please help asap!!!!!

Answer:

Jawaharlal Nehru was the first

Answer:

Jawaharlal Nehru is the first prime minister of India

The inequality that relates the number of hours to the weekly sales is:

[tex]450 + 0.20x \ge 35y[/tex]

The complete question implies that we define an inequality that represents the relationship between the number of hours worked in a week and the weekly sales

We make use of the following representation:

[tex]x \to[/tex] weekly sales from cars.

[tex]y \to[/tex] hours worked in a week

His weekly salary is then calculated as:

Salary (S) = Earnings per week + Commission * Sales from car

So, we have:

[tex]S = 450 + 20\% * x[/tex]

Express percentage as decimal

[tex]S = 450 + 0.20* x[/tex]

[tex]S = 450 + 0.20x[/tex]

Assume he works for y hours in a week.

His hourly rate is:

[tex]Hourly = \frac{S}{y}[/tex] --- i.e. weekly salary divided by number of hours

[tex]Hourly = \frac{450 + 0.20x}{y}[/tex]

For this rate to be at least [tex]\$35[/tex], the following condition must be true

[tex]Hourly \ge 35[/tex] --- i.e. is hourly rate must be greater than or equal 35

So, we have:

[tex]\frac{450 + 0.20x}{y} \ge 35[/tex]

Multiply both sides by y

[tex]450 + 0.20x \ge 35y[/tex]

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Answer:

A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds.  4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds

Step-by-step explanation:

The given table is presented as follows;

[tex]\begin{array}{ccc}Day \ 1 \ lap \ times \ (seconds)&Day \ 2 \ lap \ times \ (seconds)&Day \ 3 \ lap \ times \ (seconds)\\83&87&85\\92&90&86\\91&92&91\\89&91&93\\94&92&91\\93&95&89\\88&90&88\\84&85&84\end{array}[/tex]The number of laps in the range 82 to 84 seconds = 1

The number of laps in the range 84 to 86 seconds = 4

The number of laps in the range 86 to 88 seconds = 2

The number of laps in the range 88 to 90 seconds = 4

The number of laps in the range 90 to 92 seconds = 6

The number of laps in the range 92 to 94 seconds = 5

The number of laps in the range 94 to 96 seconds = 2

The number of laps in the range 96 to 98 seconds = 0

Therefore, the histogram that represents Blanca's lap times for the three days of practice is described as follows;

A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds.  4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds

Answer: A.

Step-by-step explanation: On Edge!

5+a2+ab-9c

let's just substitute a with 5, b with 4 and c with 0

5+5*2+5*4-9*0

= 5+10+20+0

= 35

Answer:

[tex]=5x+1[/tex]          or          [tex]=5x-1[/tex]

Step-by-step explanation:

One is given the following equation:

[tex]5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}[/tex]

The problem asks one to simplify the expression, the first step in solving this equation is to factor the equation.  Rewrite the numerator and denominator of the fraction as the product of two expressions. Remember the factoring patterns:

[tex](a-b)^2=a^2-2ab+b^2[/tex]

[tex]=5x-\frac{\sqrt{9x^2-6x+1}}{1-3x}[/tex]

[tex]=5x-\frac{\sqrt{(3x-1)^2}}{-(3x-1)}[/tex]

Now simplify the numerator. Remember, taking the square root of a squared value is the same as taking the absolute value of the expression,

[tex]=5x-\frac{\sqrt{(3x-1)^2}}{1-3x}[/tex]

[tex]=5x-\frac{|3x-1|}{-(3x-1)}[/tex]

Rewrite the expression without the absolute value sign in the numerator. Remember the general rule for removing the absolute value sign:

[tex]|a-b|\\=a -b[/tex]           or           [tex](-a-b) = b-a[/tex]

[tex]=5x-\frac{|3x-1|}{-(3x-1)}[/tex]

[tex]=5x-\frac{3x-1}{-(3x-1)}[/tex]          or          [tex]=5x-\frac{-(3x-1)}{-(3x-1)}[/tex]

Simplify both expressions, reduce by canceling out common terms in both the numerator and the denominator,

[tex]=5x-\frac{3x-1}{-(3x-1)}[/tex]          or          [tex]=5x-\frac{-(3x-1)}{-(3x-1)}[/tex]

[tex]=5x-(-1)[/tex]          or          [tex]=5x-(1)[/tex]

Simplify further by rewriting the expression without the parenthesis, remember to distribute the sign outside the parenthesis by the terms inside of the parenthesis; note that negative times negative equals positive.

