Henry made juice from a recipe that called for 1 cup of sugar, 3 cups of lime-drink mix, and 2 gallons of water. Henry filled a container with 18 gallons of water, and used 9 cups of sugar. Based on this information, what is the total number of cups of lime-drink mix Henry used?

Answer:

13. 10

14. 51

Step-by-step explanation:

Answer:

13. 10

14. 51

Step-by-step explanation:

Answer:

the number A(t) of grams of salt in the tank at a time is A(t)=150-110e-t/50

Area of the triangle = 1/2 x base x height

Area of triangle = 1/2 x 6 x 8.3 = 24.9 square feet.

Area of rectangle = length x width

Area of rectangle = 33.2 x 12 = 398.4 square feet.

To find the number of triangles that can fit in the rectangle divide the area of the rectangle by the area of the triangle:

398.4 / 24.9 = 16

Answer: 16 triangles

I'm assuming the integral is

[tex]\displaystyle \int \frac{\mathrm dx}{x+\sqrt{x^2-1}}[/tex]

Rationalize the denominator:

[tex]\dfrac1{x+\sqrt{x^2-1}} \times \dfrac{x-\sqrt{x^2-1}}{x-\sqrt{x^2-1}} = \dfrac{x-\sqrt{x^2-1}}{x^2-\left(\sqrt{x^2-1}\right)^2} = x-\sqrt{x^2-1}[/tex]

Then the integral is

[tex]\displaystyle \int\left(x-\sqrt{x^2-1}\right)\,\mathrm dx = \dfrac12x^2 - \int\sqrt{x^2-1}\,\mathrm dx[/tex]

For the remaining integral, substitute x = sec(t ) and dx = sec(t ) tan(t ) dt. Then over an appropriate domain, we have

[tex]\displaystyle\int\sqrt{x^2-1}\,\mathrm dx = \int\sec(t)\tan(t)\sqrt{\sec^2(t)-1}\,\mathrm dt = \int\sec(t)\tan^2(t)\,\mathrm dt[/tex]

Integrate by parts, taking

u = tan(t )   ==>   du = sec²(t ) dt

dv = sec(t ) tan(t ) dt   ==>   v = sec(t )

Then

[tex]\displaystyle\int\sec(t)\tan^2(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec^3(t)\,\mathrm dt[/tex]

Now for *this* remaining integral, integrate by parts again, taking

u = sec(t )   ==>   du = sec(t ) tan(t ) dt

dv = sec²(t ) dt   ==>   v = tan(t )

so that

[tex]\displaystyle\int\sec^3(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec(t)\tan^2(t)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec(t)(\sec^2(t)-1)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec^3(t)\,\mathrm dt + \int\sec(t)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \frac12\sec(t)\tan(t)+\frac12\int\sec(t)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \frac12\sec(t)\tan(t) + \frac12\ln\left|\sec(t)+\tan(t)\right| + C[/tex]

To summarize, if I denotes the original integral, we have

[tex]\displaystyle I = \frac12x^2 - \int\sqrt{x^2-1}\,\mathrm dx \\\\ I = \frac12x^2 - \int\sec(t)\tan^2(t)\,\mathrm dt \\\\ I = \frac12x^2 - \sec(t)\tan(t) + \int\sec^3(t)\,\mathrm dt \\\\ I = \frac12x^2 - \sec(t)\tan(t) + \frac12\sec(t)\tan(t) + \frac12\ln\left|\sec(t)+\tan(t)\right| + C \\\\ I = \frac12x^2 - \frac12\sec(t)\tan(t) + \frac12\ln\left|\sec(t)+\tan(t)\right| + C[/tex]

Putting everything back in terms of x, we have

sec(t ) = x

tan(t ) = √(x ² - 1)

so that

[tex]\displaystyle I = \boxed{\frac12x^2 - \frac12x\sqrt{x^2-1}+\frac12\ln\left|x+\sqrt{x^2-1}\right|+C}[/tex]

Answer:

[tex]x^3y^{-7} = \frac{x^3}{y^7}[/tex]

Step-by-step explanation:

Given

[tex]x^3y^{-7}[/tex]

Required

The equivalent

We have:

[tex]x^3y^{-7}[/tex]

Apply the following rule of exponents

[tex]a^{-b} = \frac{1}{a^b}[/tex]

So, we have:

[tex]x^3y^{-7} = x^3 * \frac{1}{y^7}[/tex]

[tex]x^3y^{-7} = \frac{x^3}{y^7}[/tex]

Answer:

the 2nd one or B

Step-by-step explanation:

Answer:

B. A linear, partial variation

Step-by-step explanation:

We know that speed = distance / time. From the table we have a linear function, and it's indirect, or partial.

32 - 7 = 25/5 = 5

so, we have 5 products being purchased, since the 7 sec check-out doesn't count as product time.

hope it helps :)

Answer:

5 items

Step-by-step explanation:

32 - 7 = 25

25 / 5 = 5

This means that 5 items are being purchased.

