Answer: B 19.6J
Explanation: The equation for Potential energy is PE=mgh
PE is the potential energy
m=Mass=0.4kg
g=Gravity=9.81m/[tex]s^{2}[/tex]
h=Height=5 metres
(0.4 kg)*(9.81m/[tex]s^{2}[/tex])*(5 metres)=19.62J
ALREADY SOLVED Thank you for looking.
Answer:
yes
Explanation:
I DO NOT WANT LINKES OR …………..
Someone help this is a test and i need to finish this quick i will give brainliest of it lets me
Sorry, I don't know but I think the correct answer is the first option.
Which of the following is correct about the time period of a pendulum, whose length (length of thread) is 2 m and mass of whose bob (metallic ball) is 2 kg, when it is set in motion?
Answer:
P = 2 * pi * (L / g)^1/2 period of simple pendulum
P = 6.28 * (2 / 9.8)^1/2 = 2.84 sec
A baseball is hit so that it travels straight upward after being struck by the bat. If its initial velocity is 29 m/s , then what is the maximum height that it will reach?
Answer:
Explanation:
Use kinematic equation v² = u² + 2as
Rearrange for distance
s = (v² - u²) / 2a
Realize that at the top of its flight, the ball has zero velocity and gravity is acting downward in an assumed upward positive reference frame.
s = (0² - 29²) / (2(-9.8))
s = 42.90816...
s = 43 m
when air gets hot, it rises and forms…
Answer:
Gas
Explanation:
Hot air rises because gases expand as they heat up. When air heats up and expands, its density also decreases.
Which of the following statements about electromagnetic radiation it true? A.electromagnetic waves with long wavelength are more energetic then electromagnetic waves with short wavelength. B.all electromagnetic radiation carries the same amount of energy. C.electromagnetic radiation in a vacuum can change frequently to become more or less energetic. D.electromagnetic waves with high frequency are more energetic then electromagnetic waves with low frequency
Given what we know, we can confirm that option D, Electromagnetic waves with high frequency are more energetic than electromagnetic waves with low frequency is true.
Why are high-frequency waves more energetic?High-frequency waves are synonymous with short wavelengths. This means that the waves are oscillating much quicker and therefore carry more kinetic energy within them. This is transformed and released as electromagnetic radiation, which is the reason why high-frequency waves are more energetic than low-frequency electromagnetic waves.
Therefore, we can confirm that the statement "Electromagnetic waves with high frequency are more energetic than electromagnetic waves with low frequency" is true.
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What is sustainability? How can we make sustainable development a reality? How sustainability can be measured?
Answer:
1)The ability to be maintained at a certain rate or amount is called sustainability.
3)Sustainability is measured by assessing performance of Social, Environmental, and Economic principles.
sorry but I don't know number 2.
I hope it will help you)):
Which of the following is the current best hypothesis for the formation of the solar system?
A. Formed by an exploding super nova star which then collapsed and coalesced into a spinning
disk forming Sun and planets
B. Our solar system has always been here and has never changed
C. Formed from the Sun’s explosion releasing particles into space forming planets and other
objects
D. Our solar system was formed by a great collision of other stars with one another
Answer:
A
Explanation:
all galaxies exploded in order to create the sun/stars
What element is chemically similar to carbon
nonmental
that should be the answer
Discuss How are the acceleration, the net force, and the mass of
an object related? SC.6.P.13.3
13 SEBS
According to Newton's second law
[tex]\\ \sf\longmapsto Force=Mass\times Acceleration[/tex]
[tex]\\ \sf\longmapsto Mass=\dfrac{Force}{Acceleration}[/tex]
[tex]\\ \sf\longmapsto Acceleration=\dfrac{Force}{Mass}[/tex]
a block starts from rest and begins sliding down an incline. The block reaches a speed of 12 meters per second as it slides a distance of 50 meters. calculate the blocks rate of acceleration
Vf² = V₁² + 2ad
(12 m/s) ² = (0 m/s) ² + 2 (a) (50m)
a = 1.44 m/s ²
Answer:
[tex]\boxed {\boxed {\sf 1.44 \ m/s^2}}[/tex]
Explanation:
We are asked to find the block's rate of acceleration.
We are given the final velocity, initial velocity, and distance. Therefore, we will use the following kinematic equation:
[tex]{v_f}^2={v_i}^2+2ad[/tex]
The block starts at rest or 0 meters per second. The block reaches a final velocity of 12 meters per second. The distance traveled is 50 meters.
[tex]v_i[/tex]= 0 m/s [tex]v_f[/tex]= 12 m/s [tex]d[/tex]= 50 mSubstitute the values into the formula.
