Given parameters:
Mass of block = 5kg
Coefficient of friction = 0.5
g = 10m/s²
Unknown
Minimum force F required to hold the block =?
Solution:
Frictional force is a force that opposes motion.
The minimum force required to hold the block to the wall is the frictional force.
Frictional force = uN
Where u is coefficient of friction
N is the normal force
N = mg
where m is the mass of the body
g is the acceleration due to gravity
So,
Frictional force = umg
= 0.5 x 5 x 10
= 25N
The force required here is 25N
Explain how hypothesis are related to theories
A hypothesis is a prediction made prior to conducting research. It is constructed in such a way that it can be tested to see if it is true. A theory is a principle developed to explain what has already been observed in data.
What is hypothesis?A hypothesis is an explanation proposed for a phenomenon. The scientific method requires that a hypothesis be testable in order for it to be considered a scientific hypothesis.
Scientists typically base scientific hypotheses on previous observations that cannot be adequately explained by existing scientific theories.
Theories are frequently used by scientists, researchers, and psychologists to guide their research and develop hypotheses.
A theory must be supported by evidence, whereas a hypothesis guides research and aids in the collection of evidence.
A theory is a tested, well-substantiated, unifying explanation for a set of verified, proven factors in science. A theory is always supported by evidence, whereas a hypothesis is only a possible outcome that can be tested and falsified.
Thus, this way one can concluded that the hypothesis and theories are related.
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You are sitting still at a stoplight. The light turns green and you
accelerate to 35 m/s and it takes you 3.2 sec. What is your acceleration? *
Answer:
Your accleration would be 3.2 seconds because it takes you that long to reach 35 miles per hour.
Explanation:
I really hopes this helps.
A car is at velocity of 20 km/h. If the car traveled 120 km in 3 hours at constant acceleration, what is its final velocity?
The derivative of a position function is a velocity function. The derivative of a velocity function is an acceleration function. A particle moves along a straight line. The distance of the particle from the starting point at time t is given by the function: s=t5−6t4 Find the value of t (other than 0 ) at which the acceleration is equal to zero. 6
Answer:
3.6secsExplanation:
Given the distance of the particle from the starting point at time t is given by the function: s=t⁵−6t⁴
velocity v(t) = ds/dt
[tex]v(t) = 5t^{5-1}-4(6)t^{4-1}\\v(t) = 5t^4-24t^3\\[/tex]
Next is to get the acceleration function:
[tex]a(t) = 4(5)t^{4-1}-3(24)t^{3-1}\\a(t) = 20t^3-72t^2[/tex]
Next is to get the value of t at which the acceleration is equal to zero
[tex]a(t) = 20t^3-72t^2\\0 = 20t^3-72t^2\\20t^3-72t^2 = 0\\t^2(20t-72) = 0\\t^2 =0 \ and \ 20t-72 = 0[/tex]
Since t ≠ 0, hence;
20t -72 = 0
20t = 72
t = 72/20
t = 3.6secs
Hence the value of t (other than 0 ) at which the acceleration is equal to zero is 3.6secs
a car is moving at 2 m/s when it accelerates at 4 m/s^2 for 2 seconds. His new velocity is?
Answer:
10m/s
Explanation:
solution:
a= v-u / t
or,4= v-2 / 2
or,8= v-2
or,8+2= v
or,v = 10
You may have noticed runaway truck lanes while driving in the mountains. These gravel-filled lanes are designed to stop trucks that have lost their brakes on mountain grades. Typically, such a lane is horizontal (if possible) and about 36.0 m36.0 m long. Think of the ground as exerting a frictional drag force on the truck. A truck enters a typical runaway lane with a speed of 50.5 mph50.5 mph ( 22.6 m/s22.6 m/s ). Use the work-energy theorem to find the minimum coefficient of kinetic friction between the truck and the lane to be able to stop the truck.
