Problem 3. The uniform beam is supported by two rods AB and CD that have cross-sectional areas of 10 mm2 and 15mm2, respectively. Determine the intensity w of the distributed load so that the average normal stress in each rod does not exceed 300 kPa.

Answer:

the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi

Explanation:

Given that;

depth 1 = 71 ft

depth 2 = 10 ft

pressure p = 17 psi = 2448 lb/ft²

depth h = 71 ft - 10 ft = 61 ft

we know that;

p = P_air + yh

where y is the specific weight of ethyl alcohol ( 49.3 lb/ft³ )

so we substitute;

p = 2448 + ( 49.3 × 61 )

= 2448 + 3007.3

= 5455.3 lb/ft³

= 37.88 psi

Therefore, the pressure at a closed valve attached to the tank 10 ft above its bottom is 37.88 psi

Answer:

P2 = 3.9 MPa

Explanation:

Given that

T₁ = 290 K

P₁ = 95 KPa

Power P = 5.5 KW

mass flow rate  = 0.01 kg/s

solution

with the help of table A5

here air specific heat and adiabatic exponent is

Cp = 1.004 kJ/kg K

and k = 1.4

so

work rate will be

W = m × Cp × (T2 - T1)              ..........................1

here T2 = W ÷ ( m × Cp) + T1    

so T2 = 5.5 ÷ ( 0.001 × 1.004 ) + 290

T2 = 838 k

so final pressure will be here

P2 = P1 × [tex](\frac{T2}{T1})^\frac{k}{k-1}[/tex]        ..............2

P2 = 95 × [tex](\frac{838}{290})^\frac{1.4}{1.4-1}[/tex]

P2 = 3.9 MPa

4 netherite scrap and 4 gold

in a crafting table

Answer:

performance bonuses

Explanation:

Answer:

8765432

Explanation:

8765433

There are the white inheritance regulatory signs are the color combinations of the regulatory signs indicate right- of-way. The general warning signs railroad crossing signs yellow. There was the used the color are the communication purposes.

What is railroad?

The term “railroad” refers to a defunct rail track. The railroad's track does not change and is permanent. In the seventeenth century, the railroad brought England into the world. Two parallel lines are permanently installed on the railroad track.

Regulatory signs are used to command speeds, such as maximum and minimum speed boundaries. The color was the used in the white background. The general warning signs in the railroads are the used in the sign's yellow color. There was the used this color are the communicated to the people.

As a result, the different color used of the communication purposes.

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Answer:

how we gonna do dat

Explanation:

Answer:https://www.chegg.com › questions-and-answers › four...

Question: Four Bit Shift Register Design a VHDL module Inputs: din, clock, reset Output dout The first D-Flip-Flop (DFF) should have its D input connected ...

1 answer

·

Top answer:

library IEEE; use IEEE.STD_LOGIC_1164.all; entity siso is port( din : in STD_LOGIC; clk : in STD_LOGIC; reset : in STD_LOGIC; dout : out STD_LOGIC ...

Explanation:

Answer: A leak in the system

Explanation:

Answer:

tapping, horizontal dusting, slash drilling

Explanation:

Answer:

Q ≅ 1.53 m³/s

Explanation:

From the given information:

The flow rate of the orifice is:

[tex]v = c_v \sqrt{2gh}[/tex]

[tex]v = 0.90 \times \sqrt{2*9.81 * 10}[/tex]

where;

[tex]Q = c_d \times \sqrt{2gh} \times A[/tex]; &

[tex]c_d = c_c \times c_v[/tex]

∴

[tex]Q = c_c \times c_v \sqrt{2gh} \times \dfrac{\pi}{4}\times d^2[/tex]

[tex]Q = 0.90 \times 0.62 \sqrt{2*9.81*10} \times \dfrac{\pi}{4}\times 0.5^2[/tex]

[tex]Q = 0.558 \times 14.00714104 \times 0.1963495408[/tex]

Q ≅ 1.53 m³/s

Answer:

A motion sensor uses one or multiple technologies to detect movement in an area. When a sensor detects motion, it sends a signal to your security systems control panel, which connects to your monitoring panel system. This alerts you and the monitoring center to a potential threat in your home.

Hope It Helps You................

Explanation:

current- amperes

resistance- ohms

voltage- volts

electrical energy- kilowatt hours

electrical power- watts

hope it helps!

Explanation:

I won't answer each of these, but will give you an explaination of how to solve for each.

You'll need to use Ohm's Law and Kirchhoff's Voltage Law.

Remember Ohm's Law as [tex]V = IR[/tex].

Kirchoff's Voltage Law says that the sum of voltages for a given circuit "loop" must equal zero. In the circuit shown, this means that the voltage provided by the battery (E_T) equals the voltage drop across each of the three resisters in the loop.

[tex]E_T = E_1 + E_2 + E_3[/tex]

A couple of other helpful notes:

These three resistors are in series which means that the current flowing through them is equal.

