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A tree is at a distance of 50 meters from a place on earth. From this place, the Angle of the tree's peak is 30. Find out the height of the tree.
sine's law
h/sin 30 = 50/sin 60
h/0.5 = 50/(0.5√3)
h=28.9 m
What is the de-Broglie wavelength of a 70kg person jogging at the rate of 2.70m/s. the mass of an electron is 9.11 x 10-28g, the speed of light is 3.00 x 108m/s, planks constant is 6.63 x 10-34js.
The de-Broglie wavelength of a person jogging at the rate of 2.70m/s is 3.5 x 10⁻³² m.
What is de-Broglie wavelength?De-Broglie wavelength is the ratio of Planck's constant h to the momentum of the electron p.
Momentum p = mass m x velocity v
Given is the mass of a person = 70kg, the speed of person 2.70m/s, Planck's constant h= 6.63 x 10⁻³⁴J.s
De- Broglie wavelength λ= h/mv
λ = 6.63 x 10⁻³⁴/ ( 70 x 2.70)
λ = 3.5 x 10⁻³² m
Thus the wavelength is 3.5 x 10⁻³² m.
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It is often said the media can make or break a person especially, sports personalities. Explain how that happens.
I'm going to school tomorrow so I can get the best of it
is it second or first law
Answer:
In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration.
Explanation:
an ldeal gas with internal energy U at 202°C is heated to 410°C.its internal energy then will be?
Internal energy is directly proportional to temperature
U1T2=U2T1U(273+410)=U2(273+202)683U=475U_2U_2=1.44UDefine the concept of heat. What is heat?
Answer:
In a simplest terms,
temperature is how hot or cold an object is, while heat is the energy that flows from a hotter object to cooler one
Suppose you were to make a three-dimensional model of magnetic force
using magnetic field lines and a magnet. Which two characteristics might
your model have?
A. The field lines exist only at the top and the bottom of the magnet.
B. Arrows on the field lines point from the magnet's north pole to its
south pole.
C. The field lines near the magnet are far apart.
D. The field lines do not cross paths as they go from one pole of the
magnet to the other.
दा
Answer:
D. Po cguro pero I will study hard to get the correct answer and I will share to you pero I try mo Lang po Yan kac halos kami dito Yan po Yung nilagay namin na answer baka kac Tama po e Kaya tau mag aral po tau ng mabuti Para MAtopad natin Yung mga pangarap natin at making tau sa mga pamilya at guro Yung Lang po good bless
A 50.0-N bowling ball is held in a person’s hand with the forearm horizontal. The biceps muscle is attached 0.030 0 m from the joint, and the ball is 0.350 m from the joint. Find the upward force F exerted by the biceps on the forearm (the ulna) and the downward force R exerted by the humerus on the forearm, acting at the joint.
The upward force F exerted by the biceps on the forearm will be 583 N.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size of the body.
Force is defined as the product of mass and acceleration. Its unit is Newton.
The torque balancing equation is found as;
[tex]\rm \tau_i=\tau_R+\tau_F+\tau_{BB}=0\\\\ R(0)+F(0.0300)-(50.0)(0.350)\\\\ F=583 \ N[/tex]
Hence,the upward force F exerted by the biceps on the forearm will be 583 N.
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Assume the roller coaster experiences no friction. What would be the speed of the roller
coaster at point F? Defend your answer in 1-2 sentences.
The roller coaster experiences no friction, the speed of the roller
coaster at point F is mathematically given as
v= 65.72 m/s
What would be the speed of the roller coaster at point F?Generally, the equation for the Mechanical enegy is is mathematically given as
ME = mgh + 1/2mv^2
Therefore
ME= 80*9.8*200 + 1/2*80*20^2
ME= 172800 J
In conclusion, the speed of the roller coaster at point F is
ME=1/2*m*V^2
172800 = 1/2*80*V^2
v= 65.72 m/s
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10. As a pharmacy technician, you will receive prescription orders with many different abbreviations, which will require conversions to calculate the dose. Now that you have learned about conversions and abbreviations, what would you do to fill a prescription with abbreviations? Also, what would you do with conversions you were not sure how to convert to the required dose. Explain
When you receive prescriptions that contain some abbreviations, you have to translate it into plain language that the patient can understand.
