A design for a garden is composed of a triangle and 2 rectangles. Some side lengths of the garden design are shown.

What is the area of the garden in square feet?

Answer:

83

Step-by-step explanation:

Answer:

6 medians.

Step-by-step explanation:

because the medians of 5 and 7 is 6.

Answer:

Step-by-step explanation:

Answer:

Jake

Step-by-step explanation:

Answer:

The answer is 1/24

Step-by-step explanation:

1stepout of the 12 is the 5th so 1/12 and divid by 2 because you want it to land on heads.

Answer:

2(y+4)=4y

2y+8=4y

8=4y-2y

8÷2=y

4=y

Therefore y =4

The fractions on the number line are 1/8, 2/8, 3/8, 4/8, 5/8, 6/8, 7/8

The range of the number line is given as:

Range = 1/8 to 7/8

Using an increment of 1/8, the fractions on the number line are:

1/8, 2/8, 3/8, 4/8, 5/8, 6/8, 7/8

Next, we plot the number line where the above fractions are placed on the number line

See attachment for the required number line.

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Answer:

Step-by-step explanation:

Question 3

Question 4

Question 5

Answer:

C

Step-by-step explanation:

In the unit circle

cos x corresponds with x

sin x corresponds with y.

Here, they are both negative so the angles lies in the third quadrant because both x and y is negative in the third quadrant

Step-by-step explanation:

the other answer we is correct.

here a few words about why :

the quadrants in a circle start in the right top corner. so, right top is number I.

left top is number II.

left bottom is number III.

right bottom is number IV.

simply because this goes with the growing angle. the angle starts at 0° at the right center. and then it grows counterclockwise and goes all around the circle until reaching 360° being equal to 0° again.

Answer:

8=5/4*-4+(b)

b=3

hence

y=(5/4)x+3

Answer:

3/6

I say that the probability is 3/6 because there are 3 spaces, and we are counting one spin. There are 6 spots total.

Answer:

maybe the answer is 3/5.

Do message me if the answer is wrong

Answer:

B. 60

Step-by-step explanation:

1. take the square root of 64

2. multiply 8*10 and 5*4

3. subtract

Square root of 64 is 8 so,

10*8 - 5*4

80 - 20 =

60

Answer:

Below.

Step-by-step explanation:

k / 22 = -66

k = 22*-66

= -1452.

The perfect square form the given numbers is 25.

Perfect squares are defined as the number which is the result of the multiplication of another number, likely integers, to itself two times.

For example, 4 = 2 × 2

So 4 is a perfect square of 2.

Here the given numbers are,

20, 21, 24, 25.

We need the perfect squares as the squares of integers.

1² = 1

2² = 4

3² = 9

4² = 16

5² = 25

So 25 is a perfect square.

20, 21 and 24 cannot be written as the square of an integer.

Hence the correct number is 25.

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Answer:

2 90/100 in decimal form would be 2.9.

Answer:

[tex]{ \underline{ \underline{ \mathfrak{ \: answer : \: \: { \tt{ \sin(D) = \frac{ \sqrt{2} }{2} \: \: }} }}}}[/tex]

Step-by-step explanation:

[tex]{ \rm{ \sin( \theta) = \frac{opposite}{hypotenuse} }} \\ [/tex]

[tex]{ \tt{h = \sqrt{ {(opposite)}^{2} + {(adjacent)}^{2} } }} \\ { \tt{h = \sqrt{ 2{(2 \sqrt{15}) }^{2} } }} \\ { \tt{h = \sqrt{2(4 \times 15)} }} \\ { \tt{h = \sqrt{120} }}[/tex]

Therefore:

[tex]{ \tt{ \sin(D) = \frac{2 \sqrt{15} }{ \sqrt{120} } }} \\ \\ { \tt{ \sin(D) = \frac{2 \sqrt{15} }{2 \sqrt{15 \times 2} } }} \\ \\ { \tt{ \sin(D) = \frac{1}{ \sqrt{2} } }} \\ \\ { \boxed{ \tt{ \sin(D) = \frac{ \sqrt{2} }{2} }}}[/tex]

Answer:

( 4u + a ) + ( y + 6 )

Step-by-step explanation:

4u(y+6) + a(y+6) ...

The answer is ( 4u + a ) + ( y + 6 )

Answer:

your missing angle is 136

Step-by-step explanation:

equation used: 360 - (136 + 88) = 136

Answer: 436.8

Step-by-step explanation:

Answer:

I'm assuming the x at the end is a variable

9, -4

Step-by-step explanation:

If we replace x with 9, we get 81-36=45 which is 45=45 so 9 is one solution.

If we replace x with -4, we get 16-36=-20 which is -20=20 so -4 is the other solution

So, the solutions are 9 and -4.

Hope this helped you! If there is a mistake in my answer, please tell me and I will correct it as soon as possible.

Answer:

2,48,000

Step-by-step explanation:

Answer:

[tex]-x - y = 2[/tex].

