from problem 2,suppose another boy, boy C pulls the heavy cabinet with 5N of force in the same direction with boy A
1. what will be the net foece on the cabinet?
2. will the cabinet move?
3. in what direction will the cabinet move?
Answers
Answer:
Searching in Google I found that in problem 2 were two boys pulling the heavy cabinet, a Boy A pulling in the left direction with 10 N of force, and a boy B pulling in the right direction with 5 N.
1. F = 10 N
2. Yes, it will move.
3. It will move to the left direction of the cabinet (same direction as the boys A and C).
Explanation:
Searching in Google I found that in problem 2 were two boys pulling the heavy cabinet, a Boy A pulling in the left direction with 10 N of force, and a boy B pulling in the right direction with 5 N.
1. Hence, if another boy (C) pull in the same direction as the boy A with 5 N of force, we have:
[tex] \Sigma F = F_{A} + F_{C} - F_{B} [/tex]
[tex] \Sigma F = 10 N + 5 N - 5 N = 10 N [/tex]
The net force on the cabinet is 10 N.
2. Yes, the cabinet will move. From point 1 we can deduce that the cabinet will move since the net force on the cabinet is different from zero (10 N).
3. The direction of the motion is the same as the Boys A and C, that is to say, to the left of the cabinet.
I hope it helps you!
The net force acting on an object, is the vector sum of all the forces acting on it
The correct values for the forces acting on the cabinet are;
1. The net force on the cabinet is 10 N
2. Yes, the cabinet will move
3. The cabinet will move in the direction of boy A and boy C
The reason the above values are correct are as follows:
Question: The possible missing part of the question is; In problem 2 boy A is pulling a heavy cabinet with [tex]F_A[/tex] = 10 N force, and boy B is pulling the same cabinet at the same time and in opposite direction with a force of [tex]F_B[/tex] = 5 N
The known parameter:
The force with which boy C pulls the heavy cabinet = 5 N
The direction in which boy C pulls the cabinet = The same direction as boy A
Question 1. The net force on the cabinet, [tex]F_{NET}[/tex] is given as follows;
Taking the direction of the force of boy A as the positive direction, we have;
[tex]\overset \longrightarrow {F_A}[/tex] = 10 N
[tex]\overset \longrightarrow {F_B}[/tex] = - 5 N
[tex]\overset \longrightarrow {F_C}[/tex] = 5 N
[tex]\overset \longrightarrow {F_{NET}}[/tex] = [tex]\overset \longrightarrow {F_A}[/tex] + [tex]\overset \longrightarrow {F_B}[/tex] + [tex]\overset \longrightarrow {F_C}[/tex]
[tex]\overset \longrightarrow {F_{NET}}[/tex] = 10 N + (-5 N) + 5 N = 10 N
The net force on the cabinet, [tex]\overset \longrightarrow {F_{NET}}[/tex] = 10 N
Question 2. Yes: Given that there is a net force acting on the cabinet, according to Newton's first law of motion, in the absence of friction force, the cabinet will move in the direction of the net force of 10 Newton
Question 3. The cabinet will move in the direction of the net fore
The direction of the net force is the direction boy A and boy C are pulling the cabinet
Therefore, the cabinet will move in the direction boy A and boy C are pulling the heavy cabinet
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If an object weighs 20 N and is sitting on the floor without moving, what must be the normal force of the floor acting on the box?
20 N up
20 N down
10 N up
10 N down
Answers
Answer:
20 N up
Explanation:
Since the object on the floor is sitting still. Based on Newton's law of force. Objects must have equal reaction and force against each other for still objects. So the answer is 20 N up. Since the force are equal on both sides making the object not moving.
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A vertical column of elements in the periodic table is called a .
A horizontal row of elements in the periodic table is called a .
Atoms of elements in the same group have the same .
As you move from left to right on the periodic table, the atomic number .
Answers
Explanation:
A vertical column of elements in the periodic table is called a group
A horizontal row of elements in the periodic table is called a period
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A frog falls from its rainforest tree. If we ignore wind resistance, (a) how much time does it take the frog to fall a distance of 12.0 m? (b) how fast is the frog falling at this point?
Answers
Answer:
Explanation:
a) Using the equation of motion
S = ut + 1/2gt²
S is the distance of fall
g is the acceleration due to gravity
t is the time taken
Given S = 12.0m, g = 9.81m/s^2, un= 0m/s
12 = 0+1/2(9.81)t²
12 = 4.905t²²²
t² = 12/4.905
t² = 2.446
t = √2.446
t = 1.56secs
b) To determine how fast is the frog falling at this point, we need to calculate the speed of the frog. Using the equaton v = u+gt
v = 0+9.81(1.56)
v = 15.34m/s
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In an aqueous solution where the H+ concentration is 1 x 10-6 M, the OH concentration must be:
A. 14 x 10-6 M
B. 1 x 10-6 M
C. 1 x 10-7 M
D. 1x 10-8 M
E. 14 x 10-8 M
Answers
Answer:
D. 1×10⁻⁸ M
Explanation:
[H⁺] [OH⁻] = 10⁻¹⁴
(1×10⁻⁶) [OH⁻] = 10⁻¹⁴
[OH⁻] = 1×10⁻⁸
The concentration of hydroxyl ion will be [tex]10^{-8}[/tex]M.
