Answer:
Vx = V0 cos 60 = V0 ./ 2 horizontal speed
Vy = V0 sin 69 = V0 * .866 = .866 V0 vertical speed
t = 107 / Vx = 214 / V0 time to travel 107 m
h = Vy t - 1/2 * g t*2 time to fall 1.7 m
-1.7 = .866 V0 * 214 / V0 - 4.9 * (214 / V0)^2 substituting
224400 / V0^2 = 187
V0 = (224400 / 187)^1/2 = 2=34.64 m/s
t = 214 / 34.64 = 6.178 stc
Check: h = Vy t - 1/2 g t^2
-1.7 = .866 * 34.64 * 6.178 - 4.9 * 6.178^2
-1.7 = -1.69
DEFINE SIGNIFICANT DIGITS.
Answer:
Significant figures are the number of digits in a value, often a measurement, that contribute to the degree of accuracy of the value. We start counting significant figures at the first non-zero digit. Calculate the number of significant figures for an assortment of numbers.
Explanation:
any of the digits of a number beginning with the digit farthest to the left that is not zero and ending with the last digit farthest to the right that is either not zero or that is a zero but is considered to be exact. — called also significant figure.
3 points
1. Using the digram below, determine which two atoms have the same
atomic number. *
8P
8N
9P
8N
8P
9N
10P
9N
2 and 3
o
2 and 4
1 and 3
ОО
3 and 4
3 points
2. The diagram below is a modern drawing of an atom. Why are no
electrone orbits drawn? *
Answer:
1 and 2 because atomic number is equal to the numbers of protons in the nucleus
Answer:
yes answer in 1 and 2 these is answer
This type of bike tire is thinner, lighter, more expensive, and punctures easily.
PLEASE HELP LIKE NOW ASAP PLZ! WILL GIVE BRAINLIEST
In the following measurements, which zeros are significant? Circle or highlight them.
0.100 cm
1200 kg
60.10 L
0.0007 s
Answer:
1200 kg?
Explanation:
A hockey puck slides across an ice lake on a straight path and eventually comes to a stop. This is an example of which of Newton's Laws?
Answer:
Newton first law
Explanation:
Newton's first law states that, if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force. The hockey puck moved because you hit it. ( tell me if I helped I hope you do good)
two resistors of resistance 6 ohm and 3 ohm are connected in series and then in parallel .calculate the equivalent series resistance and equivalent parallel resistance.
Answer:
a. RT = 9 Ohms
b. RT = 0.5 Ohms
Explanation:
Let the two resistors be A and B.
Let RT be equivalent resistance.
Given the following data;
Resistor A = 6ohms
Resistor B = 3ohms
a. To find the equivalent series resistance;
RT = RA + RB
RT = 6 + 3
RT = 9 Ohms
b. To find the equivalent parallel resistance;
RT = 1/RA + 1/RB
Substituting into the equation, we have
RT = 1/6 + 1/3
RT = 3/6
RT = 0.5 Ohms
As here the 6 ohm and 3 ohm resistors are first connected in series and then parallel, so we can just find out the equivalent series resistance by the formula of it, which is the individual sum of all resistors (for series) and for parallel combination, the reciprocal of the total resistance is the individual reciprocal sum of all resistors, so if we apply same Formula here for series first, then we will be having :
[tex]{:\implies \quad \sf R_{s}=6+3}[/tex]
[tex]{:\implies \quad \boxed{\bf{R_{s}=9\Omega}}}[/tex]
Now, for parallel combination:
[tex]{:\implies \quad \sf \dfrac{1}{R_{p}}=\dfrac13 +\dfrac16}[/tex]
[tex]{:\implies \quad \sf \dfrac{1}{R_{p}}=\dfrac{2+1}{6}}[/tex]
[tex]{:\implies \quad \sf \dfrac{1}{R_{p}}=\dfrac36}[/tex]
[tex]{:\implies \quad \sf \dfrac{1}{R_{p}}=\dfrac12}[/tex]
[tex]{:\implies \quad \boxed{\bf{R_{p}=2\Omega}}}[/tex]
For more information related to Resistances, voltage and current, make sure to check the similar question from here :
https://brainly.com/question/27101567An engineer wants to double the water supply reserve and makes a tank 1.26 times as big as the old one in linear dimension, and the diameter of the legs is 1.41 times as large. Is this big enough?
