Writing fractions with a common denominator to add or subtract

Answer:

1. [tex]\normalsize \boxed{\textsf{$4\sqrt{2}\cdot\sqrt{2}$}} \implies \boxed{8}[/tex]

2. [tex]\normalsize \boxed{\textsf{$3\sqrt{7}-2\sqrt{7}$}} \implies \normalsize \boxed{\textsf{$\sqrt{7}$}}[/tex]

3. [tex]\normalsize \boxed{\textsf{$\dfrac{\sqrt{7}}{2\sqrt{7}}$}} \implies \normalsize \boxed{\textsf{$\dfrac{1}{2}$}}[/tex]

4. [tex]\normalsize \boxed{\textsf{$2\sqrt{5}\cdot 2\sqrt{5}$}} \implies \boxed{20}[/tex]

Step-by-step explanation:

The Radical Rules by Lial et al. (2017) state that:

Product rule: [tex]\large \textsf{$\sqrt[n]{a}\cdot\sqrt[n]{b}=\sqrt[n]{ab}$}[/tex]

Quotient rule: [tex]\large \textsf{$\sqrt[n]{\dfrac{a}{b}}=\dfrac{\sqrt[n]{a}}{\sqrt[n]{b}}$}\ \ \textsf{$(b \neq 0)$}[/tex]

1.

[tex]\implies \normalsize \textsf{$4\sqrt{2}\cdot\sqrt{2}$}\\\\\normalsize \implies \textsf{$4\sqrt{2\cdot2}$}\\\\ \implies \normalsize \textsf{$4\sqrt{4}$}\\\\ \implies\normalsize \textsf{$4\cdot 2 = 8$}[/tex]

[tex]\normalsize \boxed{\textsf{$4\sqrt{2}\cdot\sqrt{2}$}} \implies \boxed{8}[/tex]

2.

[tex]\implies \normalsize \textsf{$3\sqrt{7}-2\sqrt{7}$}\\\\ \implies\normalsize \textsf{$(3-2)\sqrt{7}$}\\\\ \implies\normalsize \textsf{$1\sqrt{7}$}\\\\ \implies\normalsize \textsf{$\sqrt{7}$}[/tex]

[tex]\normalsize \boxed{\textsf{$3\sqrt{7}-2\sqrt{7}$}} \implies \normalsize \boxed{\textsf{$\sqrt{7}$}}[/tex]

3.

[tex]\implies \normalsize \textsf{$\dfrac{\sqrt{7}}{2\sqrt{7}}$}\\\\\\ \implies\normalsize \textsf{$\dfrac{1\sqrt{7}}{2\sqrt{7}}$}\\\\\\ \implies\normalsize \textsf{$\dfrac{1}{2}$}\\\\[/tex]

[tex]\normalsize \boxed{\textsf{$\dfrac{\sqrt{7}}{2\sqrt{7}}$}} \implies \normalsize \boxed{\textsf{$\dfrac{1}{2}$}}[/tex]

4.

[tex]\implies \normalsize \textsf{$2\sqrt{5}\cdot 2\sqrt{5}$}\\\\ \implies\normalsize \textsf{$2\cdot2\sqrt{5\cdot5}$}\\\\ \implies \normalsize \textsf{$4\sqrt{25}$}\\\\ \implies \normalsize \textsf{$4\cdot5=20$}\\\\[/tex]

[tex]\normalsize \boxed{\textsf{$2\sqrt{5}\cdot 2\sqrt{5}$}} \implies \boxed{20}[/tex]

Reference:

Lial, M., Hornsby, J., Schneider, D., & Daniels, C. (2017). College Algebra and Trigonometry, Global Edition (6th ed., p. 94).

Since the graph was not given, answer will be subjective. The graph that shows the solution to the system of linear inequalities of  2x – 3y <12 y < –3 is the one that has It is option B.

A linear inequality is  said to be a kind of an inequality that entails a linear function.

Note that a linear inequality is said to be made up of one of the symbols that connote inequality. It is the one that depicts the data that is not equal on a graph.

