In order for clouds to form, what must happen first?

Answer:

i feel like 3 not too sure tho

Answer:

Rotation frequency is 0.377 hertz.

Explanation:

After a careful reading of statement, we need to apply the concept of radial acceleration due to uniform circular motion, whose formula is:

[tex]a_{r} = \omega^{2}\cdot L[/tex] (Eq. 1)

Where:

[tex]a_{r}[/tex] - Radial acceleration, measured in meters per square second.

[tex]\omega[/tex] - Angular velocity, measured in radians per second.

[tex]L[/tex] - Length of the beam, measured in meters.

Now we clear the angular velocity within:

[tex]\omega = \sqrt{\frac{a_{r}}{L} }[/tex]

If [tex]a_{r} = 29.9\,\frac{m}{s^{2}}[/tex] and [tex]L = 5.33\,m[/tex], the angular velocity is:

[tex]\omega = \sqrt{\frac{29.9\,\frac{m}{s^{2}} }{5.33\,m} }[/tex]

[tex]\omega \approx 2.368\,\frac{rad}{s}[/tex]

The frequency is the number of revolutions done by device per second and can be found by using this expression:

[tex]f = \frac{\omega}{2\pi}[/tex] (Eq. 2)

Where [tex]f[/tex] is the frequency, measured in hertz.

If we know that [tex]\omega \approx 2.368\,\frac{rad}{s}[/tex], then rotation frequency is:

[tex]f = \frac{2.368\,\frac{rad}{s} }{2\pi}[/tex]

[tex]f = 0.377\,hz[/tex]

Rotation frequency is 0.377 hertz.

Answer:   Mechanical energy is the energy that is possessed by an object due to its motion or due to its position.

(The energy acquired by the objects upon which work is done)

Currently, the magnetic south pole lies about ten degrees distant from the geographic north pole, and sits in the Arctic Ocean north of Alaska. The north end on a compass therefore currently points roughly towards Alaska and not exactly towards geographic north.

Complete question:

A scallop forces open its shell with an elastic material called abductin, whose Young's modulus is about 2.0×10⁶ N/m2 .

If this piece of abductin is 3.1 mm thick and has a cross-sectional area of 0.49 cm2 , how much potential energy does it store when compressed 1.5 mm ?

Answer:

The elastic potential energy of the material is 0.036 J

Explanation:

Given;

Young's modulus, E = 2.0×10⁶ N/m²

Thickness of the abductin, l = 3.1 mm = 0.0031 m

compression of the abductin, x = 1.5 mm = 0.0015 m

area, A = 0.49 cm² = 0.49 x 10⁻⁴ m²

Young's modulus for elastic material is given by;

[tex]E = \frac{stress}{strain} = \frac{Fl}{Ax} \\\\ E = \frac{F}{x}*\frac{l}{A}\\\\ E = k*\frac{l}{A}\\\\k = \frac{AE}{l}\\\\k = \frac{(0.49 x10^{-4})(2*10^6)}{0.0031}\\\\ k = 31,612.9 \ N/m[/tex]

The elastic potential energy of the material is given by;

U = ¹/₂kx²

U = ¹/₂(31,612.9)(0.0015)²

U = 0.036 J

Therefore, the elastic potential energy of the material is 0.036 J

The cyclist's acceleration to the nearest tenth is: C. 2.7 [tex]m/s^2[/tex].

Given the following data:

To find the cyclist's acceleration to the nearest tenth:

Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.

Mathematically, acceleration is given by the formula;

[tex]A = \frac{V - U}{t}[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]A = \frac{12.5\; - \;0}{4.5} \\\\A = \frac{12.5}{4.5}[/tex]

Acceleration, A = 2.7  [tex]m/s^2[/tex]

Therefore, the cyclist's acceleration to the nearest tenth is 2.7 [tex]m/s^2[/tex].

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Answer:

Final velocity (v) = 5.148 m/s (Approx)

Explanation:

Given:

Initial velocity (u) = 3.05 m/s

Acceleration (a) = 2.82 m/s²

Displacement (s) = 18.4 m

Find:

Final velocity (v)

Computation:

v² = u² + 2as

v² = (3.05)² + 2(2.82)(3.05)

v² = 9.3025 + 17.202

v² = 26.5045

v = 5.148 m/s (Approx)

light, water, carbon dioxide

Explanation:

c02 , h20 and light

Let's see what to do buddy.....

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[tex]Acceleration = 4 \: \: \frac{mile}{ h } p( min ) [/tex]

Thus ;

The speed increases 4 units per minute.

The train has a speed of 25 mph now.

After a minute it has a speed of 29 mph.

After a minute it has a speed of 33 mph.

After a minute it has a speed of 37 mph.

Look ; 4 units per minute means 4 units per 60 seconds, thus the speed increases 1 unit per 15 seconds .

If the speed wants to increasing from 37 to 40 , needs 3 × 15 seconds = 45 sec.

