Rational numbers are fractions and their opposites. All of these numbers are rational numbers. Show that they are rational by writing them in the form (a)/(b) or (a)/(b).

A B and F seem like questions that make sense :)

Answer:

Abc

Step-by-step explanation:

they make the most reasonable answers

Answer:

x=-1

Step-by-step explanation:

x+2-1=0

-1+2=1

1-1=0

y=0

Answer:

X = -2

Step-by-step explanation:

Y = | (-2) + 2 | - 1

Y = |0| - 1

y = -1

Answer:

x= -64°, y= -63°, z=-57°

Step-by-step explanation:

→Solution,

Here,

60°=(-y-3)°[The opposite sides of a parallelogram are equal]

⇒y= -60°-3°

⇒y= -63°

⇒60°+(-2x-8)°=180°[Sum of co-interior angles is 180°]

⇒52°-2x=180°

⇒52°-180°=2x

⇒x= -128°/2

⇒x= -64°

⇒60°+(-2z+6)°=180°[Sum of co-interior angles is 180°]

⇒66°-2z=180°

⇒66°-180°=2z

⇒z= -114°/2

⇒z= -57°

Answer:

y=4x-3

Step-by-step explanation:

Using y - intercept form:

y=mx+b

Slope goes up by 4 squares and to the right by 2 squares. This means the slope is 4. The y intercept is -3, thus b is -3.

Answer: $32

Step-by-step explanation:

Answer:

see explanation

Step-by-step explanation:

(a)

∠ XBC = 55° because it corresponds to ∠ AXY

(b)

since XB = XC then Δ XBC is isosceles with base angles congruent, that is

∠ XBC = ∠ XCB = 55°

the sum of the 3 angles in Δ XBC = 180° , then

∠ BXC + 55° + 55° = 180°

∠ XBC + 110° =180° ( subtract 110° from both sides )

∠ XBC = 70°

Answer:

We can tell by looking at the graph that it is a positive slope, so we can eliminate answers b and d.

It is rise over run. from a point, it goes up 4, and over 1.

4/1

which would be 4. The answer is C! Hope this helps!

Step-by-step explanation:

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's consider two points on the line and calculate its Slope ~

Slope (m) of a line is :

[tex]\qquad \sf  \dashrightarrow \: m = \dfrac{y_2 - y_1}{x_2 - x_1} [/tex]

[tex]\qquad \sf  \dashrightarrow \:m = \dfrac{2 - 1}{8 - 4} [/tex]

[tex]\qquad \sf  \dashrightarrow \:m = \dfrac{1}{4} [/tex]

Answer:

the area of ∆ABC = 9

Step-by-step explanation:

[tex]CA=\sqrt{\left( -1-2\right)^{2} +\left( 2-5\right)^{2} } = \sqrt{18} =3\sqrt{2}[/tex]

[tex]CB=\sqrt{\left( 5-2\right)^{2} +\left( 2-5\right)^{2} } = \sqrt{18} =3\sqrt{2}[/tex]

Since CA = CB  then  A(-1,2), B (5,2) and C (2,5) are the vertices of an isosceles triangle.

Area calculation:

Let The point H be the midpoint of side AB

[tex]x_{H}=\frac{-1+5}{2} =2\\y_{H}=\frac{2+2}{2} =2[/tex]

Then

H(2 , 2)

therefore,

[tex]CH=\sqrt{\left( 2-2{}\right)^{2} +\left( 2-5\right)^{2} } =3[/tex]

Finally,

[tex]\text{the area of triangle ABC} =\frac{\text{CH} \times \text{AB} }{2} =\frac{3\times 6}{2} =9[/tex]

Answer:

y = 12 mm

Step-by-step explanation:

Volume of a rectangular prism: length × width × height

V = L×W×H

Substitute the values above and solve for y:

2,016 = 14 × 12 × y

2,016 = 168y

2,016/168 = 1395v/168

12 = y

Final answer: 12 mm

Hope this helps!

The length of lines UV, VW, WX, and UX are: = √65 units, 10 units,√65 units and 10 units respectively.