Answer:
Yes, it would be enough.
Explanation:
The volume of the tank (cylinder tank) is given by the following equation:
[tex]V_{initial}=\pi (\frac{D}{2})^{2}h[/tex]
Where:
D is the diameter of the tank
h is the height of the tank
Now, the engineer makes a tank 1.26 times as big in heigh and 1.41 times as large with respect to diameter, then the new volume of this tank will be:
[tex]V_{new}=\pi (\frac{1.41D}{2})^{2}1.26h[/tex]
[tex]V_{new}=1.41^2*1.26\pi (\frac{D}{2})^{2}h[/tex]
[tex]V_{new}=2.51\pi (\frac{D}{2})^{2}h[/tex]
in terms of the initial volume:
[tex]V_{new}=2.51V_{initial}[/tex]
Which means that the volume of the water could be doubled.
I hope it helps you!
The planet Venus has a mass of 4.87 x 10^24 kg and a radius of 6.05 x 10^6 km. What is
the magnitude of the gravitational force that an 81-kg person would experience while
standing on the surface of Venus?
(A) 179 N
(B) 719 N
(C) 259 N
(D) 7.19 x 10^8N
(E) 4.19 x 10^9N
Answer:
The gravitational force that an 81-kg person would experience while standing on the surface of Venus is approximately;
(A) 719 N
Explanation:
The question relates to gravity calculation for which we use the Newton's gravitational law which is presented as follows;
[tex]F=G \cdot \dfrac{M \cdot m}{r^{2}}[/tex]
Where;
G = The universal gravitational constant = 6.67408 × 10⁻¹¹ m³kg⁻¹s⁻²
F = The gravitational force between the two masses, "M" and "m"
r = The distance between the centers of the two masses
M = The mass of one body interacting in the gravitational force
m = The mass of the other body interacting in the gravitational force
The given parameters are;
The mass of Venus, M = 4.87 × 10²⁴ kg
The radius of the planet Venus, r (is corrected) = 6.05 × 10³ km = 6.05 × 10⁶ km
The mass of the person standing on the surface of Venus, m = 81-kg
Therefore, by plugging in the values, we get;
[tex]F=6.67408 \times 10^{-11} \cdot \dfrac{4.87 \times 10^{24} \times 81}{(6.05 \times 10^6)^{2}} = 719.2744587391571613960795027662 \ N[/tex]
From Newton's third law of motion, the gravitational force that the 81-kg person experiences while standing on the surface of Venus = F ≈ 719 N.
Which term describes this diagram
A. food web
B.trophic level
C. Food chain
D. Matter cycle
Answer:
the answer is letter; C
Explanation:
Is Muscle a group of cells that contract when stimulated?
Answer:
No.
Explanation:
Calculate the pressure of water at depth 10metre given that:Density of water=1000 kg/m^3
Answer:
We begin by solving the equation P = hρg for depth h: h=Pρg h = P ρ g . Then we take P to be 1.00 atm and ρ to be the density of the water that creates the pressure.
Explanation:
if it helps problem doesn't sorry
Timed!! please help i would really appreciate it! i will try to give brainliest!
Craig rides a skateboard on the sidewalk in front of the mall, traveling at 18km/h. How much time would it take him to travel 6.0km?
Answer:
20 minutes
Explanation:
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Question 25
2.5 pts
Which of the following statements describes a difference
between a chemical change and a physical change in a
substance?
Tim
Attei
231
o The result of a chemical change is a different
composition; in a physical change, the composition
remains the same.
o A physical change occurs only in elements: a
chemical change occurs only in compounds.
O A chemical change occurs only in elements; a
physical change occurs only in compounds.
The result of a physical change is a different
Answer:
o The result of a chemical change is a different composition; in a physical change, the composition remains the same.
Explanation:
In a chemical change, new kinds of matter are produced although the atoms are the same.
For physical changes, no new kinds of matter formed. Only the state of substances changes.
Most chemical changes are usually irreversible Physical changes are reversible in most parts. Changes in state and form are salient characteristics of physical changes. When new products are formed from the reactants, it is an indicator of a chemical change.An object has an acceleration of 18.0 m/s/s. If the net force
acting upon this object were halved (i.e., one-half of the
original net force), then its new acceleration would be
m/s/s.