Answer:
The coefficient of kinetic friction [tex]\mu_k = 0.724[/tex]
Explanation:
From the question we are told that
The length of the lane is [tex]l = 36.0 \ m[/tex]
The speed of the truck is [tex]v = 22.6\ m/s[/tex]
Generally from the work-energy theorem we have that
[tex]\Delta KE = N * \mu_k * l[/tex]
Here N is the normal force acting on the truck which is mathematically represented as
[tex]\Delta KE[/tex] is the change in kinetic energy which is mathematically represented as
[tex]\Delta KE = \frac{1}{2} * m * v^2 [/tex]
=> [tex]\Delta KE = 0.5 * m * 22.6^2 [/tex]
=> [tex]\Delta KE = 255.38m [/tex]
[tex] 255.38m = m * 9.8 * \mu_k * 36.0 [/tex]
=> [tex] 255.38 = 352.8 * \mu_k [/tex]
=> [tex]\mu_k = 0.724[/tex]
I forgot how to breath
Answer:
1-steal an inhaler 2-use it 3-your good
orrrr
1-swallow air(preferably air from space)
Answer:
then breath
Explanation:
15) A 1720 kg car accelerates at a rate of 3.0 m/s2. How much force is the car's engine producing? (use the formula F=ma
Answer:
The answer is 5160 NExplanation:
To find the force acting on an object given it's mass and acceleration we use the formula
Force = mass × accelerationFrom the question
mass = 1720 kg
acceleration = 3.0 m/s²
We have
Force = 1720 × 3
We have the final answer as
5160 NHope this helps you
Use the drop-down menus to order the steps for writing chemical formulas.
- Identify the elements in the compound.
- Write the chemical symbols in the order shown in the name.
- Use the periodic table to find the symbols of elements in the compound.
- Use prefixes to determine the number of each type of atom in the compound.
- Use subscripts to show the number of each type of atom in the compound.
Answer:
1,3,2,4,5
Explanation:
Because I had right
Following these steps will help write chemical formulas by identifying the elements, finding their symbols, arranging them in order, and determining the appropriate prefixes representing them with subscripts.
Here is the correct order for writing chemical formulas :
1) Identify the elements in the compound.
2) Use the periodic table to find the symbols of elements in the compound.
3) Write the chemical symbols in the order shown in the name.
4) Use prefixes to determine the number of each type of atom in the compound.
5) Use subscripts to show the number of each type of atom in the compound.
Therefore, Following these steps will help you correctly write chemical formulas by identifying the elements, finding their symbols, arranging them in the correct order, determining the appropriate prefixes for the number of atoms, and representing them with subscripts.
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Why does Chelsea see sparks as she removes her clothes from the clothes dryer?
conduction
induction
static discharge
static electricity
Answer:
Your answer is static discharge
Explanation:
Your negatively charged hand repels electrons in the metal, so the electrons move to the other side of the knocker. ... This allows electrons to suddenly flow from your hand to the knocker. The sudden flow of electrons is static discharge. The discharge of electrons is the spark you see and the shock you feel. I hope this helps, ( the other answer said static electricity which is wrong.) :)
Answer:
C
Explanation:
Convert 0.0000505 nanometers into scientific notation
g Katie(50 kg) tries the water slide at the county fair. The starting point is 10.0 m above the ground. She starts from the top of the slide at rest. Assuming zero frictional lost, how fast will Katie be traveling at the bottom
Answer:
v= 14 m/s
Explanation:
Assuming no friction losses, the total mechanical energy must be conserved.At the top of the slide, all the energy is gravitational potential energy, as she starts at rest.At the bottom of the slide, if we choose this level as our zero reference level for the gravitational potential energy, all the energy will be purely kinetic.So, we can write the following equality:[tex]\Delta K + \Delta U =0[/tex]⇒ΔK = -ΔU
⇒ [tex](\frac{1}{2}*m*v^{2}-0) =-(0- m*g*h) = m*g*h[/tex]
Rearranging terms and simplifying we can solve for v, as follows:[tex]v_{f} = \sqrt{2*g*h} =\sqrt{2*9.8m/s2*10.0m} = 14 m/s[/tex]
Katie's speed at the bottom of the slide will be 14 m/s.Newton's Law of Gravitation says that the magnitude F of the force exerted by a body of mass m on a body of mass M isF = GmMr2where G is the gravitational constant and r is the distance between the bodies.(a) Find dF/dr.dFdr = What is the meaning of dF/dr?dF/dr represents the rate of change of the distance between the bodies with respect to the force.dF/dr represents the rate of change of the mass with respect to the force. dF/dr represents the rate of change of the force with respect to the distance between the bodies.dF/dr represents the amount of force per distance.dF/dr represents the rate of change of the mass with respect to the distance between the bodies.What does the minus sign indicate?The minus sign indicates that the force between the bodies is decreasing.The minus sign indicates that the bodies are being forced in the negative direction. The minus sign indicates that as the distance between the bodies increases, the magnitude of the force decreases.The minus sign indicates that as the distance between the bodies decreases, the magnitude of the force remains constant.The minus sign indicates that as the distance between the bodies increases, the magnitude of the force increases.
