Can air be forced into a smaller space? Explain with an example.
I will give out brainliest to person who has best answer☺️

Answer:

Distance = 15km

Displacement = 1km

Explanation:

the total distance covered is how far Justin has travelled =  4km + 4km + 4km + 3km

Total distance covered = 15km

To get the displacement, we will use the Pythagoras theorem. Find the diagram attached.

From the diagram, the displacement D is expressed as:

D = AC - BC

From the diagram

AC = 4km

BC = 3km

D = 4km - 3km

D = 1km

Hence his displacement is 1km

Answer:

Explanation:

From  the question we are told that

   The mass of chlorine ion is [tex]m_c  =  35u  =  35 * 1.66*10^{-27} =  5.81*10^{-26}\ kg[/tex]

    The charge is  [tex]q =  5e   = 5 *  1.60 *10^{-19} = 8.0*10^{-19}\ C[/tex]

   The potential difference is  [tex]V  =  250 kV  =  250*10^{3}  \  V[/tex]

    The radius of curvature of the path is  [tex]r = 3.5 \ m[/tex]

Gnerally the magnetic force will cause the speed of the  chlorine ions to change from 0 m/s to [tex]v_y[/tex] m/s along the y -axis but will not affect the velocity along the x-axis

Generally according the law of energy conservation

          [tex]K =  PE[/tex]

Here K is the kinetic energy of the of the chlorine ions which is mathematically represented as

      [tex]K  =  \frac{1}{2} mv^2[/tex]

And  PE is electric potential  energy which is mathematically represented as

       [tex]PE  =   Q *  V[/tex]

So

      [tex] \frac{1}{2} mv^2 =  Q *  V [/tex]

=>   [tex] \frac{1}{2} *  5.81*10^{-26}  *  v^2 =  8.0*10^{-19} *  250*10^{3} [/tex]

=>    [tex] v =  sqrt{6.8847 *10^{12}} [/tex]

=>    [tex] v = 2.634 *10^{6} \ m/s [/tex]

Answer: However, the Internet takes digital photo manipulation.

Explanation: This discussion is not only limited to digital manipulation, but also includes .However, there was no way to take this image in a single exposure .

Answer:

i am just trying it could be wrong too i am not sure about it but according to me the ans is (1)let ice be allowed to float naturally in the water

Explanation:

if u put water in ice or ice in water the temperature of water decreases and then the process gets slower but if u allow to float it then the temperature of water and surrounding air decreases and the heat is lost from air and water both so here the heat is more than only just water here it allows both to give heat and in 2nd option the heat is only lost by water and gained by icehere it allows only water to give heat so the heat is less in surrounding of ice in water so more heat more faster the process therefore i think the 1st option is correct

Answer:

Gamma Rays

Explanation:

Because it has the most energetic radiation and could penetrate through six feet of concrete. It is so strong it can damage your dna.

Answer:

1. W = 8848 J

2. W = 7848 J

3. W = 6848 J

Explanation:

The work (W) can be found using the following equation:

[tex] W = E_{k} + E_{p} [/tex]

Where: E(k) is the kinetic energy and E(p) is the potential energy

Now let's find the work for every stage.

Stage 1:

[tex] W = E_{k} + E_{p} = \frac{1}{2}mv^{2} + mgh [/tex]

Where: m is the mass, g is the gravity, h is the height, v is the speed  

[tex] W = \frac{1}{2}mv^{2} + mgh = \frac{1}{2}80 kg*(5 m/s)^{2} + 80 kg*9.81 m/s^{2}*10 m = 8848 J [/tex]

Stage 2:

[tex] W = E_{k} + E_{p} = 0 + E_{p} [/tex]

The kinetic energy is equal to zero because the acceleration is constant.

[tex] W = E_{p} = mgh = 80 kg*9.81 m/s^{2}*10 m = 7848 J [/tex]

Stage 3:

[tex] W = E_{k} + E_{p} = \frac{1}{2}mv^{2} + mgh = -\frac{1}{2}80 kg*(5 m/s)^{2} + 80 kg*9.81 m/s^{2}*10 m = 6848 J [/tex]      

I hope it helps you!

