Consider the line y=9x-1.
Find the equation of the line that is perpendicular to this line and passes through the polnt (6, -5).
Find the equation of the line that is parallel to this line and passes through the point (6,-5).

Answers

Answer 1

Step-by-step explanation:

Slope=9

i)

[tex]y−y1=m(x−x1)[/tex]

When line is parallel

y+5=9(x-6)

y+5 = 9x - 54

59 = 9x-y

When line is perpendicular

y+5=-1/9(x-6)

9(y+5)= -1(x-6)

9y + 45 = -x+6

x+9y = -39

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Related Questions

What is the height of soil?

Answers

Answer:Eight to 12 inches is usually adequate. If drainage is a problem, or if the plants you are growing prefer drier soil, the bed could be taller and filled with a porous growing medium.

Step-by-step explanation:

100 points.
In a coordinate plane a figure can be reflected by a line other than the x- or y - axis.
Identify the linear equation for the reflection of Object E and E'?

Answers

Answer:

When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite (its sign is changed).

Step-by-step explanation:

hope this helps if does mark brainllest

PLSSS HELP ME
(5x5)/[10x22]-4\52

Answers

Answer: 21/572

[tex]\frac{5.5}{10 . 22} - \frac{4}{52}[/tex]

The dots stand for multiplication

Please help 50 points+Brainlest

Answers

Answer:

The correct polynomial is F. Calculation errors combining h terms and distributing -1.

Step-by-step explanation:

[tex]( - 4h + 3)( {h}^{2} + 9h - 1)[/tex]

[tex] - 4 {h}^{3} - 36 {h}^{2} + 4h + 3 {h}^{2} + 27h - 3[/tex]

[tex] - 4 {h}^{3} - 33 {h}^{2} + 31h - 3[/tex]

At a football game, 92% of people attending were supporting the home team, while 8% were supporting the visiting team. If 1564 people attending the game supported the home team, what was the total number of people attending the game?

Answers

1564 = .92x

1564 / .92. = x

1700 = x

The total number of people attending the game is 1700.

What is Percentage?

Percentage in simple terms can be defined as a part per 100.

Percentage is a ratio or number which has to be defined as a fraction of 100.It is denoted by %.

If we are asked to calculate the percent of a number simply divide it by the whole part or number and then multiply with 100.

Percent of people supporting the home team = 92%

Number of people supporting the home team = 1564

Let x be the total number of people attending the game.

⇒ [tex]\frac{1564}{x}[/tex] × 100 = 92

⇒ [tex]\frac{1564}{x}[/tex] = 0.92

⇒ x = [tex]\frac{1564}{0.92}[/tex]

⇒ x = 1700

Hence, the total number of people attending the game will be 1700.

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help me please- find the equation of line a

Answers

Check the picture below.

let's notice something, the equation of line B is in slope-intercept form, thus

[tex]y = 2x + \underset{\stackrel{\uparrow }{b}}{2}\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]

so using that grid scale, we can just get two points from the line A to get its equation, let's use those in the picture below

[tex](\stackrel{x_1}{-6}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{0}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{0}-\stackrel{y1}{(-6)}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{(-6)}}}\implies \cfrac{0+6}{6+6}\implies \cfrac{1}{2}[/tex]

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-6)}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{(-6)}) \\\\\\ y+6=\cfrac{1}{2}(x+6)\implies y+6=\cfrac{1}{2}x+3\implies y=\cfrac{1}{2}x-3[/tex]

Solve for x show work
3(2x-5)=4x+33

Answers

[tex]\qquad \qquad \huge \pink {\sf{☁Answer☁}} \\ \\ [/tex]

[tex] \large \purple { \rm{Let's \: solve→}} \\ [/tex]

[tex] \rm{3(2x-5)=4x+33} \\ \\ \rm {solving \: bracket} \\ \\ \rm{6x - 15= 4x + 33} \\ \\ \rm{arranging \: terms} \\ \\ \rm{6x - 4x = 33 + 15} \\ \\ \rm{2x = 48} \\ \\ \rm{x = \frac{48}{2} } \\ \\ \rm{x = \cancel \frac{48}{2} } \\ \\ \rm{x = 24}[/tex]

[tex]\purple{\rule{15mm}{2.9pt}} \red{\rule18mm{2.5pt}} \orange{ \rule18mm{2.5pt}}[/tex]

[tex]\sf{\:мѕнαcкεя\: ♪...}[/tex]

Answer:

[tex]\fbox{X = 24}[/tex]

Solution:

Given expression ➟ 3(2x-5) = 4x + 33,

using distributive property open the above bracket,

➳ 3×2x - 3×5 = 4x + 33

Using BODMAS solve the L.H.S,

➳ 6x - 15 = 4x + 33

now arrange the like terms aside,

➳ 6x - 4x = 33 + 15

➳ 2x = 48

➳ x = 48/2

➳ x = 24

the given expression is true for x = 24

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Can someone help me with this, I got 115 from 180-65 is this right?