So it is easy to see that... [tex]V = IR \rightarrow E_1 = 4*2 = 8 V[/tex]

Solve for the voltage across E_2 and E_3. The sum of the three voltages equals the voltage of the battery (E_T).

Solution :

1. PL [tex]$= \frac{11.53 - 10.49}{10.49 - 4.5} \times 100$[/tex]

       = 17.36 %

2. Liquid limit at 25 number of blows,

  [tex]$LL = \frac{(26-25)\times 49.8 + (25 - 2.17) \times 47.5}{26-17}$[/tex]

       [tex]$= 47.75 $[/tex] %

Since 84 % of the passes the number 200 sieve the soil is immediately fine grained and MI, OI or CI because LL = 47.75 % > 35%

Therefore, the Plasticity index, PI  [tex]$=47.75 - 17.36 = 30.39$[/tex] %

Equation of A-line [tex]$= 0.73 \times [47.75 - 20]$[/tex]

                             [tex]$=20.25 $[/tex] %

Thus the soil lies above the A-line, that is soil is medium compressible clay ---- CI

Answer:

[tex]Q_m \simeq 0.11 \ m^3/sec[/tex]

Explanation:

From the given information:

The width of the prototype [tex]L_p[/tex] = 30 m

The flow of the prototype [tex]Q_p[/tex] = 100 m/s

width of the model [tex]L_m[/tex] = 2 m

The flow rate of the model can be calculated by using  the geometrical similarities of Froude's Number Fr

[tex](Fr)_m = (Fr)_p[/tex]

[tex]\implies ( \dfrac{v}{\sqrt{ gy} }) _m = ( \dfrac{v}{\sqrt{gy}}) _p[/tex]

[tex]V_r = \sqrt{L_r}--- (1)[/tex]

[tex]Q_r = V_r *A_r[/tex]

[tex]Q_r = \sqrt { L_r} *L_r^2[/tex]

[tex]Q_r = L_r^{2.5}[/tex]

∴

[tex](\dfrac{Q_m}{Q_p}) = (\dfrac{L_m}{L_p})^{2.5}[/tex]

[tex](\dfrac{Q_m}{100}) = (\dfrac{2}{30})^{2.5}[/tex]

[tex](\dfrac{Q_m}{100}) =0.001147550621[/tex]

[tex]Q_m \simeq 0.11 \ m^3/sec[/tex]

Answer:

Work to develop software and related documents that respect the privacy of those who will be affected by that software.

Explanation:

In the Software Engineering Code of Ethics and Professional Practice, under Principle, which is section three (3) of the document, it is stated in clause 12 on what information should a professional Engineer keep private.

In it, it is stated that professionals engineers should keep private information relating to "Work to develop software and related documents that respect the privacy of those who will be affected by that software."

Answer: an Allen wrench

Explanation:

Based on the information given in the question, the option that identifies the tool that will be the best to use in the following scenario is the Allen key.

The Allen key also refered to as the hex key is a simple tool that is used in driving both screws, bolts and also used in driving the screws that have hexagonal sockets that is, six sided hole in their heads.

Answer:

[tex]P_{a}=181.324 kPa[/tex]

Explanation:

The pressure you measure on a pipeline is generally a gauge pressure, this is the difference between the pressure inside the pipe and the atmospheric pressure.

In order to find the absolute pressure, we need to add the pressure in the atmosphere to the measured pressure, so we get:

[tex]P_{a}=80kPa+101.325kPa[/tex]

the 101.325kPa is the equivalent to 1atm, so we get:

[tex]P_{a}=181.325kPa[/tex]

Answer:

[tex]F_{Net} = 14N[/tex]

[tex]a = 2m/s^2[/tex]

Explanation:

Given

[tex]Mass = 7kg[/tex]

[tex]F_{west} = 12N[/tex]

[tex]F_{opposite} = 26N[/tex]

Solving (a): The net force:

The force towards the west direction, will be regarded as negative while the opposite force will be regarded as positive.

So, the net force is:

[tex]F_{Net} = -F_{west} + F_{opposite}[/tex]

Substitute values for the given forces

[tex]F_{Net} = -12N + 26N[/tex]

[tex]F_{Net} = 14N[/tex]

The net force is 14 N

Solving (b): Acceleration

Net force is calculated as:

[tex]F_{Net} = Mass * Acceleration[/tex]

Substitute 7 kg for Mass and 14 N for Net force:

[tex]14N = 7kg* a[/tex]

Make a the subject:

[tex]a = \frac{14N}{7kg}[/tex]

[tex]a = 2N/kg[/tex]

[tex]a = 2m/s^2[/tex]

Hence, the acceleration is [tex]2m/s^2[/tex]

Answer:

First off, employees must follow all OSHA safety and health standards AND all rules issued by their employers that are intended to comply with OSHA's health and safety standards and the OSH Act. Report all occupational injuries and illnesses. Report hazardous conditions. Cooperate during an OSHA inspection.

The statement that describes one of an employee's responsibilities under OSHA's rules is to report unsafe and unhealthful working conditions to appropriate officials. Thus, the correct option for this question is D.

