5. Which equation represents a balanced chemical equation?
O CF4 + 2Br2 → CBr4 + 2F2
O N2 + 3F2 + NF3
OPA+ O2 + 2P203
O K+ Cl2 + 2KCI

Answer: Smelling salts and oxygen are introduced into a metal catalyst-containing tube (platinum). Typically warmed to get the reaction started. The alkali is then oxidized to produce nitric oxide.

Answer:

The Ostwald process is a chemical process used for making nitric acid. Wilhelm Ostwald developed the process, and he patented it in 1902. The Ostwald process is a mainstay of the modern chemical industry, and it provides the main raw material for the most common type of fertilizer production

Explanation:

The first stage of the Ostwald process involves the catalytic oxidation of ammonia into nitric oxide, using platinum as the catalyst. The nitric oxide is then transferred to a different oxidizing tower, where it is oxidized into nitrogen dioxide

The mass of the acid produced is 0.252 g from the information in the question.

The term neutralization refers to the reaction between an acid and a base that yileds salt and water only.

The equation of this reaction is; 2HCl + CaCO3 ----->CaCl2 + CO2 + H2O

Number of moles of CaCO3 =   0.350 g/100 g = 0.0035 moles

Since 2 moles of acid reacts with 1 mole of CaCO3

x moles acid reacts with 0.0035 moles of CaCO3

x = 0.007 moles

Mass of acid = 0.007 moles * 36 g/mol = 0.252 g

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Answer:

The electronic configuration for Phosphorus(P) is 1s2,2s2 2p6, 3s2 3p3

Answer:

[tex]\displaystyle K_a = 4.24\times 10^{-10}[/tex]

Explanation:

Write the base reaction of NaA with water:

[tex]\displaystyle \text{A}^-_\text{(aq)}+\text{H$_2$O}_\text{($\ell$)}\rightleftharpoons \text{HA}_\text{(aq)} + \text{OH}^-_\text{(aq)}[/tex]

Hence, the equilibrium constant expression for the reaction is:
[tex]\displaystyle K_b = \frac{[\text{OH}^-][\text{HA}]}{[\text{A}^-]}[/tex]

Thus, to find Ka, we can find Kb and use the fact that Ka × Kb = Kw.

From the reaction and initial concentration of NaA, create an ICE chart:

[tex]\begin{tabular}{llllll} & A^- &\text{H$_2$O} & \rightleftharpoons & HA & OH^- \\I & 0.563 M & \---- & & 0 M & 0 M \\C & -\text{ $ x$} & \---- & & +\text{ $x$ M} & + \text{$x$ M} \\E & \text{(0.563 - $x$) M} & \---- & & \text{$x$ M} & \text{$x$ M} \end{tabular}[/tex]

Find [OH⁻] from the given pH:
[tex]\displaystyle \begin{aligned} \text{pH} +\text{pOH} & = 14.00 \\ \\ \text{pOH} & = 14.00 - \text{pH} \\ \\ & = 14.00 - (11.56) \\ \\ & = 2.44 \\ \\ -\log[\text{OH}^-] & = 2.44 \\ \\ [\text{OH}^-] &= 10^{-2.44} \\ \\ & =0.00363 \text{ M}= 3.63\times 10^{-3} \text{ M} = x\text{ M}\end{aligned}[/tex]

Solve for all species concentrations at equilibrium from the found x value:

[tex]\displaystyle [\text{HA}] = [\text{OH}^-] = 3.63\times 10^{-3} \text{ M}[/tex]

And:

[tex]\displaystyle \begin{aligned} \ [\text{A}^-] & = 0.563 - 3.63\times 10^{-3} \text{ M}\\ \\ & = 0.559\text{ M}\end{aligned}[/tex]

Find Kb:

[tex]\displaystyle \begin{aligned} \displaystyle K_b &= \frac{[\text{OH}^-][\text{HA}]}{[\text{A}^-]} \\ \\ & = \frac{(3.63\times 10^{-3})(3.63\times 10^{-3})}{(0.559)}\\ \\ & = 2.36\times 10^{-5}\end{aligned}[/tex]

Find Ka:

[tex]\displaystyle \begin{aligned} K_a\cdot K_b & = K_w \\ \\ K_a & = \frac{K_w}{K_b} \\ \\ & = \frac{(1.00 \times 10^{-14})}{(2.36\times 10^{-5})} \\ \\ &= 4.24\times 10^{-10} \end{aligned}[/tex]

In conclusion:
[tex]\displaystyle K_a = 4.24\times 10^{-10}[/tex]

Based on the vapor pressure of the pure substances, the mole fraction of pentane is 0.45 and mole fraction of hexane at equilibrium is 0.60.

