A committee must be formed with 4 teachers and 7 students. If there are 9 teachers to choose from, and 8 students, how many different ways could the committee be made?

Answer:

[tex]x(3x-7)=3x^2-7x[/tex]

Step-by-step explanation:

[tex]\Large \begin{array}{| c | c | c |}\cline{1-3} \textsf{x} & 3x & -7\\\cline{1-3} x & 3x^2 & -7x\\\cline{1-3}\end{array}[/tex]

[tex]\textsf{Therefore,}\quad x(3x-7)=3x^2-7x[/tex]

Find the values a, b, and c to substitute into the quadratic formula.

Notice how there are a, b, and c. Everything is left of the equal sign, leaving 0 on the right.

ax² + bx + c = 0

Notice how there are a, b, and c too, just like in standard form. After we find standard form, we can substitute a, b and c values into the quadratic formula.

[tex]\displaystyle{x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} }[/tex]

Here are the steps we will follow:

Move everything to the left while keeping both sides equal.

x² + 1 = 2x – 3                 Equation from the question

x² + 1 + 3 = 2x – 3 + 3     Add three to both sides.

x² + 1 + 3 = 2x                 -3 + 3 cancels out to 0.

x² + 4 = 2x                      Simplify.

x² + 4 – 2x = 2x – 2x     Subtract 2x from both sides.

x² + 4 – 2x = 0                No numbers on the right side is the same as 0.

x² – 2x + 4 = 0                Rearrange to follow ax² + bx + c = 0.

Find a, b, and c from standard form.

ax² + bx + c = 0         Standard form

x² – 2x + 4 = 0           No number attached to x² means a = 1.

a = 1,  b = –2,  and  c = 4

Substitute a = 1, b = –2, and c = 4 into the quadratic formula.

[tex]\displaystyle{x=\frac{-b \pm \sqrt{b^{2}-4ac}}{2a} }[/tex]    

Here is how our formula set up should look:

[tex]\displaystyle{x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4(1)(4)}}{2(1)} }[/tex]

Let's compare formula set up to the options in the question.

The denominator is 2(1). So, the answer is not option B.

Inside the square root, it says –4(1)(4). So, the answer is not option D.

This leaves us with either option A or option C.

Before the ±, it says –(–2). When simplified, –(–2) is 2.

Option C has –2. So, the answer is not option C.

Inside the square root, it says (–2)², which is equal to 2².

When solving exponents of negative numbers,

The exponent 2 is even.

(–2)² = 4

∵ (–2)² = 4 and 2² = 4

∴ (–2)² = 2²

(–2)² is the same as 2².

Therefore, the answer is option A.

The length of AD in triangle ABC in which ∠1 = ∠2 is 3.75.

The (interior) bisector of an angle, also called the internal angle bisector, is the line or line segment that divides the angle into two equal parts.

Here, Let the lenght of AD be x

         AB = 10 , AC = 6 and BC = 6

by Angle-Bisector theorem which states that

if a ray bisects an angle of a triangle, then it divides the opposite side into segments that are proportional to the other two sides.

So, CD/BD =AC/AB

      CD/(BC-CD) = 6/10

       10. CD = 6.BC - 6.CD

        16 CD = 6 X 6

         16 CD = 36

          CD = 36/16

         CD  = 2.25

Now, AD = AC - CD

         AD = 6 - 2.25

         AD = 3.75

Thus, the length of AD in triangle ABC in which ∠1 = ∠2 is 3.75.

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Answer:

B

Step-by-step explanation:

answer is based on results from the Cartesian plane

Answer:

11

Step-by-step explanation:

2 dozen = 24

24-10=14

14-3=11

Answer:

11

Step-by-step explanation:

two dozens is 24 because one dozen is 12. 24-10=14-3=11

Answer:

C) 26

Simplify using the FOIL method--used to multiply binomials--and then combine real and imaginary parts of the problem.