Answer:
[tex]9\ m/s^2[/tex]
Explanation:
Net Force
The Second Newton's law states that an object acquires acceleration when an external unbalanced net force is applied to it.
The acceleration is proportional to the net force and inversely proportional to the mass of the object.
It can be expressed with the formula:
[tex]\displaystyle a=\frac{F_n}{m}[/tex]
Where
Fn = Net force
m = mass
An object has an acceleration of [tex]18\ m/s^2[/tex], thus:
[tex]\displaystyle \frac{F_n}{m}=18\ m/s^2[/tex]
If the new force is halved:
F' = F_n/2, the new acceleration will be:
[tex]\displaystyle a'=\frac{F_n/2}{m}[/tex]
[tex]\displaystyle a'=\frac{1}{2}\cdot\frac{F_n}{m}[/tex]
Substituting the given acceleration:
[tex]\displaystyle a'=\frac{1}{2}\cdot 18\ m/s^2[/tex]
[tex]\displaystyle a'=9\ m/s^2[/tex]
The new acceleration is [tex]9\ m/s^2[/tex]
A car travels along a straight road, heading east for 1 h, then traveling for 30 min on another road that leads northeast. If the car has maintained a constant speed of 52 mi/h, how far is it from its starting position
Answer:
The car is 72.75 miles away from its starting position.
Explanation:
First, remember the relation:
distance = time*speed.
Also, the distance between two points (a, b) and (c, d) is:
D = √( (a - c)^2 + (b - d)^2)
For this problem, we can assume:
The North is equivalent to the y-axis, and the East is equivalent to the x-axis.
We also assume that the initial position of the car is (0mi, 0mi)
Now the car moves to the East at a speed of 52mi/h for one hour, then the new position of the car is:
(0mi, 0mi) + (52mi/h*1h, 0mi) = (52mi, 0mi)
Now the car travels 30 mins (or 0.5 hours) to the northeast at a speed of 52mi/h.
We can assume that it moves at an exact angle of 45° from East to North, then the components of the speed can be written as:
Sx = speed in the x-axis = 52mi/h*cos(45°) = 36.77 mi/h
Sy = speed in the y-axis = 52mi/h*sin(45°) = 36.77 mi/h
Then the new position of the car is:
(52mi, 0mi) + (36.77 mi/h*0.5h, 36.77 mi/h*0.5h) = (70.385 mi, 18.385 mi)
Now we know the final position of the car.
The distance between the final position (70.385 mi, 18.385 mi) and the initial position (0mi, 0mi) is:
D = √( (70.385 mi - 0mi)^2 + (18.385 mi - 0mi)^2) = 72.75 mi
The car is 72.75 miles away from its starting position.
Ten children measured and recorded how high they could jump. The results they recorded, in inches, were as follows:
8, 9, 8, 6, 8, 12, 9, 10, 11, 16
What is the median of these measures?
A police officer is using her radar to check speeds. She is moving south at 50 mph. You are moving
north at 70 mph. What does her relative speed appear to be to you?
Answer:
the relative speed should be 40mph
Explanation:
A boy starts from point A and walks 3 meters toward the south, then turns around and walks 7 meters toward the north. What is the boys placement from point A?
Answer:
-3m+7m = 4m
Explanation:
As he walks south, he is going down 3m (-3m). Then he walks up 7m (+7m).
You subtract the final position from the initial position to get displacement.
7m - 3m = 4m
Cart A (m = 2.0 kg) is traveling to the right at 4.0 m/s toward Cart B. Cart Y (m = 8.0 kg) is traveling to the left at 2 m/s. Which cart has the larger magnitude of momentum, and why?
Answer:
1. Cart Y has a larger magnitude of momentum.
2. Because the mass of cart Y is larger than the mass of cart A.
Explanation:
The following data were obtained from the question:
Mass of cart A (mₐ) = 2 Kg
Velocity of cart A (vₐ) = 4 m/s
Mass of cart Y (mᵧ) = 8 Kg
Velocity of cart Y (vᵧ) = 2 m/s
1. Determination of which of the cart has a larger magnitude of momentum.
For Cart A:
Mass (mₐ) = 2 Kg
Velocity (vₐ) = 4 m/s
Momentum of cart A (pₐ) =?
