h(x)=3x+3 g(x)=-4x+1 find (h+g)(10)

Answer:

That would be 4.0

Step-by-step explanation:

if you have 4.2 take away 0.2 that would be 4.0

4.2

0.2

-__

4.0

Hope this helped regards

Answer:

(x)/(7)+(y)/(5)=2

Step-by-step explanation:

(x)/(7)+(y)/(5)=2

The length of the ladder that makes an angle of 75 degrees and lies against the wall of a house that's 23 feet tall is approximately 25.88 feet.

The ladder forms a right triangle as it lies against the wall as shown in the image below.

Thus:

x = length of the ladder (hypothenuse)

Reference angle [tex](\theta) = 75^{\circ}[/tex]

25 ft = Opposite

Apply SOH:

Thus,

[tex]sin(\theta) = \frac{Opposite}{Hypotenuse}[/tex]

[tex]sin(75) = \frac{25}{x}\\\\x = \frac{25}{sin(75)} \\\\\mathbf{x = 25.88}[/tex]

Therefore, the length of the ladder that makes an angle of 75 degrees and lies against the wall of a house that's 23 feet tall is approximately 25.88 feet.

Learn more here:

https://brainly.com/question/23973168

Answer:

x=32.09 feet long

Step-by-step explanation:

Answer:

There would be 36 coins left

Step-by-step explanation:

I don't know if that was the question but you would do:

11/20x2=22/40

22/40+4/40=26/40

26/40=13/20

One twentieth of 240 is 12

12x3=36

Hope this helped

Answer:

1. 2.6

2. 29.1

3. 2490

4 3.4

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

to answer this algebraic question use BDMAS rule

first solve bracket then division, multiplication,addition then subtraction.

6+8-12

14-12

2

Answer:

9.8

Step-by-step explanation:

convert your decimal into a fraction so 2.3= 23/10

23/10 + 8 - 1/2

then calculate your sum or difference

leaving you with

49/5

meaning your answer is

9.8

Determine the largest number of 34 cent stamps she can buy

The largest number of 34 cent stamps she can buy is 30

Given:

Total money = $12.25

let

x = 34 cent stamp

y = 3 cent stamp

34 cent stamp = 5 × 3 cent stamp

x + y = 0.49

x = 5y

0.34x + 0.3y = 12.25

0.35(5y) + 0.3y = 12.25

1.75y + 0.3y = 12.25

2.05y = 12.25

y = 12.25/2.05

y = 5.9756097560975

approximately, y = 6

Recall,

x = 5y

x = 5(6)

x = 30

Therefore, the largest number of 34 cent stamps she can buy is 30

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Answer:

5

-

2..................

Answer:

A 9 ounce package

Step-by-step explanation:

I think it is

Answer:

1

Step-by-step explanation:

Answer: 140m

Step-by-step explanation:

Answer and Step-by-step explanation:

(3rd option) The two lines are parallel, and they have a slope of [tex]\frac{2}{5}[/tex].

First, we can see that the two lines look parallel (meaning that if you were to go beyond what the graph shows (unless the graph shows an intersection), the lines at no point will intersect).

Second, If you found the slope of each line as well, (slope = rise over run, count up and then count right in this scenario from any point), they are the same, meaning they must be parallel to each other.

#teamtrees #PAW (Plant And Water)

I hope this helps!

Answer:

c

Step-by-step explanation:

See the attached graph.  There's no overlap between the two individual solution sets.

Answer:

3

Step-by-step explanation:

It's the same on both sides

Answer:

x + 8

Step-by-step explanation:

1. To simplify this expression, we have to combine like terms.

Therefore, the answer is x + 8.

Answer:

-2/4 can be written as -6/12

in negetive integers:: if the numerical vallues goes on increasing then the numbers are in decreasing order

so, -6/12 > -7/12

but 6/12 < 7/12

hope you understood

brainliest plz

Answer:

Step-by-step explanation:

To compare both fractions should have same denominator.