Answers

Answer:

yes

Step-by-step explanation:

your answer is correct

Answer:

115

Step-by-step explanation:

If 65 is subtracted from 180the answer is 115

Please help me ASP! Could anyone tell me what 3 x what gets me to 90?

Answers

Answer:

3*30 = 90

Step-by-step explanation:

3*30 = 90

I need this today
pls help

Answers

Answer:

5. radius= TD

inscribed angle =RQS

diameter =TA

6. radius=SY

secant=TU

Tangent=S

50 POINTS FOR THE CORRECT ANSWER!

Answers

f(n)=f(n-1)-3

So

f(2)

f(1)-317-314

f(3)

f(2)-314-311

f(4)

f(3)-311-38

Which is the exponential form of logb 14 = 2? 2b = 14 b2 = 14 b14 = 2 142 = b

Answers

Answer:

[tex]b^2 = 14[/tex]

Step-by-step explanation:

log(base)(power) = (exponent).

In this case: logb(14) = 2

Note the variable/number in place of each term. Set the equation:

base^power = exponent

[tex]log_b 14 = 2\\b^2 = 14[/tex]

[tex]b^2 = 14[/tex] is your answer.

~

#9 what is the answer

Answers

The triangles ABC and EDC have corresponding sides

The triangles ABC and EDC are similar

How to prove that the triangles ABC and EDC are similar?

The given parameters are:

ED = 8, DC = 10, EC = 12, AB = 12

BC = 15 and AC = 21

To determine that the triangles are similar, we simply divide the corresponding sides to determine the scale factor (k).

So, have:

k = AB/ED = BC/DC

This gives

k = 12/8  = 15/10

Evaluate the quotients

k = 1.5 = 1.5

The scale factors are equal

Hence, the triangles ABC and EDC are similar

Readmore about similar triangles at:

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I need help with this fast

Answers

B is the answer.
Hope this helps

i don’t understand this question

Answers

Step-by-step explanation:

to figure this out you would have to take all the numbers and do the rise over run technique

Choose the angle which is vertical to angle BFC in the following figure.
answer A angle CFD
answer B angle DFE
answer C angle AFC
answer D angle EFA

Answers

Angle DFE. Hope this helped.

Work out
21
% of
£
944.13
Give your answer rounded to 2 DP. I need right awnsers you can use calculators

Answers

Answer: £198.27

Step-by-step explanation:

944.13x0.21=198.2673Rounded to 2 decimal places that is 198.27

The sum of two positive integers is 31. If the sum of the squares of these numbers is 625,find the smaller of the numbers.

Answers

Step-by-step explanation:

It is given that, the sum of two positive integers is 31 and the sum of the squares of these numbers is 625 and we are to find the smaller of the numbers.

So, let the two positive integers be x and y.

Therefore,

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x + y = 31 \: \: ........ \: (i) }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + y {}^{2} = 625 \: ...... \: (ii)}}} \\ \\[/tex]

Now, From the first equation we have,

[tex]\\ {\longrightarrow \pmb{\sf {\qquad x + y = 31 }}} \\ \\ [/tex]

[tex] {\longrightarrow \pmb{\sf {\qquad y = 31 - x \: ...... \: (iii)}}} \\ \\ [/tex]

Now, substituting the value of y in equation (ii) we get :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x {}^{2} + (31 - x) {}^{2} = 625}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + (31 {}^{2} - 2.x.31 + x{}^{2} ) = 625}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + (961 - 62x + x{}^{2} ) = 625}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} + 961 - 62x + x{}^{2} - 625 = 0}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad 2 x {}^{2} + 336 - 62x = 0}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad 2 x {}^{2} - 62x + 336 = 0}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad 2( x {}^{2} - 31 + 168) = 0}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad \frac{2}{2} ( x {}^{2} - 31 + 168) = \frac{0}{2} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x {}^{2} - 31 + 168 = 0}}} \\ \\[/tex]

Now using the quadratic formula :

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} }}} \\ \\[/tex]

Where,

a = 1

b = -31

c = 168

[tex] \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ - (- 31) \pm \sqrt{ {31}^{2} - 4(1)(168)} }{2(1)} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 \pm \sqrt{ 961 -672} }{2(1)} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 \pm \sqrt{ 289} }{2(1)} }}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 \pm 17 }{2(1)} }}} \\ \\[/tex]

Now, we have two equations,

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 + 17 }{2} \: ... .....\: (iv)}}} \\ \\[/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 - 17 }{2} ... .....\: (v)}}} \\ \\[/tex]

So, Equation (iv) :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 + 17 }{2} }}} \\ \\ [/tex]

[tex]\\ {\longrightarrow \pmb{\sf {\qquad x = \frac{ 48 }{2} }}} \\ \\ [/tex]

[tex]\\ {\longrightarrow \pmb{\sf {\qquad x = 24 }}} \\ \\ [/tex]

Now, Equation (v) :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad x = \frac{ 31 - 17 }{2}}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \frac{ 14 }{2}}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad x = \: 7}}}\\ \\ [/tex]

So, the value of x is 7 or 24

Now, we are to find the value of y.