Momentum = mass × velocity
pₐ = mₐ × vₐ
pₐ = 2 × 4
pₐ = 8 Kgm/s
Thus, the momentum of cart A is 8 Kgm/s
For Cart Y:
Mass (mᵧ) = 8 Kg
Velocity (vᵧ) = 2 m/s
Momentum of cart Y (pᵧ) =?
Momentum = mass × velocity
pᵧ = mᵧ × vᵧ
pᵧ = 8 × 2
pᵧ = 16 Kgm/s
Thus the momentum of cart Y is 16 Kgm/s
SUMMARY:
The momentum of cart A is 8 Kgm/s
The momentum of cart Y is 16 Kgm/s
Therefore, cart Y has a larger magnitude of momentum.
2. Determination of the reason why cart Y has a larger magnitude of momentum.
Momentum is simply defined as the product of mass and velocity i.e
Momentum = mass × velocity
Thus, an increase in either mass or velocity will increase the momentum.
Considering the question given and the solution obtained:
Cart A:
Mass (mₐ) = 2 Kg
Velocity (vₐ) = 4 m/s
Momentum of cart A (pₐ) = 8 Kgm/s
Cart Y:
Mass (mᵧ) = 8 Kg
Velocity (vᵧ) = 2 m/s
Momentum of cart Y (pᵧ) = 16 Kgm/s
From the above data, we can see that the mass of cart Y (i.e 8 Kg) is larger than the mass of cart A (i.e 2 Kg).
Thus, we can conclude that the magnitude of the momentum of cart Y is larger than that of cart A irrespective of their velocities because the mass of cart Y is larger than the mass of cart A.
An oxygen atom picks up two additional, free-floating electrons. Is the charge of the newly formed oxygen ion positive, negative, or neutral?
Answer:
The atom is now a negative charge
Explanation:
Adding electrons makes things negative.
Two descriptions about physical quantities are given below:
Quantity A: It has the same unit as force.
Quantity B: It measures the amount of matter in an object.
What quantities are these most likely describing?
Both Quantity A and Quantity B are mass.
Both Quantity A and Quantity B are forces.
Quantity A is weight and Quantity B is mass.
Quantity A is mass and Quantity B is weight.
Answer:
quantity A is mass and quantity B is wright
Two reindeer-in-training pull on a sleigh. Connie pulls with a force of 200
Nat an angle of 60 degrees above the x-axis, while Randolph pulls with a
force of 800 N at an angle of 60 degrees below the x-axis. What is their
resultant force on the sleigh?
Answer:
Their resultant force magnitude on the sleigh is approximately 583.095 N
Explanation:
The given parameters are;
The magnitude and direction in which the two reindeer-in-training pull on the sleigh are;
The force with which Connie pulls on the sleigh, F₁ = 200 N
The direction in which Connie pulls on the sleigh = 60° above the x-axis
The force with which Randolph pulls on the sleigh, F₂ = 800 N
The direction in which Connie pulls on the sleigh = 60° below the x-axis
The vector form of the force with which the two reindeer-in-training pulls the sleigh is given as follows;
[tex]\underset{F_1}{\rightarrow}[/tex] = 200 × cos(60°)·i + 200 × sin(60°)·j = 100·i + (100·√3)·j
[tex]\underset{F_2}{\rightarrow}[/tex] = 800 × cos(60°)·i - 800 × sin(60°)·j = 400·i - (400·√3)·j
The resultant force, R = [tex]\underset{F_1}{\rightarrow}[/tex] + [tex]\underset{F_2}{\rightarrow}[/tex]
∴ R = 100·i + (100·√3)·j + 400·i - (400·√3)·j = 500·i - (300·√3)·j
Their resultant force magnitude on the sleigh, [tex]\left | R \right |[/tex] = √(500² + (-300)²) ≈ 583.095 N
The direction of the resultant force = arctan(-300/500) = arctan(-0.6) ≈ -30.964 which is approximately 30.964° below the x-axis.
The pressure of a liquid at the 10.2 meters depth is 80100 Pascal. - What is the density of the fluid in kg/cubic meter?
