5 postulates of neil bohr atomic model​

Answers

Answer 1

Answer:

What is Bohr’s Model of an Atom?

The Bohr model of the atom was proposed by Neil Bohr in 1915. It came into existence with the modification of Rutherford’s model of an atom. Rutherford’s model introduced the nuclear model of an atom, in which he explained that a nucleus (positively charged) is surrounded by negatively charged electrons.


Related Questions

a toy car needs a source of energy to move. how could you give gravitational potential energy to a toy car so that it will move when you let it go?​

Answers

Answer:

wait one second im about to go get some milk im thirsty

Explanation:

do you want any chicken on your salad

!!!
MULTIPLE CHOICE QUESTION
If a simple machine has a MA of 5 and you lift an object UP 2 m, how far must you push the
object along the ramp's surface?
0.5 m
10 m
0.2 m
1 m

Answers

Answer:

0.5

Explanation:

I think it is this beacause if u have the answer you have that

A rifle recoils while firing a bullet. The speed of the rifle's recoil is small because the

Answers

A rifle recoils while firing a bullet. The speed of the rifle's recoil is small because the rifle has more mass than the bullet.

[tex]p_{1} =-p_2}[/tex]

[tex]m_{1} V_{1} =-M_{2} v_{2}[/tex]

Answer:

Explanation:

A rifle recoils while firing a bullet. The speed of the rifle's recoil is small  and typically fast because the rifle has more mass than the bullet.

. True or False: A bystander intervention is the term used to define when an individual actively moves in and changes the outcome of a situation.

Answers

Answer:

true

Explanation:

what is the gravitation potential energy of a 57 kg sightseer standing at the top of the empire state building which is 381m above ground level

Answers

GPE = mgh

GPE = 57 x 9.8 x 381 = 2.12 x 10⁵ J

Derive the Schrödinger's Time independent wave equation using kinetic energy and momentum.

Answers

Consider,

[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =m\langle v(t)\rangle=m\int_{-\infty}^{\infty}x\bigg\{\dfrac{\partial \Psi^{*}(x,t)}{\partial t}\Psi (x,t)+\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial t}\bigg\}dx}[/tex]

Multiply both sides by ih and simplification will yield

[tex]{:\implies \quad \displaystyle \sf ih\langle p\rangle =m\int_{-\infty}^{\infty}x\bigg[\Psi (x,t)\bigg\{\dfrac{h^2}{2m}\dfrac{\partial^{2}\Psi^{*}(x,t)}{\partial x^2}-V(x)\Psi^{*}(x,t)\bigg\}+\Psi^{*}(x,t)\bigg\{V(x)\Psi (x,t)-\dfrac{h^2}{2m}\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}\bigg\}\bigg]dx}[/tex]

Some simplification, Then Integrate by parts and then knowing the fact that the wave function vanishes for [tex]{\bf x\to \pm \infty}[/tex] will yield:

[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =\dfrac{ih}{2}\int_{-\infty}^{\infty}\bigg\{\dfrac{\partial \Psi^{*}(x,t)}{\partial x}\Psi (x,t)-\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial x}\bigg\}dx}[/tex]

Integrating by parts and knowing the same fact by some simplification will yield:

[tex]{:\implies \quad \displaystyle \sf \langle p\rangle =-ih\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial \Psi (x,t)}{\partial x}dx}[/tex]

The momentum is thus contained within the wave function, so we can then deduce that:

[tex]{:\implies \quad \sf p\rightarrow -ih\dfrac{\partial}{\partial x}}[/tex]

[tex]{:\implies \quad \sf p^{n}\rightarrow \bigg(-ih\dfrac{\partial}{\partial x}\bigg)^{n}}[/tex]

[tex]{:\implies \therefore \quad \displaystyle \sf \langle p^{2}\rangle =-h^{2}\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}dx}[/tex]

Now the kinetic energy

[tex]{:\implies \quad \displaystyle \sf \langle K\rangle =\dfrac{\langle p^{2}\rangle}{2m}=\dfrac{-h^2}{2m}\int_{-\infty}^{\infty}\Psi^{*}(x,t)\dfrac{\partial^{2}\Psi (x,t)}{\partial x^2}dx}[/tex]