Answer:

2.405 m/s

Explanation:

Given that,

Mass of a women, m₁ = 60 kg

Mass of a ball, m₂ = 3.9 kg

Velocity of the ball, v₂ = 37 m/s

We need to find the velocity of the woman. It is a concept based on the conservation of linear momentum. Let v₁ is the velocity of the woman. So,

[tex]m_1v_1=m_2v_2\\\\v_1=\dfrac{m_2v_2}{m_1}\\\\v_1=\dfrac{3.9\times 37}{60}\\\\v_1=2.405\ m/s[/tex]

So, the velocity of the woman is 2.405 m/s.

Answer:

The radius of curvature of the curved path of the airplane is 23784.356 meters (23.784 kilometers).

Explanation:

We assume that airplane can be represented as a particle. The free body diagram of the vehicle is presented below as attachment, whose variables are:

[tex]W[/tex] - Weight of the airplane, measured in newtons.

[tex]F[/tex] - Lift, measured in newtons.

[tex]\theta[/tex] - Banking angle, measured in sexagesimal degrees.

The equations of equilibrium associated with the airplane are, respectively:

[tex]\Sigma F_{r} = F\cdot \sin \theta = m\cdot \frac{v^{2}}{R}[/tex] (Eq. 1)

[tex]\Sigma F_{z} = F\cdot \cos \theta - W = 0[/tex] (Eq. 2)

From (Eq. 2):

[tex]F = \frac{W}{\cos \theta}[/tex]

In (Eq. 1):

[tex]W\cdot \tan \theta = m\cdot \frac{v^{2}}{R}[/tex]

By using the definition of weight, we eliminate the mass of the airplane:

[tex]g\cdot \tan \theta = \frac{v^{2}}{R}[/tex]

Where:

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]v[/tex] - Speed, measured in meters per second.

[tex]R[/tex] - Radius of curvature, measured in meters.

Lastly, we clear the radius of curvature with the expression:

[tex]R = \frac{v^{2}}{g\cdot \tan \theta}[/tex]

If we know that [tex]v = 250\,\frac{m}{s}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\theta = 15^{\circ}[/tex], the radius of curvature is:

[tex]R = \frac{\left(250\,\frac{m}{s} \right)^{2}}{\left(9.807\,\frac{m}{s^{2}} \right)\cdot \tan 15^{\circ}}[/tex]

[tex]R = 23784.356\,m[/tex]

The radius of curvature of the curved path of the airplane is 23784.356 meters (23.784 kilometers).

Answer:

a. N = 2.49W b.  0.40

Explanation:

a. What is the magnitude of the normal force FNFN between a rider and the wall, expressed in terms of the rider's weight W?

Since the normal force equals the centripetal force on the rider, N = mrω² where r = radius of cylinder = 3.05 m and ω = angular speed of cylinder = 0.450 rotations/s = 0.450 × 2π rad/s = 2.83 rad/s

Now N = mrω² = m(3.05 m) × (2.83 rad/s)² = 24.43m

The rider's weight W = mg = 9.8m

The ratio of the normal force to the rider's weight is

N/W = 24.43m/9.8m = 2.49

So the normal force expressed in term's of the rider's weight is

N = 2.49W

b. What is the minimum coefficient of static friction µsμs required between the rider and the wall in order for the rider to be held in place without sliding down?

The frictional force, F on the rider by the wall of the cylinder equals the weight, W of the rider. F = W.

Since the frictional force F = μN, where μ = coefficient of static friction between rider and wall of cylinder and N = normal force between rider and wall of cylinder.

So, the normal force equals

N = F/μ = W/μ = mg/μ = mrω²

μ  = mg/mrω²

= W/N

= 9.8m/24.43m

= 0.40

Answer:

Same, 2 km/h/s

Explanation:

Acceleration is change in velocity over time.

a = Δv / Δt

The car's acceleration is:

a = (65 km/h − 60 km/h) / 2.5 s

a = 2 km/h/s

The bicycle's acceleration is:

a = (5 km/h − 0 km/h) / 2.5 s

a = 2 km/h/s

Answer: (B) Too many to count

Explanation: Have a wonderful day everyone! :D

The exercises that encompasses stretching in the human body is : B) too many to count

exercises can be defined as any activity that puts your muscle to work and helps burn calories in your body.

exercises are one of the keys to staying and living healthy.

exercises are of different types and forms and some encompasses stretching in the human body.

In conclusion, The exercises that encompasses stretching in the human body is too many to count

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Answer:

Mass of bullet is m=0.01kg

Mass of the block is M=4kg

Coefficient=0.25,distance=20m

So, let the speed of the block just after the bullet embedded in it be V and v be the speed of bullet before striking the block,

By applying conservation of momentum,

mv=(m+M)V

V=

M+m

mv

Explanation:

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The initial velocity of the bullet is 382 m/s

The given parameters;

Apply the principle of conservation of mechanical energy;

The maximum potential energy of the bullet-wood system at the top of the port  = maximum kinetic energy of the system at the base of the port.

