatus with the lid (cover) which is used to cover the crucible to prevent spilling of the boiling chemical.
--> Crucible tong: These are scissors like tools used to grasp hot crucible.
--> Ring support with clay triangle: the clay triangle is used to hold crucible when they are being heated. They usually sit on a ring stand.
--> Bunsen burner: Produces a single open gas flame which can be used for heating.
With the safety equipments listed above, you can carry out experiment using the crucible. These equipments helps minimise laboratory hazard that may occur should Incase it's not available.
Safety goggles, crucible with lid, crucible tong, ring support with clay triangle, Bunsen burner and heat resistant tiles equipment should be ready to start the crucible experiment.
What is crucible?Crucible is having a cup like structure and formed by the mixture of graphite and porcelain, and these two are having very high melting or boiling point; that's why crucible is used to heat any sample at high temperature.
Before doing any experiment with crucible you have to carry:
Safety goggles: In any experiment many kind of chemical used so to protect eyes by that chemicals, this goggles are used.Crucible with lid: It is required to cover the upper open part of crucible.Crucible tong: This is the scissors like tool which is used to carry hot crucible as it is not possible to carry that hot crucible.Ring support with clay triangle: The clay triangle is used to hold crucible when we are doing heating. They usually sit on a ring stand.Bunsen burner: It is used to produces a single open gas flame to produce heat. Heat resistant tiles: It is used to put at the bottom place of the burner.Equipment we should ready to start crucible experiment are safety goggles, crucible with lid, crucible tong, ring support with clay triangle, Bunsen burner and heat resistant tiles.
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What does the last line of the poem suggest
Answer:
that the poem needs to be finished heh pog
Explanation:
Answer:
Where is the poem?
Explanation:
What is the molarity of a solution that is made by mixing 35.5 g of Ba(OH)2 in 325 mL of solution?
Given :
Mass of Ba(OH)₂ , m = 35.5 g.
Volume of mixture, V = 325 mL = 0.325 L.
To Find :
The molarity of a solution.
Solution :
We know, molarity of a solution is given by :
[tex]M = \dfrac{Given \ Weight}{Molecular\ Mass\times Volume( L ) }[/tex]
We know, molecular mass of Ba(OH)₂ is given by :
M.M. = 171 g/mol
Putting all these values in given equation, we get :
[tex]M = \dfrac{35.5}{171\times 0.325}\ M\\\\M = 0.64\ M[/tex]
Hence, this is the required solution.
Calculate the mass of sodium bicarbonate produced bu complete decompostion of 16.8h of nahco3
Answer:what is nacho3???
Explanation:
2055 Q. No. 10^-2
mole of KOH is dissolved in 10 litres of
water. What will be the pH of the solution?
12
Ans: pH = 11
Answer:
11
Explanation:
Moles of KOH = [tex]10^{-2}[/tex]
Volume of water = 10 liters
Concentration of KOH is given by
[tex][KOH]=\dfrac{10^{-2}}{10}\\\Rightarrow [KOH]=10^{-3}\ \text{M}[/tex]
[tex][KOH][/tex] is strong base so we have the following relation
[tex][KOH]=[OH^{-}]=10^{-3}\ \text{M}[/tex]
[tex]pOH=-\log [OH^{-}]=-\log10^{-3}[/tex]
[tex]\Rightarrow pH=14-3=11[/tex]
So, pH of the solution is 11
Why do plant cells need chloroplasts
Answer:
Plants need chloroplasts to capture light energy.
Plant cells use light energy to make food.
The cell uses the energy from food.
Hope it helps ;)
What is the answer to this?
A population’s carrying capacity is the number of individuals that die over a given time period. True or false
Answer:
I believe its false
Explanation:
a carrying capacity is the maximum amount of living things that can be held in a single container
Answer:
Populations vary in their capacity to grow. The maximum rate at which a population can increase when resources are unlimited and environmental conditions are ideal is termed the population's biotic potential. Each species will have a different biotic potential due to variations in
the species' reproductive span (how long an individual is capable of reproducing)
the frequency of reproduction (how often an individual can reproduce)
"litter size" (how many offspring are born each time)
survival rate (how many offspring survive to reproductive age)
There are always limits to population growth in nature. Populations cannot grow exponentially indefinitely. Exploding populations always reach a size limit imposed by the shortage of one or more factors such as water, space, and nutrients or by adverse conditions such as disease, drought and temperature extremes. The factors which act jointly to limit a population's growth are termed the environmental resistance. The interplay of biotic potential and density-dependent environmental resistance keeps a population in balance.
6. How many ions of Na are in 45.6 g of Na2SO4?
Answer:
3.85 ×10²³ Na⁺ ions
Explanation:
Given data:
Mass of Na₂SO₄ = 45.6 g
Number of ions of Na = ?
Solution:
Number of moles of Na₂SO₄:
Number of moles = mass/ molar mass
Number of moles = 45.6 g/ 142.04 g/mol
Number of moles = 0.32 mol
1 mole of Na₂SO₄ contain 2 moles of Na⁺ ion.