LCM of 4 and 12  is 12

[tex]\dfrac{-2}{4}=\dfrac{-2*3}{4*12}=\dfrac{-6}{12}[/tex]

[tex]\dfrac{-6}{12} \ is \ bigger \ than \ \dfrac{-7}{12}\\\\\dfrac{-2}{4} \ is \ bigger \ than \ \dfrac{-7}{12}\\\\[/tex]

Answer:

D.

Step-by-step explanation:

AB is NOT equal to BA in matrix multiplication.

It is not commutative.

Answer:

27h+16=178 I believe would work as an equation for this problem

Step-by-step explanation:

The required time to plant the rest of the saplings is 6 hours, and 27 + 16 = 178 is the required expression.

The equation model is defined as the model of the given situation in the form of an equation using variables and constants.

Here,
Let the number of hours be h,
He can plant 27 saplings per hour.
He needs to plant 178 total saplings and has already planted 16 saplings.
So, according to the quesiton,
27h + 16 = 178,
27h = 162
h = 162/27

h = 6

Thus, the required time to plant the rest of the saplings is 6 hours,

Learn more about models here:
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#SPJ2

Answer:

1) 14/3 (D)

2) -0.6 (C)

Step-by-step explanation:

1) 5-(2/3)*(2/3//4/3)

2)|-1.2-2.03|-2.03/-2

Answer:

64 miles per hour

Step-by-step explanation:

512 divided by 8 equals 64

Answer:

jkb jhb n

Step-by-step explanation:

Answer:

159

Step-by-step explanation:

5*(1+7×3)=5*(22)

5*(22)=5+7×22=159

Answer:

what's the problem i know that "tickets for the school play cost 6 dollars for the adults and 3.50 for the students" but you didn't say how many people are going

Step-by-step explanation:

Answer:

X = 2

Step-by-step explanation:

Answer:

148 cm2

Step-by-step explanation:

5 * 4 * 2 = 40

6 * 5 * 2 = 60

6 * 4 * 2 = 48

40 + 60 + 48 = 148

Answer:

Step-by-step explanation:

T.S.A (TOTAL SURFACE AREA) OF CUBOID :

→ 2(lb + bh + lh)

( l = length, b = breadth , h = height )

→ Given :

• Length (l) = 6cm

• Breadth (b) or width = 4cm

• Height (h) = 5cm

Total Surface area of cuboid :

• 2( 6×4+ 4×5+ 5×6) cm²

• 2 ( 24 + 20 + 30 ) cm²

• 2 ( 74 ) cm²

• 148 cm²

Answer:

$6.69

Step-by-step explanation:

Since we know the total cost of 5 pairs of gloves, all we have to do to find the unit price is divide the total cost by how many gloves were are being sold:

33.45 / 5 = 6.69

Therefore, one pair of gloves costs $6.69

Hope this helps :)

Hello salvadorbea340!

[tex] \huge \boxed{\mathfrak{Question} \downarrow}[/tex]

[tex] - (6y - 4) + (6y - 4) - ( - 2)[/tex]

[tex] \large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}[/tex]

[tex]-(6y-4)+(6y-4)-(-2)[/tex]

Firstly, let's open the brackets of the 1st term, i.e. - (6y - 4).

[tex] -( 6y - 4) \\ = \underline{\underline{- 6y + 4}}[/tex]

Now, the 2nd term [ (6y - 4) ].

[tex] + ( 6y - 4) \\ = \underline{\underline{ + 6y - 4}}[/tex]

Now, the 3rd term ⇨ - (- 2)

[tex] -( - 2) \\ = \underline{\underline{ + 2}}[/tex]

Now, let's bring the equation together.

[tex]- (6y - 4) + (6y - 4) - ( - 2) \\ = - 6y + 4 + 6y - 4 + 2[/tex]

Now, let's solve the equation.

