X-5•(x^2-5x+6)/(x^2-12x+35)

Answer:

As the x-values increase, the function increases towards positive infinity.

Step-by-step explanation:

I just did this on study island :D

For the exponential function as the x-values increase, the function increases towards positive infinity.

Exponential function is a function that involves exponents. Exponential function has a constant as its base and a variable as its exponent.

According to the given problem,

f(x) = [tex]3^{x}[/tex]

Let the value of x be -1,

⇒ f(x) = [tex]3^{-1}[/tex]

         = 0.33

Now, let the value of x be 1,

⇒ f(x) = [tex]3^{1}[/tex]

          = 3

Hence, we can conclude, as the x-values increase, the function increases towards positive infinity.

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Answer:

Y=x+6

Step-by-step explanation:

Answer:

5/4

Step-by-step explanation:

m = y2-y2 / x2-x3

Answer: 210/1000

Step-by-step explanation:

80+ 60+30+40= 210/100

Answer:

The answer to this is 3(2n-9)

Answer:

Step-by-step explanation:

Simplifying

x = 8 + 3y

Answer:

here u goooooooo

Step-by-step explanation:

x= 8-3y

Answer:

Step-by-step explanation:

y=15x+65

Answer:

0!

Step-by-step explanation:

If anything 0 is powered to a number, it will always be zero.

Answer:

Answer is 18 degree as per the question

Answer: A. 18°

Step-by-step explanation:

Your formula is 108°+54°+X=180°
To find X, add 108° & 54°. The sum is 162°.
Next you need to subtract your sum from 180°.
180°-162°=18°
X=18°

Answer:

323

Step-by-step explanation:

Answer:

323 ;)

Step-by-step explanation:

Answer:

4 batches!!

Step-by-step explanation:

apples + blackberries = 16 cups

blackberries = 1 for one batch

apples = 3 for one batch

1 x 4 = 4

3 x 4 = 12

12 + 4 = 16

Answer:

The Correct Answer Is B.) 4 Batches

Step-by-step explanation:

Answer:

5/12

Step-by-step explanation:

8/12 + -3/12

Answer:

2/3 - 1/4 =

8/12 - 3/12 = 5/12

:)

Answer:

2 feet

Step-by-step explanation:

yes

Step-by-step explanation:

Answer:

You can. It's just a method used however.

Step-by-step explanation:

Step 1 Divide all terms by a (the coefficient of x2). Step 2 Move the number term (c/a) to the right side of the equation. Step 3 Complete the square on the left side of the equation and balance this by adding the same value to the right side of the equation.

Answer:

to solve quadratic equations you need to first figure out how many terms you have and if you have more than 3, your in luck but the AZB formula will not include the terms 1 2 or 3

Step-by-step explanation:

Answer:

hello im good

Step-by-step explanation:

Answer:

Yes it is a linear relation cause it has a common differences of +10.

Answer:

b i think

Step-by-step explanation:

Answer:

1,100 ounces because 20 × 30 + 10 × 50 = 1,100

Step-by-step explanation:

Answer:

SAS Axiom

QP=MN

Angle M = Angle P

NP=MQ

Answer:

-1/2

Step-by-step explanation:

You find the change in the y coordinates. 6 -> 5 is -1. Now the same for the x. 2 -> 4 is +2. now place them in a fraction with the y/x -1/2. if both were negative then you would just cancel out the negatives.

Answer:

Tiffany

Step-by-step explanation:

Ramon is 4 to 1 water to sugar

Tiffany is 3 to 1 water to sugar

The nectar that is more sugary is Tiffany's nectar.

A ratio shows us the number of times a number contains another number.

Given that Ramon makes nectar for a hummingbird feeder by mixing 8 cups of water with 2 cups of sugar. Therefore, the ratio of sugar to water can be written as,

Sugar / Water = 2 cups of sugar / 8 cups of water

Sugar / Water = 1/4

Sugar / Water = 0.25 cups of sugar per cup of water

Also, given that Tiffany makes nectar by mixing 9 cups of water with 3 cups of sugar. Therefore, the ratio of sugar to water can be written as,

Sugar / Water = 3 cups of sugar / 9 cups of water

Sugar / Water = 1/3

Sugar / Water = 0.33 cups of sugar per cup of water

Since the ratio of sugar to water is more in Tiffany's nectar (0.33 > 0.25). Therefore, Tiffany's nectar is more sugary.

