You are given the following system of equations: y:
- 13x + 85 and y = 15 + 4x . It is
known that this system of equations has two solutions. If the variable k represents the product of the two
×-values that satisfy the system, what is the value of k?

Answer:

  √61 ≈ 7.81

Step-by-step explanation:

It appears that the polygon can be enclosed by a rectangle that is 12 units wide and 10 units high. The enclosing circle is the one that will circumscribe that rectange. Its radius is half the length of the diagonal, so is ...

  (1/2)√(12² +10²) = 1/2√244 = √61

The smallest circle that will surround the polygon will have a radius of √61 ≈ 7.81 units.

_____

The Pythagorean theorem is used to find the length of the diagonal. It tells you the square of the diagonal is the sum of the squares of the sides of the rectangle. Our radius is half the diagonal, so is half the square root of the sum of the squares of the side lengths.

The maximum possible area is 36 square units.

Answer:

36sq Units at max? i think

Step-by-step explanation:

Have a good day!

#ViolentJax~

Answer:

t = 4 s

Step-by-step explanation:

Given function:

[tex]h(t)=-16t^2+48t+64[/tex]

where:

When the ball hits the ground, its height will be 0 ft.

Therefore, set the function to zero and solve for t:

[tex]\begin{aligned}h(t) &=0\\ \implies -16t^2+48t+64 & =0\\ -16(t^2-3t-4)& =0\\ t^2-3t-4 &=0\\ t^2+t-4t-4&=0\\ t(t+1)-4(t+1)&=0\\(t-4)(t+1)&=0\\ \implies t&=4, -1\end{aligned}[/tex]

As time is positive, t = 4 s (only).

Given

[tex]h = - 16 {t}^{2} + 48t + 64[/tex]

Where:- h= Height of ball (given in feet[ft]) and,

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎t= time (in seconds [s])

Time = (t)

We know,

[tex] \text{When the ball hits the ground its height will be 0}[/tex]

[tex] \therefore h(t) = 0[/tex]

[tex] \implies - 16 t^{2} + 48t + 64 = 0 \\ \\ \fbox{taking - 16 as common multiple} \\ \\ \implies - 16(t {}^{2} - 3t - 4) = 0 \\ \\ \implies t {}^{2} - 3t - 4 = 0 \\ \\ \fbox {factorising the \: equation} \\ \\ \implies t {}^{2} - t - 4t - 4 = 0 \\ \\ \implies t(t + 1) - 4(t + 1) = 0 \\ \\ \implies(t - 4)(t + 1) = 0[/tex]

[tex] \tt{Either} \\ t - 4 = 0 \\ t = \red{ 4 } \\ \\ \tt{Or} \\ t + 1 = 0 \\ t = \red{ - 1}[/tex]

We know, Time cannot be negative.

So, Time (t) = 4 seconds

Answer:

-8,2

Step-by-step explanation:

180 Rotation formula: -x,-y

Given: 8,-2

Apply: -x,-y

Outcome: -8,2

Answer:

least common denominator=6

Step-by-step explanation:

For the fractions, 1/3 and 1/6th, 3*2=6. making the fraction 2/6 and leaving the other the same 1/6th.

[tex]\large{\mathcal{QUESTION:}}[/tex]

if p(x) = -2x²-3x+1, find p( -2)

[tex]\large{\mathcal{ANSWER:}}[/tex]

the answer is on the photo

The names in bold are found in the word scramble. After each name, I wrote "figure 1" through "figure 4" to indicate which diagram to check out below. For instance, Abel is in figure 2 representing all of the horizontal letter configurations.

Some names like "Euclid" don't have last names.

The diagrams are shown below.

When you cross everything out used in figures 1 through 4, you'll be left with what you see in figure 5. The remaining letters not crossed out (when read left to right, top to bottom) spell out: Leopold Kronecker. He was a mathematician born 1823 and died 1891. The remaining letters are marked in green.