[tex](12 \ m/s)^2 = (0 m/s)^2 + 2a (50 \ m)[/tex]
Solve the exponents.
(12 m/s)² = 12 m/s * 12 m/s = 144 m²/s²(0 m/s)² = 0 m/s * 0 m/s = 0 m²/s²[tex]144 \ m^2/s^2= 0 m^2/s^2 + 2a (50 \ m)[/tex]
The 0 can be subtracted from both sides, or simply canceled.
[tex]144 \ m^2/s^2 = 2a (50 \ m)[/tex]
Multiply 2 and 50 meters.
[tex]144 \ m^2/s^2 = (2 *50 \ m)* a[/tex]
[tex]144 \ m^2/s^2 = (100 \ m)* a[/tex]
We are solving for a, so we must isolate the variable. It is being multiplied by 100 meters. The inverse of multiplication is division, so we divide both sides by 100 meters.
[tex]\frac {144 \ m^2/s^2}{100 \ m}= \frac{(100 \ m)*a}{100 \ m}[/tex]
[tex]\frac {144 \ m^2/s^2}{100 \ m}=a[/tex]
[tex]1.44 \ m/s^2 =a[/tex]
The block's rate of acceleration is 1.44 meters per second squared.
A box is 30 cm wide, 40 cm long and 25 cm high. Calculate the volume of the box in cubic centimeter.
A) 3,000
B) 30,000
C) 15,000
D) 1,200
Answer:
The correct answer would be A: 3,000.
Explanation:
To find the volume of a box, you have to do l * w * h. You multiply 30, 40, and 25 which gives you an answer of 3,000 cubic centimeters.
In a vacuum light travels at which speed?
Answer:
Light traveling through a vacuum moves at exactly 299,792,458 meters (983,571,056 feet) per second. That's about 186,282 miles per second
Explanation:
Two particles of a gas collide. Why is this considered an elastic collision? (1 point)
O They bounce off each other, conserving momentum only.
O They stick together, conserving momentum.
O They bounce off each other, conserving energy only.
O They bounce off each other, conserving energy and momentum.
They bounce off each other, conserving energy and momentum.
This is considered an elastic collision because they bounce off each other, conserving energy only.
Gas is the state of matter that is made up of particles which freely move about its container and they bounce off each other.
As the particles move over each other they collide without exerting any force in each other. This is known as elastic collision.
Kinetic energy is conserved in elastic collisions which occurs between gas molecules.
While in inelastic collision, momentum is conserved and kinetic energy is not.
Because the gas particles do not stick together as they collide, no force is exerted and kinetic energy is therefore conserved.
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Compare and contarst the difference between saturated and unsaturated solutions and supersaturated
Answer:
Unsaturated Solution: Less amount of salt in water, clear solution, no precipitation. Saturated Solution: The maximum amount of salt is dissolved in water, Colour of the solution slightly changes, but no precipitation. Supersaturated Solution: More salt is dissolved in water, Cloudy solution, precipitation is visible
PLEASE HELP ME!!!!!!!!!!!!!
Answer:
D gravity
Explanation:
please mark me brainliest
Answer:
D. The force that the branch applies to the kitten
Explanation:
I just took the quiz and got it correct!
A boy 11.0 m above the ground in a tree throws a ball for his dog, who is standing right below the tree and starts running the instant the ball is thrown. If the boy throws the ball upward at 50.0 ∘ above the horizontal, at 8.00 m/s .
How fast must the dog run to catch the ball just as it reaches the ground?
How far from the tree will the dog catch the ball?
12414253
Explanation:
what is deviation of light by prism
Answer:
When a ray of light passes from one medium to another it changes its path, this phenomenon of light is called the deviation of light. When a ray of light passes through a prism it suffers refraction twice. Once while it enters the prism and again while it emerges from it.
Speed depends on how far something travels and
Answer:
Speed depends on how far something is travelling and the time taken for the object to travel that distance
Explanation:
(In reference to the speed formula) Speed=[tex]\frac{Distance(m)}{Time(m/s)}[/tex]
Definition of speed:
Speed is the magnitude (unit) of the rate at which an object is moving.
(pls do correct me if I have any mistakes it makes a big difference to help each other out!)
The weather that characterizes an area is the O latitude of that area O barometric pressure of that area climate of that area O geography of that area
Answer:
climate of that area
Explanation:
Light of 650 nm wavelength illuminates two slits that are 0.20 mm
apart. (Figure 1) shows the intensity pattern seen on a screen behind the slits.
What is the distance to the screen?
PLEAsE URGENT. thank you
We have that for the Question "Light of 650 nm wavelength illuminates two slits that are 0.20 mm apart. (Figure 1) shows the intensity pattern seen on a screen behind the slits.