[tex]=5x-(-1)[/tex]          or          [tex]=5x-(1)[/tex]

[tex]=5x+1[/tex]          or          [tex]=5x-1[/tex]

Answer:

hello,

Step-by-step explanation:

[tex]u_1=2=2*3^0\\u_2=6=2*3^1\\u_3=18=2*3^2\\u_4=54=2*3^3\\\\....\\u_n=2*3^{n-1}\geq 100000\\\\3^{n-1}\geq 50000\\\\(n-1)*ln(3)\geq ln(50000)\\\\n-1\geq 9,848586...\\\\n\geq 10.848586....\\\\\boxed{n=11}\\[/tex]

Answer:

Yo mean correct way??

yo can divide minute by 60 to convert minute into hour

For example

To convert 10 minute into hour. then we should divide 10 by 60. 10/60

Answer:

In any conversion you have to establish  ratios (or rates) for the different units being converted.

The process will be performed by a series of multiplications that will cancel out the "unwanted" units.

multiplication by one (1) does not change the value in an equation.

you have to multiply by a "series of ones" that take into account the units being converted..

for example  

1 minute/60 seconds   or  1 inch = 2.54 cm   or  1 day = 24 hours

in your problem you have minutes... lets say you have 100 minutes

100 minutes * 1 hour             minutes cancel and you have  100/60 = 1 [tex]\frac{2}{3}[/tex] hrs

                       60 minutes

Step-by-step explanation:

Answer:

Step-by-step explanation:

To solve this, we are going to make an age table:

                       Age Now                 Age 10 years ago

Tanya

Elliot

Filling the in the Age Now column comes from the first sentence. If Elliot is 2 times Tanya's age and we don't know Tanya's age, then Tanya's age is x and Elliot's age is 2x:

            Age Now                Age 10 years ago

Tanya         x

Elliot         2x

Filling in the Age 10 years ago column simply requires that we take their ages in the Age Now column and subtract 10 from each age:

         Age Now                Age 10 years ago

Tanya     x                              x - 10

Elliot      2x                           2x - 10

Since the question is How old is Elliot now based on the fact that 10 years ago....blah, blah, blah, we are using the ages in the 10 years ago column to write our equation. It says:

10 years ago, Elliot was 4 times as old as Tanya. Translated into mathspeak:

2x - 10 = 4(x - 10) and

2x - 10 = 4x - 40 and

-2x = -30 so

x = 15. That means that Elliot is 30 and Tanya is 15

Answer:

C) -1.255

Step-by-step explanation:

We are tasked to solve for the residual value given that when x equals 29, y will be equals to 27.255. But, when it is tested, y actual value is 26. The formula in solving residual is shown below:

Residual value = Observed value - predicted value

Residual value =  26 - 27.255

Residual values = -1.255

The answer is -1.255 for residual value.

Answer:

x=10

Step-by-step explanation:

Step 1: Multiply 4 with X and 3. You'll get 4x+12=x+42

Step 2: Keep the variable on one side and the number on the other side. you would subtract X and subtract 12. You'll get 3x=30

Step 3: Divide by the 3 on both sides and you'll get x=10

Given:

[tex] \\ ⇢ \tt \: 4(x + 3) = x + 42 \\ [/tex]

Solution:

[tex] \\ ⇢ \tt \: 4(x + 3) = x + 42 \\ \\ \\ \tt⇢ 4x + 12 = x + 42 \: \: \\ \\ \\ \tt \: ⇢4x - x = 42 - 12 \: \\ \\ \\ \tt \: ⇢3x = 30 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \tt \: ⇢x = \frac{30}{3} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \tt \: \pink{ \pmb{ \mathfrak{⇢x = 10}}} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ [/tex]

Verification:

[tex] \\ ⇢ \tt \: 4(10+ 3) = 10+ 42 \\ \\ \\ \tt⇢ 40 + 12 = 10 + 42 \: \: \\ \\ \\ \tt \: ⇢52 = 52 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \: ⇢ \purple{ \pmb{ \bold{L.H.S = R.H.S}}}\\ \\ \\ [/tex]