0.32 mol × 2= 0.64 moles of Na⁺ ion
1 mole contain 6.022×10²³ Na⁺ ions
0.64 mol × 6.022×10²³ Na⁺ ions / 1 mol
3.85 ×10²³ Na⁺ ions
Which of the following substances would form when aluminum and sulfur undergo a combination/synthesis reaction?
Aluminum and Sulfur react to produce Aluminum sulfide(Al₂S₃)
Further explanationGiven
The reaction of Aluminium and Sulfur
Required
The products of the reaction
Solution
There are several types of reactions that can occur
Synthesis/combination reaction : 2 elements combine to form a single product
The general formula :
A + B ⇒ AB
For reaction above :
2Al + 3S ⇒ Al₂S₃
This is not multiptle choice
Sound: Now click the Sound tab.
Part A
On the Sound tab, investigate briefly all the phenomena you explored with water waves above and describe any similarities in your results for sound. Specifically, describe
wave pattern as seen on the screen
shape and amplitude of the graph
effect of frequency on wavelength
effect of frequency on velocity
pattern with two sources
wave pattern with a single-slit barrier
Question 3
Light: Now click the Light tab.
Part A
On the Light tab, once again investigate briefly all the phenomena you explored with water and sound above. Describe any similarities in your results for light. Specifically describe
wave pattern as seen on the screen
shape and amplitude of the graph
effect of frequency on wavelength
effect of frequency on velocity
pattern with two sources
wave pattern with a single-slit barrier
Answer: Sound waves
The wave pattern that i observed in sound waves are longitudinal wave patterns.
The mathematical graph function looks like is a sine function graph. The pattern that i observed in the amplitude of the wave is longitudinal wave pattern
When you increase the frequency of the sound waves the wave moves faster but the wavelength becomes shorter. The higher the frequency results in higher the pitch of the sound.
If you increase the frequency the velocity of the sound wave remains constant for all valuses of frequencies.
i am currently completing this assigment. i am not usre if the answer are correct but i tried my best
I also got this from course hero it's your choise to put the one you want.
The wave pattern is identical to the pattern of the water. The graph is the same as the water except the wave height isn’t as big. Increasing the frequency increases the wavelength. Increasing the frequency also increases the velocity of the waves by a lot. With two sources the waves pass through each other. The wave pattern with a single slit barrier is the same as the water pattern.
Explanation:
Answer: Sound waves
The wave pattern that i observed in sound waves are longitudinal wave patterns.
The mathematical graph function looks like is a sine function graph. The pattern that i observed in the amplitude of the wave is longitudinal wave pattern
When you increase the frequency of the sound waves the wave moves faster but the wavelength becomes shorter. The higher the frequency results in higher the pitch of the sound.
If you increase the frequency the velocity of the sound wave remains constant for all valuses of frequencies.
i am currently completing this assigment. i am not usre if the answer are correct but i tried my best
I also got this from course hero it's your choise to put the one you want.
The wave pattern is identical to the pattern of the water. The graph is the same as the water except the wave height isn’t as big. Increasing the frequency increases the wavelength. Increasing the frequency also increases the velocity of the waves by a lot. With two sources the waves pass through each other. The wave pattern with a single slit barrier is the same as the water pattern.
Explanation:
100. mL of 0.100 M HCl aqueous solution is mixed with 200. mL of 0.100 M CaCl2 solution to make a 300.mL solution. Find the molarity of the Cl- and pOH in the mixed solution Question 7 options:
Answer:
Explanation:
HCl ⇄ H⁺ + Cl⁻
HCl is a strong electrolyte so it will ionize completely .
moles of Cl⁻ in 100 mL of .1 HCl = .1 x .1 = .01 gram - ion .
CaCl₂ = Ca⁺² + 2 Cl⁻
1 mole 2 mole
moles of CaCl₂ in 200 mL of .1 M CaCl₂ = .2 x .1 = .02 gram mole .
.02 gram mole of CaCl₂ will give 2 x .02 = .04 gram-ion of Cl⁻ ion .
Total gram - ion of Cl⁻ = .01 + .04 = .05 gram-ion .
Total volume = 300mL = .3 L
molarity of Cl⁻ = .05 / .3 = .167 M .
HCl ⇄ H⁺ + Cl⁻
moles of H⁺ = moles of Cl⁻ = .01 gram-ion .
volume of solution = .3 L
molarity of H⁺ = .01 / .3 = 33.33 x 10⁻³ M .
[ H⁺] [ OH⁻] = 10⁻¹⁴
33.33 x 10⁻³ [ OH⁻] = 10⁻¹⁴
[ OH⁻] = 3 x 10⁻¹³
pOH = - log[OH⁻] = - log3 x 10⁻¹³
13-log3
= 13 - .477
12.52
or ,
pH = - log[H⁺] = - log33.33 x 10⁻³
3 - log 33.33
= 3 - 1.52
= 1.48
pOH = 14 - 1.48 = 12.52