Vapor pressure of of a liquid is the pressure that is excreted on the walls of a sealed vessel by the molecules of the liquid that have been converted to gaseous phase.

TO determine the mole fraction of pentane in the solution, we use the vapor pressure of the pure substances.

Let the mole fraction of pentane in the mixture be X.

The mole fraction of hexane will be 1 - X

Vapor pressure of solution = 383 torr

(mole fraction of pentane × vapor pressure of pentane) + (mole fraction of hexane × vapor pressure of hexane) = 383 torr

X × 511 + (1 - X) × 150 = 383

511X - 150X + 150 = 383

511X = 233

X = 0.45

Also , at equilibrium, the vapor pressure of pentane = 0.45 × 511 = 230 torr

mole fraction of hexane in the vapor that is in equilibrium with this solution = 230/383

mole fraction of hexane at equilibrium = 0.60

Therefore, the mole fraction of pentane is 0.45 and mole fraction of hexane at equilibrium is 0.60.

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Answer:

temperature, or true. I don't know which you want.

Explanation:

hope this helps

mol = 6.78 x 10²⁵ : 6.02 x 10²³ = 112.62

MM Al₂(SO₄)₃ = 2.27 + 3.32+12.16 =342 g/mol

mass = 112.62 x 342 = 38516.04 g = 38.5 kg

The total mass of 6.78*[tex]10^{25}[/tex] molecules of [tex]Al_{2}(SO_{4})^3[/tex] is (b) 38.5 Kg.

Hence, the total weight of 6.78*[tex]10^{25}[/tex] molecules of [tex]Al_{2}(SO_{4})^3[/tex] is (b) 38.5 Kg.

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If he rubs his foot on the carpet or touches the metal doorknob it would increase his chances of being zapped.

Rubbing his feet would be friction.

Touching the doorknob would be potential energy.

Side note: I love the format for this question, was not expecting to see John Travolatge on here today >O< !!!  

Answer:

Positively charged ions move to the negative electrode during electrolysis

Explanation:

Electrolysis is the process by which electric current is passed through a substance to effect a chemical change

I hope I was able to help

Explanation:

N2 (g) + H2 (g) gives out NH3 (g)

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.

Now balance it. You have two reactants with compositions involving a single element, which makes it very easy to keep track of how much is on each side. I would balance the nitrogens, and then the hydrogens.(If you balance the hydrogen reactant with a whole number first, I can guarantee you that you will have to give NH3 a new stoichiometric coefficient.)

N2 (g) + 3H2 (g) gives out 2NH3 (g)

The stoichiometric coefficients tell you that if we can somehow treat every component in the reaction as the same (like on a per-mol basis, hinthint), then one "[molar] equivalent" of nitrogen yields two [molar] equivalents of ammonia.

Luckily, one mol of anything is equal in quantity to one mol of anything else because the comparison is made in the units of mols.

So what do we do? Convert to

mols (remember the hint?).

28g N2 × 1 mol N2/ 2 × 14.007) g N2

= 0.9995 mol N2

At this point you don't even need to calculate the number of mols of H2 . Why? Because H2 is about 2 g/mol, which means we have over 10 mols of H2. We have 1 mol N2, and we need three times as many mols of H2 as we have

N2.

After doing the actual calculation you should realize that we have about 4 times as much H2 as we need. Therefore the limiting reagent is clearly N2.

Thus, we should yield 2×0.9995=1.9990 mols of NH3 (refer back to the reaction). So this is the second and last calculation we need to do:

1.9990 mol NH3 × 17.0307 g NH3/ 1 mol NH3

= 34.0444 g NH3

Hope it helpz~

34grams of NH₃ can be produced from the reaction of 28g of N₂ and 25g of H₂ and 19g of the excess reagent is left over.

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.

A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.

Given,

Mass of N₂ = 28g

Mass of H₂ = 25g

Moles of N₂ = mass / molar mass

                    = 28 / 28

                   = 1 mole

Moles of H₂ = 25 / 2

                     = 12.5 moles

Since the number of moles of N₂ is lesser, the amount of products formed depends on the moles of N₂.

From the reaction,

1 mole of N₂ gives 2 moles of NH₃

So, Mass of NH₃ in 2 moles = 2 × 17

                                              = 34g

B) From the reaction,

1 mole of N₂ reacts with 3 moles of H₂.

The number of Moles of H₂ left = 12.5 - 3

                                                    = 9.5 moles

Mass of excess reagent left = moles left × molar mass of H₂

                                             = 9.5 × 2

                                             = 19g

Therefore, 34grams of NH₃ can be produced from the reaction of 28g of N₂ and 25g of H₂ and 19g of the excess reagent is left over.

