4% of 50
Percent of a quantity
M

Answers

Answer 1

Answer:

4% of 50 is 2

Step-by-step explanation:


Related Questions

Graph the line with slope 2/3 passing through the point (-3,-3)

Answers

Step-by-step explanation:

y=mx+b

y=(2/3)x+b

-3=(2/3)(-3)+b

-3=-2+b

-1=b

y=(2/3)x-1 . y-intercept at (0,-1)  

0=(2/3)x-1

1=(2/3)x

3=2x

3/2=x . x-intercept at (1.5,0)

A jewelry store is having a sale, and all items are 15% off. If a necklace was originally price at $85.00, what is the sale price?

Answers

85*.15=12.75
85-12.75
72.25
The sale price is $72.25

please answer the question above​
it's (Septagon)

Answers

Answer:

128.57

Step-by-step explanation:

each angle is equal and all of them will sum 900 degrees

Answer:

128.6... degrees

Step-by-step explanation:

Because regular shapes have all equal angles, we can do this:

900/7

regular septagons/heptagons have 7 sides

900/7 = 128.571429 or about 128.6

2) The management company of a popular, but unstable, rapper is worried about their investment
in his up-coming world tour, so they purchase a 1-year $1 million insurance policy for $137,000.
The probability the rapper will successfully complete the 1-year world tour is 0.87352. What is
the expected value of the policy from the perspective of the management company?

Answers

Answer:

137,000

Step-by-step explanation:

its math bro

The graph shows a proportional relationship between the number of cans of tennis balls and the total number of tennis balls.
What does the point (2, 6) represent in this situation?

Tennis Balls graph showing number of tennis balls on the y axis and number of cans on the x axis. A line begins at the origin and passes through the points 1 comma 3 and 2 comma 6.

Answers

Answer:

There are 6 tennis balls in 2 cans.

Answer: c and e

Step-by-step explanation:

because im smart like that

100 Points. Help solve. The sides are X, y, and 8. The reference angle is 60 degrees. Thanks

Answers

Step-by-step explanation:

y=8tan60=8√3

x=8/cos60 = 8 × 2 =16

Last year 300 people attended a play with ticket price of $8. The school estimates that 20 fewer people attend for each $1 increase in price. What ticket price would give the greatest income?

Answers

Answer:

$12

Step-by-step explanation:

If we stuck with the price of $8, then we end with an income of $2400

Increasing it by $1 will decrease attendance by 20

8 x 300 = 2400

9 x 280 = 2520

10 x 260 = 2600

11 x 240 = 2640

12 x 220 = 2640

13 x 200 = 2600

We're starting to go down, so let's stop there

The ticket price of $11 or $12 appears to give the most income

I would stick with $12 since your still getting more money from one ticket

The price of a ticket stick at $12 since you still get more money from one ticket.

What ticket price would give the greatest income?

Last year 300 people attended a play with a ticket price of $8.

The school estimates that 20 fewer people attend for each $1 increase in price.

If we keep the price at $8, we'll end up with a $2400 profit.

Increasing it by $1 will result in a 20 percent drop in attendance.

8 × 300 = 2400

9 × 280 = 2520

10 × 260 = 2600

11 × 240 = 2640

12 × 220 = 2640

13 x 200 = 2600

Let's come to a halt here since we're starting to descend.

The $11 or $12 ticket price looks to generate the most revenue.

I'd continue with $12 because you'll still make more money with one ticket.

More about the greatest income link is given below.

https://brainly.com/question/9453332

#SPJ2

Angles 4 & 8 are an example of which type of angle? *
O Alternate Exterior
O Alternate Interior
O Corresponding
O Vertical

Answers

Answer:

Corresponding

Step-by-step explanation:

They are on the same side which makes them corresponding angles

The equation
(p-1)x^2 + 4x + (p-5)=0, where p is a constant,
has no real roots.
(a) Show that p satisfies p^2 - 6p+1>0.

Answers

Answer:

Proof is shown below.