Who is a pharmacy technician?A pharmacy technician is a skilled personnel who assists a pharmacist in a health facility. The pharmacy technician usually writes out prescriptions for patients.
When you receive prescriptions that contain some abbreviations, you have to translate it into plain language that the patient can understand. If you are not clear about the abbreviation you can ask the pharmacist for help or the doctor.
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How much work is done on the object as it moves from 6.0m to 9.0m
Answer:
W = 3F
Explanation:
Work is defined as the inner product between force and displacement. The inner product picks out the force components which point in the same direction as the displacement. The vertical components do not matter in the horizontal displacement. I am assuming you're dealing with 1-dimensional motion? Then the work would be:
[tex]W=Fd[/tex]
The displacement is 3 meters. Therefore, the work is:
[tex]W=3F[/tex]
You haven't gave the force being applied to the object, so I cannot give an explicit answer. Just multiply the force by 3 to get the work.
Two differences between science activities carried out in a science laboratory and those carried out side of science laboratory.
Please answer quickly for brainliest
In a science lab, there is the adequate availability of raw materials for experiments such as chemicals while outside a science lab there isn't.
In a science lab, the availability of apparatuses and sources of heat is higher than outside a science lab.
What is science laboratory?The science lab is a place where the experiments related to the science background are performed with the use of apparatus.
The science lab has plenty of equipment to perform the experiment whether related to physics or chemistry or biology.
Thus, source of heat and availability of raw material and equipment are the differences between the science activities carried out in a science laboratory and those carried out side of science laboratory.
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pleaseeee help mehhhh
The units of Work, Energy and power are________ ________units.
Answer:
the units of work and energy is joule and unit of power is Watt
5 postulates of neil bohr atomic model
Answer:
What is Bohr’s Model of an Atom?
The Bohr model of the atom was proposed by Neil Bohr in 1915. It came into existence with the modification of Rutherford’s model of an atom. Rutherford’s model introduced the nuclear model of an atom, in which he explained that a nucleus (positively charged) is surrounded by negatively charged electrons.
what is the difference between 1 Newton/ metre² and 1 Pascal
Explain !!
Answer:
One pascal is equivalent to 1 newton (N) of force applied over an area of 1 square meter (m2). The pascal is also used to measure stress, specifically tectonic stress in the Earth's plates.
Explanation:
The expression of x=4t+2t^2 Where x is distance and t=time What is displecement ?
Answer:
x = 4 t + 2 t^2
the displacement is x which is zero at t = 0 and then increases indefinitely as t increases indefinitely
What is one way that trees can be like fossil fuels? A. They do not produce carbon dioxide when burned. B. They both grow. C. We can use our supply fa … ster than they can be replenished. D. They can not be replenished at all.
Answer:
Answer C. But don't be surprised if it isn't.
Explanation:
You can't use D. Trees can be replenished. Maybe not as well as God planted them in the first place, but we can replenish them.
A is incorrect. when burned, trees will produce CO2. In fact, trees produce more CO2 when burned that do fossil fuels do
Fossil fuels don't grow. Their rate of discovery might, but they themselves don't grow. Not B
C is your only choice. The problem is that it is not entirely true. We can replenish trees. Whether enough trees can be used as a clean fuel and be replaced in amounts we are used is the question.
An object is being shot from a horizontal ground at an incline angle of 30 degree with respect to the ground at a speed of 52 m/s. Find the duration in seconds that the object is above the height of 14 m. Give your answer with one decimal place.
When an object is thrown at an angle from the horizontal, the path followed by the body is called the projectile motion. The duration in seconds that the object is above the height of 14 m is 4.698 s.
What is speed?Speed is the time rate at which velocity is changing.
Vertical speed component is
V₀y = 52sin 30°= 26 m/s
Given is the height h=14m
Using second equation of motion,
S=ut+ 1/2 at²
Substituting the values, we get
14 = 26t - 4.9t²
4.9t² - 26t +14 =0
Solving the quadratic equation, we get the time as
taking the positive sign, t =4.698 s
taking the negative sign , t = 0.6082 s
Thus, the duration in seconds that the object is above the height of 14 m is 4.698s.
