Find the magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B.

Answers

Answer 1

Answer:

[tex]B=1.61\times 10^{-4}\ T[/tex]

Explanation:

The attached figure shows the path followed by an electron in the semicircular path from A to B.

Velocity of the electron is, [tex]v=1.42\times 10^6\ m/s[/tex]

It can be seen from the figure that the radius of thenpath, r = 5 cm or 0.05 m

The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,

[tex]Bqv=\dfrac{mv^2}{r}[/tex]

B is the magnitude of the magnetic field

[tex]B=\dfrac{mv}{rq}\\\\\text{Putting all the values}\\\\B=\dfrac{9.1\times 10^{-31}\times 1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}\\\\B=1.61\times 10^{-4}\ T[/tex]

So, the magnitude of the magnetic field is [tex]1.61\times 10^{-4}\ T[/tex].

Find The Magnitude Of The Magnetic Field That Will Cause The Electron To Follow The Semicircular Path
Answer 2

The magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B will be  [tex]B=1.61\times 10^-{4]\ T[/tex]

What is magnetic field?

The magnetic field is defined as when the current passes through the wire, then the magnetic field is generated around the wire in a circular pattern.

The attached figure shows the path followed by an electron in the semicircular path from A to B.

The velocity of the electron is, [tex]v=1.42\times 10^6\ \frac{m}{s}[/tex]

It can be seen from the figure that the radius of then path, r = 5 cm or 0.05 m

The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,

[tex]Bqv=\dfrac{mv^2}{r}[/tex]

B is the magnitude of the magnetic field

[tex]B=\dfrac{mv}{rq}[/tex]

[tex]B=\dfrac{9.1\times 10^{-31}\times1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}[/tex]

[tex]B=1.61\times 10^{-4}\ T[/tex]

So, the magnitude of the magnetic field is  [tex]B=1.61\times 10^-{4]\ T[/tex]

To know more about the magnetic field, follow

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Related Questions

What is the ostrich’s average acceleration from 9.0 to 18s

Answers

Answer:

Explanation:

10.00 5

A force of 50 N acts upon a 10 kg block. Calculate the acceleration of the object.

Answers

acceleration = force / mass = 50/10 = 5 m/s^2

What effect docs temperature have on the dissolution rate in sugar water?

Answers

Sugar dissolves faster in hot water than it does in cold water because hot water has more energy than cold water. When water is heated, the molecules gain energy and, thus, move faster. As they move faster, they come into contact with the sugar more often, causing it to dissolve faster.

Which statement is supported by Kepler's laws?
O The closer a planet is to the Sun, the faster it moves.
O The farther a planet is from the Sun, the faster it moves.
O As a planet moves away from the Sun, its gravitational force increases.
O As a planet moves away from the Sun, its gravitational force remains the same.

Answers

Answer:

A. The closer a planet is to the Sun, the faster it moves.

Explanation:

According to this law, planets move around the sun in elliptical orbits. An imaginary lines drawn from the center of Sun to center of planets will sweep  equal area in equal time interval.

Answer option B,C&D  is incorrect because planets that are far away from the Sun take more time to move all around the Sun and experience less gravitational force and move slower than those near the Sun.

Answer:

a

i am never wrong


8. According to the passage, in order for LeBron James to score a slam-dunk, what must he
exert?

Answers

Answer:

Kenetic Energy?

Explanation:

I need more context of what you are studying here...

I’ve been stuck on this question, what’s the answer to this question?

Answers

Explanation:

[tex]\sf{H_2CO_3 + NaOH \longrightarrow NA_2CO_3 + H_2O}[/tex]

Where [tex]\sf{H_2CO_3 }[/tex] is Carbonic AcidWhere [tex]\sf{ NaOH }[/tex] is Sodium HydroxideReaction gives out [tex]\sf{ NA_2CO_3 + H_2O}[/tex]Where [tex]\sf{ NA_2CO_3 }[/tex] is Sodium HydroxideAnd [tex]\sf{ H_2O}[/tex] is water.

So, [tex]\sf{ NA_2CO_3 }[/tex] Sodium Carbonate is the answer.

Hope it helps :)

What is the frequency of a short-wave radio transmission with a wavelength of 20. m?

Answers

Answer:

just do that

Explanation:

λ = C/f

 Where,

λ (Lambda) = Wavelength in meters

c = Speed of Light (299,792,458 m/s)

f = Frequency

ASAP PLEASE :)
How can we add kinetic energy to a baseball or football?

Answers

Answer:

Hitting it or throwing it with force.

Which is the correct answer?? Can you help please?

Answers

A.) it considered societal needs


I believe so

d2 = 20 m, d1= 50m
What is the magnitude of the resultant?​

Answers

Answer:

53.85m

Explanation:

If we are assuming that d1 is one side of a triangle, and d2 is the other, and we are looking for the magnitude, which is essentially the hypotenuse, we use Pythagorean Theorem. a^2+b^2=c^2. 20^2 + 50^2 = 2900.