[tex]K.E_{max} = P.E_{max}\\\\\frac{1}{2} mv_{max}^2 = mgh_{max}\\\\v^2_{max} = 2gh_{max}\\\\v_{max} = \sqrt{2gh_{max}} \\\\v_{max} = \sqrt{2\times 9.8\times 2} \\\\v_{max} = 6.26 \ m/s[/tex]

Apply the principle of conservation of linear momentum to determine the initial velocity of the bullet;

[tex]m_1u_1 + m_2u_2 = v(m_1 + m_2)\\\\0.6(0) + 0.01(u_2) = 6.26((0.6 + 0.01)\\\\0.01u_2 = 3.819\\\\u_2 = \frac{3.819}{0.01} \\\\u_2 = 381.9 \ \approx 382 \ m/s[/tex]

Thus, the initial velocity of the bullet is 382 m/s

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When faced with limited funding to complete a year-long study on the relationship between certain diseases and people's diets she can best overcome this by conduct smaller studies for more than a one-year period, study only a very small group of people, conduct a study about something else, use data from a similar study and adjust it to fit her study.

The correct answer would be all of the above.

There are several strategies the scientist can consider to overcome this limitation. Each option has its own advantages and potential drawbacks, so the scientist should carefully evaluate which approach aligns best with her research goals and available resources.

1. Conduct smaller studies for more than a one-year period: Instead of one large-scale study, the scientist can break down the research into smaller, more manageable studies. This approach allows for incremental progress, and findings from each smaller study can contribute to the overall understanding of the topic. By conducting multiple studies over an extended period, the scientist can still gather valuable data and draw meaningful conclusions.

2. Study only a very small group of people: Focusing on a small group of participants can reduce costs and streamline data collection and analysis. While the sample size may be limited, the scientist can still gain insights into the relationship between diseases and diet within this specific group. However, generalizing the findings to a larger population may be challenging due to the limited sample size.

3. Conduct a study about something else: If funding limitations prevent the scientist from conducting the intended study, she could consider redirecting her research efforts towards a related but more feasible topic. This allows her to leverage her expertise and resources while still generating valuable scientific knowledge.

4. Use data from a similar study and adjust it to fit her study: The scientist could explore existing datasets or previous studies that are relevant to her research question. By analyzing and adapting this data to fit her study's context, she can gain insights without incurring the costs and time associated with primary data collection. However, it is crucial to ensure that the adjusted data aligns with the specific objectives and parameters of her study.

Ultimately, the scientist should carefully assess the feasibility, potential impact, and trade-offs associated with each option. It may also be beneficial to seek guidance from peers, mentors, or funding agencies to explore alternative funding sources or collaborative opportunities that could support her research goals.

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an antibody is a blood protein produced in response to and counteracting a specific antigen. Antibodies combine chemically with substances which the body recognizes as alien, such as bacteria, viruses, and foreign substances in the blood.

Antibodies are proteins that help fight off infections and can provide protection against getting that disease again (immunity). Antibodies are disease specific.

Answer:

D

Explanation:

when you try to find out if it is positive, the line goes from left to right, and in this question the line is going upward.

Answer:

θ = Cos⁻¹[A.B/|A||B|]

A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result

Explanation:

We can use the formula of the dot product, in order to find the angle between two non-zero vectors. The formula of dot product between two non-zero vectors is written a follows:

A.B = |A||B| Cosθ

where,

A = 1st Non-Zero Vector

B = 2nd Non-Zero Vector

|A| = Magnitude of Vector A

|B| = Magnitude of Vector B

θ = Angle between vector A and B

Therefore,

Cos θ = A.B/|A||B|

θ = Cos⁻¹[A.B/|A||B|]

Hence, the correct answer will be:

A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result

Average acceleration is how much the car increases (on average) per second.  So, since it increases by 30 m/s in 8 s, then dividing 30 by 8 will give you an average acceleration of 3.75 m/s^2 (remember that acceleration is ever increasing, so the unit is s^2, not just s)

Explanation:

1) N₂ + O₂ → 2 NO

Kc = [NO]² / ([N₂] [O₂])

Set up an ICE table:

[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\N_{2}&0.114&-x&0.114-x\\O_{2}&0.114&-x&0.114-x\\NO&0&+2x&2x\end{array}\right][/tex]

Plug into the equilibrium equation and solve for x.