5 × 5 = 25 + positive 1(i) = 26

Answer:

option c, 26

Step-by-step explanation:

(5 + i)(5 - i)

Apply complex arithmetic rule: (a + bi)(a - bi) = a^2 + b^2

a = 5, b =1

(5)^2 + (1)^2

(5)^2 = 25

(1)^2 = 1

25 + 1

Answer:

9) Vincent will not get the correct answer because the + 484 is unneccesary, as he already subtracted it.

10a) 310,000 + x = 465,000; so x = 155,000

10b) 930,000/310,000 = 3 times more

Step-by-step explanation:

[tex]~~~~~37^x = 12\\\\\implies \ln\left( 37^x \right) = \ln(12)\\\\\implies x \ln (37) = \ln(12)\\\\\implies x = \dfrac{\ln(12)}{\ln(37)}\\\\\implies x \approx 0.689[/tex]

Answer: [tex]i\sqrt{5}[/tex]

Step-by-step explanation:

[tex]\sqrt{-5}=\sqrt{(-1)(5)}=\sqrt{-1} \sqrt{5}=\boxed{i\sqrt{5}}[/tex]

Answer:

Both graphs in 2 separate attachments--placed in order

Hope it helps.

Hello ~

My name is Sxnnysoul, and I will be answering your question today! :D

Let's solve for x ~

⇢ [tex]\sf{x^2 \: + \: y^2 \: = \: 4}[/tex]

⇢  [tex]\sf{Step \: 1: \: Add \: -y^2 \: to \: both \: sides.}[/tex]

⇢  [tex]\sf{x^2 \: + \: y^2 \: + \: -y^2 \: + \: = \: 4 \: + \: -y^2}[/tex]

⇢  [tex]\sf{x^2 \: + \: -y^2 \: + \: 4}[/tex]

⇢  [tex]\sf{Step \: 2: \: Take \: square \: root.}[/tex]

⇢  [tex]\sf{x \: = \sqrt{-y^2 \: + \: 4} \: or \: = - \sqrt{-y^2 \: + \: 4}[/tex]

P.S here's the graph that might help you!

Let's solve of x ~

⇢  [tex]\sf{x^2 \: + \: y^2 \: = \: 32}[/tex]

⇢  [tex]\sf{Step \: 1: \: Add \: -y^2 \: to \: both \: sides.}[/tex]

⇢  [tex]\sf{x^2 \: + \: y^2 \: + \: -y^2 \: + \: = \: 32 \: + \: -y^2}[/tex]

⇢  [tex]\sf{x^2 \: + \: -y^2 \: + \: 32}[/tex]

⇢  [tex]\sf{Step \: 2: \: Take \: square \: root.}[/tex]

⇢  [tex]\sf{x \: = \sqrt{-y^2 \: + \: 32} \: or \: x \: = - \sqrt{-y^2 \: + \: 32}[/tex]

P.S here's the second image of the graph. so, you won't get confused.

Hope It Helps! ~

~ Learn With Sxnnysoul ~

[tex]\underline{Answer :}[/tex]

ꜱ x ɴ ɴ ʏ ꜱ ᴏ ᴜ ʟ

Answer: 180 minutes

90 miles in 3 hours

Step-by-step explanation:

60 minutes = 1 hour

60 mins/20 mins = 3

60*3 = 180

30 miles per hour for 3 hours is 90 miles

Answer:

x = 27.19

Step-by-step explanation:

Sin(54) =22/x

0.81=22/x

x0.81= 22

x = 27.19

See

x is decreased by 3 .

and y is increased by 5

So translation is

Hence

So

x will go 3 units right

y will go 5units up

Graph attached

Answer:

Translations

For [tex]a > 0[/tex]

[tex]f(x+a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units left}[/tex]

[tex]f(x-a) \implies f(x) \: \textsf{translated}\:a\:\textsf{units right}[/tex]

[tex]f(x)+a \implies f(x) \: \textsf{translated}\:a\:\textsf{units up}[/tex]

