A freight train consists of two 8.00 \times 10^5~\text{kg}8.00×10 ​5 ​​ kg engines and 45 cars with average masses of 5.50 \times 10^5~\text{kg}5.50×10 ​5 ​​ kg. What force must each engine exert backward on the track to accelerate the train at a rate of 5.00 \times 10^{-2}~\text{m/s}^25.00×10 ​−2 ​​ m/s ​2 ​​ if the force of friction is 7.50 \times 10^5 ~\text{N}7.50×10 ​5 ​​ N, assuming the engines exert identical forces? This is not a large frictional force for such a massive system. Rolling friction for trains is small, and consequently trains are very energy-efficient transportation systems.

Complete question:

A scallop forces open its shell with an elastic material called abductin, whose Young's modulus is about 2.0×10⁶ N/m2 .

If this piece of abductin is 3.1 mm thick and has a cross-sectional area of 0.49 cm2 , how much potential energy does it store when compressed 1.5 mm ?

Answer:

The elastic potential energy of the material is 0.036 J

Explanation:

Given;

Young's modulus, E = 2.0×10⁶ N/m²

Thickness of the abductin, l = 3.1 mm = 0.0031 m

compression of the abductin, x = 1.5 mm = 0.0015 m

area, A = 0.49 cm² = 0.49 x 10⁻⁴ m²

Young's modulus for elastic material is given by;

[tex]E = \frac{stress}{strain} = \frac{Fl}{Ax} \\\\ E = \frac{F}{x}*\frac{l}{A}\\\\ E = k*\frac{l}{A}\\\\k = \frac{AE}{l}\\\\k = \frac{(0.49 x10^{-4})(2*10^6)}{0.0031}\\\\ k = 31,612.9 \ N/m[/tex]

The elastic potential energy of the material is given by;

U = ¹/₂kx²

U = ¹/₂(31,612.9)(0.0015)²

U = 0.036 J

Therefore, the elastic potential energy of the material is 0.036 J

Answer:

[tex]B=1.61\times 10^{-4}\ T[/tex]

Explanation:

The attached figure shows the path followed by an electron in the semicircular path from A to B.

Velocity of the electron is, [tex]v=1.42\times 10^6\ m/s[/tex]

It can be seen from the figure that the radius of thenpath, r = 5 cm or 0.05 m

The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,

[tex]Bqv=\dfrac{mv^2}{r}[/tex]

B is the magnitude of the magnetic field

[tex]B=\dfrac{mv}{rq}\\\\\text{Putting all the values}\\\\B=\dfrac{9.1\times 10^{-31}\times 1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}\\\\B=1.61\times 10^{-4}\ T[/tex]

So, the magnitude of the magnetic field is [tex]1.61\times 10^{-4}\ T[/tex].

The magnitude of the magnetic field that will cause the electron to follow the semicircular path from A to B will be  [tex]B=1.61\times 10^-{4]\ T[/tex]

The magnetic field is defined as when the current passes through the wire, then the magnetic field is generated around the wire in a circular pattern.

The attached figure shows the path followed by an electron in the semicircular path from A to B.

The velocity of the electron is, [tex]v=1.42\times 10^6\ \frac{m}{s}[/tex]

It can be seen from the figure that the radius of then path, r = 5 cm or 0.05 m

The magnetic force acting on the electron is balanced by the centripetal force acting on it. It means,

[tex]Bqv=\dfrac{mv^2}{r}[/tex]

B is the magnitude of the magnetic field

[tex]B=\dfrac{mv}{rq}[/tex]

[tex]B=\dfrac{9.1\times 10^{-31}\times1.42\times 10^6}{0.05\times 1.6\times 10^{-19}}[/tex]

[tex]B=1.61\times 10^{-4}\ T[/tex]

So, the magnitude of the magnetic field is  [tex]B=1.61\times 10^-{4]\ T[/tex]

To know more about the magnetic field, follow

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light, water, carbon dioxide

Explanation:

c02 , h20 and light

Answer:

neutron beta particle and proton (last option in the list)

Explanation:

The neutron beta particle and proton inside a neutron is a clear example of a negative particle (beta particle) and a positive particle (proton) experiencing electromagnetic force (attraction between positive and negative charges) at a very short distance.

Answer:

I'm pretty sure it's the flashlight because electromagnetic force produces electricity.

