At a local market, Vijay buys two spice blends.
• Tandoori Seasoning: 3.5 ounces for $3.60 an ounce
• Garam Masala: 4 ounces for $2.75 an ounce
He calculates the total cost for the spice blends using the steps shown below.
Use the drop-down menus to explain Vijay's error.
Vijay's Calculation
Garam
Masala
Tandoori
Seasoning
Total Cost
of Tandoori
Seasoning
Total Cost
of Garam
Masala
Total Cost
of Both
Spices
2.88
3.60
x 3.5
2.75
4
+ 11.00
13.88
11.00
1800
+1080
2.880
Click the arrows to choose an answer from each menu.
The total cost of Choose.....
is incorrect. Vijay
Choose...
▼
when multiplying Choose...
cost of both spice blends is actually Choose...
x
Y
The total
Answers
Answer:
Step-by-step explanation:
The total cost of Tandoori Seasoning is incorrect.
Vijay made an error when multiplying 3.5 ounces by $3.60 .
Cost of both spice blends is actually $23.6.
What is a error?
it is defined as the deviation of an entitiy from its corrected value while calculating.
Now it is given that,
Tandoori Seasoning = 3.5 ounces for $3.60 an ounce
Garam Masala = 4 ounces for $2.75 an ounce
Hence, total cost of Tandoori Seasoning = 3.5*$3.60
⇒ total cost of Tandoori Seasoning = $12.6
and total cost of Garam Masala = 4*$2.75
⇒ total cost of Garam Masala = $11
Therefore, total cost for the spices =cost of Tandoori Seasoning + cost of Garam Masala
⇒ total cost for the spices = $12.6 + $11
⇒ total cost for the spices = $23.6
Hence, we conclude that,
The total cost of Tandoori Seasoning is incorrect.
Vijay made an error when multiplying 3.5 ounces by $3.60 .
Cost of both spice blends is actually $23.6.
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Answer:
75°
Step-by-step explanation:
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x = 90
Step-by-step explanation:
[tex]m\angle 1+m\angle 2=90[/tex]
[tex]\Longleftrightarrow x+\frac{x}{5} =90[/tex]
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Step-by-step explanation:
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Factor the expression completely
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Answer:
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Step-by-step explanation:
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Answers
Answer:
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Step-by-step explanation:
Given,
Volume of cone ( V ) = 2307.9 mm³
Height ( h ) = 5 mm
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Formula : -
Volume of cone = πh/3 r²
Note : -
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Step-by-step explanation:
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Answers
Answer:
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Step-by-step explanation:
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Answers
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Answers
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Answers
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Step-by-step explanation:
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Answers
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Step-by-step explanation:
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Answers
Answer:
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Step-by-step explanation:
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[tex]=\sqrt{(2-2)^2+(15-7)^2}[/tex]
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[tex]=8[/tex]
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Answers
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Step-by-step explanation:
If you do 9x5=45 and 11x5=55
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Answers
Answer:
120
Step-by-step explanation:
Use the counting principle.
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Answers
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Answers
Answer:
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Step-by-step explanation:
Option d is the correct answer.
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Answers
Answer:
Yes, by ASA congruence.
Step-by-step explanation:
Solving :
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[tex]\huge\underline{{\sf Answer}}[/tex]
[tex] \textbf{Let's check if the two triangles are } [/tex][tex] \textbf{congruent} [/tex] ~
[tex] \large\textsf{Given information } [/tex]:
[tex] \textsf{Two angles of a triangle is equal to corresponding} [/tex] [tex] \textsf{two angles of another triangle, and they} [/tex][tex] \textsf{have one side in common (should be equal} [/tex][tex] \textsf{for both) } [/tex]
[tex] \textsf{So, after analyzing this information, we can } [/tex][tex] \textsf{conclude that the two triangles are congruent by} [/tex][tex] \textsf{AAS congruency criteria.} [/tex]
[tex] \texttt{[ since two angles are equal and one} [/tex][tex] \texttt{non included side is common/equal ]} [/tex]
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Answers
Answer:
X=7
Step-by-step explanation:
3x+4=25 (Subtract 4 on both sides)
3x=21 (Divide by 3 on both sides)
x=7
Answer: x is a variable and the number the variable is standing for is 7
Step-by-step explanation:
3x7=21 .. 21+4=25
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Please I need your help
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[tex]\qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\ \textit{\underline{x} varies directly with }\underline{z^5}\qquad \qquad \stackrel{\textit{constant of variation}}{x=\stackrel{\downarrow }{k}z^5~\hfill } \\\\[-0.35em] ~\dotfill[/tex]
[tex]\stackrel{\textit{"y" varies directly with "x"}}{y=kx}\qquad \textit{we also know that} \begin{cases} x=\frac{2}{3}\\ y = 6 \end{cases}\implies 6=k\cfrac{2}{3} \\\\\\ 18=2k\implies \cfrac{18}{2}=k\implies 9=k~\hfill \boxed{y=9x} \\\\\\ when~x=10\frac{1}{3}\textit{ what is "y"?}\qquad y=9\left( 10\frac{1}{3} \right)\implies y=9\cdot \cfrac{31}{3}\implies y=93[/tex]
