Explanation:
The atomic number of Uranium is 92. The electron configuration is: [U] = [Rn] 5f3; 7s4 where Radon Rn has 86 electrons and a complete period. This result is respecting the Madelung. BUT … U is an exception !!!
On the period 7 are only 6 electron left for Uranium (92–86). The first 2 electrons are on the principal energy level 7 and occupy the 7s-orbital block. The 3rd electron is placed in the 5f-orbital block. The next 3 electrons are place here as well. The last electron has the unique quantum label (n; l; ml; s) = (5; 3; 0; 0)
To understand this: The first electron of the 5f-orbital block has the label (5; 3, -3; 0). The following electrons have the labels (5; 3; -2, 0), (5; 3; -1; 0), (5; 2; 0; 0). You notice, that the HUND’S RULE is satisfied. ( I always use head 0 before tail 1 to represent the spin.) The f-orbital block is made up of 7 orbitals and therefore can be filled up by at most 14 electrons. When the first electron has the spin 0 then the next 6 electrons must also have the spin 0. With the electron 8 you get the label (5; 3; -3, 1) which tells us, that the spin is opposite to 0. It must be 1. The next 6 electrons also will have spin 1 but are placed in the orbitals -2; -1; 0; 1; 2; 3. Their labels are: (5; 3; -2; 1), (5; 3; -1; 1), (5; 3; 0; 1), (5; 3; 1; 1), (5; 3; 2; 1) and (5; 3; 3; 1) Now the f-block is full !!!
ANSWER: The last electron of U has the label (5; 3; 0; 0). BUT … !!!!!
I hope that you can verify now the correctness of the answer by yourself according to the Madelung.
Please, apply the definitions of the 4 quantum numbers correctly by also respecting the MANDELUNG’S RULE, the OCTET RULLE, the HUND’S RULE.
NOTICE: The Madelung has 21 exceptions. (Wikipedia lists only 20 and treats Ni not as an exception)
Cr, Ni, Cu, Nb, Mo, Ru, Rh, (Pd), Ag, Pt, Au and
La, Ce, Gd, Ac, (Th), Pa, U, Np, Cm, Lr.
In the first group listed: 1 electron moves inwards. In the second group listed: 1 electron moves outwards. Pd and Th have 2 moving electron each. YOU CAN SEE, THAT U IS AN EXCEPTION !!!
CORRECT ANSWER: The last electron of U has the label (6; 2; 0; 0). Can you see the moving electron ??? ❮❮(5; 3; 0; 0) becomes (6; 2; 0; 0)❯❯ Can you see the moving outwards ???
The 21 exception were discovered with spectral analysis. The MADELUNG is not a principle !!! It is only a very simple rule to memorise the electron configurations. By respecting the exceptions, you can correct you Madelung answer !!! Learn the 21 exceptions by heart !
Did you get it ??? (6; 2; 0; 0) is the label of the last electron of U.
How many molecules are in 2.0 moles?
Answer:
12 or 1.24e
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Explain the four basic types of chemical reactions. Be sure to include a sample equation for each type.
Acid Base reaction (Neutralization reaction)
it is the reaction between acid and base which neutralize each other to give salt and water.
example: Hydrochloric acid + Sodium hydroxide --------> sodium chloride + water
HCl + NaOH--------> NaCl + H2O
what happens when ethanol reacts with alkaline potassium permanganate?
Answer:When ethanol is oxidised with alkaline potassium permanganate (alkaline KMnO 4) or acidified potassium dichromate (acidified K 2 Cr 2 O 7), ethanoic acid is formed. Alkaline potassium permanganate and acidified potassium dichromate are strong oxidising agents, as they provide oxygen for oxidising other substances in the reaction
Explanation:
Lithium Oxide (Li2O) is a highly reactive chemical species which reacts to give electrons to other atoms, following a general reaction scheme of:
Li2O + X → LiX + O2
Data were collected from a series of reactions involving lithium oxide and one other element.
Which statement is best supported by the evidence in the table?
The ionization energy of oxygen is lower than that of boron, beryllium, and lithium.
The electronegativity of oxygen is lower than that of fluorine, carbon, and nitrogen.
The electronegativity of oxygen is higher than that of boron, beryllium, and lithium.
The ionization energy of oxygen is higher than that of fluorine, carbon, and nitrogen.
Answer:
I think that A is the correct answer might not be
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How many molecules of methane (CH4) do you need to burn in order to get 9.03 x 1023
molecules of carbon dioxide (CO2)? Avogadro's number is 6.02 x 1023 molecules/mol.
CH4 + O2 - CO2 + 2H2O
Answer:
9.03*10^23 molecules CH4
Explanation:
In the equation CH4 + O2 -> CO2 + 2H2O, the molar ratio of CH4 to CO2 is 1:1. It takes 1 mole of CH4 burned to form 1 mole of CO2. If we convert molecules to moles, we do 9.03 x 10^23 divided by 6.02 x 10^23 = 1.5 moles of CO2. Since we know the ratio is 1:1, that meant it would take 1.5 moles of CH4 burned to make that much CO2. So we convert our 1.5 moles of CH4 into molecules by multiplying 1.5 * 6.02 x 10^23 which equals 9.03*10^23 molecules CH4.
Which of the following sets of quantum numbers (n, l, ml, ms) cannot occur within an atom of gallium?