Firstly, bring the like terms together.

[tex]- 6y + 4 + 6y - 4 + 2 \\ = - 6y + 6y + 4 - 4 + 2[/tex]

Now cancel out -6y & +6y and 4 & -4 as they make 0.

[tex]- 6y + 6y + 4 - 4 + 2 \\ = \bcancel{- 6y }+ \bcancel{6y} + \bcancel{ \: \: 4 } \: \: - \bcancel{ \: 4 }+ 2 \\ = 0 + 2 \\ = 2[/tex]

And, the only number left is 2. So our answer is 2.

[tex] = \large\boxed{\boxed{ 2}}[/tex]

__________________

Hope it'll help you!

ℓu¢αzz ッ

Answer:

Either [tex]x = (-\pi / 6)[/tex] or [tex]x = (\pi / 6)[/tex].

Step-by-step explanation:

Angle sum identity for cosine:

[tex]\cos(a + b) = \cos(a)\, \cos(b) - \sin(a) \, \sin(b)[/tex].

Double-angle identity for cosine and sine:

[tex]\begin{aligned}& \cos(2\, a)\\ &= \cos^{2}(a) - \sin^{2} (a) \\ &= (\cos^{2}(a) + \sin^{2}(a) - 2\, \sin^{2}(a) \\ &= 1 - 2\, \sin^{2}(a)\end{aligned}[/tex].

[tex]\sin(2\, a) = 2\, \cos(a) \, \sin(a)[/tex].

The secant of an angle is the inverse reciprocal of the cosine of that angle:

[tex]\displaystyle \text{$\sec(x) = \frac{1}{\cos(x)}$ if $\cos(x) \ne 0$}[/tex].

Apply these identities to rewrite the left-hand side of the equation.

[tex]\begin{aligned} & \sec(x) \, \cos(3\, x) \\ =\; & \frac{1}{\cos(x)} \cdot \cos(3\, x) \\ =\; & \frac{1}{\cos(x)} \cdot (\cos(x)\, \cos(2\, x) - \sin(x)\, \sin(2\, x)) \\ =\; &\cos(2\, x) \\ & - \frac{1}{\cos(x)} \cdot (\sin(x)\, \sin(2\, x)) \\ =\; & \cos(2\, x)\\ & - \frac{1}{\cos(x)} \cdot (\sin(x) \cdot (2\, \sin(x)\, \cos(x))) \\ =\; & \cos(2\, x) - 2\, \sin^{2}(x) \\ =\; & (1 - 2\, \sin^{2}(x)) - 2\, \sin^{2}(x) \\ =\; &1 - 4\, \sin^{2}(x) \end{aligned}[/tex].

Solve the rewritten equation:

[tex]\displaystyle \sin^{2}(x) = \frac{1}{4}[/tex].

Either [tex]\sin(x) = (1/2)[/tex] or [tex]\sin(x) = (-1/2)[/tex].

The question required that [tex](-\pi / 2) \le x \le (\pi / 2)[/tex]. The sine function is one-to-one over this range. In other words, for each [tex]y[/tex] between [tex](-1)[/tex] and [tex]1[/tex], there is exactly one [tex]x[/tex] between [tex](-\pi / 2)[/tex] and [tex](\pi / 2)[/tex] such that [tex]\sin(x) = y[/tex].

If [tex]\sin(x) = (-1/2)[/tex] and [tex](-\pi / 2) \le x \le (\pi / 2)[/tex], then [tex]x = (-\pi / 6)[/tex].

Otherwise, if [tex]\sin(x) = (1/2)[/tex] and [tex](-\pi / 2) \le x \le (\pi / 2)[/tex], then [tex]x = (\pi / 6)[/tex],

Verify that [tex]\cos(x) \ne 0[/tex] for either of the two [tex]x[/tex] values, such that the [tex]\sec(x)[/tex] in the original equation takes a real value.