NEED HELP ASAP!!!
On a coordinate plane, sketch the graphs. y=|x| , y=|x+3| , and y=|x-2|

Answer:

12

Step-by-step explanation:

Answer:

24 cubic units

Step-by-step explanation:

Count the front layer by fours because there are 3 rows of 4 and 3 rows of 4 on the other side.So count by 4's on the front layer then the back layer.

Step-by-step explanation:

3(2x - 5) = 4(x+3)

Distribute. Multiply 3 by 2x so the product keeps the variable, multiply 3 by 5 and keep the subtraction symbol. Multiply 4 by x so it would be 4x, multiply 4 by 3

(6x-5=4x+12) Answer

The vertex form of quadratic equation is f(x) = -5(x-1)^2 + 6

A quadratic equation is written in its vertex form in order to easily determine the maximum or minimum point on the curve.

The standard vertex form of an equation is given as:
a(x-b)^2 + k

From the given option, we can see that the only eqeuation writen in this form is f(x) = -5(x-1)^2 + 6

Hence the vertex form of quadratic equation is f(x) = -5(x-1)^2 + 6

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Answer:

p = 2

q = -1

k = -1

Step-by-step explanation:

Cosine functions always start above or below 0. So, the one that starts at (0, 1) is f(x) = (p)cosx + q. Sine functions always start at 0. So, the one that starts at (0, 0) is g(x) = (k)sinx.

Using the help image attached, we know that:

p and k = amplitude (top to midline)

q = vertical shift (movement of midline)

For f(x) = (p)cosx + q:

p = 2

q = -1

For g(x) = (k)sinx:

k = -1

Hope this helps!

The points A, B, C and D are collinear points

The length of the segment AD is 7 units

The given parameters are:

AB = 1

BC = 2

CD = 4

Because the points are on the same line, then the following is the possible equation

AD = AB + BC + CD

Substitute known values

AD = 1 + 2 + 4

Evaluate the sum

AD = 7

Hence, the length of the segment AD is 7 units

Read more about line segments at:

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Answer:

choice for your help today 12 m is not answering me, sorry I think 25m

Answer:

Step-by-step explanation:

The given relations allow us to write three equations in the three unknown values. We can let x, y, z represent the three numbers, in order.

__

  x +y +z = 10 . . . . . . . the sum of the three numbers is 10

  2x +4y +5z = 33 . . . . . designated sum is 33

  6x -y = 28 . . . . . . . . 6 times the first is 28 more than the second

__

There are many ways to solve a system of equations like this. Perhaps one of the easiest is to enter the equations as an augmented matrix in your calculator, and let it do the work. (Some calculators will solve the equations directly.)

The three numbers are 5, 2, and 3.

_____

Additional comment

The third equation lets you write an expression for y in terms of x:

  y = 6x -28

Substituting this into the first two equations, we get ...

  x +(6x -28) +z = 10   ⇒   7x +z = 38

  2x +4(6x -28) +5z = 33   ⇒   26x +5z = 145

Subtracting the second from 5 times the first of these equations gives ...

  5(7x +z) -(26x +5z) = 5(38) -(145)

  9x = 45 . . . . . the y-variable is eliminated

  x = 5

Use equations from above to find z and y.

  z = 38 -7x = 3

  y = 6(5) -28 = 2

Answer:x=70

Step-by-step explanation:

STEP

1

:

           40

Simplify   ——

           x

Equation at the end of step

1

:

 4    40

 — -  ——  = 0

 7    x

STEP

2

:

           4

Simplify   —

           7

Equation at the end of step

2

:

 4    40

 — -  ——  = 0

 7    x

STEP

3

:

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       7

     The right denominator is :       x

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

7 1 0 1

Product of all

Prime Factors  7 1 7

                 Number of times each Algebraic Factor

           appears in the factorization of:

   Algebraic    

   Factor      Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

x  0 1 1

     Least Common Multiple:

     7x

Calculating Multipliers :

3.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = x

  Right_M = L.C.M / R_Deno = 7

Making Equivalent Fractions :

3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      4 • x

  ——————————————————  =   —————

        L.C.M              7x  

  R. Mult. • R. Num.      40 • 7

  ——————————————————  =   ——————

        L.C.M               7x  

Adding fractions that have a common denominator :

3.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

4 • x - (40 • 7)     4x - 280

————————————————  =  ————————

       7x               7x  

STEP

4

:

Pulling out like terms :

4.1     Pull out like factors :

  4x - 280  =   4 • (x - 70)

Equation at the end of step

4

:

 4 • (x - 70)

 ————————————  = 0

      7x    

STEP

5

:

When a fraction equals zero :

5.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 4•(x-70)

 ———————— • 7x = 0 • 7x

    7x  

Now, on the left hand side, the  7x  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  4  •  (x-70)  = 0

Equations which are never true:

5.2      Solve :    4   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

5.3      Solve  :    x-70 = 0

Add  70  to both sides of the equation :

                     x = 70

One solution was found :

x = 70

Answer:

  no solution

Step-by-step explanation:

A graphing calculator shows the left-side expression is never equal to the right-side expression for any real-number value of A.

The equation is not an identity, and has no solution.

__

Additional comment

By subtracting the right-side expression from the left-side expression, we get an equation of the form f(A)=0. Any solutions will be x-intercepts of the graph. The graph for this equation never comes close to crossing the x-axis.

Answer:

x = 4, 1/4

solving steps

[tex]\sf \rightarrow x + \dfrac{1}{x}=4\dfrac{1}{4}[/tex]

make the denominators same

[tex]\sf \rightarrow \dfrac{x(x)}{x} + \dfrac{1}{x}=4\dfrac{1}{4}[/tex]

simplify the following

[tex]\sf \rightarrow \dfrac{x^2}{x} + \dfrac{1}{x}=\dfrac{17}{4}[/tex]

join both fractions together

[tex]\sf \rightarrow \dfrac{x^2+1}{x}=\dfrac{17}{4}[/tex]

cross multiply

[tex]\sf \rightarrow 4(x^2+1)=17(x)[/tex]

simplify

[tex]\sf \rightarrow 4x^2-17(x)+4=0[/tex]

completing square

[tex]\sf \rightarrow 4x^2-16(x)-x+4=0[/tex]

factor

[tex]\sf \rightarrow 4x(x-4)-1(x-4)=0[/tex]

group the variables

[tex]\sf \rightarrow (4x-1)(x-4)=0[/tex]

simplify

[tex]\sf \rightarrow (x-4)=0, \ (4x-1) =0[/tex]

final answer

[tex]\sf \rightarrow x=4, \ x =\dfrac{1}{4}[/tex]

Answer:

[tex]\boxed{x = \dfrac{1}{4}}[/tex] and [tex]\boxed{x = 4}[/tex]

Step-by-step explanation:

Given equation:

[tex]x + \dfrac{1}{x} = 4\dfrac{1}{4}[/tex]

Step-1: Convert the mixed fraction on the R.H.S into improper fraction

[tex]x + \dfrac{1}{x} = 4\dfrac{1}{4}[/tex]

[tex]x + \dfrac{1}{x} = \dfrac{4 \times4 + 1}{4}[/tex]

[tex]x + \dfrac{1}{x} = \dfrac{16 + 1}{4}[/tex]

[tex]x + \dfrac{1}{x} = \dfrac{17}{4}[/tex]

Step-2: Make common denominators on the L.H.S:

[tex]x + \dfrac{1}{x} = \dfrac{17}{4}[/tex]

[tex]\dfrac{x^{2} }{x} + \dfrac{1}{x} = \dfrac{17}{4}[/tex]

Step-3: Combine the denominators on the L.H.S

[tex]\dfrac{x^{2} }{x} + \dfrac{1}{x} = \dfrac{17}{4}[/tex]