What is concentration?The amount of a chemical substance in a mixture is expressed by the substance's concentration.
Calculation of concentration.
Given data:
Concentration of H+ = 1 x [tex]10^{-6}[/tex] M.
It is known that,
[[tex]H^{+}[/tex]][[tex]OH^{-}[/tex]] = [tex]10^{-14}[/tex]M
Now, put the value of concentration of [[tex]H^{+}[/tex]] in above equation.
[1× [tex]10^{-6}[/tex]][[tex]OH^{-}[/tex]] = [tex]10^{-14}[/tex]M
[[tex]OH^{-}[/tex]] = [tex]10^{-14}[/tex] / [1× [tex]10^{-6}[/tex]]M
[[tex]OH^{-}[/tex]] = [tex]10^{-8}[/tex]M
Therefore, the concentration of hydroxyl ion will be [tex]10^{-8}[/tex]M.
Hence, the correct answer will be an option (D).
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Answer:
1. Solid, liquid, gas, plasma
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4. melting
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Answer:
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2. In a solid and liquid, the particles are close together. In a solid, the particles are packed close together and are held in a fixed position. ... In liquids, particles are usually almost as close to each other as in solids.
3. latent heat of vaporization
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An arrow is shot at 27.0° above the horizontal. Its velocity is 54 m/s, and it hits the target.
Answers
Explanation:
(a) What is the maximum height the arrow will attain?
Given:
v₀ᵧ = 54 sin 27.0° m/s = 24.5 m/s
vᵧ = 0 m/s
aᵧ = -9.8 m/s²
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(0 m/s)² = (24.5 m/s)² + 2 (-9.8 m/s²) Δy
Δy = 30.7 m
(b) The target is at the height from which the arrow was shot. How far away is it?
Given:
Δy = 0 m
v₀ᵧ = 54 sin 27.0° m/s = 24.5 m/s
aᵧ = -9.8 m/s²
Find: t
Δy = v₀ᵧ t + ½ aᵧt²
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Given:
v₀ₓ = 54 cos 27.0° m/s = 48.1 m/s
aₓ = 0 m/s²
t = 5.00 s
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WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!TO THE FIRST PERSON WHO ANSWERS!!!!!!!!!!!!!!!!!!!!!
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Answer:
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Answers
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Fill in the names of the neuron parts and their functions. After you've filled in all the answers, click on
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B is the cell body
C is the Axon and the little yellow things are called Schwann cells
E is Axon terminals
And the green thing in the cell body is called the Nucleus
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Brainliest is very appreciated
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A) Dendrite
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What is the sum of all forces that act upon an object called?
a
Net force
b
Balanced force
c
Unbalanced force
d
Gravitational force
Answers
Answer:
net force
Explanation:
The net force is the vector sum of all the forces that act upon an object. That is to say, the net force is the sum of all the forces, taking into account the fact that a force is a vector and two forces of equal magnitude and opposite direction will cancel each other out.
Answer:
a
Explanation:
23 14
2. Calculate: You can use trigonometry to find the initial horizontal and vertical components of the ball's
velocity. Take out your calculator now. Click Reset, and turn off Show velocity vector and Show velocity
components. Set Vinitial to 50.0 m/s and 8 to 60.0 degrees.
A.
To calculate vy, multiply Vinitial by the cosine of the angle: V = Viral · cos(O):
B. To calculate vy, multiply Vmisial by the sine of the angle: v, = Vinitial sin(C):
C. Turn on Show velocity components. Were you correct?
Answers
Answer:
(A). The horizontal initial velocity is 25 m/s.
(B). The vertical initial velocity is 43.3 m/s.
(C). The velocity component is
[tex]u_{x}=u\cos\theta[/tex]
[tex]u_{y}=u\sin\theta[/tex]
Explanation:
Given that,
Initial velocity = 50.0 m/s
Angle = 60°
We need to calculate the component of velocity
Using formula of component
(A). Horizontal initial velocity
[tex]\cos\theta=\dfrac{u_{x}}{u}[/tex]
Put the value in to the formula
[tex]\cos60=\dfrac{u_{x}}{50}[/tex]
[tex]u_{x}=50\times\cos60[/tex]
[tex]u_{x}=25\ m/s[/tex]
(B). Vertical initial velocity
[tex]\sin\theta=\dfrac{u_{y}}{u}[/tex]
Put the value in to the formula
[tex]\sin60=\dfrac{u_{y}}{50}[/tex]
[tex]u_{y}=50\times\sin60[/tex]
[tex]u_{y}=43.3\ m/s[/tex]
The velocity component is
[tex]u_{x}=u\cos\theta[/tex]
[tex]u_{y}=u\sin\theta[/tex]
Hence, (A). The horizontal initial velocity is 25 m/s.
(B). The vertical initial velocity is 43.3 m/s.
(C). The velocity component is
[tex]u_{x}=u\cos\theta[/tex]
[tex]u_{y}=u\sin\theta[/tex]
if a big stone and a small stone is dropped simultaneously from the certain height. they fall together why??