Answer:
Explanation:
Mars has two moons, Phobos and Deimos. Phobos orbits Mars at a distance of 9380 km from Mars's center, while Deimos orbits at 23,500 km
from the center.
What is the ratio of the orbital period of Deimos to that of Phobos?
Answer:
The ratio is [tex]\frac{T_1}{T_2} = 3.965 [/tex]
Explanation:
From the question we are told that
The radius of Phobos orbit is R_2 = 9380 km
The radius of Deimos orbit is [tex]R_1 = 23500 \ km[/tex]
Generally from Kepler's third law
[tex]T^2 = \frac{ 4 * \pi^2 * R^3}{G * M }[/tex]
Here M is the mass of Mars which is constant
G is the gravitational constant
So we see that [tex]\frac{ 4 * \pi^2 }{G * M } = constant[/tex]
[tex]T^2 = R^3 * constant [/tex]
=> [tex][\frac{T_1}{T_2} ]^2 = [\frac{R_1}{R_2} ]^3[/tex]
Here [tex]T_1[/tex] is the period of Deimos
and [tex]T_1[/tex] is the period of Phobos
So
[tex][\frac{T_1}{T_2} ] = [\frac{R_1}{R_2} ]^{\frac{3}{2}}[/tex]
=> [tex]\frac{T_1}{T_2} = [\frac{23500 }{9380} ]^{\frac{3}{2}}][/tex]
=> [tex]\frac{T_1}{T_2} = 3.965 [/tex]
The given values are:
Radius, r = 23500 kmDistance = 9380 kmWe know the formula,
→ [tex]v = \frac{2 \pi r}{T}[/tex]
then,
→ [tex]\sqrt{\frac{GM_{mars}}{r} } =\frac{2 \pi r}{T}[/tex]
or,
→ [tex]T = 2 \pi \sqrt{\frac{r^3}{GM_{mars}} }[/tex]
Now,
The orbital period of Deimos will be:
[tex]= 2 \pi \sqrt{\frac{(23500)^3}{GM_{mars}} }[/tex]
The orbital period of Phobos will be:
[tex]= 2 \pi \sqrt{\frac{(9380)^3}{GM_{mars}} }[/tex]
hence,
The ratio will be:
→ [tex]\frac{T_{deimos}}{T_{Phobos}}[/tex] = [tex]\frac{2 \pi \sqrt{\frac{(23500)^3}{GM_{mars}} } }{2 \pi \sqrt{\frac{(9380)^3}{GM_{mars}} }}[/tex]
= [tex]\sqrt{(\frac{23500}{9380})^3 }[/tex]
= [tex]3.96[/tex]
Thus the above answer is correct.
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Suppose you take a trip that covers 180 km and takes 3 hours to make.