Answer:

111

Step-by-step explanation:

Answer:

See below, please

Step-by-step explanation:

We know

[tex]f(x) = {x}^{2} + 3x - 7[/tex]

[tex]g(x) = 3x + 5[/tex]

[tex]h(x) = 2 {x}^{2} - 4[/tex]

Hence

[tex]f(g(x))[/tex]

[tex] = {(3x + 5)}^{2} + 3 \times (3x + 5) - 7[/tex]

[tex] = (9 {x}^{2} + 30x + 25) + (9x + 15) - 7[/tex]

[tex] = 9 {x}^{2} + 39x + 33[/tex]

[tex]h(g(x))[/tex]

[tex] = 2 \times {(3x + 5)}^{2} - 4[/tex]

[tex]2 \times (9 {x}^{2} + 30x + 25) - 4[/tex]

[tex] = 18 {x}^{2} + 60x + 50 - 4[/tex]

[tex] = 18 {x}^{2} + 60x + 46[/tex]

[tex](h - f)(x)[/tex]

[tex] = h(x) - f(x)[/tex]

[tex] = (2 {x}^{2} - 4) - ( {x}^{2} + 3x - 7)[/tex]

[tex] = {x}^{2} - 3x + 3[/tex]

[tex](f + g)(x)[/tex]

[tex] = f(x) + g(x)[/tex]

[tex] = ( {x}^{2} + 3x - 7) + (3x + 5)[/tex]

[tex] = {x}^{2} + 6x - 2[/tex]

Answer:

(i) 350 g; (ii) 18 m². This is done by using proportion

Step-by-step explanation:

Answer:

isaiah must get a score of 115

Answer:

Step-by-step explanation:

Answer: The answer is [tex](x+2)^2[/tex]

Step-by-step explanation:

Because  [tex](x+2)^2[/tex] means  [tex](x+2)(x+2)[/tex]

So we use the foil method to factor

First: [tex]x*x=x^2[/tex]

Outside: [tex]x*2=2x[/tex]

Inside: [tex]2*x=2x[/tex]

Last: [tex]2*2=4[/tex]

So we now write the following equation [tex]x^2+2x+2x+4[/tex]

Simplfied [tex]x^2+4x+4[/tex]

Answer:

p=75(alternative) , t=105(sum of all sides) ,

q=105(sum of all sides) , s=105(straight angle)

r=75(sum of all sides)

Answer:

24 units²

Step-by-step explanation:

Given:

To find:

The area enclosed by these lines can be expressed as:

[tex]\displaystyle \large{\int_0^6 \int_2^6 dy dx }[/tex]

For:

[tex]\displaystyle \large{\int_2^6 dy}[/tex]

Recall:

[tex]\displaystyle \large{\int_a^b dy = [y]_b^a = a-b}[/tex]

Therefore:

[tex]\displaystyle \large{\int_2^6 dy = [y]_2^6 = 6-2 = 4}[/tex]

Now we we have:

[tex]\displaystyle \large{\int_0^6 4dx}[/tex]

Recall:

[tex]\displaystyle \large{\int_a^bk dx = [kx]_a^b = kb-ka}[/tex]

for k = constant

Therefore:

[tex]\displaystyle \large{\int_0^6 4 dx = [4x]_0^6 = 4(6)-4(0) = 24}[/tex]

Hence, the area of region is 24 units²

Answer:

x =  12.714

Step-by-step explanation:

Vertical angles sum to 180 degrees

8x-12     + 6x + 14 = 180

   solve for x = 12.714

Answer:

x=8

Step-by-step explanation:

Answer:

44 items in 4 bags means there are 11 items in each bag (44/4).

each bag has 3 erasers + x stickers. So, 3 + x = 11

subtract three from each side of the equation to isolate the variable (x):

3+x-3=11-3

x=8

Answer:

The correct option is C because it shows the accurate cosine rule

Equation to get the third side :  [tex]c = \sqrt{(42^2 +35^2 -2\times 42\times35\times cos(120\degrees ))}[/tex]

The correct option is C.

Given, that sides of triangle are 42 cm and 35 cm .

The third side can be found using the Law of Cosines,

[tex]c^2 = a^2 +b^2 - 2ab\times cos(C)[/tex]

where C is the angle opposite the third side (c) .

For the given side lengths, then the third side can be found .

Here,

a = 42

b = 35

∠C = 120°

Substitute the values,

[tex]c = \sqrt{(42^2 +35^2 -2\times 42\times35\times cos(120\degrees ))}[/tex]

[tex]c = \sqrt{1764 + 1225 + 1470} \\c = \sqrt{4456}\\c = 66.75[/tex]

Hence the third side is of 66.75 units.