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A train moving west with an initial velocity of 20 m/s accelerates at 4 m/s' for 10 secon
moves a distance of
a
meters.
Answer:
Distance of 400m.
Explanation:
Use your kinematics equation to solve for distance (we can use kinematics b/c acceleration is constant).
d = (initial velocity x time) + 1/2 at^2
d = (20 x 10) + 1/2 (4) (10)^2
d = 200 + 200
d = 400 m
Two identical pucks of equal but unknown mass head straight towards each other with velocities
of 8.0 m/s and -6.0 m/s. They collide and stick together. What is their resulting velocity?
inelastic collision
m.8 - m.6 = 2mv'
2m = 2mv'
v' = 1 m/s
Answer:
1 m/s
Explanation:
According to the Law of Conservation of Momentum, (for inelastic collisions)
v = m₁v₁ + m₂v₂ / m₁ + m₂v = 8m - 6m / 2mv = 2m/2mv = 1 m/sA diverging lens with f = -33.5 cm is placed 14 cm behind converging lens with f = 20cm. where will an object at infinity be focused?
Answer:
Explanation:
Focal length of diverging lens,
fd= -33.5 cm
focal length of converging lens,
fc = 20 cm
Now let s is object distance and s' is image distance.
Now using lens formula for conversing lens
\frac1{f_c}=\frac1{s}+\frac1{s'}
f
c
1
=
s
1
+
s
′
1
Putting all values(object is at s=infinity)
Then image distance
\frac1{s'}= \frac1{f_c}- \frac1{s}
s
′
1
=
f
c
1
−
s
1
=\frac1{20}- \frac1{\infin}=
20
1
−
∞
1
s'=20cms
′
=20cm
Now using lens formula for diversing lens
s''=14-20=-6cm
Using lens formula
\frac{1}{-33.5} = \frac{1}{-6 }+ \frac{1}{s''' }\\s'''=\frac{(6)\times(-33.5)}{(-33.5+6)}\\s'''=\frac{(-201) }{(-27.5) }
−33.5
1
=
−6
1
+
s
′′′
1
s
′′′
=
(−33.5+6)
(6)×(−33.5)
s
′′′
=
(−27.5)
(−201)
image distance for diverging lens
s''' = 7.3 cm (behind the diverging lens)
A diverging lens with f = -33.5 cm is placed 14 cm behind converging lens with f = 20cm. image distance for diverging lens, s''' = 7.3 cm (behind the diverging lens)
what are the type of lens ?When a lens in the path of a beam of parallel rays causes the rays to diverge after refraction, it is referred to as a diverging lens.
It always creates a virtual image and has a thinner core than its boundaries.
Concave lenses(diverging lenses) function as diverging lenses because they cause light rays to diverge as they pass through them.
Therefore, when used with air as the operating medium, a concave lens can be thought of as a diverging lens.
The concave lens has several applications, including in telescopes, cameras, lasers, glasses, binoculars, and other optical devices.
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Compute g at a height of 7 RE above the surface of Earth (RE=6.4E+6m, ME=6.0E+24kg).
The acceleration due to gravity g at height 7 times the radius of Earth above the surface of the Earth is 8.933 m/s².
What is acceleration due to gravity?It is the acceleration caused by any object when placed on the surface on the Earth due to its weight.
The acceleration due to gravity is related to the distance as
g =GM/R²
where G is the gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²
Given is the height R = 7 x 6.4 x 10⁶ m and mass of Earth M = 6 x 10²⁴ kg
Substitute the values into the expression to find the acceleration due to gravity.
g = ( 6.67 x 10⁻¹¹ x 6 x 10²⁴)/ ( 7 x 6.4 x 10⁶)²
g = 8.933 m/s²
Thus, the acceleration due to gravity g at height 7 times the radius of Earth above the surface of the Earth is 8.933 m/s².
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Spirderman’s nemesis Electro delivers 4kJ of electrical energy in half a second. How powerful is he?