The classical formula for the total energy

[tex]{:\implies \quad \sf \dfrac{p^2}{2m}+V(x)=E}[/tex]

Multiplying this equation by [tex]{\sf \Psi (x,t)=\psi (x)exp\bigg(\dfrac{-iEt}{h}\bigg)}[/tex] and use the above equations and simplify it we will be having

[tex]{:\implies \quad \boxed{\bf{\dfrac{-h^2}{2m}\dfrac{d^{2}\psi (x)}{dx^{2}}+V(x)\psi (x)=E\psi (x)}}}[/tex]

This is the Famous Time-Independent Schrödinger wave equation

Note:- If I write all the explanation then the Answer box willn't allow me to submit the answer


What arguments can you think of for staying single

Answers

Answer:

Staying single makes it a whole lot easier to focus on yourself, gain self love, and work on yourself!

Explanation:

Vhat are you looking for when you research a potential employer?
personal information about the managers
company history
related industry news
what its product or service is

Answers

B because I had it before

A body of mass 200gram is executing SHM with amplitude of 20mm. The magnitude of maximum force which acts upon it is 0.6N. Calculate its maximum velocity?

Answers

Given ,

Mass of the body (m) = 200g

Amplitude (A) = 20mm

Maximum force (F) = 0.6 N

Maximum velocity (vmax) =?

We know that

Fmax = mv2max/A

or , 0.6 = 200×10-3xv2max/20×10-3

or , 0.6×20/200= v2max

or , vmax = 0.24 m/s

∴ Maximum velocity = 0.24 m/s2

The value of maximum velocity will be 0.3464 m/s². Energy or work is equal to the product of force and displacement.

What is velocity?

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

Mass of the body is,(m= 200g)

Amplitude is,(A  =20 mm)

Maximum force is,F= 0.6 N

To find;

Maximum velocity

Energy or work is equal to the product of force and displacement.

[tex]\rm KE = \frac{1}{2} mV_{max}^2 \\\\ \rm F_{max} \times A = \frac{1}{2} mV_{max}^2 \\\\ F_{max}= \frac{1}{2}\frac{ mV_{max}^2}{A} \\\\ 0.6= \frac{1}{2}\times \frac{ 0.2 \times V_{max}^2}{20 \times 10^{-3}} \\\\ V_{max}=0.3464 \ m/sec^2[/tex]

Hence,the value of maximum velocity will be 0.3464 m/s².

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Monitoring cash flow and keeping track of the bottom line of a business are responsibilities for whom?

Answers

Answer:
A financial manager.

Explanation:
This is because a financial manager oversees the financial operations of a company. Generally, a financial manager assumes accounting responsibilities for the company. A financial manager is responsible for planning and managing the company's financial resources.


Side note:
Hope this helps!
Please give Brainliest!

7. It has been suggested that rotating cylinders about 20 km in length and 8 km in diameter be placed in space and used as colonies. The purpose of the rotation is to simulate gravity for the inhabitants. Explain this concept for producing an effective imitation of gravity.

Answers

The concept of the centrifugal force is used for producing an effective imitation of gravity. It is an important concept in the mechanics.

What is centrifugal force?

when any body is executing circular motion about a fixed axis, an outward force act on that object to balance the body and to execute the circular motion. The outward force is known as the centrifugal force.

It is the pseudo force act in order to balance the centripetal force acting inward during the circular motion.

The centrifugal force is comes into the picture when any body executes circular motion about a fixed axis.

To simulate gravity for the inhabitants, the concept of the centrifugal force is used.

Hence, the concept of the centrifugal force is used for producing an effective imitation of gravity.

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How to calculate magnitude of tension if given an angle of 10°

Answers

Answer:

Mag isip ka po wag Kang tanong ng tanong kac kami po Yung nahihirapan mag hanap ng answer

A small object with a mass of 1 kg moves in a circular path with a constant speed of 5 m/s. What is the change in momentum during 1⁄2 of period; one period?