The square root of 2900 is 53.85164. Therefore, that is your hypotenuse.

What is true about radioactive isotopes of an atom?


They are less stable.


They are more abundant.


They are more scarce.


They are more stable.

Answers

Answer:

they are less stable

Explanation:

i took the test

The fuel is ignited in a model rocket sitting on a launch pad, which blasts the rocket upward. The rocket goes up because: Group of answer choices air friction pushes on the escaping fuel. the downward force of gravity is less than the downward momentum of the fuel. None of the above. the fuel pushes on the launch pad. the downward force of gravity is greater than the downward momentum of the fuel.

Answers

Answer: The fuel pushes on the launch pad.

Explanation: This is a case of Newton's Third Law of Motion which states for every action in nature, there is an opposite and equal reaction.

Inside the rocket, the fuel is combusted creating a force that exerts on the launch pad by pushing it. As a reaction, the pad pushes the rocket upward, allowing it to go up. This is an example of Newton's Third Law of motion.

If a musician increases the wavelength of the sound waves
she produces without changing their speed, what must be happening to the frequency?
Explain your answer.

Answers

Answer:

The frequency decreases

Explanation:

The frequency will decrease as the wavelength continues to increase.

Wavelength is the distance between successive crests or troughs on a wave motion.

Frequency is the number of waves that passes through a point per unit of time.

    it is expressed as;

                  f  = [tex]\frac{speed }{wavelength}[/tex]

We can see that frequency is inversely proportional to wavelength.

As wavelength increases the frequency reduces.

           

An electron is accelerated from rest by a potential difference of 435 V. It then enters a uniform magnetic field of magnitude 167 mT with its velocity perpendicular to the field. Calculate (a) the speed of the electron and (b) the radius of its path in the magnetic field.

Answers

Answer:

(a) the speed of the electron is 1.237 x 10⁷ m/s

(b) the radius of its path in the magnetic field is 4.21 x 10⁻ m

Explanation:

Given;

potential difference, V = 435 V

magnetic field, B = 167 mT = 0.167 T

(a) the speed of the electron

eV = ¹/₂mv²

[tex]v = \sqrt{\frac{2eV}{m} }\\\\ v = \sqrt{\frac{2(1.6*10^{-19})(435)}{(9.1*10^{-31})}}\\\\v = 1.237*10^7 \ m/s[/tex]

(b) the radius of its path in the magnetic field

[tex]r = \frac{mv}{eB}\\\\r = \frac{(9.1*10^{-31})(1.237*10^7)}{(1.6*10^{-19})(0.167)}\\\\r = 4.21 *10^{-4} \ m[/tex]

10. when creating a cardiovascular fitness routine which program would be appropriate?
A Sprint a short distance
B Lift a heavy weights
C Run for a long time
D Use the entire range of motion

13. what would be an appropriate amount of time to hold a static stretch?
A 5 seconds
B 20 seconds
C 1 minute
D 5 minute

14. what activity may help prevent injury if it is performed prior to playing a sport?
A weight thing
B dynamic stretching
C high intensity interval training
D sprints

15. when your workout routines gets too easy what should you do?
A Increase the frequency
B Increase the intensity
C Increase the time
D All​




PLEASE HELP

Answers

Answer:

10. B

13. It's actually 30 seconds but 20 comes closest so B

14. B, any type of stretching is good before you perform any type of physical activity because it loosens up the muscles

15. D, all of the above

Explanation:

I have done many sports in my life and am still very active, I grew to know most of these things through the years.

A box weighing 52.4 N is sliding on a rough horizontal floor with a constant friction force of magnitude LaTeX: ff. The box's initial speed is 1.37 m/s and it stops after 2.8 s. Determine the magnitude of the friction force exerted on the box.A box weighing 52.4 N is sliding on a rough horizontal floor with a constant friction force of magnitude LaTeX: ff. The box's initial speed is 1.37 m/s and it stops after 2.8 s. Determine the magnitude of the friction force exerted on the box.

Answers

Answer:

The magnitude of the friction force exerted on the box is 2.614 newtons.

Explanation:

Since the box is sliding on a rough horizontal floor, then it is decelerated solely by friction force due to the contact of the box with floor. The free body diagram of the box is presented herein as attachment. The equation of equilbrium for the box is:

[tex]\Sigma F = -f = m\cdot a[/tex] (Eq. 1)

Where:

[tex]f[/tex] - Kinetic friction force, measured in newtons.

[tex]m[/tex] - Mass of the box, measured in kilograms.

[tex]a[/tex] - Acceleration experimented by the box, measured in meters per square second.