[tex]\dfrac{x^{2} +1}{x} = \dfrac{17}{4}[/tex]

Step-4: Use cross multiplication

[tex]\dfrac{x^{2} +1}{x} = \dfrac{17}{4}[/tex]

[tex]x^{2} +1} = \dfrac{17x}{4}[/tex]

[tex]4(x^{2} +1}) = {17x}[/tex]

Step-5: Simplify the distributive property

[tex]4(x^{2} +1}) = {17x}[/tex]

[tex]4x^{2} +4} = {17x}[/tex]

[tex]-17x + 4x^{2} +4} = 0[/tex]

Step-6: Change "-17x" to "-16x - x" as it is equivalent

[tex]-17x + 4x^{2} +4} = 0[/tex]

[tex](-16x - x) + 4x^{2} +4} = 0[/tex]

Step-7: Factor the common terms

[tex](-16x - x) + 4x^{2} +4} = 0[/tex]

[tex]-16x - x + 4x^{2} +4} = 0[/tex]

[tex]4x(-4 + x) - 1(x - 4) = 0[/tex]

Step-8: Group the terms

[tex]4x(-4 + x) - 1(x - 4) = 0[/tex]

[tex](x - 4)(4x - 1) = 0[/tex]

Step-9i: Use cross multiplication for (x - 4)

[tex](x - 4)(4x - 1) = 0[/tex]

[tex]x - 4 = \dfrac{0}{4x - 1 } = 0[/tex]

Step-9ii: Use cross multiplication for (4x - 1)

[tex](x - 4)(4x - 1) = 0[/tex]

[tex]4x - 1 = \dfrac{0}{x - 4} = 0[/tex]

Thus [tex]x - 4 = 0[/tex] and [tex]4x - 1 = 0[/tex].

Step-10: Simplify both equations

[tex]4x - 1 = 0[/tex]                  [tex]x - 4 = 0[/tex]

[tex]4x = 0 + 1[/tex]                  [tex]x = 0 + 4[/tex]

[tex]4x = 1[/tex]                          [tex]\boxed{x = 4}[/tex]

[tex]\boxed{x = \dfrac{1}{4}}[/tex]

Answer:

x = 25

Step-by-step explanation:

This is just algebra involved with geometry!

Your objective is to solve for x.

The line dividing the 2x-5 and x+20 is the bisector

A bisector means the two angles have to be equal!

Your objective is to solve for x.

The line dividing the 2x-5 and x+20 is the bisector

A bisector means the two angles have to be equal!

2x-5=x+20 should be the equation!

Subtract x from both sides

x-5=20

Now add 5 to both sides

x=20+5

x=25

Now you need to plug the answers in!

50-5 for 2x-5

25+20 for x+20

45+45 = 90      

I don't really know about the 125 but if that was excluded then this is it ^^^

The value of x is,

⇒ x = 33.3°

An angle is a combination of two rays (half-lines) with a common endpoint. The latter is known as the vertex of the angle and the rays as the sides, sometimes as the legs and sometimes the arms of the angle.

Given that;

The value of total angle is, 125°

Hence, By definition of angles we get;

⇒ (2x - 5) + (x + 20) = 125°

⇒ 3x + 15 = 125°

⇒ 3x = 125 - 15

⇒ 3x = 110

⇒ x = 33.3°

Thus, The value of x is,

⇒ x = 33.3°

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The different recital programs that are possible is 80,730 ways

Permutation has to do with arrangement while combination has to do with the selection.

According to the question, a pianist plans to play 5 pieces at a recital from her repertoire of 27 pieces, this shows that he can select the 5 pieces in any form.

