Write each of the following equations in general form.
a. 1 − 2x = y
b. 9y + 7x = 16 − 3y + x
c. x = 3
d. 2y − 4x − 1 = 7

Answer:

Ok I'm assuming that know what??

Step-by-step explanation:

Answer:

+∞.

Step-by-step explanation:

That would be positive infinity.

The extreme value of the given polynomial [tex]f(x) = x^{2} -4[/tex] is ∞.

Extreme values of a polynomial are the peaks and valleys of the polynomial—the points where direction changes.

The following steps which are required to find the extreme value of polynomial are:

According to the given question.

We have a polynomial

[tex]f(x) = x^{2} -4[/tex]

Since, in the given polynomial the coefficient of [tex]x^{2}[/tex] is positive . Therefore, the extreme value of the given polynomial is infinity because the value will continue to grow as x increases.

Hence, the extreme value of the given polynomial [tex]f(x) = x^{2} -4[/tex] is ∞.

Find out more information about extreme value of a polynomial here:

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Answer:

b

Step-by-step explanation:

A proportional relationship is a straight line.  Is must also go through the point (0,0)

b

Answer:

Step-by-step explanation:

A proportional relationship is a straight line.  Is must also go through the point (0,0)

Answer:

Mean = Sum of all numbers divided by the amount of numbers

[tex]Mean/Average=\frac{3+1+1.5+1.25+2.25+4+1+2}{8} =\frac{16}{8} =2[/tex]

Median = the middle number when the ordered from least to greatest.

If there are two middle numbers, find the mean/average of those numbers:

[tex]\frac{1.5+2}{2} =\frac{3.5}{2} =1.75[/tex]

Therefore, the answer would be:

Step-by-step explanation:

Given:

[tex]A=1.5\:\text{cm}^2×\left(\frac{1\:\text{m}^2}{10^4\:\text{cm}^2}\right)=1.5×10^{-4}\:\text{m}^2[/tex]

[tex]d = 2.0\:\text{mm} = 2.0×10^{-3}\:\text{mm}[/tex]

The charge stored in a capacitor is given by [tex]Q = CV.[/tex] In the case of a parallel-plate capacitor, its capacitance C is given by

[tex]C = \epsilon_0\dfrac{A}{d}[/tex]

where [tex]\epsilon_0[/tex] = permittivity of free space. The amount of charge stored in the capacitor is then

[tex]Q = \left(\epsilon_0\dfrac{A}{d}\right)V[/tex]

[tex]\:\:\:\:\:=\left[\dfrac{(8.85×10^{-12}\:\text{F/m})(1.5×10^{-4}\:\text{m}^2)}{(2.0×10^{-3}\:\text{m})}\right](12\:\text{V})[/tex]

[tex]\:\:\:\:\:=8.0×10^{-12}\:\text{C}[/tex]

Answer:

24cm

Step-by-step explanation:

Question: Find the length of side OR.

Answer + explanation:

24cm

Since PQ = 24 cm, OR = 24 cm because they're paralleled and congruent!

Answer:

<O = 125

OR = 24

Step-by-step explanation:

consecutive angles are supplementary in a parallelogram

<R + <O = 180

55 + <O =180

<O = 180-55

< O = 125

opposite sides are congruent in a parallelogram

PQ = OR = 24

Answer:

x = -5

Step-by-step explanation:

4-2(x+7) = 3(x+5)

Distribute

4 - 2x-14 = 3x+15

Combine like terms

-2x-10 = 3x+15

Add 2x to each side

-2x-10 +2x =3x+2x+15

-10 = 5x+15

Subtract 15 from each side

-10-15 = 5x+15-15

-25 = 5x

Divide by 5

-25/5 = 5x/5

-5 =x

Answer:

Part A)

About 0.51% per year.

Part B)

About 0.30% per year.

Part C)

About 28.26%.

Step-by-step explanation:

We are given that the population of Americans age 55 and older as a percentange of the total population is approximated by the function:

[tex]f(t) = 10.72(0.9t+10)^{0.3}\text{ where } 0 \leq t \leq 20[/tex]

Where t is measured in years with t = 0 being the year 2000.

Part A)

Recall that the rate of change of a function at a point is given by its derivative. Thus, find the derivative of our function:

[tex]\displaystyle f'(t) = \frac{d}{dt} \left[ 10.72\left(0.9t+10\right)^{0.3}\right][/tex]

Rewrite:

[tex]\displaystyle f'(t) = 10.72\frac{d}{dt} \left[(0.9t+10)^{0.3}\right][/tex]

We can use the chain rule. Recall that:

[tex]\displaystyle \frac{d}{dx} [u(v(x))] = u'(v(x)) \cdot v'(x)[/tex]

Let:

[tex]\displaystyle u(t) = t^{0.3}\text{ and } v(t) = 0.9t+10 \text{ (so } u(v(t)) = (0.9t+10)^{0.3}\text{)}[/tex]

Then from the Power Rule:

[tex]\displaystyle u'(t) = 0.3t^{-0.7}\text{ and } v'(t) = 0.9[/tex]

Thus:

[tex]\displaystyle \frac{d}{dt}\left[(0.9t+10)^{0.3}\right]= 0.3(0.9t+10)^{-0.7}\cdot 0.9[/tex]

Substitute:

[tex]\displaystyle f'(t) = 10.72\left( 0.3(0.9t+10)^{-0.7}\cdot 0.9 \right)[/tex]

And simplify:

[tex]\displaystyle f'(t) = 2.8944(0.9t+10)^{-0.7}[/tex]

For 2002, t = 2. Then the rate at which the percentage is changing will be:

[tex]\displaystyle f'(2) = 2.8944(0.9(2)+10)^{-0.7} = 0.5143...\approx 0.51[/tex]

Contextually, this means the percentage is increasing by about 0.51% per year.