Step-by-step explanation:

Use quadratic Formula, where from the standard form ax^2 + bx + c = 0, where a is not zero, we identify a = p-1, b=4, c = p-5, and since the given equation has no real roots, the discriminant b^2 - 4ac < 0, so that substituting we have that,

4^2 - 4(p-1)(p-5) < 0

16 - 4(p^2 - 6p + 5) < 0

16 - 4p^2 +24p - 20 < 0

-4p^2 + 24p - 4 < 0,

p^2 - 6p + 1 > 0, by dividing both sides of the inequality by -4.  

Select the values that are solutions to the inequality x2 + 3x – 4 > 0.

–6

–2

0

5

Answers

the answer to this question is -6&5

Student football game tickets cost $20 Adult tickets cost $30. Write a function that shows
the total cost for s student tickets and a adult tickets.

Answers

Answer:

Here are the answers for the whole QC for CA students.

1. C

2. A

3. no

4. c

5. A

Step-by-step explanation:

How many centimeters are in a kilometer?

Answers

Answer:

100,000

Step-by-step explanation:

Answer:

there are 100000 meters in 1 kilo meter

Step-by-step explanation:

Find the unknown number in the equation 4 x 12 = 6 x n.

Answers

Answer:

n = 8

Step-by-step explanation:

hope this helps

Allowance method entries

The following transactions were completed by Wild Trout Gallery during the current fiscal year ended December 31:

Jan. 19. Reinstated the account of Arlene Gurley, which had been written off in the preceding year as uncollectible. Journalized the receipt of $2,560 cash in full payment of Arlene’s account.
Apr. 3. Wrote off the $14,670 balance owed by Premier GS Co., which is bankrupt.
July 16. Received 25% of the $26,300 balance owed by Hayden Co., a bankrupt business, and wrote off the remainder as uncollectible.
Nov. 23. Reinstated the account of Harry Carr, which had been written off two years earlier as uncollectible. Recorded the receipt of $4,175 cash in full payment.
Dec. 31. Wrote off the following accounts as uncollectible (compound entry): Cavey Co., $11,035 ; Fogle Co., $3,275 ; Lake Furniture, $ 8,420 ; Melinda Shryer, $2,380.
Dec. 31. Based on an analysis of the $1,299,500 of accounts receivable, it was estimated that $56,500 will be uncollectible. Journalized the adjusting entry.
Required:

1. Record the January 1 credit balance of $53,800 in a T account presented below in requirement 2b for Allowance for Doubtful Accounts.

2. a. Journalize the transactions. If an amount box does not require an entry, leave it blank. Note: For the December 31 adjusting entry, assume the $1,299,500 balance in accounts receivable reflects the adjustments made during the year.
2. b. Post each entry that affects the following T accounts and determine the new balances:
3. Determine the expected net realizable value of the accounts receivable as of December 31 (after all of the adjustments and the adjusting entry).
$fill in the blank 73711efa1fe301a_1
2,290,000

4. Assuming that instead of basing the provision for uncollectible accounts on an analysis of receivables, the adjusting entry on December 31 had been based on an estimated expense of ½ of 1% of the sales of $8,020,000 for the year, determine the following:

a. Bad debt expense for the year.
b. Balance in the allowance account after the adjustment of December 31.

c. Expected net realizable value of the accounts receivable as of December 31 (after all of the adjustments and the adjusting entry).

Answers

Using the Allowance Method, the relevant transactions can be completed in the books of Wild Trout Gallery as follows:

1. Allowance for Doubtful Accounts

Accounts                                          Debit       Credit

Jan. 1 Beginning balance                             $53,800

Jan. 19 Accounts Receivable                           2,560

Apr. 3 Accounts Receivable       $14,670

July 16 Accounts Receivable        19,725

Nov. 23 Accounts Receivable                         4,175

Dec. 31 Accounts Receivable       25,110

Dec. 31 Ending balance          $56,500

Dec. 31 Bad Debts Expenses                   $55,470

Totals                                        $116,005  $116,005

Accounts Receivable

Accounts                                          Debit               Credit

Jan. 1 Beginning balance           $2,290,000

Jan. 19 Allowance for Doubtful           2,560

Jan. 19 Cash                                                            $2,560

Apr. 3  Allowance for Doubtful                                14,670

July 16  Allowance for Doubtful                              19,725

July 16  Cash                                                             6,575

Nov. 23  Allowance for Doubtful         4,175

Nov. 23 Cash                                                             4,175

Dec. 31  Allowance for Doubtful                             25,110

Dec. 31   Sales Revenue            8,020,000

Dec. 31   Cash                                               $8,944,420

Dec. 31 Ending balance                                 $1,299,500

Totals                                        $10,316,735 $10,316,735

3. Expected net realizable value of the accounts receivable as of December 31 = $1,243,000 ($1,299,500 - $56,500)

Allowance for Doubtful Accounts ending balance = $40,100 ($8,020,000 x 0.5%)