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Answer:

The correct answer is Graph B

Step-by-step explanation:

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The height of the pencil box is 2 inches

The given parameters are:

Volume = 176

Length = 8

Width = 11

The height of the pencil box is calculated using

Height = Volume/(Length * Width)

So, we have:

Height = 176/(8 * 11)

Evaluate

Height = 2

Hence, the height of the pencil box is 2 inches

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Answer:

2 Inches

Step-by-step explanation:

Good Luck

Reason:

Distance = rate*time

time = distance/rate

time = (38 miles)/(2 mph)

time = 38/2 hours

time = 19 hours

Answer: = 3 acres per day

Showing Work

This is a fraction equal to

3 acres ÷ 1 days

We want a unit rate where

1 is in the denominator,

so we divide top and bottom by 1

3 acres ÷ 1

__________

1 days ÷ 1

=

3 acres

_____

1 day

=

3 acres

______

day

= 3 acres per day

Answer:

................

Step-by-step explanation:

Answer:

50

Step-by-step explanation:

Each question is 6%/3 = 2% worth. If each question is worth 2% then total questions must be 50 (cuz that would be 2% x 50 (total question) = 100%).

Answer:

Step-by-step explanation:

I calculated it.

Answer:

the answer is 21

21

ΔAGF ≅ ΔCGE because they are both created from perpendicular diagonals that are intersected at the midpoint by line FE.

A perpendicular line is a straight line that is at right angle with another line. That is both lines intersect each other at right angles.

Lines EG and FG  are ≅ because the are dissected by a line that runs through the diagonal of rectangle ABCD

Lines JK ≅ HL because they are both created by parallel lines JL and HI.

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The measure of angle ∠CAB will be 68 degrees and the measure of angle ∠CAD will be 22 degrees.

It is the center of an equidistant point drawn from the center. The radius of a circle is the distance between the center and the circumference.

In the circle below, stack AD with a bar on top is diameter and stack AB with a left-right arrow on top is tangent at A. Suppose m stack ADC with over parenthesis on top equals 224 degrees.

Then the measures of m angle ∠CAB and m angle ∠CAD will be  

Then we have

We know that

mADC = mAD + mDC

  224° = 180° + mDC

 mDC = 44°

Then we know the theorem, A chord's degree in the centre is double that of the chord's degree at the perimeter. Then we have

2 ∠CAD = 44°

  ∠CAD = 22°

Then the angle ∠CAB and angle ∠CAD are complementary angles. Then we have

∠CAB + ∠CAD = 90°

   ∠CAB + 22° = 90°

            ∠CAB = 68°

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Answer:

Step-by-step explanation:

Answer:

9y(c=7) witch means the answer is 8,6

Step-by-step explanation:

I took it and got 5 out of 5 right ✅

Answer:

5600x10=56000

56000=B ten thousands

Answer:

Ten Thousands

Step-by-step explanation:

5,600x10=56000

So the 5 will be in the ten thousand place if u get a chart/

ignore the numbers on the chart

The recursive function is h(n) = -1/3h(n - 1) where h(0) = 63

The function is given as:

[tex]h(n) = 63* (-\frac{1}{3})^n[/tex]

Set n to 0

[tex]h(0) = 63* (-\frac{1}{3})^0[/tex]

Evaluate

h(0) = 63

This means that the function h(n) has the following parameters:

First term = 63

Rate = -1/3

Hence, the recursive function is h(n) = -1/3h(n - 1) where h(0) = 63

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A rhombus is a quadrilateral whose all sides are of equal length. The measure of the ∠QPR is 42°.

A rhombus is a quadrilateral whose all sides are of equal length, and the opposite are parallel to each other.

The diagonals of a rhombus intersect each other at 90°. Therefore, the measure of ∠QTR can be written as,

∠QTR = 90°

(6y+6) = 90°

6y = 90 - 6

6y = 84

y = 14

Also, the diagonals of the rhombus divide the angle into two equal angles, therefore,

∠QPR = ∠SPR

∠QPR = 3y

∠QPR = 3(14)

∠QPR = 42°

Hence, the measure of the ∠QPR is 42°.

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From the calculations, we can see that the number of beetles after three years is 11618 beetles.

The term "exponential problem" has to do with any problem in which the increase or decrease occurs exponentially.