Answer:
8165.138kg/cubic meter
Explanation:
Pressure= 80100 Pascal.= 1N/m^2
Height=10.2 meters
density of the fluid in kg/cubic meter= ?
g=acceleration due to gravity= 9.81m/s^2
The pressure of a system can be calculated using the expression below
P = ρ g h
Where
p =pressure,
h =depth of the liquid,
ρ = density of the liquid,
g = acceleration due to gravity.
If we substitute those values we have
80100 1N/m^2= ρ × 9.81m/s^2
ρ= 80100/9.81
ρ=8165.138kg/cubic meter
Hence, the density of the fluid in kg/cubic meter is 8165.138kg/cubic meter
if a 5000-kg is moving at a speed of 43 m/s, what is its momentum?
Answer:
215000kgm/s
Explanation:
Given parameters:
Mass of the moving body = 5000kg
Velocity = 43m/s
Unknown:
Momentum = ?
Solution:
The momentum of a body is the amount of motion a body possess.
It is mathematically expressed as:
Momentum = mass x velocity
Now:
Momentum = 5000 x 43 = 215000kgm/s
What are four drawbacks to using fossil fuels in Alberta thermal power stations?
Plz I’m desperate!!! Explain your answer
Answer:
Fossil fuels have been used for centuries to generate power, but there are many disadvantages associated with their use:
Fossil fuels pollute the environment.
Fossil fuels are non-renewable and unsustainable.
Drilling for fossil fuels is a dangerous process.
Explanation:
can you help me please? https://brainly.com/question/21745542
The blades of your skates slide more easily over ice than do
the soles of your shoes because the skate blades
a
are smoother than your shoes.
b exert less force on the ice.
C
make you weigh less on the ice.
d
none of the above.
Answer:
A
Explanation:
They Are Smoother and the other guy makes no sense.
On a nice winter day at the South Pole, the temperature rises to −54°F. What is the approximate temperature in degrees Celsius?
The approximate temperature at the South Pole is equal to -47.7 °C.
How to convert the temperature in Fahrenheit to Celsius?Fahrenheit to Celsius formula can be used to change the temperature from the scale Fahrenheit to Celsius. Both scales are utilized to determine the temperature and it offers a way to determine the object’s hotness and coldness. The symbol used to express Fahrenheit is °F. Similarly, the symbol used to represent Celsius is °C. The Celsius scale of temperature is also called centigrade scale.
Fahrenheit to Celsius formula is commonly used to convert the given temperature in Fahrenheit to Celsius.
[tex]^oC =(^oF-32)\times \frac{5}{9}[/tex]
Where F is the temperature in Fahrenheit and C is the temperature in Celsius.
Given, the temperature in Fahrenheit = -54 °F
The temperature in Celcius at the South Pole can be calculated as:
T (°C) = (-54 -32) × (5/9)
T (°C) = -47.7 °C
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can you help me I am in trouble plz help
Answer:
A velocity
B acceleration
C ms^-2
A race car weighs 6958 N. What is its mass?
Answer:
710kg
Explanation:
Given parameters:
Weight of race car = 6958N
Unknown:
Mass of the race car = ?
Solution:
The weight of a body is the force of gravity acting on that body. It is mathematically expressed as:
Weight = mass x acceleration due to gravity
Acceleration due to gravity = 9.8m/s²
6958 = mass x 9.8
mass = 710kg
HELP!!!!
Clouds form when the air is cooled below the
dew point
relative humidity
water content
percent saturation
Answer:
Clouds form when below the dew point
Clouds form when the air is cooled below the dew point. The dew point is the temperature at which the air becomes saturated, meaning it can no longer hold all the water vapor it contains. The correct answer is the dew point.
When the air cools below this temperature, the excess water vapor condenses into tiny water droplets or ice crystals, forming clouds.
The dew point is an important concept in meteorology and refers to the temperature at which the air becomes saturated, leading to the formation of dew, fog, or clouds. It is the temperature at which the air can no longer hold all the water vapor it contains, resulting in the condensation of water vapor into liquid water droplets.
When air is cooled, its capacity to hold water vapor decreases. As the temperature drops, the air reaches a point where it becomes saturated, meaning the air is holding the maximum amount of water vapor it can at that specific temperature and pressure. This temperature is known as the dew point.
Therefore, while relative humidity, water content, and percent saturation are relevant factors in understanding the moisture content of the air, clouds specifically form when the air is cooled below the dew point. The correct answer is the dew point.
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