[tex]f(x)-a \implies f(x) \: \textsf{translated}\:a\:\textsf{units down}[/tex]

Parent function:

[tex]f(x)=\left(\dfrac{1}{4}\right)^x[/tex]

Translated 3 units to the right:

[tex]f(x-3)=\left(\dfrac{1}{4}\right)^{x-3}[/tex]

Translated 5 units up:

[tex]f(x-3)+5=\left(\dfrac{1}{4}\right)^{x-3}+5[/tex]

[tex]\implies g(x)=f(x-3)+5[/tex]

Therefore:

[tex]\textsf{g(x) is a translation of f(x) by }\left(\begin{array}{c}3\\5\\\end{array}\right)[/tex]

Answer:

true

Step-by-step explanation:

2log2 6- log2 9+ 1/3log2 27 =

= log2 6² - log2 9 + log2 27^(1/3)

= log2 36 - log2 9 + log2 3

= log2 [(36 × 3)/9]

= log2 12

The statement is true.

The algebraic proof shows that the angles in an equilateral triangle must equal 60° each

Trigonometry is the branch of mathematics which set up a relationship between the sides and angle of the right-angle triangles.

From the question, we are to use the law of cosines to write an algebraic proof that shows that the angles in an equilateral triangle must equal 60°.

Given any triangle ABC, the measures of angles A, B, and C by the law of cosines are

cos A = (b² + c² - a²)/2bc

cos B= (a² + c²- b²)/2ac

cos C = (a²+ b²- c²)/2ab  

Now, given that the triangle is equilateral, with each of the side lengths equal to s

That is, a = b = c = s

Then, we can write that

cos A = (s² + s² - s²)/(2s×s)

cos A = (s² )/(2s²)

cos A = 1/2

cos A = 0.5

∴ A = cos⁻¹(0.5)

A = 60°

Also

cos B = (s² + s² - s²)/(2s×s)

cos B = (s²)/(2s²)

cos B = 1/2

cos B = 0.5

∴ B = cos⁻¹(0.5)

B = 60°

and

cos C = (s² + s² - s²)/(2s×s)

cos C = (s² )/(2s²)

cos C = 1/2

cos C = 0.5

∴ C = cos⁻¹(0.5)

C = 60°

Thus,

A = 60°, B = 60° and C = 60°

Hence, the algebraic proof above shows that the angles in an equilateral triangle must equal 60° each.

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1/5 = 60/100 * x

1/5 * 100/60 = x

100/300 = x

1/3 = x

Answer:

[tex] \frac{1}{3} [/tex]

Step-by-step explanation:

According to what we know, one-fifth is 60% of a number. Let us call that unknown number x. Since

[tex] \frac{1}{5} = 60\% \: \\ then \\ x = 100\%[/tex]

60% as a fraction is 6/10 or 3/5, in that case 100% as a fraction would be 5/5.

Recall: 60% = 3/5 and 100% = 5/5

therefore:

1/5 = 3/5

x = 5/5

note in order to find the value of x we cross multiply*

[tex] \frac{1}{5} ( \frac{5}{5}) = \frac{3}{5} x[/tex]

[tex] \frac{1}{5} = \frac{3}{5} x \\ \\ \frac{ \frac{1}{5} }{ \frac{3}{5} } = \frac{ \frac{3}{5} }{ \frac{3}{5} } x \\ \\ \frac{1}{5} \times \frac{5}{3} = x[/tex]

[tex] \frac{1}{3} = x[/tex]

Answer:

42 degrees

Step-by-step explanation:

48+90=138

180-138=42

Answer:

500 km

Step-by-step explanation:

300 plus 200 is 500km this is how far it is

The distance between City A & City C is approximately 171.3km

Given that, city A is 300 km due east of city B.

City C is 200 km on a bearing of 123° from city B.