What is the distance to the screen?" it can be said that the distance to the screen
d=1.168m
From the question we are told
Light of 650 nm wavelength illuminates two slits that are 0.20 mm
apart. (Figure 1) shows the intensity pattern seen on a screen behind the slits.
What is the distance to the screen?
Generally the equation for the distance is mathematically given as
[tex]d=\frac{0.33*10^{-2}*0.23*10^{-3}}{650*10^{-9}}\\\\d=1.160m[/tex]
d=1.168m
Therefore
The distance to the screen
d=1.168m
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In these images taken a few days apart, the light part of the Moon appeared to get smaller
over time. Why did this happen? (1)
a) The Moon moved farther away from the sun so less sunlight reached the Moon's
surface.
b) Earth moved so its shadow was blocking more of the Moon so the student astronomer
was able to see less of it.
c) The Moon rotated so that less of the light-colored rock on the Moon's surface faced
Earth
d) The Moon moved so that the student astronomer was able to see less of the half that
facer the sun
Answer:
Explanation:
d) The Moon moved so that the student astronomer was able to see less of the half that faced the sun.
describe an experiment to demonstrate surface tension in a liquid
Answer:
mę břöőda I dunno this answer
Explanation:
hope you find it
The following question has two parts. First, answer part A. Then, answer part B.
Part A:
Why did the author most likely choose the title “Breaking Barriers” for this text?
A.
to show that Elizabeth worked hard to make people like her
B.
to show that Elizabeth accomplished things never done before
C.
to show that Elizabeth proved to be smarter than those around her
D.
to show that Elizabeth tried to show she was the better than other doctors
Part B:
Which sentences from the text best support your answer in part A? Select two options.
A.
“Elizabeth loved learning, and she developed a passion for reading.”
B.
“When Elizabeth was 11 years old, her family moved to America.”
C.
“When she was just 16, she became a teacher.”
D.
“Finally, the Geneva Medical College in New York accepted her as a student.”
E.
“When people in town ignored the woman with the strange ambition, Elizabeth treated them in a polite, quiet manner.”
F.
“She became the first woman in the country to obtain a medical degree.”
Answer:
for part A the answer is D and for part B the answer is F
A +8.75 μC point charge is glued down on a horizontal frictionless table. It is tied to a -6.50 μC point charge by a light, nonconducting 2.50 cm wire. A uniform electric field of magnitude 1.85×108N/C is directed parallel to the wire, as shown in the figure. (Figure 1)
Part A
Find the tension in the wire.
Express your answer with the appropriate units.
Part B
What would the tension be if both charges were negative?
Express your answer with the appropriate units.
(a) The tension on the wire when the two charges have opposite signs is 383.5 N.
(b) The tension on the wire if both charges were negative is 3.640.25 N.
The given parameters;
first charge, q₁ = 8.75 μC second charge, q₂ = -6.5 μC electric field, E = 1.85 x 10⁸ N/Cdistance between the two charges, r = 2.5 cm(a)
The attractive force between the charges is calculated as follows;
[tex]F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = -819 \ N[/tex]
The force on the negative charge due to the electric field is calculated as follows;
[tex]F_2 = Eq_2\\\\F_2 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_2 = 1202.5 \ N[/tex]
The tension on the wire is the resultant of the two forces and it is calculated as follows;
[tex]T = F_2 + F_1\\\\T = 1202.5 - 819\\\\T = 383.5 \ N[/tex]
(b) when the two charges are negative
The repulsive force between the two charges is calculated as follows;
[tex]F_1 = \frac{kq_1q_2}{r^2} \\\\F_1 = \frac{(9\times 10^9) \times (-8.75\times 10^{-6})\times (-6.5\times 10^{-6})}{(0.025)^2} \\\\F_1 = 819 \ N[/tex]
The force on the first negative charge due to the electric field is calculated as follows;
[tex]F_2 = Eq_1\\\\F_2 = (1.85 \times 10^8)\times (8.75 \times 10^{-6})\\\\F_2 = 1618.75 \ N[/tex]
The force on the second negative charge due to the electric field is calculated as follows;
[tex]F_3 = Eq_2\\\\F_3 = (1.85 \times 10^8) \times (6.5 \times 10^{-6})\\\\F_3 = 1202.5 \ N[/tex]
The tension on the wire is the resultant of the three forces and it is calculated as follows;
[tex]T= F_1 + F_2 + F_3\\\\T= 819 + 1618.75 + 1202.5\\\\T = 3,640.25 \ N[/tex]
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A diffraction grating, ruled with 300 lines per mm, is illuminated with a white light source at normal incidence.