Algebraic expression that gives the distances between pairs of points in terms of their coordinates

Given that:  U(7,9), V(0,5), W(-6,-3) ,X(1,1)

The length can be find by using Distance Formula,

Length of UV,

= [tex]\sqrt{(0-7)^{2} + (5-9)^{2}}[/tex]

= [tex]\sqrt{49+16}[/tex]

= √65 units

Length of VW,

= [tex]\sqrt{(-6-0)^{2}+(-3-5)^{2}}[/tex]

= [tex]\sqrt{36 + 64}[/tex]

=√100 units

= 10 units

Length of WX,

=[tex]\sqrt{(1-(-6))^{2}+(1-(-3))^{2}}[/tex]

= √49+ 14

= √65 units

Length of XU,

= [tex]\sqrt{(7-1)^{2}+(9-1)^{2}}[/tex]

= √36+64

=√100 units

= 10 units

Length of UW,

= [tex]\sqrt{(-6-7)^{2}+(-3-9)^{2}}[/tex]

= √169+144

=√313 units

Length of VX,

= [tex]\sqrt{(1-0)^{2}+(5-1)^{2}}[/tex]

= √1+16

=√17 units

Thus, Length of opposite sides are equal but the length of diagonals are not Equal. So, the quadrilateral is a parallelogram.

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Answer:

96 days. Divide 3072 by 32 and you get 96.

Answer:

m<1 = 94

m<2 = 132

Step-by-step explanation:

This is a right trapezoid

Since the base lines are parallel, the facing angles would be supplementary and their sum is equal to 180 which means:

m<1 + 86 = 180 so m<1 = 94

and

m<2 + 48 = 180 so m<2 = 132

Answer:

The last one is 4(6)(18).

Please give Brainliest

Answer:

4(6)(18)

Step-by-step explanation:

the last option is your right answer

Answer:

sequence

Step-by-step explanation:

Answer:

she could buy 5 outfits

Step-by-step explanation:

you multiply 7.17 by 3 = 21.51

700 - 21.51 = 678.49

678.49 - 242.33 = 436.16

436.16 - 33.68  = 402.48

402.48 divided by 77.40 = 5

For equation 1:

y intercept = (0, 1)

x intercept = (-0.5, 0)

For equation 2:

y intercept = (0, -1)

x intercept = (-1, 0)

Option B is correct

Answer:

Soup A

Step-by-step explanation:

For this we need to find the number of sodium per cup. To do this, we divide the ratios by the number of cups. 8:10 would be 10/10 (1 cup) and 8/10 (.8 g per cup). 7:14 would be 14/14 (1 cup) and 7/14 (.5 g per cup). So, soup A has .8 g of sodium per cup and soup B has .5 g of sodium per cup. .8>.5, so soup A has more sodium.

Hope this helps!

Answer:

13/40.

Step-by-step explanation:

We add the probability in this case.

So it is 1/5 + 1/8

=  8/40 + 5/40

= 13/40.

Answer:

6x+54 should be the answer

Step-by-step explanation:

Answer:

Make use of the fact that as long as [tex]\sin(\theta) \ne 0[/tex] and [tex]\cos(\theta) \ne 0[/tex]:

[tex]\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}[/tex].

[tex]\displaystyle \csc(\theta) = \frac{1}{\sin(\theta)}[/tex].

[tex]\sin^{2}(\theta) + \cos^{2}(\theta) = 1[/tex].

Step-by-step explanation:

Assume that [tex]\sin(\theta) \ne 0[/tex] and [tex]\cos(\theta) \ne 0[/tex].

Make use of the fact that [tex]\tan(\theta) = (\sin(\theta)) / (\cos(\theta))[/tex] and [tex]\csc(\theta) = (1) / (\sin(\theta))[/tex] to rewrite the given expression as a combination of [tex]\sin(\theta)[/tex] and [tex]\cos(\theta)[/tex].

[tex]\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \left(\frac{1}{\sin(\theta)}\right)^{2} \, \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^{2} - 1 \\ =\; & \frac{\sin^{2}(\theta)}{\sin^{2}(\theta)\, \cos^{2}(\theta)} - 1\\ =\; & \frac{1}{\cos^{2}(\theta)} - 1\end{aligned}[/tex].