We need to find the distance between the cities A and C,

Here we will use the concept of Cosine rule,

{Refer to the figure attached}

From ∆ABC, to find |AC|,

The cosine rule will be used.

|AC|² = |BC|² + |AB|² - 2(|BC|)(|AB|)cosB

Let |AC| = x

x² = 200² + 300² - 2(200)(300)cos33

x² = 40000 + 90000 - 120000cos33

x² = 130000-100644

x² = 29356

x = √29356

x = 171.3359

x ≈ 171.3km

Therefore, the distance between City A & City C is approximately 171.3km

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Answer:

A) 400 + 72

Step-by-step explanation:

Let the certain number be denoted by x.

⇒ 5x = 40 [Equation 1]

⇒ 9x = 72 [Equation 2]

Multiply Equation 1 by 10 :

⇒ 10(5x) = 40(10)

⇒ 50x = 400 [Equation 3]

Finding the sum of Equation 2 and Equation 3 :

⇒ 50x + 9x = 400 + 72

⇒ 59x = 400 + 72

Hence, 59 times a certain number is represented by : 400 + 72

The amount of money accumulated after investing the given amount of money at the given rate and time period is $85389.

Interest is simply the amount of money a lender or financial institution receives for lending out money or pays for receiving money.

The formula for calculating compound interest is expressed as;

A = P(1 + r/k)^(k*t)

Where A is final amount, P is initial principal balance, r is interest rate, k is  number of times interest applied per time period and t is number of time periods elapsed.

Given that;

A = P(1 + r/k)^(k*t)

A = 40500(1 + 0.038/1)¹ˣ²⁰

A = 40500 × (1.038)²⁰

A = 40500 × 2.10837

A = $85389

Therefore, the amount of money accumulated after investing the given amount of money at the given rate and time period is $85389.

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Answer:

Step-by-step explanation:

6z² + 12z +1 8​

= 6(z^2 + 2z + 3).

That's it.

Answer:

No, it will not

Step-by-step explanation:

as square of 2 is 4

Answer: 128°

Step-by-step explanation:

   There are 360° in a trapezoid. Since this is a right trapezoid, two of those angles will be equal to 90°. We will set up the following equation, and solve.

360° = 90° + 90° + 52° + x°

360° = 90° + 90° + 52° + x°

360° = 232° + x°

128° = x

x = 128°

   The obtuse angle has a measure of 128°.

Answer:

4.19

Step-by-step explanation:

Find the mean:

[tex]\text{Mean}=\frac{12+19+9}{3}=\frac{40}{3}[/tex]

Find the standard deviation:

[tex]\text{Standard Deviation}=\sqrt{\frac{(12-\frac{40}{3})^2+(19-\frac{40}{3})^2+(9-\frac{40}{3})^2}{3}}=\sqrt{\frac{158}{9}}\approx4.19[/tex]

Answer: 189 people preferred running.

Step-by-step explanation: 35% is equal to 35/100. Since 540 people were surveyed, we can multiply 35/100 by 540 to find that 189 people out of 540 preferred running. Hope this helps!

Answer:

  b) 70

  c) 62

Step-by-step explanation:

Numbers are relatively prime when they have no factors in common.

__

The factors of 51 are ...

  51 = 3×17

The factors of the other numbers are ...

  84 = 2²×3×7 . . . . . has a factor of 3 in common with 51

  70 = 2×5×7 . . . . . . no factors in common

  62 = 2×31 . . . . . . . no factors in common

  30 = 2×3×5 . . . . . has a factor of 3 in common with 51

The numbers 70 and 62 are relatively prime to 51.

Answer:

Here!! Hope i helped.

Answer: 3

Step-by-step explanation:

Answer:

a) 6.3; b) (2;1).

Step-by-step explanation:

[tex]a) \ |PQ|=\sqrt{(X_P-X_Q)^2+(Y_P-Y_Q)^2}=\sqrt{4+36}=\sqrt{40} =6.3;[/tex]

[tex]b) \ (\frac{X_P+X_Q}{2};\frac{Y_P+Y_Q}{2}); \ = > \ (2;1).[/tex]