So we have : 1 min + 1 min + 1 min + 45 sec .

3 minutes and 45 seconds or 225 seconds need to the speed increasing from 25 mph to 40 mph.

_________________________________

And we're done.....♥️♥️♥️♥️♥️

Answer:

ω = 15275.25 rad/s

Explanation:

Given that,

Radial acceleration of an ultracentrifuge is, [tex]a=5\times 10^5g[/tex]

Distance from the axis, r = 2.1 cm = 0.021 m

g is the free-fall acceleration such that g = 9.8 m/s²

We need to find the angular speed of an ultracentrifuge. The formula that is used to find the angular speed is given by formula as follows :

[tex]a=r\omega^2[/tex]

Putting all the values,

[tex]\omega=\sqrt{\dfrac{a}{r}} \\\\\omega=\sqrt{\dfrac{5\times 10^5\times 9.8}{0.021}} \\\\\omega=15275.25\ rad/s[/tex]

So, the required angular speed, ω, of an ultracentrifuge is 15275.25 rad/s.

Answer:

The viscosity is  [tex]\eta  = 0.76243 \ kg/ m \cdot s [/tex]  

Explanation:

From the question we are told that

  The  density is  [tex]\rho  =  7.80 *10^{3} \  kg/m^3[/tex]

  The diameter is  [tex]d =  3.0 \  mm =0.003 \ m[/tex]

    The  time taken is  [tex]t  =  12 \ s[/tex]

   The  distance covered is  [tex]d =  0.60 \ m[/tex]

Generally the velocity of the ball is  

      [tex]v  =  \frac{d}{t}[/tex]

=>    [tex]v  =  \frac{0.60}{12}[/tex]

=>    [tex]v  =  0.05 \ m/s [/tex]

Generally the mass of the steel ball is  

    [tex]m  =  \rho  *  V[/tex]

Here  V  is the volume and this is mathematically represented as

     [tex]V  =  \frac{4}{3} *  \pi  * [\frac{d}{2}  ]^3[/tex]

=>    [tex]V  =  \frac{4}{3} *  3.142  * [\frac{0.003}{2}  ]^3[/tex]

=>      [tex]V  = 1.414 *10^{-8} \  m^3[/tex]

So

     [tex]m  = 7.80 *10^{3}  *   1.414 *10^{-8}[/tex]

     [tex]m  = 0.00011 \  kg [/tex]

Generally the viscosity is mathematically represented as  

     [tex]\eta  =  \frac{m  *  g}{6\pi  *  r  *  v }[/tex]

Here  r is the radius represented as

      [tex]r =  \frac{d}{2}[/tex]

=>   [tex]r =  \frac{0.003}{2}[/tex]

[tex]r =  0.0015  \  m [/tex]

So

  [tex]\eta  =  \frac{0.00011  *  9.8}{6 *  3.142   * 0.0015  * 0.05 }[/tex]    

=> [tex]\eta  = 0.76243 \ kg/ m \cdot s [/tex]

Answer:

The acceleration will decrease due to less force acting on the object.

Explanation:

Answer:

The height of the  object is 5007.4 miles.

Explanation:

Given that,

Weight of object = 200 lb

We need to calculate the value of [tex]Gmm_{e}[/tex]

Using formula of gravitational force

[tex]F=\dfrac{Gmm_{e}}{r^2}[/tex]

Put the value into the formula

[tex]200=\dfrac{Gmm_{e}}{(3958.756)^2}[/tex]

[tex]200\times(3958.756)^2=Gmm_{e}[/tex]

[tex]Gmm_{e}=3.134\times10^{9}[/tex]

We need to calculate the height of the  object

Using formula of gravitational force

[tex]F=\dfrac{Gmm_{e}}{r^2}[/tex]

Put the value into the formula

[tex]125=\dfrac{200\times(3958.756)^2}{r^2}[/tex]

[tex]r^2=\dfrac{200\times(3958.756)^2}{125}[/tex]

[tex]r^2=25074798.5[/tex]

[tex]r=\sqrt{25074798.5}[/tex]

[tex]r=5007.4\ miles[/tex]

Hence. The height of the  object is 5007.4 miles.

Given parameters:

Mass given  = 1kg

Unknown:

Weight of the body at pole and equator = ?

Solution:

Both locations are on the surface of the earth. Generally, we take 9.8m/s² as the acceleration due to gravity on the earth.  

       Weight  = mass x acceleration due to gravity

But little disparity occurs in the value of acceleration due to gravity from the pole to equator. This is due to equatorial bulge.

   At the equator  , 9.780 m/s²

               pole  9.832 m/s²

Weight at equator = 1 x 9.780  = 9.78N

Weight at the pole = 1  x 9.832 = 9.832N  

Answer:

Explanation:

given:

distance = 270 km

speed = 85 km/h

find:

how long does it take to get into his audition in hours?

solution:

velocity = distance / time

85 km/h =  270 km  

                      t

85 (t) = 270

t = 270 / 85

t = 3.176 hours

Answer:

The heat will travel through the wire to your hand.