The number of ways this can be done is given as:
[tex]27C_5=\frac{27!}{(27-5)!5!}\\ 27C_5=80,730[/tex]

Hence the different recital programs that are possible is 80,730 ways

Learn more on combination here: https://brainly.com/question/11732255

Answer:

30.125

the answer is 30.125 so that is the answer of this question

Let

[tex]S_n = \displaystyle \sum_{k=0}^n r^k = 1 + r + r^2 + \cdots + r^n[/tex]

where we assume |r| < 1. Multiplying on both sides by r gives

[tex]r S_n = \displaystyle \sum_{k=0}^n r^{k+1} = r + r^2 + r^3 + \cdots + r^{n+1}[/tex]

and subtracting this from [tex]S_n[/tex] gives

[tex](1 - r) S_n = 1 - r^{n+1} \implies S_n = \dfrac{1 - r^{n+1}}{1 - r}[/tex]

As n → ∞, the exponential term will converge to 0, and the partial sums [tex]S_n[/tex] will converge to

[tex]\displaystyle \lim_{n\to\infty} S_n = \dfrac1{1-r}[/tex]

Now, we're given

[tex]a + ar + ar^2 + \cdots = 15 \implies 1 + r + r^2 + \cdots = \dfrac{15}a[/tex]

[tex]a^2 + a^2r^2 + a^2r^4 + \cdots = 150 \implies 1 + r^2 + r^4 + \cdots = \dfrac{150}{a^2}[/tex]

We must have |r| < 1 since both sums converge, so

[tex]\dfrac{15}a = \dfrac1{1-r}[/tex]

[tex]\dfrac{150}{a^2} = \dfrac1{1-r^2}[/tex]

Solving for r by substitution, we have

[tex]\dfrac{15}a = \dfrac1{1-r} \implies a = 15(1-r)[/tex]

[tex]\dfrac{150}{225(1-r)^2} = \dfrac1{1-r^2}[/tex]

Recalling the difference of squares identity, we have

[tex]\dfrac2{3(1-r)^2} = \dfrac1{(1-r)(1+r)}[/tex]

We've already confirmed r ≠ 1, so we can simplify this to

[tex]\dfrac2{3(1-r)} = \dfrac1{1+r} \implies \dfrac{1-r}{1+r} = \dfrac23 \implies r = \dfrac15[/tex]

It follows that

[tex]\dfrac a{1-r} = \dfrac a{1-\frac15} = 15 \implies a = 12[/tex]

and so the sum we want is

[tex]ar^3 + ar^4 + ar^6 + \cdots = 15 - a - ar - ar^2 = \boxed{\dfrac3{25}}[/tex]

which doesn't appear to be either of the given answer choices. Are you sure there isn't a typo somewhere?

Answer:

C. -3/7

Step-by-step explanation:

Irrational numbers: cannot be written as a fraction

Rational numbers: can be written as a fraction

The only option that contains a fraction, is C

Hope this helps!

Option C

Hope it helps.

Do comment if you have any query.

       Upon asking I got the rest of the information needed to answer this question.

-> Which one becomes a repeating decimal?

Your answer is D. 1/9.

       1/9 = 0.111111111111111111111111111111111 ... or 0.1 repeating. It can be written with a line over the 1 asyou can see in the attached.

       This means that D is the answer to your question.

The sample size for part (a) is 2401, and the sample size for part (b) is 1417 if the margin of error is no more than two percentage points and use a confidence level of 95%

It is defined as an error that gives an idea about the percentage of errors that exist in the real statistical data.

The formula for finding the MOE:

[tex]\rm MOE= Z{score}\times \frac{s}{\sqrt{n} }[/tex]

Where  Z_{score} is the z score at the confidence interval

             s is the standard deviation

             n is the number of samples.