Congress created OSHA to assure safe and healthful conditions for working men and women by setting and enforcing standards and providing training, outreach, education, and compliance assistance. Under OSHA law, employers are responsible for providing a safe and healthful workplace for their workers.

Employees shall use safety equipment, personal protective equipment, and other devices and procedures provided or directed by the agency and necessary for their protection. Employees shall have the right to report unsafe and unhealthful working conditions to appropriate officials.

At first, employees must have to follow all sorts of OSHA safety and health standards. All rules and regulations are issued by their employers that are intended to comply with OSHA's health and safety standards and the OSH Act.

Therefore, the correct option for this question is D.

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Answer:

Technician B says that prior to customer pick up of the repaired vehicle you should ensure that no damage to the vehicle has been sustained during repair

Explanation:

After a vehicle has been repaired, the technician should check that no damage was placed on the vehicle during repair. For the customer it is important to check;

Report to technicians if you notice any problem.

Question:

All of the following are advantages of using a pressure transducer rather than a vacuum gauge EXCEPT:

A. greater accuracy.  

B. easier identification of the cylinder.

C. measuring higher pressures.

D. ability to see the levels graphically

Answer:

The correct answer is D) ability to see the levels graphically

Explanation:

The above question derives from the Rudiments of Automotive Technology.

The function of the pressure transducer is to enable the diagnostic who is testing the engine vacuum to detect the cylinder with a faulty vacuum.

The pressure transducer does allow its user to see the vacuum graphically NOT  the levels.

Cheers.

Answer:

an Allen wrench

Explanation:

it is hexagonal

Answer:

550kN

Explanation:

We are required to find the maximum allowable load that will satisfy geotechnical ULS requirements

P' = pu/FOS ---1

Pu = design load

FOS = factor of safety

We get the design of safety

Pu = 0.75p

= 0.75 x 2200

= 1650kN

Factor of safety = 3

Design load = 1650

P' = 1650/3

= 550kN

So we have the maximum allowable load to be 550kN

Answer: There are no major convergent boundaries in the Atlantic, which is where these events are more likely to occur

Explanation:

Answer:

defining the need

Explanation:

Of course, since the first stage of the engineering design phase involves defining the need of the design, it is at this stage that the researcher/engineer should determine the criteria and constraints.

This stage involves asking such questions as:

Answer:

Aluminum cross sectional area = 1.99 * 10^-5 mm^2

Steel cross sectional area = 9.95* 10^-6 mm^2

Explanation:

Given data:

Tensile strength of Grunerite = 3.5 * 10^2 kg/mm^2 = 3.5 * 10^-4 kg/um^2

Tensile strength of Aluminum = 2.5 × 10^4 lb/in2 =  2.5 × 10^4 * 703.07 kg/m^2

Tensile strength of Steel number 5137 = 5.0 × 10^4 lb/in2 = 5.0 × 10^4*703.07 kg/m^2

Calculating the cross sectional area of the wires of aluminum and steel No5137

first we will determine the cross sectional area of the aluminum wire ( A ) by equating tensile strength of aluminum with the tensile strength

of Grunerite

(2.5 × 10^4 * 703.07)  * A = 3.5 * 10^-4 kg

Hence ; A = 1.99 * 10^-5 mm^2

Next we calculate the cross sectional area of steel

5.0 × 10^4*703.07 kg/m^2 * A" = 3.5 * 10^-4 kg

Hence ; A" = 9.95* 10^-6 mm^2

Solution :

The percentage of the students who have a chance of repeating their current year = 3%

The drop out students for the first year and the sophomores = 6%

Drop out rate of first year and the seniors = 4%

Now for the state space :

S = { first year(1), sophomores(2), juniors(3), seniors(4), graduates(G), Dropouts(D) }

Therefore

the first year students are indicated as '1'

Sophomores are indicated as '2'

Juniors are indicated as '3'

Seniors are indicated as '4

Graduates are indicated as 'G'

Dropouts are indicated as 'D'

The transition diagram is attached below.

The probability of the students who have the chance of repeating their current year = 3/100 = 0.03

Probability of first year dropouts and sophomores = 6/100 = 0.06

Probability of dropout rate of juniors and seniors = 4/100 = 0.04

Therefore, the probability matrix can be made as :

              1        2        3        4       G        D

    [tex]\begin{matrix}1\\ 2\\ 3\\ 4\\ G\\ D\end{matrix}[/tex]      [tex]\begin{bmatrix}0.03 & 0.91 & 0 & 0 & 0 & 0.06\\ 0& 0.03 & 0.91 & 0 & 0 & 0.06\\ 0& 0 & 0.03 & 0.93 & 0 & 0.04\\ 0& 0 & 0 & 0.03 & 0.93 & 0.04\\ 0& 0 & 0 & 0 & 1 & 0\\ 0& 0 & 0 & 0 & 0 & 1\end{bmatrix}[/tex]  

Here, G represents 'graduates' and D represents 'Dropouts.'