Explanation:

Thats the one that makes the most sense.

Answer:

[tex]B=1.61\times 10^{-4}\ T[/tex]

Explanation:

The attached figure shows the path followed by an electron in the semicircular path from A to B.

Velocity of the electron is, [tex]v=1.42\times 10^6\ m/s[/tex]

It can be seen from the figure that the radius of thenpath, r = 5 cm or 0.05 m

The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,

[tex]Bqv=\dfrac{mv^2}{r}[/tex]

B is the magnitude of the magnetic field

[tex]B=\dfrac{mv}{rq}\\\\\text{Putting all the values}\\\\B=\dfrac{9.1\times 10^{-31}\times 1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}\\\\B=1.61\times 10^{-4}\ T[/tex]

So, the magnitude of the magnetic field is [tex]1.61\times 10^{-4}\ T[/tex].

The magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B will be  [tex]B=1.61\times 10^-{4]\ T[/tex]

The magnetic field is defined as when the current passes through the wire, then the magnetic field is generated around the wire in a circular pattern.

The attached figure shows the path followed by an electron in the semicircular path from A to B.

The velocity of the electron is, [tex]v=1.42\times 10^6\ \frac{m}{s}[/tex]

It can be seen from the figure that the radius of then path, r = 5 cm or 0.05 m

The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,

[tex]Bqv=\dfrac{mv^2}{r}[/tex]

B is the magnitude of the magnetic field

[tex]B=\dfrac{mv}{rq}[/tex]

[tex]B=\dfrac{9.1\times 10^{-31}\times1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}[/tex]

[tex]B=1.61\times 10^{-4}\ T[/tex]

So, the magnitude of the magnetic field is  [tex]B=1.61\times 10^-{4]\ T[/tex]

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Answer:

neutron beta particle and proton (last option in the list)

Explanation:

The neutron beta particle and proton inside a neutron is a clear example of a negative particle (beta particle) and a positive particle (proton) experiencing electromagnetic force (attraction between positive and negative charges) at a very short distance.

Answer:

I'm pretty sure it's the flashlight because electromagnetic force produces electricity.

Answer:

Explanation:

Ideal gas equation- The volume (V) occupied by the n moles of any gas has pressure(P) and temperature (T) Kelvin,

the relationship for these variables PV=nRT where R gas constant is called the ideal gas law

Derivation of the Ideal Gas Equation

Let us consider the pressure exerted by the gas to be ‘p,’

The volume of the gas be – ‘v’  

Temperature be – T  

n – be the number of moles of gas

Universal gas constant – R

According to Boyle’s Law,

it constant n & T, the volume bears an inverse relation with the pressure exerted by a gas.

i.e. v∝1p ………………………………(i)

According to Charles’ Law,

When p & n are constant, the volume of a gas bears a direct relation with the Temperature.

i.e. v∝T ………………………………(ii)

According to Avogadro’s Law,

When p & T are constant, then the volume of a gas bears a direct relation with the number of moles of gas.

i.e. v∝n ………………………………(iii)

Combining all the three equations, we have-

v∝nTp

or pv=nRT

where R is the Universal gas constant, which has a value of 8.314 J/mol-K

Answer:

The question has too wide of a focus, as though all situations can be studied at once

Explanation:

I took the test

Answer:

The question has too wide of a focus, as though all situations can be studied at once

Explanation:

i took ed test

Answer:

D. all of the above

Explanation:

hope it helps

moves farther in the same amount of time.

Explanation:

based on my answer......

we supposed to assume that both cars are equal except for speed. So they would have the same mass.....

Anyway, the question doesn't tell you anything about weight or size, so you can't tell from the information given which has more mass.

But the very definition of 'faster' is 'moves farther in the same amount of time'.

Hope this helps

Answer:

They both moves at the same speed

Explanation:

hope it works

Answer:

its temperature stays constant

Explanation:

Answer: 46 meters

Explanation:

The maximum height reached by the base ball is 45.9 meters.

To find the maximum height the given values are,

Mass = 25 Kg

speed v = 30 meters per second.

As the ball goes up, it acts due to the gravity.

The gravity slows an upward-moving object,

Acceleration due to gravity = 9.8 m/s every second,

the baseball reaches its greatest height in (30/9.8) = 3.06 seconds.

At that instant, its speed is zero.

The baseball's average speed from toss to peak is

            (1/2) (30 + 0)  =  15 m/s .

The baseball average speed = 15 m/s

And the time for greatest height = 3.06 seconds.

Substituting the given values,

The ball rises can be calculated as

 (15 x 3.06)  =  45.9 meters.

Thus, the baseball reached the maximum height approximately is 45.9 meters.

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