A. 4, 0, 0, ½
b. 4, 2, 1, ½
c. 4, 1, 1, ½
d. 4, 1, 2, ½
e. 4, 3,1, 1/2
The following sets of quantum numbers ( n, I, ml, ms ) that cannot occur within an atom of gallium are :
4, 2, 1, ½ ( B ) 4, 1, 2, ½ ( D ) 4, 3,1, 1/2 ( E )Determine the sets of quantum numbers that cannot occur within an atom of gallium
Given that
Ga ( 31 ) = 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p¹
[ 4r ] 3d¹⁰ 4s²4p¹
where : n = principal quantum numbers, l = azimuthal quantum numbers, ml = magnetic quantum numbers, ms = spin quantum numbers.
For option B
Given that 4d shell is absent for Gallium the set cannot occur within the atom of Gallium
For Option D and E
All quantum number cannot occur here because the value of l = 2 for option D while for option E the value of l = 3
Hence we can conclude that sets of quantum numbers ( n, I, ml, ms ) that cannot occur within an atom of gallium are as listed above.
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How much work, , must be done on a system to decrease its volume from 19.0 L to 11.0 L by exerting a constant pressure of 6.0 atm?
w = ________ kJ
Answer:
Explanation:
w = 16.0KJ
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What mass, in grams, of sodium sulfate is needed to make 234.9 g of a 1.7 % (m/m) aqueous solution of sodium sulfate?
Answer:
I think its this 4.125 g Na2SO4 or this 4.125 g
If a sample originally had 120 atoms of carbon-14, how many atoms will remain after 17,145 years? Assume the half life of C14 is 5715 years.
Answer:
15 atoms left after 3 half lives
Explanation:
17145 y / 5715 y/halflife = 3 half lives
(1/2)^3 = 1/8 of original is left
1/8 ( 120 atoms) = 15 atoms left
2C6H6 + 1502 →12CO2 + 6H20
Calculate the number of moles of C6H6 needed to produce 50.0g of water.
Show steps
Answer:
.926 moles
Explanation:
Rounding :
H2 0 = 18 gm/mole
50 gm would then be 50 / 18 = 2.7777 moles of water
every two moles of 2 C6H6 produces 6 moles of water
2.7777/6 * 2 = .926 moles
21.10g of NaOH and Ba3(OH)2 mixture is dissolved water to prepare 1.0dm³ Solution. To neutralize 25.OO mL of this solution needs 0.5 moldm-³ HCl 15.00mL. calculate the percentage of NaOH by mass in the mixture.
From the equation of te reaction, we know that the mass percent of NaOH in the mixture is 1.4%.
What is neutralization?Neutralization is a reaction that occurs between an acid and a base to yield salt and water only.
In tis case, the reaction of the NaOH and HCl occurs as follows; NaOH + HCl ----> NaCl + H2O
Number of moles of HCl reacted = 15/1000 * 0.5 moldm-³ = 0.0075 moles
Since the reaction is 1:1, 0.0075 moles of NaOH reacted.
Mass of NaOH = 0.0075 moles of NaOH * 40 g/mol = 0.3 g
Percent of NaOH = 0.3 g/21.10g * 100/1 = 1.4%
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particles in the liquid state have _________ IM attractive forces than in the gas state
Answer:
Particles in the liquid state have greater IM attractive forces than in the gas state.
What are ways in which the body is gain and loses soduim?
Answer:
You gain sodium basically through the food you eat and lose it basically by excretion through urine,sweat
Why do scientists listen to ocean around plate boundary?
Answer:
Scientists discovered that when the locations of earthquakes were plotted on a world map, these locations occurred in a pattern, or variety of patterns.
Explanation:
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A molecule that is either cycloheptane or cycloheptene is treated with bromine and the sample immediately absorbs the red bromine color—which compound is present?
The compound that is most likely present when treated with bromine and the sample absorbs the red bromine color is ; Cycloheptene
What is cyclohepteneCycloheptene is an unsaturated colorless oily liquid which is insoluble in water it absorbs Bromine when used in performing unsaturation test due it unsaturated nature.
The red bromine color will be absorbed when used to treat Cycloheptene but will not be absorbed when used to treat cycloheptane due to its saturated nature.
Hence we can conclude that the compound that is present is Cycloheptene.
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Which type of reaction is shown?
(1 point)
Fission is shown because mass is being converted into energy as nuclei combine
Fission is shown because nuclei are being split into smaller and smaller places
Fusion is shown because mass is being converted into onergy as nuclei combine
Fusion is shown because nuclei are being split into smaller and smaller places,
According to the image in this question, the type of reaction shown is that of fission because nuclei are being split into smaller and smaller places.
What is nuclear fission?Nuclear fission in radioactivity is the process whereby the nuclei of atoms split into smaller particles.
In the above diagram, an atom of uranium is labeled and its nucleus is shown to split into smaller particles in succession.
Therefore, the reaction exemplifies a nuclear fission because nuclei are being split into smaller and smaller places.
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Thermal energy always moves from a greater energy level to a lesser energy level
Theory or law?
Give an explanation please
Answer:
[tex]\fbox{Law -Based \: on \: laws \: of \: thermodynamic}[/tex]
Explanation:
At constant pressure Thermal energy always moves from a greater energy level to a lesser energy level, laws of thermodynamics prove that.
Nature always likes to attain equilibrium either it's movement of heat energy or flow of water from higher region to lower region. The first and second law of thermodynamics are profe of that, the first law says that the total energy of universe is Constant. Energy can not be destroyed it always changes from one form to another, by work and heat. The second law explains why thermal energy moves from a greater energy level to a lesser energy level, it deals with the change in entropy of a system and surrounding and states heat flows from hot environment to cold environment.
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