Answers

The change in momentum of the object during the half period is -10 kgm/s.

The change in momentum of the object during the one period is 0.

Change in momentum of the object during ¹/₂ period

The change in momentum of the object during the half period is calculated as follows;

ΔP(¹/₂) = Pf - Pi

where;

Pf is final momentumPi is the initial momentum

ΔP(¹/₂) = (-5 x ) - (5 x 1)  

ΔP(¹/₂) = -10 kgm/s

Change in momentum of the object during 1 period

ΔP(1) = Pf - Pi

ΔP(1) = (5 x 1) - (5 x 1) = 0

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The magnetic field lines of a bar magnet spread out from the
A. north end to the south end.
B. south end to the north end.
C. edges to the center.
D. center to the edges.

Answers

Answer:

I think the letter B. But I'm not sure pero I try mo Lang po baka Yan po ang tamang sagot kac Yan po Yung nilagay na sagot saakin e Kaya try mo Lang po

A 23900N/C electric field points down. What is the value of a charge placed in the field if it experiences a force of 7520N up?

Answers

Answer:

0.315C

Explanation:

Force/Electric field

7520N/23900C

A tourist, who weighs 805 N, is walking through the woods and crosses a small horizontal bridge. The bridge rests on two concrete supports, one at each end. He stops one-fourth of the way along the bridge. Assume that the board of the bridge has negligible weight. What is the magnitude of the vertical force that a concrete support exerts on the bridge at the far end?

Answers

The magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.

What is force?

The force is an action of push or pull which makes a body to move or stop.

Given is the weight of tourist W = 805 N and L is the length of the bridge.

Let the reaction force at both the ends of the bridge is R1 and R2.

Taking the moments about point A,

R1 x 0 - W x L/4 +R2 x L =0

R2 = W/4

R2 = 805 /4

R2 = 201.25 N

Thus, the magnitude of the vertical force that a concrete support exerts on the bridge at the far end is 201.25 N.

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4) The specific heat of aluminum is 0.88 J/g °C. How much heat is released when a 10 g piece of aluminum foil is taken out of the oven and cools from 100° to 50°?
4.40 J
568 J
440 J​

Answers

Answer:

See below

Explanation:

The units of the specific heat hint at how to solve these types of problems

.88 J/(g-C)   * 10 g  *  (100- 50 C) = 440 J  

                                  ( see how the g and the C 'cancel out' ?)


1. The object or point from which movement is determined is called a
of

Answers

Answer: reference point

Explanation: A reference point could be a put or question utilized for comparison to decide in case something is in movement.

Why the range of a clinical thermometer kept between 35°C and 42°C? ​

Answers

Answer:

Because it is the standard operational range for measuring the body temperature of a living individual.

Explanation:

When making a measuring equipment like a thermometer, you attempt to keep the reading range (Span) as small as possible so that the reading is as accurate as feasible. Because sensors are often rated in percent of span (in this example, span = 45 C–32 C = 13 degrees Celsius), One percent of 13 equals 0.13 degrees Celsius, thus if your sensor has a usual accuracy of 1%, your temperature reading is accurate to roughly 0.1 degrees Celsius.

Your precision would be 0.2 degrees Celsius if you doubled the span. The reading accuracy is now becoming unsatisfactory. Readability is another advantage of analog and mercury clinical thermometers. The markings for 0.1 deg C would be ten times closer together if a mercury thermometer had ten times the range (span). There is a limit to the device's readability.

what is the main function of a diode​

Answers

Answer:

acts as a one-way switch for current

-10m/s² and vertical height of 0.6m.How will we use this information to find the velocity of the falling object?

Answers

i think we should ask our teach

What is specific heat capacity??​

Answers

Specific heat capacity is the unit mass of a substance is defined as the amount of heat absorbed (kg) (J), when its temperature rises 1 K (or 1 ° C), and its units J / ( kg K) or J / happen. (Kg ° C).