By applying definitions of weight ([tex]W = m\cdot g[/tex]) and uniform accelerated motion ([tex]v = v_{o}+a\cdot t[/tex]), we expand the previous expression:

[tex]-f = \left(\frac{W}{g} \right)\cdot \left(\frac{v-v_{o}}{t}\right)[/tex]

And the magnitude of the friction force exerted on the box is calculated by this formula:

[tex]f = -\left(\frac{W}{g} \right)\cdot \left(\frac{v-v_{o}}{t}\right)[/tex] (Eq. 1b)

Where:

[tex]W[/tex] - Weight, measured in newtons.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]v_{o}[/tex] - Initial speed, measured in meters per second.

[tex]v[/tex] - Final speed, measured in meters per second.

[tex]t[/tex] - Time, measured in seconds.

If we know that [tex]W = 52.4\,N[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], [tex]v_{o} = 1.37\,\frac{m}{s}[/tex], [tex]v = 0\,\frac{m}{s}[/tex] and [tex]t = 2.8\,s[/tex], the magnitud of the kinetic friction force exerted on the box is:

[tex]f = -\left(\frac{52.4\,N}{9.807\,\frac{m}{s^{2}} } \right)\cdot \left(\frac{0\,\frac{m}{s}-1.37\,\frac{m}{s} }{2.8\,s} \right)[/tex]

[tex]f = 2.614\,N[/tex]

The magnitude of the friction force exerted on the box is 2.614 newtons.

The period of a pendulum is measured 16 times. The average value of the period over these 16 trials is calculated to be 1.50 seconds, whereas the standard deviation is found to be 0.24 seconds. The standard error (or standard deviation of the mean) therefore is 0.24 seconds divided by the square root of 16, yielding 0.06 seconds. Assuming that the uncertainty of this period arises solely from random error for these 16 trials, about how many additional trials would need to be completed to reduce the standard error to 0.03 seconds? ______________

Answers

Answer:

The additional trials needed is 48 trials

Explanation:

Given;

initial number of trials, n = 16 trials

the standard deviation, σ = 0.24 s

initial standard error, ε = 0.06 s

The standard error is given by;

[tex]\epsilon = \frac{\sigma}{\sqrt{n} }[/tex]

To reduce the standard error to 0.03 s, let the additional number of trials = x

[tex]0.03= \frac{0.24}{\sqrt{n+x} } \\\\0.03= \frac{0.24}{\sqrt{16+x} }\\\\0.03\sqrt{16+x} = 0.24\\\\\sqrt{16+x} = \frac{0.24}{0.03} \\\\\sqrt{16+x} = 8\\\\16+x = 8^2\\\\16+x = 64\\\\x = 64 -16\\\\x = 48 \ trials[/tex]

Therefore, the additional trials needed is 48 trials.

is it better to walk or run in the rain?

Answers

Answer:

Not gonna lie. I actually had to think about this a lot XD

Running in the rain can cause you to slip and get hurt. Which I think isn't what you would want.

Walking in the rain (although it is sad), is actually a better idea than running.

Hope this helps!

Answer:

Walk

Explanation:

Running might stop you from being outside for as long, but running on wet ground will most likely result in a not-so-graceful faceplant.

A crate is pulled with a force of 165 N at an angle 30°
northwest. What is the resultant horizontal force on the crate?
Help asap?

Answers

Answer: 143 N

Explanation:

3. Pencils should not be used inside the computer to change the setting of switches or to
and
pry off jumpers because the tip contains lead which can act as a
may damage the computer Components.​

Answers

Answer: True

Explanation:

Pencils indeed should not be used as tools when working inside a computer because it is made of Lead.

Lead is a conductor of electricity and as such if it is left inside the computer at even miniscule quantities, it can redirect electricity and damage components in the process.

If one wants to work inside a computer, it is best to use tools like tweezers and needle-nose pliers.

Due to the presence of graphite(A good conductor of electricity), Pencils should not be used inside the computer to change the setting of switches.

What is the meaning of conductors?

The conductors are the materials that can allow electricity and heat to pass through them.

Since the pencils are made up of graphite which is a good conductor of electricity. When we use pencils to do something inside the computer circuits and if some portion of the graphite remains on the circuit board.

Now due to the good conducting property of the graphite, it will allow the current to flow and the short circuit of the circuit board can take place which will damage the computer.

Thus due to the presence of graphite(A good conductor of electricity). Pencils should not be used inside the computer to change the setting of switches.

To know more about Conducting materials follow.

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Sheba is texting and driving. She does not see the baby chinchila
sitting in the road! If she was traveling at 35 m/s, and at best her
car can accelerate at -3.5 m/p/s, how far would it take her to stop?

Answers

Answer:

dfmwekognjioq 4eijqgi24gno3p2qtijoq2 gjo23ijgto32tneqew gqewkgnoweqgmnlqwe gwjoegkqwji4toqn34goti34

Explanation:

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