Allowance for Doubtful Accounts

Accounts                                          Debit       Credit

Jan. 1 Beginning balance                             $53,800

Jan. 19 Accounts Receivable                           2,560

Apr. 3 Accounts Receivable       $14,670

July 16 Accounts Receivable        19,725

Nov. 23 Accounts Receivable                         4,175

Dec. 31 Accounts Receivable       25,110

Dec. 31 Ending balance           $40,100

Dec. 31 Bad Debts Expenses                  $39,070

Totals                                        $99,605   $99,605

4. a. Bad Debt Expense for the year = $39,070

4.b. Balance for Allowance Accounts = $40,100

4.c. Expected net realizable value of the accounts receivable = $1,259,400 ($1,299,500 - $40,100)

Data Analysis:

Jan. 19 Accounts Receivable $2,560 Allowance for Uncollectible Accounts $2,560

Jan. 19 Cash $2,560 Accounts Receivable $2,560

Apr. 3 Allowance for Uncollectible Accounts $14,670 Accounts Receivable $14,670

July 16 Cash $6,575 Allowance for Uncollectible Accounts $19,725 Accounts Receivable $26,300

Nov. 23 Accounts Receivable $4,175 Allowance for Uncollectible Accounts $4,175

Nov. 23 Cash $4,175 Accounts Receivable $4,175

Dec. 31 Allowance for Uncollectible Accounts $25,110 Accounts Receivable $25,110

Accounts Receivable ending balance = $1,299,500

Allowance for Uncollectible Accounts ending balance = $56,500

Learn more: https://brainly.com/question/22984282

can somebody help me with my social studies cause if you do i will give you brainlist

Answers

Answer:

sure if it is about something i know

1. Solve 4x – 5 > 2x + 17.
There’s a line _ under the greater sign

Answers

Answer:

X is grater than or equal to 6

Step-by-step explanation:

4x -5 > 2x + 17

+5 > 2x - 5

4x > 2x + 12

--

4

Please help! I'll give anyone who helps 10 points.

Answers

Answer:

the bottom one b and c

Step-by-step explanation:

it goes at a steady rate of 2b=c

Bryon purchased a box of candy at the store. On his way home he ate 1/4 of the candy from the box. At dinner with friends later that night he served 1/2 of what was left. If there are 6 chocolates left in the box, how many did the box contain to start with?​

Answers

Answer:

6+6=12

12= 3/4th of the entire box

4=1/4th of the entire box

12+4=16

There was 16 chocolates originally.

Step-by-step explanation:

6 are left , 1/2 was eaten and a 1/4 was eaten. 6 left is equal to a 1/4. if a quater is 6 and their are 4 1/4 in a whole at 6 represent each quarter then 6*4=24

Which statements are true about rational expression multiplication? Check all that apply.

The closure property states that the sum of two rational expressions is an irrational number.
Rational expressions are closed under multiplication.
The commutative property states that changing the order of two or more factors does not change the value of the product.
The associative property states that the way in which two or more factors are grouped in a product changes the value of the product.
The properties of rational expression multiplication are parallel to the properties of rational number multiplication.

Answers

9514 1404 393

Answer:

  B, C, E

Step-by-step explanation:

(a) <does not refer to multiplication> FALSE

(b) Rational expressions are closed under multiplication.TRUE

(c) The commutative property states that changing the order of two or more factors does not change the value of the product. TRUE

(d) The associative property states that the way in which two or more factors are grouped in a product changes the value of the product. FALSE, the product will be unchanged.