Substituting the value of x (24) in equation (iii) :

[tex] \\ {\longrightarrow \pmb{\sf {\qquad y = 31 - x \:}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad y = 31 - 24 \:}}} \\ \\ [/tex]

[tex]{\longrightarrow \pmb{\sf {\qquad y = 7 \:}}} \\ \\ [/tex]

Again, Substituting the value of x (7) in equation (iii) :

[tex]\\ {\longrightarrow \pmb{\sf {\qquad y = 31 - x \:}}} \\ \\ [/tex]

[tex] {\longrightarrow \pmb{\sf {\qquad y = 31 - 7 \:}}} \\ \\ [/tex]

[tex]\\ {\longrightarrow \pmb{\sf {\qquad y = 24 \:}}} \\ \\ [/tex]

Therefore,

The value of y is also 7 or 24.

[tex] \\ [/tex]

So, The smaller of the numbers is 7 .

Question : -

The sum of two positive integers is 31. If the sum of the squares of these numbers is 625, find the smaller of the numbers.

Given : -

Sum of two positive numbers = 31

Sum of squares of these numbers = 625

To Find : -

We have to find the smaller of the numbers .

Concept : -

This question belongs to quadratic equations so we have to find the answer by making equation and solving it .

To Assume : -

Let the first no. be x

Let the second no. be y

So let's get started with Solution :

According to question , sum of two positive integers is 31 . So ,

x + y = 31 --------- ( Equation 1 )

According to question , sum of square

of these numbers is 625 . So ,

x² + y² = 625 --------- ( Equation 2 )

From equation 1 ( x + y = 31 ) , Value

of x :

x = 31 - y

Now , putting value of x in eq. 2 :

x² + ( 31 - x )² = 625

x² + ( 31 )² - ( 2 × 31 × x ) + x² = 625

2x² + 961 - 62x = 625

2x² - 62x = 625 - 961

2x² - 62x = -336

2x² - 62x + 336 = 0

2(x² - 31x + 168 ) = 0

x² - 31x + 168 = 0

Solving it by using middle term

splitting :

x² -24x -7x + 168 = 0

x ( x - 24 ) -7 ( x - 24 ) = 0

( x - 7 ) ( x - 24 )

So ,

First number ,

x - 7 = 0x = 7 { Smaller Number }

Second Number ,

x - 24 = 0x = 24

Verification :

According to question ,

Sum of numbers is equal to 31 :

x + y = 31

7 + 24 = 31

L.H.S = R.H.S

Sum of squares of these numbers is equal to 625 :

x² + y² = 625

7² + 24² = 625

49 + 576 = 625

625 = 625

L.H.S = R.H.S

Therefore , our value for x and y are true. Thus our answer is valid.

#[tex] \rm{Keep \: Learning}[/tex]

Does anybody know this? I really need help.

Answers

Answer:

22 is th area

Step-by-step explanation:

Hi please help with an explanation as well, I’ll reward branliest!!!

Answers

Answer:

1. B = 6 m²

2. h = 2 m

3. V = 12 m³

Step-by-step explanation:

the base is a right triangle

Then

[tex]B=\frac{3\times 4}{2} =6\ m^{2}[/tex]

____________

The height of the prism is the length of the segment that join the base to its opposite face

Then

h = 2m (given)

___________

The volume of the prism :

[tex]V=B\times h=6\times 2=12 m^3[/tex]

Can someone please help me with this question thank you !!

Answers

Answer:

Area of cube = 6l²

= 6×2²

= 24 ft²

given:

2 feet.

to find:

how many square feet of wood he used to build the box.

solution:

each side measures 2ft.

A=L²=(2 ft)²=4 ft²

A cube has 6 sides so the total quantity of wood is:

Wood=6×A

=6×4 ft²

=24 ft²

he used 24 ft² of wood to build the box.

A train museum has a toy train that goes around the entire museum. the train goes around 10 times in 2 hours.

A student calculated the amount of times it takes for the train to go around 1 time. the work is shown.

2 hours ÷ 10 = 0.2 hour

0.2 is the same as 0.20, so it takes 20 minutes for the train to go around 1 time

the student's work is incorrect.

explain any error in the student's work
explain how to correct the student's work and find the amount of time it took for the train to go around the museum 1 time

Answers

Answer:

See below

Step-by-step explanation:

.2 of an hour   is     .2 * 60 min = 12 min

120 min / 10 times = 12 min per trip

The train takes 12 minutes to go around the museum once.