The correct option is C .

Know more about cosine law,

https://brainly.com/question/30766161

#SPJ5

Answer:

Surface area is the sum of all areas/faces of a solid, INCLUDING bases.

Lateral surface area is the surface area of a solid WITHOUT bases.

hope this helps :)

Answer:

See below ↓

Step-by-step explanation:

Let the odd integers be :

Solving

Examples

Answer:

Let one odd number be (2n + 1)

Therefore, its consecutive odd number is (2n + 3)

Difference between the two squares of these numbers:

[tex]\begin{aligned}\sf (2n+3)^2-(2n+1)^2 & = \sf (4n^2+12n+9)-(4n^2+4n+1)\\ & = \sf4n^2+12n+9-4n^2-4n-1\\ & = \sf 8n+8\\ & = \sf8(n+1)\end{aligned}[/tex]

Thus proving that the difference between the squares of any two consecutive odd numbers is always a multiple of 8.

Answer:

I think its this answer I believe 0.7853982 if this is correct can u mark me brainliest

Answer:

8.2 meters

Step-by-step explanation:

This problem will form a Right angle triangle.

Where;

6.4 m and 5.2 m are the adjacent and opposite sides of the triangle while the distance that Lillian needs to throw the ball to get it to Jenna is the hypotenuse of the right angle triangle. Thus;

h = √(6.4² + 5.2²)

h = √68

h = 8.2

Answer:

Step-by-step explanation:

Number of shells she had in the begining = 40

Number of shells collected in the morning and at noon = 6 + 3 = 9

Now the number of shell at the end = 40 + 9 = 49

Icreased shells = 49 - 40 = 90

[tex]\text{Percentage increase = $\dfrac{49- 40}{40}*100$}[/tex]

                                [tex]=\dfrac{9}{40}*100\\\\\\= 22.5 \ \%[/tex]

Hope the picture will help you

Answer: $19.59

Step-by-step explanation:

9.91 + 9.68 = 19.59

Answer:

he will get 150$

Step-by-step explanation:

you times 500 to 0.1 then times that by 3

Answer:

x = 9 m

y = 1 m

Step-by-step explanation:

6/1 = x/1.5

x = 1.5 × 6

x = 9

6/1 = 6/y

6y = 6

y = 1

Answer:

(x = 0,y = 0),(x = 1, y = 5),(x= 2, y =10)

Step-by-step explanation:

the rule is to multiply x by 5.

when x = 0, y =5(0) = 0

when x = 1, y =5(1) = 5

when x = 2, y =5(2) = 10

Hope this helps!

Please mark as brainliest!

0

5

10

A table can be completed by plugging x-values into an equation or by graphing.

Plug in x-values

First, plug 0 into the equation to find the first y-value.

Next, plug in 1 for x

Finally, plug in 2

Additionally, each of these y-values increases by 5. So, once we found the first y-value, 0, we can just add 5 to find the next y-values.

Graphing

Also, you can use a graph to find the missing values. The y-intercept is 0 and the slope is 5. Using this information you can graph the equation. Then, find the x-values on the graph and match these values to y-values.

Answer:

4988 pounds

Step-by-step explanation:

Volume of Hemisphere

4/3 x π x r^3 = 4/3 x 3^3 x π = 4/3 x 27π = 36π = Volume of Sphere

To calculate volume of Hemisphere = 36π / 2 = 18π foot^3

Weight of the liquid

88.2 pounds / foot^3 means that every cubic foot weighs 88.2 pounds so

88.2 pounds x 18π = 4987.5925 which to the nearest pound = 4988 pounds.

Answer:

k>1 1/3

Step-by-step explanation:

i have rsm too bro

The given equation has no solution when K is any real number  and k>12

We have given that

3x^2−4x+k=0

△=b^2−4ac=k^2−4(3)(12)=k^2−144.

If Δ=0, it has 1 real solution,

Δ<0 it has no real solution,

Δ>0 it has 2 real solutions.

We get,

Δ=k^2−144 here Δ is not zero.

It is either >0 or <0

Δ<0 it has no real solution,

Therefore the given equation has no solution when K is any real number.

To learn more about the solution visit:

https://brainly.com/question/1397278