Answer:

B. 3ˣ + 8x + 4

General Formulas and Concepts:

Pre-Algebra

Algebra I

Step-by-step explanation:

Step 1: Define

Identify

f(x) = 3ˣ + 10x

g(x) = 2x - 4

Step 2: Find

Answer:

3^x+8x+4

Step-by-step explanation:

f(x) = 3^x + 10x

g(x) = 2x - 4

(f- g)(x)=3^x + 10x  - (2x - 4)

Distribute the minus sign

(f- g)(x)=3^x + 10x  - 2x + 4

Combine like terms

         3^x+8x+4

Question isn't well formatted, a picture if the question is attached below.

Answer:

1 / 4

Step-by-step explanation:

From the plot, each dot represent a gamer ; therefore, the total number of gamers will be counting all the dots ;

Total number of gamers = 24

Fraction of gamers that have 7 / 8 of the way to go ;

This means that they have 7/8 of the way left to proceed to next level ;

The fraction is : 1 - 7/8 = 1 /8

This means the number of of people whose progress are on 1/8 ; this is 6

Hence, fraction of gamers that have 7/8 of the way to go :

6 / 24 = 1 / 4

Answer:

207y

Step-by-step explanation:

Answer:

8z - 1

Step-by-step explanation:

Given

3 + 4(2z - 1) ← multiply each term in the parenthesis by 4

= 3 + 8z - 4 ← collect like terms

= 8z - 1

Answer:

-1 + 8z

Step-by-step explanation:

First use the distributive property of multiplication (Just multiply 4 with all numbers in the parenthesis):

3 + 4(2z - 1)

3 + 8z - 4

Group like terms:

3 + 8z - 4

-1 + 8z

The answer is -1 + 8z

Hope this helped.

Answer:

Step-by-step explanation:

I am not sure if you are asking for the graph of

√(x-16) that has a x intercept at (16,0)

or

√ x -16 that has a y intercept at (0, -16)

The distance between the intercepts of both lines is 2 units

The equation of a line in slope intercept form is:

[tex]y = mx + b[/tex]

Where:

[tex]m \to[/tex] slope

[tex]b \to[/tex] y intercept

For the first line, we have:

[tex]m_1 = 3[/tex] ---- the slope

So, the equation of the first line is:

[tex]y = 3x + b_1[/tex]

For the second line, we have:

[tex]m_2 = 5[/tex] --- the slope

So, the equation of the second line is:

[tex]y = 5x + b_2[/tex]

Both lines intersect at (10,15) means that (10,15) is a common solution to the equation of both lines

i.e.

[tex](x,y) = (10,15)[/tex]

Substitute these values in the first equation and solve for b

[tex]y = 3x + b_1[/tex]

[tex]15 = 3*10 + b_1[/tex]

[tex]15 = 30 + b_1[/tex]

[tex]b_1 = 15 - 30[/tex]

[tex]b_1 = -15[/tex]

So, the equation of the first line is

[tex]y = 3x - 15[/tex]

Repeat the same process for the second line

[tex]y = 5x + b_2[/tex]

[tex]15 = 5*10 + b_2[/tex]

[tex]15 = 50 + b_2[/tex]

[tex]b_2 = 15 - 50[/tex]

[tex]b_2 = -35[/tex]

So, the equation of the second line is

[tex]y =5x - 35[/tex]

The x intercept is when [tex]y =0[/tex]

So, we substitute 0 for y and solve for x in the equations of both lines

For line 1

[tex]y = 3x - 15[/tex]

[tex]0 = 3x - 15[/tex]

[tex]3x= 15[/tex] ---- Collect like terms

[tex]x = 5[/tex] --- Divide both sides by 3

The x intercept of line 1 is 5

For line 2

[tex]y =5x - 35[/tex]

[tex]0 = 5x - 35[/tex]

[tex]5x = 35[/tex] --- Collect like terms

[tex]x = 7[/tex] -- Divide both sides by 5

The x intercept of line 2 is 7

The distance (d) between both is the difference in the intercepts:

[tex]d = 7 - 5[/tex]

[tex]d = 2[/tex]