Answers
Because it takes more force to accelerate a mass, and gravity exerts more force on a greater mass. So every object winds up with the same acceleration.
And THAT, of course, says that all objects in the same gravity will pick up the same speed in the same time, and fall the same distance in the same time.
A boat moving at a constant speed travels 15 meters in 8 seconds. How far does it travel
in 40 seconds?
O 75 meters
53 meters
335 meters
480 meters
Answers
How long does it take sound to travel 3525 meters (speed of sound is 330 m/s)?
Answers
3525 / 330 = amount of seconds
Amount if seconds = 11.75
Hope this helped :)
A goose is flying due south at 20 km/hr, the goose is flying into a 15 km/hr due north wind. What is the gooses resultant velocity?
Answers
Answer:
5 km/hr due south
Explanation:
We need to subtract the two velocities due to the fact that they are in opposite directions (one due south and the other one due north). Then, for an observer located on earth, the goose will be flying at :
20 km/hr - 15 km/hr = 5 km/hr
Which of the following is a vector quantity?
A. 30 miles
B. 30 mph northwest
C. 55 m/s
D. 20 mph
Answers
Answer:
B) 30 mph northwest
Explanation: Vector quantities have both direction and magnitude. In this case the direction is northwest, and magnitude is 30 mph.
The following is a vector quantity, 30 mph northwest. Option B is correct.
What is a vector quantity?A vector quantity is a physical quantity that has both magnitude and direction. Examples of vector quantities include displacement, velocity, acceleration, force, and momentum.
In contrast, a scalar quantity is a physical quantity that has only magnitude and no direction associated with it. Examples of scalar quantities include speed, distance, mass, temperature, and time.
Here,
A vector quantity is a physical quantity that has both magnitude and direction. In this case, the magnitude is 30 mph and the direction is northwest, which makes it a vector quantity.
Option A is a scalar quantity because it only has a magnitude, but no direction associated with it. Option C is also a vector quantity because it has both magnitude and direction, but it is not given a direction in the question. Option D is a scalar quantity because it only has a magnitude.
Thus, the following is a vector quantity, 30 mph northwest. Option B is correct.
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a cheerleader throws herself into the air with a velocity of 12 m/s at an angle of 75 degrees above the horizontal. what are the x- and y components of her velocity (show work)
Answers
Answer:
Vx = 3.10 [m/s]
Vy = 11.59 [m/s]
Explanation:
To solve this problem we must decompose the velocity vector by means of the angle on the horizontal.
v = 12 [m/s]
Vx = 12*cos (75) = 3.10 [m/s]
Vy = 12*sin (75) = 11.59 [m/s]
what we call the state in a human body if cerebrum is not functioning well
Answers
If nitrogen, which has an electronegativity of 2.0, bonda with hydrogen, which has an electronegativity of 2.1, the bond between the two atoms will be classified as a(n) _________ covalent bond.
Answers
Answer: it’s Nonpolar
Explanation:
Atoms with small differences in their electronegativities are said to form nonpolar covalent bonds.
Answer:
caden
Explanation:
1 hr 16 minutes equal how many minutes ?
Answers
Answer:
76 minutes.
Explanation:
There are 60 minutes in an hour + 16 minutes= 76 minutes.
What phase of the moon would this be?
1st quarter, waxing half moon
3rd quarter, waning half moon
waxing gibbous
waning gibbous
Answers
Answer:
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Explanation:
Todd and Angela set up a ramp and released several cars from the top. If Todd and Angela want to determine the average speed of their cars down the ramp, what information do they need? Group of answer choices
Answers
Answer:
The ramps length, height, degree, and the weight of the car.
Explanation:
Answer:
I think they need the slope of the ram(degree) .
& current gravitational acceleration
& the length of the ram and also l don't think mass of the cars are not needed becoz the acceleration of the cars are given by its,
Gravitational acceleration * sin( slope).
So then use that in v^2=u^2+2as equation.
s for length
a for acceleration
v for end velocity
u for start velocity
you walk at a speed of 1.5 m/s and it takes you 1800 seconds to get to your friends house. if you follow the same route, how fast would you need to travel to get there un 600 seconds
Answers
Answer:
4 miles per hour
Explanation:
Your welcome
The geometry of a hydrogen-bromide molecule is ____.
Answers
Answer:
polar-molecule
Explanation:
Please help it’s physics and I suck at this subject :(
Answers
Because acceleration is just the change if it starts moving
A 6.46 kg object moving with a velocity of 5.23 m/s is struck from behind by a moving 11.77 kg object. They stick together, moving off with a mutual velocity of 17.93 m/s. What was the original velocity of the 11.77 kg object before the collision?
Answers
Answer:
its z trust me
Explanation:
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What is the height where a 110.8 kg woman would have a gravitational potential energy of 8741 J?
Answers
Answer:
8.042m
Explanation:
Ep = mgh
given that ,
m = 110.8kg
h =?
g = 9.81 m/s^2
Ep= 8741J
8741= 110.8 × 9.81 × h
h= 8741 ÷ ( 110.8 × 9.81 )
h = 8.042m