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A precipiatate of mass 0.013 g is formed when you mix 75.0 mL of a NaOH solution with pOH of 2.58 and  125.0 mL of a 0.0018 M MgCl2 solution

In stoichiometry, calculations are made based on mass - mole or mole - volume relationships. First we must put down the balanced reaction equation; 2NaOH(aq) + MgCl2(aq) -----> Mg(OH)2(s) + 2NaCl(aq)

Now Ionically;

2OH^-(aq) + Mg^2+(aq)  -----> Mg(OH)2(s)

Concentration of OH^- = Antilog (-2.58) = 2.6 * 10^-3 M

Number of moles of OH^- = 2.6 * 10^-3 M * 75/1000 = 0.000195 moles

Concentration of Mg^2+ = 0.0018 M

Number of moles of Mg^2+ =0.0018 M * 125/1000 = 0.000225 moles

Since;

1 mole of Mg^2+ reacts with 2 moles of  OH^-

x moles of Mg^2+ reacts with 0.000195 moles of  OH^-

x = 0.0000975 moles

Mg^2+  is the limiting reactant.

1 mole of Mg^2+ yields 1 mole of the precipitate

0.000225 moles of Mg^2+ yields 0.000225 moles of precipitate.

Hence, a precipitate is formed.

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Answer: D. Fusion reactions in the sun convert small amounts of mayter into large amounts of energy.

Answer:

X-rays are a form of electromagnetic radiation, similar to visible light. Unlike light, however, x-rays have higher energy and can pass through most objects, including the body. Medical x-rays are used to generate images of tissues and structures inside the body.

Explanation:

Answer:

A. Boron-11 with atomic number 5

Answer:

Explanation:

Calculate the pH of solution

that has

[H+]of 8.1 x10^-4

Heart-shaped faces is the characteristic all owl families share and it is denoted as option D.

This is a type of bird which is known for its heart shaped face, big round eyes and reversible toe.

This animal has majority of its species as night time hunters which is why option D was chosen.

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Answer:

The forces that keep liquid particles together are called intermolecular forces of attraction.

Answer:

See below

Explanation:

From periodic chart

Mg = 24.305 gm per mole

24.305 * 3 = 72.915 gm

Na = 22.989

Cl = 35.45            summed = 58.439 gm per mole

   58.439 * 4.2 = 245.4438 gm

For the first ionization energy of mercury is 1006 kJ/mol. The energy change for the reaction  is mathematically given as

dH = 1006KJ/mol

The amount of energy required to remove an electron from a neutral atom is called ionization energy. from the question, the electron is removed from the neutral atom Hg to give the first ionization energy

Hg→Hg +e

therefore the energy change for the reaction is

dH = 1006KJ/mol

In conclusion, the energy change for the reaction is

dH = 1006KJ/mol

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The number of protons in X would be 6 while that of Y would also be 6. Thus, the two atoms would be isotopes of the same element.

The mass number of an atom is the sum of protons and neutrons present in the atom.

For X with mass number 12 and neutron number 6, the number of protons would be:

                                 12 - 6 = 6 protons

For Y with mass number 13 and neutron number 7, the number of protons would be:

                                     13 - 7 = 6 protons.

Thus, both atoms have the same number of protons, meaning that they are likely isotopes of the same element.

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Answer:

The kinetic energy decreases

Explanation:

When water freezes, it is losing heat. Heat and energy are interchangeable, meaning it loses energy.

Answer:

The kinetic energy of the molecules decreases.

Explanation:

because when temperature decreases the average kinetic energy of the gas molecules decreases as well.

Answer:

Coal

Explanation:

Answer:

CARBOHYDRATES AND CARBOHYDRATE METABOLISM

Answer:

Aerosol cans are pressurized, High temperatures increase the pressure in an aerosol can, potentially to the point of explosion.

Answer:

hydrocarbon

Explanation:

it reacts with oxygen to produce water and carbon dioxide.

hope this helps.

Answer:

Explanation:

Observation. Observational skills are the starting point for critical thinking. People who are observant can quickly sense and identify a new problem.

Analysis. Once a problem has been identified, analysis skills become essential. ...

Answer:

liberates 1790 kJ of heat.

Explanation:

Since the molecule is able to immediately absorb the red color of the bromine, the molecule would be cycloheptene.

Unsaturation in organic compounds refers to the presence of double or triple bonds in the compounds.

One way to test for unsaturation is to use bromine water. A saturated compound will not be able to absorb bromine because it is already saturated.

An unsaturated compound, on the other hand, will be able to absorb bromine due to the unsaturation. Therefore, the red color of bromine will disappear due to absorption.

Cycloheptane is saturated while cycloheptene is unsaturated. Thus, the latter will absorb the red color of bromine.

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