Since [tex]\cos(\theta) \ne 0[/tex]:

[tex]\displaystyle 1 = \frac{\cos^{2}(\theta)}{\cos^{2}(\theta)}[/tex].

Substitute this equality into the expression:

[tex]\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots\\ =\; & \frac{1}{\cos^{2}(\theta)} - 1 \\ =\; & \frac{1}{\cos^{2}(\theta)} - \frac{\cos^{2}(\theta)}{\cos^{2}(\theta)} \\ =\; & \frac{1 - \cos^{2}(\theta)}{\cos^{2}(\theta)}\end{aligned}[/tex].

By the Pythagorean identity, [tex]\sin^{2}(\theta) + \cos^{2}(\theta) = 1[/tex]. Rearrange this identity to obtain:

[tex]\sin^{2}(\theta) = 1 - \cos^{2}(\theta)[/tex].

Substitute this equality into the expression:

[tex]\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots \\ =\; & \frac{1 - \cos^{2}(\theta)}{\cos^{2}(\theta)} \\ =\; & \frac{\sin^{2}(\theta)}{\cos^{2}(\theta)}\end{aligned}[/tex].

Again, make use of the fact that [tex]\tan(\theta) = (\sin(\theta)) / (\cos(\theta))[/tex] to obtain the desired result:

[tex]\begin{aligned}& \csc^{2}(\theta) \, \tan^{2}(\theta) - 1\\ =\; & \cdots \\ =\; & \frac{\sin^{2}(\theta)}{\cos^{2}(\theta)}\\ =\; & \left(\frac{\sin(\theta)}{\cos(\theta)}\right)^{2} \\ =\; & \tan^{2}(\theta)\end{aligned}[/tex].

Rational expressions are those that have fractional terms. We state restrictions because it may cause the equation to be undefined in some values of x. The most common restriction for rational expressions is N/0. This means any number divided by zero is undefined.

A rational expression is nothing more than a fraction in which the numerator and/or the denominator are polynomials. Here are some examples of rational expressions.

To find the restrictions on a rational function, find the values of the variable that make the denominator equal 0.

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The best statement that describes the relationship between lines s and t : (C). Lines s and t are parallel.

A line can be defined as a figure that is one dimensional. It is a trace that is made by the movement of points in opposite direction.

Parallel lines can be defined as a group of lines that are of the same orientation. They face the same direction and are on the same axis.

In conclusion, The best statement that describes the relationship between lines s and t : Lines s and t are parallel.

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Answer:

33.5410196625 ????

Step-by-step explanation:

   [tex]\rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}[/tex]

    Find the slope using the following points:

        (20, -10) (6, -20)

[tex]\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}[/tex]

Use the slope formula:-

                    [tex]\LARGE\text{$\displaystyle\frac{y_2-y_1}{x_2-x_1}$}[/tex]

Replace letters with numbers as follows:-

                             [tex]\Large\text{$\displaystyle\frac{-20-(-10)}{6-20}$}[/tex]

On simplification,

                                  [tex]\Large\text{$\displaystyle\frac{-20+10}{-14}$}[/tex]

On further simplification,

                                        [tex]\Large\text{$\displaystyle\frac{-10}{-14}$}[/tex]

Reducing the fraction,

                               [tex]\large\text{$\displaystyle\frac{10}{14}$}[/tex]

               [tex]\large\text{$\displaystyle\frac{5}{7}$}\leftarrow\:slope[/tex]

[tex]\rule{300}{1}[/tex]

Answer:

The triangle is a right triangle.

Step-by-step explanation:

Since The Pythagorean Theorem only works on right triangles, we can use this knowledge to prove whether this triangle is right:

[tex]a^2 + b^2 = c^2\\10^2 + (2\sqrt{39})^2 = 16^2\\100 + (4 \times 39) = 256\\100 + 156 = 256\\256 = 256[/tex]

Therefore, the triangle is right.

Answer: n < -7 and n > -5

Step-by-step explanation:

-10|n+6| < -10

first divide by -10 on both sides

[tex]\frac{-10|n+6|}{-10}[/tex] < [tex]\frac{-10}{-10}[/tex]

since we are dividing, we have to flip the sign

|n+6| > 1

subtract the absolute value of 6

You are left with n < -7 and n > -5