Hope it helps u

Stay safe, stay healthy and blessed.Have a good day !Thank you

#Jennifer

Answer:

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

calculate the work done 36 kg boxes lifted onto a shelf 1.5 m high​

Answers

Answer:

529.2 joules

Explanation:

Work done = force x distance = mass x gravity x distance

= 36x9.8 x1.5 =529.2 joules

What kind of object are the light rays interacting with in the model below?

Convex mirror
Convex lens
Concave mirror
Concave lens

Answers

Answer:

Concave lens

.............

How much kinetic energy does a 0.30-kg stone have if it is thrown at44

Answers

Answer:

290.4 joules

Explanation:

As the formula to find kinetic energy is 1/2 mv^2.

So if we put the given data in it,the answer comes 290.4 joules

light frequency of 3.6 x 10^14 hz what is the wavelength

Answers

8.3×10 to the power minus 7

Explanation:

lambda equals velocity over frequency.

An empty hot air balloon weighs 1000 newtons (N). As the balloon is released in the air, the atmosphere provides a lift force of 3300 N. What is the magnitude and direction of the net force?

2300 N upward
4300 N upward
2300 N downward
4300 N downward

Answers

[tex]\Large{\green}\fcolorbox{blue}{cyan}{\bf{\underline{\red{\color{red}Answer}}}}[/tex]

2300 N upward

Explanation:

The force by weight of balloon = 1000 N

The atmospheric force experienced by balloon = 3300 N

While weight of balloon is attracted by gravity so the force of weight will act downward

And the atmospheric force gives upward lifting force to the balloon

Net force = atmospheric force - weight of balloon

= 3300 - 1000

= 2300 N

As the atmospheric force is more dominating the balloon will goes upward with 2300 N force

1. The sketch shows two 4 kg blocks on a horizontal surface, joined by a string S. They are attached to a 2 kg mass by another string which passes over a frictionless pulley, allowing the 2 kg mass to hang freely. Each of the blocks experiences 6 N of friction.
a) Show that the system accelerates to the right at 0.8 m/s². Calculate the tension in string S.
b) 4 kg S 4 kg 2 kg [4] [4]

Answers

Answer:

M g - T =  M a     acceleration of hanging block   (M = 2)

2 g - T = 2 a        where M = 2

T = 2 g - 2 a

T = 8 * a + 12 N       acceleration of blocks on table

2 g - 2 a = 8 a + 12

10 a = 2 g - 12  

a = .8 m/s^2   (assuming g = 10 m/s^2)

T = 2 g - 2 a = 2 * 10 - 2 * .8 = 20 - 1.6 = 18.4 N

Check: For blocks on table

a = (18.4 - 12) / 8 = 6.4 / 8 = .8 m/s^2

1. Some ripples spread across a pond with a frequency of 5 Hz. How much would be the period of these ripples.


2. A sound wave has a time period of 0.01 seconds. What is its frequency?


3. A radio wave has a time period of 0.0000002 seconds. What is its frequency?

Answers

1)The period of these ripples will be 0.2 sec.

2)The time period of sound wave will be 100 Hz.

3)The frequency of the sound wave will be 5×10⁶ Hz.

What is frequency?

Frequency is defined as the number of repetitions of a wave occurring waves in 1 second.

Frequency is given by the formula as,

Frequency of  ripples (f₁)=5 Hz

The period of these ripples will be;

T₁=1/f₁

T₁=1/5

T₁=0.2 sec

The time period of sound wave (T)=0.01 seconds

The time period of sound wave;

f=1/T

f=1/0.01

f=100 Hz

Time period of A radio wave = 0.0000002 seconds

The frequency of the sound wave is;

f=1/T

f=1/0.0000002

f=5×10⁶ Hz

Hence,the period of these ripples will be 0.2 sec.

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86. What is the average velocity if the initial velocity is at rest and the final velocity of 16 m/s? a) 16 m/s b) 12 m/s c) 8 m/s d) 4 m/s​

Answers

Answer:

8 m/s

Explanation:

(16-0)/2 = 8 m/s

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