Answer:

Explanation:

Ideal gas equation- The volume (V) occupied by the n moles of any gas has pressure(P) and temperature (T) Kelvin,

the relationship for these variables PV=nRT where R gas constant is called the ideal gas law

Derivation of the Ideal Gas Equation

Let us consider the pressure exerted by the gas to be ‘p,’

The volume of the gas be – ‘v’  

Temperature be – T  

n – be the number of moles of gas

Universal gas constant – R

According to Boyle’s Law,

it constant n & T, the volume bears an inverse relation with the pressure exerted by a gas.

i.e. v∝1p ………………………………(i)

According to Charles’ Law,

When p & n are constant, the volume of a gas bears a direct relation with the Temperature.

i.e. v∝T ………………………………(ii)

According to Avogadro’s Law,

When p & T are constant, then the volume of a gas bears a direct relation with the number of moles of gas.

i.e. v∝n ………………………………(iii)

Combining all the three equations, we have-

v∝nTp

or pv=nRT

where R is the Universal gas constant, which has a value of 8.314 J/mol-K

Complete Question

A parallel plate capacitor contains a positively charged plate on the left, and a negatively charged plate on the right. An electron in between the plates is moving to the right. Which statement is true?

Group of answer choices

a The potential energy of the electron is decreasing and it is moving to a region having a higher potential

b The potential energy of the electron is decreasing and it is moving to a region having a lower potential.

c The potential energy of the electron is increasing and it is moving to a region having a lower potential

d  The potential energy of the electron is increasing and it is moving to a region having a higher potential.  

Answer:

The correct option is  C

Explanation:

From the question we are told that

  An electron in between the plates is moving to the right

Generally the potential energy of the electron is mathematically represented as  

          [tex]PE  =  e *  V[/tex]

Here  e is the charge on the electron and  V  is the electric potential of the electron

Generally the left side with the positive charge has a higher potential than the right side with the negative  charge

Now when the potential energy of the electron increases it will move toward the plate with the lower potential  which is the left plate

Answer:

The heat will travel through the wire to your hand.

Explanation:

Thats the one that makes the most sense.

Answer:   Mechanical energy is the energy that is possessed by an object due to its motion or due to its position.

(The energy acquired by the objects upon which work is done)

Answer:

D. all of the above

Explanation:

hope it helps

Answer:

its temperature stays constant

Explanation:

Answer:

The reason behind the given instance is summarized below.

Explanation:

Given parameters:

Mass given  = 1kg

Unknown:

Weight of the body at pole and equator = ?

Solution:

Both locations are on the surface of the earth. Generally, we take 9.8m/s² as the acceleration due to gravity on the earth.  

       Weight  = mass x acceleration due to gravity

But little disparity occurs in the value of acceleration due to gravity from the pole to equator. This is due to equatorial bulge.

   At the equator  , 9.780 m/s²

               pole  9.832 m/s²

Weight at equator = 1 x 9.780  = 9.78N

Weight at the pole = 1  x 9.832 = 9.832N  

Answer: 46 meters

Explanation:

The maximum height reached by the base ball is 45.9 meters.

To find the maximum height the given values are,

Mass = 25 Kg

speed v = 30 meters per second.

As the ball goes up, it acts due to the gravity.

The gravity slows an upward-moving object,

Acceleration due to gravity = 9.8 m/s every second,

the baseball reaches its greatest height in (30/9.8) = 3.06 seconds.

At that instant, its speed is zero.

The baseball's average speed from toss to peak is

            (1/2) (30 + 0)  =  15 m/s .

The baseball average speed = 15 m/s

And the time for greatest height = 3.06 seconds.

Substituting the given values,

The ball rises can be calculated as

 (15 x 3.06)  =  45.9 meters.

Thus, the baseball reached the maximum height approximately is 45.9 meters.

Learn more about the height due to gravity,

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#SPJ6

Answer:

43

Explanation:

you divide 2600 by 60 and your answer is 43.3333333

I just took the quiz and got it right!

Answer:

ω = 15275.25 rad/s

Explanation:

Given that,

Radial acceleration of an ultracentrifuge is, [tex]a=5\times 10^5g[/tex]

Distance from the axis, r = 2.1 cm = 0.021 m

g is the free-fall acceleration such that g = 9.8 m/s²

We need to find the angular speed of an ultracentrifuge. The formula that is used to find the angular speed is given by formula as follows :

[tex]a=r\omega^2[/tex]

Putting all the values,

[tex]\omega=\sqrt{\dfrac{a}{r}} \\\\\omega=\sqrt{\dfrac{5\times 10^5\times 9.8}{0.021}} \\\\\omega=15275.25\ rad/s[/tex]

So, the required angular speed, ω, of an ultracentrifuge is 15275.25 rad/s.