1.00×10⁻⁵ = (2x)² / ((0.114 − x) (0.114 − x))

1.00×10⁻⁵ = (2x)² / (0.114 − x)²

√(1.00×10⁻⁵) = 2x / (0.114 − x)

0.00316 = 2x / (0.114 − x)

0.00361 − 0.00316x = 2x

0.00361 = 2.00316x

x = 0.00018

The volume is 1.00 L, so the concentrations at equilibrium are:

[N₂] = 0.114 − x = 0.11382

[O₂] = 0.114 − x = 0.11382

[NO] = 2x = 0.00036

2(a) Cl₂ → 2 Cl

Kc = [Cl]² / [Cl₂]

[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\Cl_{2}&2.0&-x&2.0-x\\Cl&0&+2x&2x\end{array}\right][/tex]

1.2×10⁻⁷ = (2x)² / (2 − x)

1.2×10⁻⁷ (2 − x) = 4x²

2.4×10⁻⁷ − 1.2×10⁻⁷ x = 4x²

2.4×10⁻⁷ ≈ 4x²

x² ≈ 6×10⁻⁸

x ≈ 0.000245

2x ≈ 0.00049

2(b) F₂ → 2 F

Kc = [F]² / [F₂]

[tex]\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\F_{2}&2.0&-x&2.0-x\\F&0&+2x&2x\end{array}\right][/tex]

1.2×10⁻⁴ = (2x)² / (2 − x)

1.2×10⁻⁴ (2 − x) = 4x²

2.4×10⁻⁴ − 1.2×10⁻⁴ x = 4x²

2.4×10⁻⁴ ≈ 4x²

x² ≈ 6×10⁻⁵

x ≈ 0.00775

2x ≈ 0.0155

F₂ dissociates more, so Cl₂ is more stable at 1000 K.

Answer:

no but yes at the same time

Explanation:

they are going a different direction but they are the same speed.

Answer: 9 km/h

Explanation:i’m pretty sure

Answer:

Well, it depends on the type of car but a regular car like a toyota 4x4 only goes at 5k/h if the car starts when complete rest

Complete Question

Find the force that must be exerted on the rod to maintain a constant current of 0.173 A in the resistor.

The figure below shows a zero-resistance rod sliding to the right on two zero-resistance rails separated by the distance L = 0.451 m . The rails are connected by a [tex]12.6 \Omega \   resistor[/tex], and the entire system is in a uniform magnetic field with a magnitude of 0.751 T .

The diagram illustrating this question is shown on the first uploaded image

Answer:

The value is  [tex]F =  0.0586 \ N [/tex]

Explanation:

  From the question we are told that  

   The current is  [tex]I  =  0.173 \ A[/tex]

    The length of separation is  [tex]L= 0.451 \ m[/tex]

     The resistance is  [tex]12.6 \Omega[/tex]

    The magnetic field is  [tex]B  =   0.751\  T[/tex]

Generally the force is mathematically represented as

    [tex]F =  BIL sin (\theta )[/tex]

Given that the velocity is perpendicular to magnetic field then [tex]\theta  =  90[/tex]

=>   [tex]sin(90)  =  1[/tex]

So

    [tex]F =  0.751 *0.173  * 0.451 sin (\theta )[/tex]

    [tex]F =  0.751 *0.173  * 0.451 * 1[/tex]

    [tex]F =  0.0586 \ N [/tex]

Answer:

a = 4 [m/s^2]

Explanation:

To solve this problem we must use Newton's second law, which tells us that force is equal to the product of mass by acceleration.

F = m*a

where:

F = force = 40 [N]

m = mass = 10 [kg]

a = 40/10

a = 4 [m/s^2]

Answer:

about 15 hours and 13 minutes

Explanation:

If the average speed on road trips is 47 mph, then we use the formula for speed to estimate the time it would take to cover a distance of 715 miles:

speed = distance / time

solve for "time" by cross-multiplication:

time = distance / speed

time = 715 / 47 = 15.212 hours

Which is about 15 hours and 13 minutes

Answer:

g = G*M/R^2, where g is the acceleration due to gravity, G is the universal gravitational constant, M is mass, and R is distance.