(e) The properties of rational expression multiplication are parallel to the properties of rational number multiplication. TRUE

Answer:

The answer is B, C, E. aka, 2,3,5

Step-by-step explanation:

Here is proof! Hope you pass<33

write the simplest polynomial function with the given zeros 2 √2, √5 and -3

Answers

Answer:

A. P(x) = x⁵ + 3x⁴ - 13x³ - 39x² + 40x + 120

Step-by-step explanation:

With the given zero's, the polynomial is:

P(x) = (x - 2√2)(x - √5)(x + 3)

Open parenthesis in steps:

1. (x - 2√2)(x - √5) = x² - (2√2 + √5)x + 2√10 = x² - 2x√2 - x√5 + 2√10

2. (x² - 2x√2 - x√5 + 2√10)(x + 3) =

x³ - 2√2x² - √5x² + 2√10x + 3x² - 6√2x - 3√5x + 6√10 =

x³ + 3x² - 2x²√2 - x²√5 - 6x√2 - 3x√5 + 2x√10 + 6√10

This is not matching any options so we add two more zero's: -2√2 and -√5

New polynomial looks like:

P(x) = (x - 2√2) (x + 2√2)( x - √5)(x - √5)(x + 3)

Open parenthesis in steps:

1. (x - 2√2) (x + 2√2) = x² - 82. (x - √5) (x + √5) = x² - 53. (x² - 8)(x² - 5) = x⁴ - 8x² - 5x² + 40 = x⁴ - 13x² + 404. (x⁴ - 13x² + 40)(x + 3) = x⁵ + 3x⁴ - 13x³ - 39x² + 40x + 120P(x) = x⁵ + 3x⁴ - 13x³ - 39x² + 40x + 120

I NEED HELP PLEASE!!!

Passing through (7,-2) and perpendicular to the line whose equation is y=1/2x+2

Point slope form=

Slope-intercept form=

Answers

Answer:

yyou slope intrecept is already there

Step-by-step explanation:

2+2=4

Answer:

9x+3y=36

Step-by-step explanation:

boom

Please help!!!
I need help finding the answer.

Answers

Answer:

2nd option

Step-by-step explanation:

The shaded area = outside area - inner area

                           = x² - (x - 6)² ← expand using FOIL

                         = x² - (x² - 12x + 36) ← distribute parenthesis by - 1

                        = x² - x² + 12x - 36 ← collect like terms

                        = 12x - 36

Mercury is one of only two elements that are liquid at room temperature. Mercury is nonliquid for
temperatures less than -38.0°F or greater than 673.8°F. Write a compound inequality for the temperatures
at which mercury is nonliquid.

Answers

Answer:

greater than 673.8°F. Write a compound

Step-by-step explanation:

PLEASE HELP WITH THIS ONE QUESTION

Answers

Answer:

dont know

Step-by-step explanation:

sorry

A polyhedron with 16 edges cannot be a prism. Explain why this must be true

Answers

Answer:

This prism has: 5 Faces. 6 Vertices (corner points) 9 Edges.

Step-by-step explanation:

james likes to make sculptures. First he makes a scale and then he blows it up to normal size. The height of the scale model is 3 inches. The scale he is using is 1inch = 3 feet. How tall is the sculpture?

Answers

The height of the full size sculpture is 9 feet

How do you close a revenue account?

A)

Credit Capital; debit Revenue

B)

Debit Capital; credit Revenue

C)

Debit Income Summary; credit Revenue

D)

Credit Income Summary; debit Revenue

Answers

Answer:

D)

Credit Income Summary; debit Revenue

how do i solve this step by step? i dont know how to set up this equation

Answers

Answer:

23

Step-by-step explanation:

The markings show that the vertical line and the hypotenuse are bisected. That means that the common ratio is 1/2.

(x - 8) / 30 = 1/2                     Cross multiply

2(x - 8) = 30                           Divide both sides by 2

x - 8 = 30/2      

x - 8 = 15                                Add 8 to both sides

x-8+8 =15+8

x = 23

A baseball game has



Answers

Answer:

ummm whats the chioces

Step-by-step explanation:

HELPPPPPPPPPPPPPPPppppppppppppp

Answers

The blue area on the graph are all the possible solutions. The chili beans need to be less than 3 and the corn husks need to be less than 7

Answers are: A, B, C and E

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