A horizontal force acts on an object on a fric- tionless horizontal surface. If the force is halved and the mass of the object is doubled, the acceleration will be (1) four times, (2) two times, (3) one-half, (4) one-fourth as great. (b) If the acceleration of the object is , and the force on it is doubled and its mass is halved, what is the new acceleration

Answers

Answer 1

(a)  If the force is halved and the mass of the object is doubled, the acceleration will be one-fourth as great.

(b)  if the force on it is doubled and its mass is halved, the new acceleration will be four times as great.

The force on an object is determined by applying Newton's second law of motion;

F = ma

[tex]\frac{F_1}{m_1a_1} = \frac{F_2}{m_2a_2}[/tex]

(a)

when the force is halved, F₂ = 0.5F₁,

mass is doubled, m₂ = 2m₁

[tex]\frac{F_1}{m_1a_1} = \frac{0.5F_1}{2m_1a_2} \\\\2m_1a_2F_1 = 0.5F_1 m_1a_1\\\\2a_2 = 0.5a_1\\\\a_2 = \frac{0.5a_1}{2} = \frac{a_1}{2 \times 2} = \frac{a_1}{4} \\\\a_2 = \frac{1}{4} (a_1)[/tex]

Thus, If the force is halved and the mass of the object is doubled, the acceleration will be one-fourth as great.

(b)

when the force is doubled, F₂ = 2F₁,

mass is halved, m₂ = 0.5m₁

[tex]\frac{F_1}{m_1 a_1} = \frac{2F_1}{0.5m_1 a_2} \\\\0.5m_1a_2 F_1 = 2F_1m_1a_1\\\\0.5a_2 = 2a_1\\\\a_2 = \frac{2a_1}{0.5} \\\\a_2 = 4(a_1)[/tex]

Thus, if the force on it is doubled and its mass is halved, the new acceleration will be four times as great.

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Answer: 6m

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Answer:

This section assumes you have enough background in calculus to be familiar with integration. In Instantaneous Velocity and Speed and Average and Instantaneous Acceleration we introduced the kinematic functions of velocity and acceleration using the derivative. By taking the derivative of the position function we found the velocity function, and likewise by taking the derivative of the velocity function we found the acceleration function. Using integral calculus, we can work backward and calculate the velocity function from the acceleration function, and the position function from the velocity function.

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Explanation:

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two children, A and B, fire identical 10.0g all bearings from a catapult. the elastic band of each catapult extended by 0.10m and then released to fire the ball bearings. Child A's elastic band has a spring constant of 144N/m. calculate the energy transferred to the kinetic energy store of the child A's ball bearing.


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Answers

The energy transferred to the kinetic energy store of the child A's ball bearing is 0.72 J.

Energy transferred to the kinetic energy

The energy transferred to the kinetic energy store of the child A's ball bearing is determined from the principle of conservation of energy as shown below;

K.E = Ux = ¹/₂kx²

K.E = ¹/₂ x 144 x 0.1²

K.E = 0.72 J

Thus, the energy transferred to the kinetic energy store of the child A's ball bearing is 0.72 J.

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Answers

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Example

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Answers

Answer:

The time period is

T

=

3.0

s

.

The distance between two crests is

λ

=

8.0

m

.

The frequency of wave can be calculated as,

f

=

1

T

f

=

1

3.0

s

f

=

1

3

s

1

The speed of wave can be calculated as,

v

=

f

λ

v

=

(

1

3

s

1

)

(

8

m

)

v

=

2.67

m

/

s

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id k if im right or not but gl and have a nice day!

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Using the information depicted on the distance - time graph, the slope of the graph is could be used to infer the velocity of each cyclist. Hence, cyclist A and B do not have the same velocity at 3 seconds.

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Therefore, the cyclists do not have the same velocity at time, t = 3 seconds.

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Answers

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Below

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Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same wavelength to be continuously emitted.

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Inside a laser apparatus, the stimulation and relaxation of electrons in atoms cause many photons with the same wavelength to be continuously emitted. When these photons are emitted, they travel between two reflective surfaces to form the wave that is represented in the simulationThis wave is the summation of all the photons being introduced with every oscillation, and as they continue to travel, the amplitude increases.This occurs because the photons are emitted in a coherent fashion; however, amplitude when the photons overlap in an incoherent fashion.In a laser device, a small portion of photons are permitted to escape (for use in an application). This is emulated in the simulation, by settling the Damping to Lots such that amplitude remains relatively constant when compared to damping of None. (Damping represents the Loss of photons.The generation of multiple wavelengths is possible in some laser-producing systems, and the diffraction angle can be varied to allow the isolation of different wavelengths. Finally, when the power of a laser is described, the wave property that is being referenced is a function of its frequency and amplitude.

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Answer:

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Answers

Answer:

The size of the frictional force is 577 N.

Explanation:

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Frictional forces are exerted every time you have two surfaces sliding across one another. Friction depends on:

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There are two types of friction:

static friction [tex]f_s[/tex];dynamic (sliding) friction [tex]f_d[/tex].

Now let's attack the problem:

First, you have to write the data down:

[tex]\bullet \quad m= 63\,kg\\\\\bullet \quad F= 577\,N\\\\\bullet \quad v= 2.4\,m/s[/tex]

If the boy and the sled moves on constant velocity, Newton's First Law Of Motion states that the net force acting on them must be zero:

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Applying Newton's Second Law Of Motion, we get:

[tex]F-f_d=0[/tex]

which means that:

[tex]F=f_d[/tex]

In other words, the dynamic frictional force equals the force that moves the boy and sled. So we may write:

[tex]\boxed{f_d=577\,N}[/tex]

Conclusion: the size of the (dynamic) frictional force is 577 N.

Happy studying!

Brainly Team

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