Explanation:

These two laws lead to the most useful form of the formula for calculating acceleration due to gravity

Answer:

a) The average force that acts on the man is [tex]2.508\times 10^{8}[/tex] newtons.

b) The average force that acts on the man is 1023.673 newtons.

c) The force of the ground on the man is 1612.093 newtons upwards.

Explanation:

a) After a careful reading of the statement we construct the following model by applying Impact Theorem, that is:

[tex]m\cdot \vec v_{A} + \vec F \cdot \Delta t = m\cdot \vec v_{B}[/tex] (Eq. 1)

Where:

[tex]m[/tex] - Mass of the man, measured in kilograms.

[tex]\vec v_{A}[/tex] - Initial velocity of the man, measured in meters per second.

[tex]\vec v_{B}[/tex] - Final velocity of the man, measured in meters per second.

[tex]\Delta t[/tex] - Impact time, measured in seconds.

[tex]\vec F[/tex] - Average net force, measured in newtons.

Now we proceed to clear average net force within expression:

[tex]\vec F \cdot \Delta t = m\cdot (\vec v_{B}-\vec v_{A})[/tex]

[tex]\vec F = \frac{m}{\Delta t}\cdot (\vec v_{B}-\vec v_{A})[/tex] (Eq. 2)

If we know that [tex]m = 60\,kg[/tex], [tex]\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex], [tex]\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex] and [tex]\Delta t = 1\times 10^{-6}\,s[/tex], we obtain the following vector:

[tex]\vec F = \frac{60\,kg}{1\times 10^{-6}\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right][/tex]

[tex]\vec F = 2.508\times 10^{8}\,\hat{j}\,\,\,[N][/tex]

The average force that acts on the man is [tex]2.508\times 10^{8}[/tex] newtons.

(b) If we know that  [tex]m = 60\,kg[/tex], [tex]\vec v_{A} = -4.18\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex], [tex]\vec v_{B} = 0\,\hat{j}\,\,\,\left[\frac{m}{s} \right][/tex] and [tex]\Delta t = 0.245\,s[/tex], we obtain the following vector:

[tex]\vec F = \frac{60\,kg}{0.245\,s} \cdot (4.18\,\hat{j})\,\,\,\left[\frac{m}{s} \right][/tex]

[tex]\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right][/tex]

The average force that acts on the man is 1023.673 newtons.

(c) From Second Newton's Law we find the following equation of equilibrium:

[tex]\vec F = \vec N -\vec W[/tex] (Eq. 3)

Where:

[tex]\vec F[/tex] - Average force that acts on the man, measured in newtons.

[tex]\vec N[/tex] - Force of the ground on the man, measured in newtons.

[tex]\vec W[/tex] - Weight of the man, measured in newtons.

By applying the concept of weight, we expand the previous equation:

[tex]\vec F = \vec N -m\cdot \vec g[/tex] (Eq. 3b)

Where [tex]\vec g[/tex] is the gravitational acceleration, measured in meters per square second.

And then we clear the force of the ground on the man:

[tex]\vec N = \vec F +m\cdot \vec g[/tex] (Eq. 4)

If we get that [tex]\vec F = 1023.673\,\hat{j}\,\,\,\left[N\right][/tex],  [tex]m = 60\,kg[/tex] and [tex]\vec g = 9.807\,\hat{j}\,\,\,\left[\frac{m}{s^{2}} \right][/tex], the average force is:

[tex]\vec N = 1023.673\,\hat{j}\,\,\,[N]+(60\,kg)\cdot (9.807\,\hat{j})\,\,\,\left[\frac{m}{s^{2}} \right][/tex]

[tex]\vec N = 1612.093\,\hat{j}\,\,\,\left[N\right][/tex]

The force of the ground on the man is 1612.093 newtons upwards.

Answer:

v = 20.69 m/s

Explanation:

Given that,

Initial speed of a stone, u = 7.59 m/s

he stone subsequently falls to the ground, which is 18.9 m below the point where the stone leaves his hand, h = 18.9 m

We need to find the speed of the stone impact the ground. Let the speed be v. Using the equation of kinematics to find v. So,

[tex]v^2-u^2=2as[/tex]

Here, a = g

So,

[tex]v^2=2gs+u^2\\\\v=\sqrt{2gs+u^2} \\\\v=\sqrt{2\times 9.81\times 18.9+(7.59)^2} \\\\v=20.69\ m/s[/tex]

So, the speed of the stone impact the ground is 20.69 m/s.