Your average speed is
8. 33 m/s
b. 16.66 m/s
c. 27.78 m/s
d. 41.67 m/s
Answer:
v = 16,66 m/s
Explanation:
To obtain the velocity of the train we must use the velocity formula for a uniform line movement:
v = x/t
Where x is the space and t is time.
replacing given values:
v = 180 km / 3 h
v = 60 km/h
to pass this value to international units:
v = 60 / 3,6 m/s
v = 16,66 m/s
The current in the wires of a circuit is 180.0 milliamps. If the resistance of the circuit were doubled ( with no change in voltage), then its new current would be
Answer:
I = 0.09[amp] or 90 [milliamps]
Explanation:
To solve this problem we must use ohm's law, which tells us that the voltage is equal to the product of the voltage by the current.
V = I*R
where:
V = voltage [V]
I = current [amp]
R = resistance [ohm]
Now, we replace the values of the first current into the equation
V = 180*10^-3 * R
V = 0.18*R (1)
Then we have that the resistance is doubled so we have this new equation:
V = I*(2R) (2)
The voltage remains constant therefore 1 and 2 are equals and we can obtain the current value.
V = V
0.18*R = I*2*R
I = 0.09[amp] or 90 [milliamps]
Please help, Thanks if you do!!! :)
Answer:
The Elements are arranged from left to right and top to bottom in order of increasing atomic number, and aslo
The arrangement of the periodic table was formulated in order to give a very informative representation of the chemical elements
A ball is thrown upwards which, which quantity remains constant among speed, kinetic energy, acceleration and velocity
Answer:
So uhh.... Acceleration means to accel or to go higher or like better. So not that one and velocity is speed too so, it has to be kinetic energy or something lke that.
Explanation:
A machine gun fires 50gm bullets at a speed of 1000m/s. the Gunner, holding the machine gun in his hand,can exert an average force of 180N against the gun. determine the maximum number of bullets he can fire per minute.
Answer:
We are given:
m = 50g OR 0.05 kg
v = 1000 m/s
Force applied by the gunner in a second = 180 N
Momentum(p) of the bullet:
p = mv
p = 0.05 * 1000
p = 50 kg m/s
Finding the recoil force:
The units kg m/s are also known as 'N' (newtons)
So, we can say that the force exerted on every bullet is 50 N
According to the law of conservation of momentum, every bullet fired applies a force of 50N towards the gunner
Hence, we can say that the recoil force of every bullet is 50N
Finding the number of bullets fired in a minute:
We are given that the gunner applied an average force of 180N on the gun
we know that that can also be written as 180 kg m/s. Notice the 's' in the units of the momentum, it tells us that this force is applied every second
So, to find the amount of force applied in a minute, we can multiply it by 60
Force applied by the gunner in a minute = (60 * 180) = 10800 N
Let n be the number of bullets fired in a minute
We can say that the force applied by the gunner is equal to the force applied by a bullet times the number of bullets fired
F(gunner) = n * F(bullet)
10800 = n * 50
n = 10800/50
n = 216 bullets / minute
The gunner shoots 216 bullets in a minute
Energy is always conserved. It cannot be created or destroyed. It can,
however be transferred from on form to another. Which of the following
is true of the relationship between kinetic and potential energy? *
A: When a system loses kinetic energy, It loses potential energy
B: as kinetic energy decreases, potential energy decreases
C: When a system gains kinetic energy, it loses potential energy
D: As kinetic energy increases, potential energy increases
Answer:
the answer is C
Explanation:
hope it helped!!!
Can someone who knows how to do physics please answer this
Answer:
about 3.17647 hours
Explanation:
The appropriate relation is ...
time = distance/speed
time = (270 km)/(85 km/h) = 3 3/17 h ≈ 3.17647 h
It will take Derek about 3.17647 hours to drive the distance.