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Answer:

c=6

Step-by-step explanation:

In order to solve the original equation, we would have to square both sides of the equation:

\begin{aligned}\sqrt{29+4w}&=23-cw\\\\ \left(\sqrt{29+4w}\right)^2&=(23-cw)^2\\\\ 29+4w&=(23-cw)^2\end{aligned}  

29+4w

​  

(  

29+4w

​  

)  

2

29+4w

​  

=23−cw

=(23−cw)  

2

=(23−cw)  

2

​  

However, squaring both sides of an equation can create extraneous solutions! [Why?]

Hint #22 / 4

Let's plug \blueD w=\blueD{5}w=5start color #11accd, w, end color #11accd, equals, start color #11accd, 5, end color #11accd into the last equation we obtained:

\begin{aligned}29+4\blueD w&=(23-c\blueD{w})^2\\\\ 29+4(\blueD 5)&=(23-c(\blueD{5}))^2\\\\ 49&=(23-5c)^2\end{aligned}  

29+4w

29+4(5)

49

​  

=(23−cw)  

2

=(23−c(5))  

2

=(23−5c)  

2

​  

This equation is correct, both when 23-5c=723−5c=723, minus, 5, c, equals, 7 and when 23-5c=-723−5c=−723, minus, 5, c, equals, minus, 7.

However, the original equation is not correct for 23-5c=-723−5c=−723, minus, 5, c, equals, minus, 7, since this way we obtain \sqrt{49}=-7  

49

​  

=−7square root of, 49, end square root, equals, minus, 7.

Hint #33 / 4

Therefore, an extraneous solution is obtained for the ccc-value that makes 23-5c23−5c23, minus, 5, c equal -7−7minus, 7, which is c=6c=6c, equals, 6.

Substituting this back into the original equation gives \sqrt{29+4w}=23-6w  

29+4w

​  

=23−6wsquare root of, 29, plus, 4, w, end square root, equals, 23, minus, 6, w. You can now solve this for www and see for yourselves that w=5w=5w, equals, 5 is indeed extraneous.

Hint #44 / 4

The answer is:

c=6c=6

c = 6, makes w = 5 an extraneous solution of the equation √(29 + 4w) = 23 - cw.

A root of a transformed equation that is not a root of the original equation because it was omitted from the domain of the original equation is referred to as an extraneous solution.

In the question, we are asked to find the value for the constant c, that makes w = 5, an extraneous solution in the equation:

√(29 + 4w) = 23 - cw.

We first try to solve this equation, by squaring both sides,

29 + 4w = (23 - cw)²,

or, 29 + 4w = 23² - 2(23)(cw) + (cw)²,

or, 29 + 4w = 529 - 46cw + c²w²,

Now, we substitute w = 5, in the above equation to get:

29 + 4(5) = 529 - 46c(5) + c²(5)²,

or, 29 + 20 = 529 - 230c + 25c²,

or, 25c² - 230c + 480 = 0.

Solving this by the quadratic formula, we get:

[tex]c = \frac{-(-230)\pm \sqrt{(-230)^{2}-4(25)(480)}}{2(25)}[/tex] ,

or, [tex]c = \frac{230\pm \sqrt{52900-48000}}{50}[/tex] ,

or, [tex]c = \frac{230\pm \sqrt{4900}}{50}[/tex] ,

or, [tex]c = \frac{230\pm 70}{50}[/tex] ,

or, c = 300/50 or 160/50,

or, c = 6 or c = 3.2.

Now, we will check these values in the original equation by keeping w = 5.

When c = 6:

√(29 + 4w) = 23 - cw,

or, √(29 + 4(5)) = 23 - (6)(5),

or, √(29 + 20) = 23 - 30,

or, √49 = -7,

or, 7 = -7, which is not true.

Hence, c = 6 makes w = 5 an extraneous solution.

When c = 3.2,

√(29 + 4w) = 23 - cw,

or, √(29 + 4(5)) = 23 - (3.2)(5),

or, √(29 + 20) = 23 - 16,

or, √49 = 7,

or, 7 = 7, which is true.

Hence, c = 3.2 makes w = 5 a proper solution.

Therefore, c = 6, makes w = 5 an extraneous solution of the equation √(29 + 4w) = 23 - cw.

The question mentioned is not understandable. For proper question, refer to the attachment.

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Answer:

10, 21, 36, 12, 24, 5, 33, 14