Ray X strikes a flat mirror at an angle of 0 = 26 degrees. What is the incidence?
The incidence is maybe 26=9
Sana loved swimming.She joined a new smimmimg club .When she looked at the floor of the pool to estimate its depth she found that it was shallow .But when she dived in the pool she found out that the pool was quiet deep.Write down the scientific reason for this situation?
Answer:
Refraction
Explanation:
When light passes from a rarer medium into a denser medium, it bends in the medium away from the normal. This creates the phenomenon of "apparent depth" as given in the question.
2.25 A car's speed is 30m/s, then it slows down in rate 6m/s2, after 4 seconds its speed will be ..... m/s
Answer:
A
Explanation:
Applying the First Equation of Motion :
⇒ v = u + at
⇒ v = 30 + (-6)(4)
⇒ v = 30 - 24
⇒ v = 6 m/s
How are u? I hope u doing well ااااااااااااااااا
Answer:
Hey
I'm alright and you
I also hope you're doing well
a simple generator has 200 loop square coil 10 cm on a side .how fast must it turn in a 0.25 T field to produce 24v peak out put
Hi there!
Recall Faraday's Law:
[tex]\epsilon = N\frac{d\Phi_B}{dt}[/tex]
ε = Emf (V)
N = Number of loops
ΦB = Magnetic Flux (Wb)
t = time (s)
Since the magnetic field is constant, we can take this out of the time derivative:
[tex]\frac{d\Phi_B}{dt} = B * \frac{dA}{dt}[/tex]
Therefore:
[tex]\epsilon = N B \frac{dA}{dt}[/tex]
We can express 'A', the area in which the magnetic field passes as:
[tex]A = Acos(\omega t)[/tex]
Taking the time derivative:
[tex]\frac{dA}{dt} = A\omega sin(\omega t)[/tex]
ω = angular speed of coil (rad/sec)
Now, combine with the above expression:
[tex]\epsilon = NBA\omega sin(\omega t)[/tex]
The maximum output will occur when the loop's area vector is PERPENDICULAR to the field, so sin(ωt) = 1.
Therefore:
[tex]\epsilon = NBA\omega \\\\[/tex]
Rearrange to solve for ω:
[tex]\omega = \frac{\epsilon}{NBA}\\\\\omega = \frac{24}{(200 * (.10^2) * 0.25} = \boxed{48 \frac{rad}{sec}}[/tex]
A spherical convex mirror has a radius of 30 cm. An object with a height of 0.30 m is placed 20 cm from the mirror. Note that in +/- sign conventions, f is negative (–) if the mirror is a convex mirror. a. Calculate the image distance. b. Calculate the image height. c. Calculate the magnification. d. Summarize the properties of the image formed in terms of its LOST (location, orientation, size, and type). e. Draw the set-up using graphical methods (ray diagramming). Apply scale drawing. Make sure that your illustration matches well with what you have calculated and presented in a-d.
a)A spherical convex mirror form the image at image distance is 8.57cm.
b) Mirror forms the image of height is 12.855 cm.
c)The magnification of the spherical convex lens is 0.4285.
What is convex mirror?The mirror which is a part of sphere with radius R is painted from inside forms the convex mirror.
The focal length of convex lens, f = R/2
Given , the radius of mirror is R =30cm, the focal length will be
f =30cm/2 = 15cm
a) Object distance u =20 cm, object height =0.30m, then the image distance will be 1/f = 1/u + 1/v where v is the image distance from the lens.
1/15 = 1/20 + 1/v
v= 8.57 cm
Thus, the image distance is 8.57cm.
b) Ratio of image distance to the object distance is equal to the ratio of image height to the object height.
Substitute the values into the expression, we get the image height as
h(image) = 8.57/20 x 30
h(image) = 12.855 cm
Thus, the image height is 12.855 cm.
c) The magnification is the ratio of image height to the object height.
Putting the values, we have
= 12.855/30
= 0.4285
Thus, the magnification is 0.4285.
d) Size of object is large as compared to the size of image. Object distance is small as compared to the image distance. The image formed is virtual.
e) The setup drawing is attached.
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