Step-by-step explanation:

If the slope of a line in a plane is [tex]m[/tex] and the [tex]y[/tex]-intercept of that line is [tex]b[/tex], the slope-intercept equation of that line would be [tex]y = m\, x + b[/tex].

Rearrange the equation of the given line [tex]-x + y = 7[/tex] in the slope-intercept form to find the slope of this line:

[tex]-x + y = 7[/tex].

[tex]x -x + y = x + 7[/tex].

[tex]y = x + 7[/tex].

Notice that in the slope-intercept equation of this given line, the coefficient of [tex]x[/tex] is [tex]1[/tex]. Thus, the slope of the given line would be [tex]m_{1} = 1[/tex].

Two lines in a plane are perpendicular to one another if the product of their slopes is [tex](-1)[/tex]. In other words, if [tex]m_{1}[/tex] and [tex]m_{2}[/tex] are the slopes of two lines perpendicular to each other, then [tex]m_{1}\, m_{2} = (-1)[/tex].

Since [tex]m_{1} = 1[/tex] for the given line, the slope of the line perpendicular to this given line would be:

[tex]m_{2} = (-1) / m_{1} = (-1) / 1 = -1[/tex].

If the slope of a line in a plane is [tex]m[/tex], and that line goes through the point [tex](x_{0},\, y_{0})[/tex], the equation of that line in point-slope form would be:

[tex]y - y_{0} = m\, (x - x_{0})[/tex].

The slope of the line in question is [tex]m = (-1)[/tex]. It is given that this line goes through the point [tex](-1,\, -1)[/tex], where [tex]x_{0} = (-1)[/tex] and [tex]y_{0} = (-1)[/tex]. Thus, the equation of this line in point-slope form would be:

[tex]y - y_{0} = m\, (x - x_{0})[/tex].

[tex]y - (-1) = (-1)\, (x - (-1))[/tex].

[tex]y + 1 = -(x + 1)[/tex].

Rearrange this equation to match the format of the choices:

[tex]y + 1 = -x - 1[/tex].

[tex]x + y = -2[/tex].

[tex]-x - y = 2[/tex].

[tex]\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}[/tex]

if we ever face a number written in the form of [tex]\underline{x^{n}}[/tex]where x denotes the base and n denotes the exponent or power , we can expand it in the following way -

[tex] x^{n} = x \times x \times x \times.... x ( upto\: " n " \: times )[/tex]

therefore ,

[tex]8 {}^{5} = 8 \times 8 \times 8 \times 8 \times 8[/tex]

option ( B )

hope helpful -,-

                     - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

[tex]\diamond\:\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\:\diamond[/tex]

           ✶ How would you write [tex]\bold{8^5}[/tex] as a multiplication expression [tex]\textit{?}[/tex]

[tex]\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to solve:-}}}}\diamond[/tex]

    ✶ The exponent indicates how many times a certain number was multiplied by itself.

      ✶ In this case we have [tex]\bold{8^5}[/tex], so 8 was multiplied by itself five times.

So we conclude that [tex]\bold{8^5}[/tex] written as a multiplication expression looks as follows:-

[tex]\bigcirc\!\!\!\!\checkmark[/tex] 8•8•8•8•8

             - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Answer:

x/y.

Step-by-step explanation:

Deal with each number or letter at a time:

3 / 3 = 1

x^3/x^2 = x

y^4 / y^5 =  y^-1 = 1/y

z / z = 1

So the answer is  1*x * 1/y * 1

= x/y.

Answer:

The cross section is a trapezoid.

Step-by-step explanation:

Answer:

6x⁵+12x⁴+3x³

Step-by-step explanation:

3x³(2x² + 4x + 1) = 3x³ × (2x² + 4x + 1)

therefore

3x³(2x² + 4x + 1) =

(3x³ × 2x²) + (3x³ × 4x) + (3x³ × 1)

*NOTE: for the brackets the multiplication law of indices is applied, i.e:

nª × n^b = n^a+b therefore

x³ × x² = x^3+2 = x⁵

x³ × x = x^3+1 = x⁴

x³ × x⁰ = x^3+0 = x³

*Note the quoeficents multiple each other, i.e:

3 × 2 = 6

3 × 4 = 12

3 × 1 = 3

so:

= 6x⁵ + 12x⁴ + 3x³

Answer:

[tex](x−3)(x+5) .....is.. the.. factorised.. form.. of.. the.. expression[/tex]

Step-by-step explanation:

[tex]x^2 + 2x > =15 \\x^2 + 2x - 15 > = 0 \\(x + 4)(x - 2) < 0 , \\{x + 4 < 0 and .x - 2 > 0} or {x + 4 > 0 ,\\and .x - 2 < 0} , \\{x < -4 and .x > 2} or {x > -4 and. x < 2},\\ Discard .x < -4 and. x > 2 because. it. has. no. solutions,\\ leaving .just x > -4 and .x < 2 , -4 < x < 2[/tex]