Hope it helps c:

Answer:

4^8

Step-by-step explanation:

If the second 4 is an exponent, as in (4^2)^4, then multiply the exponents.

(4^2)^4 = 4^(2 * 4) = 4^8

Answer:

42

Step-by-step explanation:

5²+3(2)+5+6

25+6+5+6

31+11

42

Hope it helps

Answer:

a

Step-by-step explanation:

assuming theyre asking you to graph y = (x-2)(x+3)  -cant see the signs in your photo

the x-intercepts would be 2 and -3 , so option a!

Answer:

250°

There are 250°……………

Answer:

The similarity statement is RTS and ACB. Other options are correct

Answer:

75%

Step-by-step explanation:

9 ÷ 12 = 0.75

0.75 x 100 = 75 = 75%

Answer:

3/4

Step-by-step explanation:

Experimental probability, is the probability determined according to the results of an "experiment" or a trial. In Carla's "experiment", she attempted 12 total shots and made 9 shots. The probability that she made a shot would be 9/12, or 3/4.

Answer:

It's answer is 200 cents bun not sure

Answer:

 R=.2,P=.25, G=.55

Step-by-step explanation:

Answer:

1.8 x 10^7 gallons in one hour.

Step-by-step explanation:

60 x 60 = 1,200 = 1.2 x 10^3 (Amount of seconds in an hour)

(1.5 x 10^4) x (1.2 x 10^3)

= 1.8 x 10^7

Answer:

hi friends good evening

Answer:

33π square feet

Step-by-step explanation:

Volume = base area × height

132π = base area × 4

or, base area = 132π/4

or, base area = 33π

Answered by GAUTHMATH

Answer:

1/4

Step-by-step explanation:

First, add up the marbles:

2 + 9 + 7  = 18

Multiply by 2 because you pick two:

18 × 2 = 36

Simplify:

9/36 = 3/12 = 1/4

Hope this helped.

Answer:

Step-by-step explanation:

30

Answer:

-4, 4, 7i, -7i

Step-by-step explanation:

Basically any or each bracket must be equal to 0. If x^2+16 = 0, then x can be 4 and -4, and if x^2+49 is 0, then x =7i or -7i

Answer:

x=180-125

=55

z=55

y=180-(55+55)

y=70

The diagram is missing and so i have attached it.

Answer:

Next step is;

to keep the same compass width and draw an arc centered at H crossing the previous arc in the image.

Step-by-step explanation:

A perpendicular line is to be drawn to line GH through point A.

The steps are;

1. Identification of the two end points of the line which has been done.

2. Place one leg of the compass at point G and draw a small arc above the line GH. This has been done.

3. Without changing the span of the compass, place the same leg of the compass at point H and draw another small arc above the line GH to intersect the previously drawn small arc.

4. Make use of a straight object to connect the point of intersection of the two small arcs to the point A.

This line is the perpendicular line to GH.

In the figure attached, they have just finished point 2 I wrote above. Thus, the next step is point 3.

Answer:

to keep the same compass width and draw an arc centered at H crossing the previous arc in the image.

Step-by-step explanation:

Answer:

it is a 30 degree angle

Step-by-step explanation:

Answer:

a) log 2 (48 ×3 ×9 )

log 2 1296

10.3

b) log 4 24 - log 4 3/4 log 4 2

log 4 36

2.58

Answer: 60

Step-by-step explanation:

The blank space can be filled with 60, as this is a simple problem of distributive property

Answer: Approximately 904

volume = (4/3) · π · r³

(4/3) · 3.14 · 6³ = (4/3) · 3.14 · 216 = (4/3) · 678.24 = 904.32 ≈ 904

Answer:

904 units^3

Step-by-step explanation:

The formula for finding the volume of a sphere is V = 4/3 πr³

π is assumed to be 3.14, and the radius is 6.

V = 4/3 * 3.14 * 216

V = 4.18666666 * 216

Volume = 904.32, which can be rounded to 904 units cubed

Answer:

Stratified sampling

Step-by-step explanation:

Convenient: Sample drawn from a conveniently available pool.

Random: Basically, put all the options into a hat and drawn some of them.

Systematic: Every kth element is taken. For example, you want to survey something on the street, you interview every 5th person, for example.

Cluster: Divides population into groups, called clusters, and each element in the cluster is surveyed.

Stratified: Also divides the population into groups. However, then only some elements of the group are surveyed.

In this question:

Divided by groups(according to age)

A certain amount of each group is sampled.

Thus, stratified sampling is used.

[tex]\bf \large \rightarrow \: \:2x \: \: ( \: 4 {x}^{2} \: - \: 3xy \: + \: {y}^{2} \: )[/tex]

[tex]\bf \large \rightarrow \: \: 8 {x}^{3} \: - \: 6 {x}^{2}y \: + \: 2x {y}^{2} [/tex]

Option ( B) is the correct answer

.................................