The coefficient of friction for an object sliding across a rough floor is 0.7. A 125 N horizontal force causes the object to accelerate at 1.2 m/s2 . What is the objects weight
Answer:
152 N
Explanation:
From the question,
F-F' = ma................. Equation 1
Where F = Horizontal force, F' = Frictional force, m = mass of the object, a = accleration of the object.
But,
F' = mgμ............... Equation 2
Where g = acceleration due to gravity, μ = coefficient of friction.
make m the subject of the equation
Substitute equation 2 into equation 1
F-mgμ = ma.
make m the subject of the equation
m = F/(gμ+a).............. Equation 3
Given: F = 125 N, g = 9.8 m/s², μ = 0.7, a = 1.2 m/s²
Substitute these value into equation 3
m = 125/[(9.8×0.7)+1.2)
m = 125/8.06
m = 15.51 kg.
But,
W = mg.............. Equation 4
Where W = weight of the object.
W = 15.51(9.8)
W = 152 N
Who? What? Where? When? Why?
1- Write Gauss’ Law.
2- Consider an electric field line passing through a closed surface. What is the sign of the flux if:
a) The line passes from inside to outside?
b)The line passes from outside to inside?
Think of a conductor as having both positive and negative mobile charges. Consider a conductor in electrostatic equilibrium – that is, whose charges are stationary.
3- Given that all of the charges are stationary, what must the E-field be at any point inside of the conductor?
1)The total of the electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity. The electric flux through an area is defined as the electric field multiplied by the area of the surface projected in a plane perpendicular to the field.
The word photokinetic means “moving in response to light”. Why does this make sense based on the two main parts (morphemes) in this word?
Explanation:
photo means light in latin
kinetic means to move
5. Two buses X and Y started moving in opposite directions
from a point. After 5 minute Xcovered distance of 250mm
and y covered the distance of 300m. Calculate the relative
velocity.
Answer:
v = 0.166 [mm/min]
Explanation:
To solve this problem we must calculate the speed of each bus by means of the following formula that relates the displacement with time.
V = displacement / time
displacement = 250 [mm]
time = 5[min] = 300 [s]
Vx = 250/300 = 0.833[mm/min]
Vy = 300/300 = 1 [mm/min]
The relative velocity is the subtraction of the velocities, since the velocities are in opposite directions.
v = (1 - 0.833) = 0.166 [mm/min]
if you double the period of a pendulum. what happens to its length?
The only way you COULD double the period would be to make the string 4 times as long as it is now.
A 57 kg paratrooper falls through the air. How much force is pulling him down?
Answer:
Explanation:
Force = Mass * acceleration due to gravity.
Given
Mass of the paratrooper = 57kg
Acceleration due to gravity = 9.81m/s²
Required
Force pulling him down
Substitute unto formula;
F = 57 * 9.81
Force = 559.17 N
Hence the force pulling him down is 559.17N
The force pulling the paratrooper as he falls down is 558.6 N.
The given parameters;
mass of the paratrooper, m = 57 kgacceleration due to gravity, g = 9.8 m/s²The force pulling the paratrooper is force of gravity and the magnitude can be determined by applying Newton's second law of motion as shown below;
F = mg
F = 57 x 9.8
F = 558.6 N
Thus, the force pulling the paratrooper as he falls down is 558.6 N.
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Laws of motion are important for the study of objects that are not in motion and objects in motion. Is it true or false?
FIGURE 1 shows a horizontal human arm lifting a dumbbell. The forearm is
in equilibrium under the action of the weight of the dumbbell, the tension
in the tendon connected to the biceps muscle, and the force exerted on the
forearm itself. (For clarity, the point A where the tendon is attached is drawn
farther from the elbow than its actual position) Given the weight of the forearm
is 20 N and the mass of the dumbbell is 20 kg. The angle between the tension
force and the horizontal, is 80°. The length of the horizontal arm is 0.30 m.
The horizontal distance between elbow pivot and point A is 0.050 m. Find and
the vector and draw free body diagram for this case
Answer:
Explanation:
See attached file for answer.