Answer:

i feel like 3 not too sure tho

Answer:

Final velocity (v) = 5.148 m/s (Approx)

Explanation:

Given:

Initial velocity (u) = 3.05 m/s

Acceleration (a) = 2.82 m/s²

Displacement (s) = 18.4 m

Find:

Final velocity (v)

Computation:

v² = u² + 2as

v² = (3.05)² + 2(2.82)(3.05)

v² = 9.3025 + 17.202

v² = 26.5045

v = 5.148 m/s (Approx)

Answer:

The viscosity is  [tex]\eta  = 0.76243 \ kg/ m \cdot s [/tex]  

Explanation:

From the question we are told that

  The  density is  [tex]\rho  =  7.80 *10^{3} \  kg/m^3[/tex]

  The diameter is  [tex]d =  3.0 \  mm =0.003 \ m[/tex]

    The  time taken is  [tex]t  =  12 \ s[/tex]

   The  distance covered is  [tex]d =  0.60 \ m[/tex]

Generally the velocity of the ball is  

      [tex]v  =  \frac{d}{t}[/tex]

=>    [tex]v  =  \frac{0.60}{12}[/tex]

=>    [tex]v  =  0.05 \ m/s [/tex]

Generally the mass of the steel ball is  

    [tex]m  =  \rho  *  V[/tex]

Here  V  is the volume and this is mathematically represented as

     [tex]V  =  \frac{4}{3} *  \pi  * [\frac{d}{2}  ]^3[/tex]

=>    [tex]V  =  \frac{4}{3} *  3.142  * [\frac{0.003}{2}  ]^3[/tex]

=>      [tex]V  = 1.414 *10^{-8} \  m^3[/tex]

So

     [tex]m  = 7.80 *10^{3}  *   1.414 *10^{-8}[/tex]

     [tex]m  = 0.00011 \  kg [/tex]

Generally the viscosity is mathematically represented as  

     [tex]\eta  =  \frac{m  *  g}{6\pi  *  r  *  v }[/tex]

Here  r is the radius represented as

      [tex]r =  \frac{d}{2}[/tex]

=>   [tex]r =  \frac{0.003}{2}[/tex]

[tex]r =  0.0015  \  m [/tex]

So

  [tex]\eta  =  \frac{0.00011  *  9.8}{6 *  3.142   * 0.0015  * 0.05 }[/tex]    

=> [tex]\eta  = 0.76243 \ kg/ m \cdot s [/tex]

moves farther in the same amount of time.

Explanation:

based on my answer......

we supposed to assume that both cars are equal except for speed. So they would have the same mass.....

Anyway, the question doesn't tell you anything about weight or size, so you can't tell from the information given which has more mass.

But the very definition of 'faster' is 'moves farther in the same amount of time'.

Hope this helps

Answer:

They both moves at the same speed

Explanation:

hope it works

Answer:

Explanation:

given:

distance = 270 km

speed = 85 km/h

find:

how long does it take to get into his audition in hours?

solution:

velocity = distance / time

85 km/h =  270 km  

                      t

85 (t) = 270

t = 270 / 85

t = 3.176 hours

Answer:

Rotation frequency is 0.377 hertz.

Explanation:

After a careful reading of statement, we need to apply the concept of radial acceleration due to uniform circular motion, whose formula is:

[tex]a_{r} = \omega^{2}\cdot L[/tex] (Eq. 1)

Where:

[tex]a_{r}[/tex] - Radial acceleration, measured in meters per square second.

[tex]\omega[/tex] - Angular velocity, measured in radians per second.

[tex]L[/tex] - Length of the beam, measured in meters.

Now we clear the angular velocity within:

[tex]\omega = \sqrt{\frac{a_{r}}{L} }[/tex]

If [tex]a_{r} = 29.9\,\frac{m}{s^{2}}[/tex] and [tex]L = 5.33\,m[/tex], the angular velocity is:

[tex]\omega = \sqrt{\frac{29.9\,\frac{m}{s^{2}} }{5.33\,m} }[/tex]

[tex]\omega \approx 2.368\,\frac{rad}{s}[/tex]

The frequency is the number of revolutions done by device per second and can be found by using this expression:

[tex]f = \frac{\omega}{2\pi}[/tex] (Eq. 2)

Where [tex]f[/tex] is the frequency, measured in hertz.

If we know that [tex]\omega \approx 2.368\,\frac{rad}{s}[/tex], then rotation frequency is:

[tex]f = \frac{2.368\,\frac{rad}{s} }{2\pi}[/tex]

[tex]f = 0.377\,hz[/tex]

Rotation frequency is 0.377 hertz.

Answer:

the reason why is that if it is hit with the same force the moon has a lot less gravity than the earth dose so the golf ball will hit the ground on earth first before the golf ball on moon dose

Currently, the magnetic south pole lies about ten degrees distant from the geographic north pole, and sits in the Arctic Ocean north of Alaska. The north end on a compass therefore currently points roughly towards Alaska and not exactly towards geographic north.