Read more about intercepts at:

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Answer:

hhghhhhhhhhh

Step-by-step explanation:

yyyyjuiynrjdjf

Answer:

C - exponential growth

Step-by-step explanation:

Answer:

The answer should be C

Step-by-step explanation:

The opposite angles in a cyclic quadrilateral are supplementary. i.e., the sum of the opposite angles is equal to 180˚

So using theorem we find that

∠A+∠C = 180

x + 108 = 180

x = 180 - 108

x = 72

∠B+∠D = 180

88 + y = 180

y = 180 - 88

y = 92

Answered by Gauthmath must click thanks and mark brainliest

The required value of angle x and angle y is 72 and 92 respectively.

Given that,
A figure of the circle has been shown,
A quadrilateral is inscribed in the circle,
Angles in the quadrilateral are given as
∠A = x, ∠B = 82, ∠C = 108 and ∠y
The value of angles x and y is to be determined.

A quadrilateral is an irregular four-sided shape as given in the picture in question.

Since quadrilateral has a property that describes that the sum of opposite angle of the quadrilateral is 180°,
Here in the given quadrilateral sum of angle A + C and angle B + D is equal to 180.
⇒
∠A + ∠C = 180
∠A + 108 = 180
∠A = 72°
Similarly
∠B + ∠D = 180
88 + ∠D = 180
∠D = 92

Thus, the required value of angle x and angle y is 72 and 92 respectively.

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#SPJ5

Answer:

answer of this qn is 15in^2

Answer:

brackets stand for multiplication therefore this means multiply 5.9 by 1.102..

I hope this helps and sorry if it's wrong

Answer:

The sample size needed is of 10,484.

Step-by-step explanation:

We have to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.98}{2} = 0.01[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a p-value of [tex]1 - 0.01 = 0.99[/tex], so Z = 2.327.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

The weekly earnings of students in one age group are normally distributed with a standard deviation of 88 dollars.

This means that [tex]\sigma = 88[/tex]

Find the sample size needed to assure with 98 percent confidence that the sample mean will not differ from the population mean by more than 2 dollars.

This is n for which M = 2. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]2 = 2.327\frac{88}{\sqrt{n}}[/tex]

[tex]2\sqrt{n} = 2.327*88[/tex]

[tex]\sqrt{n} = \frac{2.327*88}{2}[/tex]

[tex](\sqrt{n})^2 = (\frac{2.327*88}{2})^2[/tex]

[tex]n = 10483.3[/tex]

Rounding up:

The sample size needed is of 10,484.

Answer:

D

Step-by-step explanation:

Answer:

It's D on there

Step-by-step explanation:

Answer:

Step-by-step explanation:

let the horizontal distance be x

(17.8-1.5)/x = tan 38

or x = 16.3/tan38

or x = 20.863

Answer:

540 is the answer

Step-by-step explanation:

hope u liked!

We can expect to roll a prime number 48 times.

Theoretically, when you roll a number cube all the possible numbers have the same probability, 1/6.

We know that the numbers in a number cube are {1, 2, 3, 4, 5, 6}

Of these, the primes are: 2, 3, and 5.

So half of the outcomes of a number cube are primes.

This means that, in every single roll, the probability of getting a prime number is 1/2.   (1/6 + 1/6 + 1/6 = 3/6 = 1/2)

Then for 96 rolls, we should expect to see in half of these a prime number as an outcome.

This means that we should expect to roll a prime number 96/2 = 48 times.

If you want to learn more about probability, you can read:

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You should expect to roll a prime number 64 times.

To determine, if you roll a number cube 96 times, how many times would you expect to roll a prime number, the following calculation must be performed, knowing that the prime numbers are those that can only be divided by 1 or by themselves:  

A cube has 6 sides. Therefore, the numbers in the cube will be 1, 2, 3, 4, 5 and 6. Of these numbers, only 4 and 6 are not prime, since 4 is divisible by 2 and 6 is divisible by 2 and 3.

Therefore, 4/6 numbers are prime, that is, 66.66% of the numbers in the cube.

Therefore, if you roll a number cube 96 times, since 96 x 4/6 equals 64, you should expect to roll a prime number 64 times.

Learn more in https://brainly.com/question/23715861.