What is multiplication?

A mathematical arithmetic operation is multiplication. Moreover, it is the practice of repeatedly adding the same expression kinds.

Example: 2 x 3 means that 2 is multiplied by 3 or that 3 is multiplied by 2 times.

A toy train that travels the length of a train museum is present. In two hours, the train travels roughly ten times.

The error in the student's work is converting 0.2 hours to 20 minutes. 0.2 hours is equal to 12 minutes, not 20 minutes.

To correct the student's work, we can multiply 0.2 by 60 to convert it to minutes:

0.2 hours × 60 minutes/hour = 12 minutes

Therefore, it takes 12 minutes for the train to go around the museum 1 time.

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What is the scale factor? Multiple choice

Answers

Answer:

0.753/4post/pre

Step-by-step explanation:

In general, a scale factor is applied to an original (pre) to obtain an image (post). It is the ratio post/pre that expresses the relationship between image dimensions and original dimensions.

Here, that post/pre ratio is 3/4 = 0.75.

BRAINLIEST TO WHOEVER GETS IT RIGHT
Which of the following accurately shows the first step when solving the following system of equations by substitution?
f(x) = -4x^2 + 3x + 1
g(x) = -6x +5
a -4x^2+ 3x + 1 = -6x +5
b 4x^2 + 3x +1 - 6x + 5 = 0
c g(x)= -6(-4x^2 + 3x + 1) + 5
df() = -4(-6x + 5)^2 +3(-6x + 5) +1

Answers

Answer:

c and d

Step-by-step explanation:

because

- In f(x),evey time you find  X you write(-6x+5) instead

4x²-----------4(-6x+5)²

3x+1------------3(-6x+5) +1

-In g(x),evey time you find  X you write(-4x² +3x+1)  instead          

1. What is the 90th percentile if the sample size is 11?

2. What is the simple size if the degree of freedom is 30?
A. 29
B. 31
C. 28
D. 30

3. What is the t-value if the sample size is 16 and area is 0.10?

4. In the t-distribution, what is the degree of freedom if n = 19?

I NEED IT NOW PLSS

Answers

The answer should be D. I believe so

Find the length of the third side. If necessary, write in simplest radical form.

IMAGE DOWN BELOW!

SOMEONE PLEASE HELP ME!! ILL GIVE YOU BRAINLIST ANSWER

Answers

Answer:

square root of 39

Step-by-step explanation:

5^2+b^2=8^2

25+b^2=64

64-25=39

It’s the square root of 39

How were the policies of President Kennedy and President Johnson similar and different?

Answers

The ways that the policies of President Kennedy and President Johnson are similar and different is given below:

Both President were similar as they both were from heavily political and big families.  Kennedy and Johnson were known to be similar in a lot of the ways especially in the way that they ran the country.

After the assassination of Kennedy, Johnson was known to have followed the footsteps of his predecessor's and went ahead on implementing some of his programs.  Johnson was known to have went ahead with the the anti-poverty program and the Civil Rights Bill.

What is a difference between John F. Kennedy and Lyndon Johnson?

The differences between the both presidents were:

President Kennedy was known to be a better public speaker when compared to President Johnson.President Kennedy has his origin from the North, while that of Johnson was from the South.President Kennedy was used to be seen in affluent crowd, but Johnson was known to be a  simple Texan Man.

Conclusively, these two president were said to be very were similar, and yet they were different.

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A Magic 8 Ball has the diameter of 5" how much space is occupied by the water round to the nearest 10th(PLEASE ANSWER PLEASE)

Answers

Answer:2.4 isn’t occupied, whilst 13.3 is full

Step-by-step explanation: answerrr

Does anyone know the perimeter and the area of them?

Answers

perimeter: 1+4+4+2 = 11
perimeter: 2+9+4+6+7+3 = 31

evaluate: 3 /7 + ( −11 /4 ) + 16 /5 − ( −18 /7 )

Answers

Answer:

This is hard

Step-by-step explanation:

I'm so sorry I can't do it

Answer:

[tex]\frac{69}{20}[/tex]

Step-by-step explanation:

[tex]\frac{3}{7} -\frac{11}{4} +\frac{16}{5} +\frac{18}{7}[/tex]

= [tex]\frac{3}{7} +\frac{18}{7}-\frac{11}{4} +\frac{16}{5}[/tex]

= [tex]\frac{21}{7} -\frac{11}{4} +\frac{16}{5}[/tex] As both denominators have 7 you can add their numerators

=[tex]\frac{21}{7} -(-\frac{9}{20})[/tex]     L.C.M

=[tex]\frac{21}{7} +\frac{9}{20}[/tex]   L.C.M

=[tex]\frac{69}{20}[/tex]

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