In this case we have P = Poe^rt

Po = 10,000

r = 0.05

t = 3

P =  10,000 e^(0.05 * 3)

P= 11618 beetles

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Answer: Reflection, translation

Step-by-step explanation:

Answer:

Step-by-step explanation:

If m and n are both 1 then

Minimum value = 10^(1+1) * 3^(1-1) * 225

= 325.

If m and n have to be different, then m = 2 and n = 1

Minimum value = 10^3 * 3^1 * 15^2

= 675,000.

An example of how to sketch the Ferris Wheel diagram is given in the image attached.

To solve for the angular speed, you can use the formula of"

Given that the diameter is 80 feet, so we know the radius will be 40 feet.

The Ferris wheel bottom is 20 feet high, so we add the radius we get that the middle of the Ferris wheel is 60 feet high.

Finally, the Ferris wheel completes 1 ½ rotation (2π radians) in 1 minutes. So we say that the Ferris wheel is said to spins at π rad/min.

Angular velocity ( 1 ½ rev/1min)( 1min/60 sec)

C = 2π(60)

C ≈ 377.04 feet

540 revolution (1 ½ rotations) is 60 seconds, the speed is then

s = d/t

s = 377.06 ft / 60 sec

s = 6.28 ft/sec

To plot the graph, the  final equation will be h(t) = 40sin(πt + π/2) + 60.

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Answer:

the answer is 4×b=4b

Step-by-step explanation:

product=×

4×b=4b

Answer:

If we square both sides then we get

x2-8x+16 = (x-4)2

Now if we expand the right side of the equation we get

x2-8x+16 = (x-4)(x-4)

x2-8x+16 = x2-8x+16

So no matter what x is, the right side will be equal to the left side.

However, if we look at the original equation on the left side, √(x2-8x+16) , the value under the square root symbol has to be greater than or equal to zero (otherwise we get an imaginary number and you might not be working with those yet)

Step-by-step explanation:

So in order for √(x2-8x+16) to be greater than or equal to zero, x has to be greater than or equal to 4. If x is less than 4 you get a negative number. If x is greater than 4, you'll get the same answer on both sides no matter what x is

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's solve ~

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 8x + 16} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 4x - 4x + 16} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{} (x - 4) - 4(x - 4)} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 4)(x - 4)} [/tex]

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ (x - 4) {}^{2} } [/tex]

[tex]\qquad \sf  \dashrightarrow \: x - 4[/tex]

Now, it's given that ~

[tex]\qquad \sf  \dashrightarrow \:x \geqslant 4[/tex]

plug the value of x as 4 :

[tex]\qquad \sf  \dashrightarrow \:4 - 4[/tex]

[tex]\qquad \sf  \dashrightarrow \:0[/tex]

So, we can infer that :

Value of the required expression lies in :

[tex]\qquad \sf  \dashrightarrow \: \sqrt{ {x}^{2} - 8x + 16} \geqslant 0[/tex]

it's value is always greater than pr equal to 0, satisfying the given condition ~

Answer: D (bottom option)

Not Congruent

Step-by-step explanation:

Assuming the trapezoids are to scale, they are not the same shape. This means that they could not be congruent even if they were centered on top of each other.

Answer:

binomial

Step-by-step explanation:

i learned about binomials

Answer:

the value of x=9 and AB(h)=9.396

Answer:

y = 10

Step-by-step explanation:

if the figure is to be a parallelogram, then

∠ ACB and ∠ DAC are alternate angles and are congruent , that is

5y - 13 = 7 + 3y ( subtract 3y from both sides )

2y - 13 = 7 ( add 13 to both sides )

2y = 20 ( divide both sides by 2 )

y = 10

jt- 22x+9..

It clearly says JT=22X+9

try 22+9..?

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

The given equation is a Quadratic equation, so it's graph must be a parabola, and the Coefficient of x² is positive that means the parabola must have an opening upward.

And 2 is added to the ideal equation, so the parabola must have shift 2 units up from x - axis.

From the above information, we can easily conclude that the Correct representation is done in graph 4

Explanation:

Volume of rectangular prism: Length * Width * Height

Solve:

1)

Volume: 9 * 9 * 9 = 9³ = 729 cm³

2)

Volume: 7 * 3 * 2 = 42 m³

3)

Volume: 7 * 7 * 7 = 7³ = 343 cm³