We have:

MOE = 2% = 0.02 and

α = 1-0.95 = 0.05

Let's assume the value of p = 0.5, and q = 0.5

From the table:

Z_(0.05/2) = Z_(0.025) = 1.96

[tex]\rm n = 0.5\times0.5\frac{1.96^2}{0.02^2}[/tex]

n = 2401

For part (b):

p = 18% = 0.18, and q = 0.82

[tex]\rm n = 0.18\times0.82\frac{1.96^2}{0.02^2}[/tex]

n = 1417.5 = 1417

Thus, the sample size for part (a) is 2401, and the sample size for part (b) is 1417 if the margin of error is no more than two percentage points and use a confidence level of 95%

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Answer:

1/6

Step-by-step explanation:

it is like a cube just with slightly different numbers on each side. but the probabilty structure is still the same.

we have 6 different possible outcomes, all with the same basic probabilty (as every field on the spinner is seemingly of the same size as the others).

and we desire one of these possible outcomes (6).

so the probabilty to get 6 is still 1/6 (1 desired over 6 possible outcomes).

Answer:

Answer is {C}

Step-by-step explanation:

Answer:

97.31 [tex]m^2[/tex]

Step-by-step explanation:

The area of the octagon is:

[tex]\frac{8 * 5.3 * 2.65\sqrt{3} }{2}[/tex] ~97.31 m^2

Answer:

y = 5

Step-by-step explanation:

y + 6 = –3y + 26

y + 3y + 6 = 26

4y + 6 = 26

4y = 26 - 6

4y = 20

y = 5

I hope this helps!

Answer:

1432.25

Step-by-step explanation:

8.50 x 40 = 340

340 x  4 = 1360

half of 8.50 is 4.25

4.25 x 10 = 42.5

4.25 x 5 = 21.25

4.25 x 2 = 8.5

add

1360 + 42.5 + 21.25 + 8.5  = 1432.25

i hope i did my math right, good luck mate

Answer:

The missing value is 6a

Step-by-step explanation:

Given:

[tex]\displaystyle \large{A(-3a,b)}\\\displaystyle \large{B(3a,b)}[/tex]

Find:

Missing Value

Distance Formula:

[tex]\displaystyle \large{\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}[/tex]

Determine:

[tex]\displaystyle \large{(x_2,y_2)=(3a,b)}\\\displaystyle \large{(x_1,y_1)=(-3a,b)}[/tex]

Input given information above in the formula:

[tex]\displaystyle \large{AB=\sqrt{(3a-(-3a))^2+(b-b)^2}}\\\displaystyle \large{AB=\sqrt{(3a+3a)^2+(0)^2}}\\\displaystyle \large{AB=\sqrt{(6a)^2}}\\\displaystyle \large{AB=6a}[/tex]

The length is 6a but since we want to find the value in the square root then the answer is still 6a

133, 117, 152, 127, 168, 146, 174.

range.

first arrange the numbers in order, which gives you:

= 117, 127, 133, 146, 152, 168, 174

then subtract the lowest number from the highest, which gives you:

174 - 117

= 57

range= 57.

Answer:

Camille can make 6 cards and will have 2 ribbons left

Step-by-step explanation:

Answer:

1030 [tex]yd^{2}[/tex]

Step-by-step explanation:

split it into 2 different rectangular prisms

first one is 27 yd by 8 yd by 9 yd

second is 10yd by 8 yd by 12 yd

Answer:

1494 [yd²].

Step-by-step explanation:

1) the required area can be calculated as (see the attached picture):
A=A1+A2+A3+A4+A5+A6+2*A7;

2) finally,

A=9*8+17*8+8*12+10*8+(12+9)*8+27*8+2*(27*9+12*10);

A=1494 [yd²].

Note, the suggested solution is not the shortest one.

Answer:

The axis of symmetry is x=2

Step-by-step explanation:

Answer:

24x-7

Step-by-step explanation:

First, we distribute the 2x.

2x * 8 = 16x

2x * 4 = 8x

16x+8x-7

24x-7

This is the final result / your answer :

24x-7

Answer:

24x-7

Step-by-step explanation:

1. Add 8 and 4, this leaves us with 2x(12)-7

2. Multiply 12 and 2. This leaves us with 24x-7