(i) What is the angular separation, in the third-order spectrum, between the 400 nm and 600 nm lines? [5]
(ii) Water (of refractive index 1.33) now fills the whole space between the grating and the screen. What is the angular separation, in the first-order spectrum, between the 400 nm and 600 nm lines? [5]
the expression for diffraction grating allows to find the results for the questions for the angular separation are:
i) The third order is Δθ = 0.203 rad.
ii) The first order with water is Δθ = 0.046 rad.
The diffraction grating is a system formed by a large number of equally spaced lines whose diffraction is given by the expression.
d sin θ = m λ
Where d is the distance between two lines, θ is the angle of diffraction, the order of diffraction and λ is the wavelength.
i) Let's start by looking for the separation between two lines
Let's use a rule of direct proportions. If there are 300 lines in 1 mm, what distance is there between two lines.
d = 1 lines (1 mm / 300 lines) = 3,333 10⁻³ mm
d = 3.333 10⁻⁶ m
Let's find the angle of diffraction for the third order (m = 3) for each wavelength.
λ₁ = 400 nm = 400 10⁻⁹ m
sin θ₁ = [tex]\frac{m \ \lambda }{d}[/tex]m λ/ d
sin θ₁ = [tex]\frac{3 \ 400 \ 10^{-9} }{3.333 \ 10^{-6} }[/tex]
θ₁ = sin⁻¹ 0.3600
θ₁ = 0.368 rad
λ₂ = 600 nm = 600 10⁻⁹ m
sin θ₂ = [tex]\frac{3 \ 600 \ 10^{-9} }{3.333 \ 10^{-6} }[/tex]
θ₂ = sin⁻¹ 0.5401
θ₂ = 0.571 rad
The angular separation is
Δθ = θ₂ - θ₁
Δθ = 0.571 - 0.368
Δθ = 0.203 rad
ii) In this case, the separation between the network and the observation screen is filled with water.
When the rays leave the network they undergo a refraction process, for which they must comply with the relationship.
[tex]n_i \ sin \theta_1 = n_r \ sin \theta_r[/tex]
The incident side is in the air, therefore its refractive index is n_i = 1 and when it passes into the water with refractive index n_r = 1.33.
Let's start looking for the incident angles for the first order of diffraction.
m = 1
λ₁ = 400 nm
θ₁ = sin⁻¹ [tex]\frac{1 \ 400 \ 10^{-9}}{3.33 \ 10^{-6}}[/tex]
θ₁ = 0.120 rad
λ₂ = 600 nm
θ₂ = sin⁻¹¹ [tex]\frac{1 \ 600 \ 10^{-9} }{3.33 \ 10^{-6}}[/tex]
θ₂ = 0.181 rad
we use the equation of refraction.
[tex]\theta_r[/tex] = sin⁻¹ ([tex]\frac{n_i}{n_r} \ sin \ \theta_i[/tex] )
λ₁ = 400 nm
θ₁ = sin¹ ([tex]\frac{1 sin 0.120}{1.33}[/tex]
θ₁ = 0.090 rad
λ₂ = 600 nm
θ₂ =sin⁻¹ [tex]\frac{1 sin 0.181}{1.33}[/tex]
θ₂ = 0.1358 rad
The angular separation is
Δθ = 0.1358 - 0.090
Δθ = 0.046 rad.
In conclusion using the relation for the diffraction grating we can find the results for the questions about angular separation are:
i) The third order is Δθ = 0.203 rad.
ii) The first order with water is Δθ = 0.046 rad.
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9) A policeman investigating an accident measures the skid marks left by a car. He determines that 9) the distance between the point that the driver slammed on the brakes and the point where the car came to a stop was 28.0 m. From a reference manual he determines that the coefficient of kinetic friction between the tires and the road under the prevailing conditions was 0.300. How fast was the car going wh~er applied the brakes? (This car was not equipped with anti-lock brakes.)
Answer:
Explanation:
Provided the car did not collide with anything during its slide,
Kinetic energy will convert to work of friction
½mv² = Fd
½mv² = μmgd
v = √(2μgd)
v = √(2(0.300)(9.81)(28.0))
v = 12.8377...
v = 12.8 m/s
what is the difference between soldering and solder?
Answer:
Soldering is a technique or a process to bond metals with the help of solder. Solder is a metal alloy with a low melting point and is often regarded as the base metal for soldering. The piece or structure that is being bonded together does not get hot enough to melt and this is where solder (base metal) comes into play and creates the connection.
Explanation:
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A box is pushed horizontally with constant speed across a rough horizontal surface. Which of the following must be true?
a) The friction is less than the applied force
b) There is no friction acting on the box
c) The friction is greater than the applied force
d) The friction is equal to the applied force