Part B)

Evaluate f'(t) when t = 17. This yields:

[tex]\displaystyle f'(17) = 2.8944(0.9(17)+10)^{-0.7} =0.3015...\approx 0.30[/tex]

Contextually, this means the percetange is increasing by about 0.30% per year.

Part C)

For this question, we will simply use the original function since it outputs the percentage of the American population 55 and older. Thus, evaluate f(t) when t = 17:

[tex]\displaystyle f(17) = 10.72(0.9(17)+10)^{0.3}=28.2573...\approx 28.26[/tex]

So, about 28.26% of the American population in 2017 are age 55 and older.

Answer:

123123 3213123 12312 dasdsd aw dasd sda asdasd

Step-by-step explanation:

Answer:

Option C

Step-by-step explanation:

From the picture attached,

m∠ABC = 40° [Given]

Since, measure of the intercepted arc is double of the measure of the inscribed angle.

Therefore, m(arc AC) = 2(m∠ABC)

m(arc AC) = 2(40°)

                 = 80°

m(arc FB) = 115° [Given]

By applying theorem of the angles formed by the chords inside a circle,

m∠2 = [tex]\frac{1}{2}(\text{arc}AC+\text{arc}FB)[/tex]

        = [tex]\frac{1}{2}(80^{\circ}+115^{\circ})[/tex]

        = 97.5°

m∠1 + m∠2 = 180° [Linear pair of angles are supplementary]

m∠1 + 97.5° = 180°

m∠1 = 180° - 97.5°

       = 82.5°

Option C is the answer.

Answer:

Remember that for a circle centered in the point (a, b) and with a radius R, the equation is:

(x - a)^2 + (y - b)^2 = R^2

Here we know that the submarine is located at the point (0, 0)

And the radar range has the equation:

2*x^2 + 2*y^2 = 128

You can see that this seems like a circle equation.

If we divide both sides by 2, we get:

x^2 + y^2 = 128/2

x^2 + y^2 = 64 = 8^2

This is the equation for a circle centered in the point (0, 0) (which is the position of the submarine) of radius R = 8 units.

The graph can be seen below, this is just a circle of radius 8.

We also want to see if the submarine's radar can detect a ship located in the point (6, 6)

In the graph, this point is graphed, and you can see that it is outside the circle.

This means that it is outside the range of the radar, thus the radar can not detect the ship.

Answer:

The angles are 45 and 135

Step-by-step explanation:

The two angles form a straight line, which is 180 degrees

c+ 3c = 180

4c = 180

Divide by 4

4c/4 =180/4

c = 45

3c = 3(45) = 135

The angles are 45 and 135

Answer:

45 and 135 ...

Answer:

The remainder is -2.

Step-by-step explanation:

According to the Polynomial Remainder Theorem, if we divide a polynomial P(x) by a binomial (x - a), then the remainder of the operation will be given by P(a).

Our polynomial is:

[tex]P(x) = x^3-4x^2-6x-3[/tex]

And we want to find the remainder when it's divided by the binomial:

[tex]x+1[/tex]

We can rewrite our divisor as (x - (-1)). Hence, a = -1.

Then by the PRT, the remainder will be:

[tex]\displaystyle\begin{aligned} R &= P(-1)\\ &=(-1)^3-4(-1)^2-6(-1)-3 \\ &= (-1)-4(1)+(6)-3 \\ &= -2 \end{aligned}[/tex]

The remainder is -2.

Answer:

2 with 3 left over

Step-by-step explanation:

17 divided by 2 is 14 with 3 remaining

Answer:

2 pies

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Y => - 3 that is {−3, −2, −1, 0, . . .}

Answer:

You should expect 5 days in July with daily rainfall of more than 11.5 mm.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

In Waterville, the average daily rainfall in July is 10 mm with a standard deviation of 1.5 mm.

This means that [tex]\mu = 10, \sigma = 1.5[/tex]

Proportion of days with the daily rainfall above 11.5 mm.

1 subtracted by the p-value of Z when X = 11.5. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{11.5 - 10}{1.5}[/tex]

[tex]Z = 1[/tex]

[tex]Z = 1[/tex] has a p-value of 0.84.

1 - 0.84 = 0.16.

How many days in July would you expect the daily rainfall to be more than 11.5 mm?

July has 31 days, so this is 0.16 of 31.

0.16*31 = 4.96, rounding to the nearest whole number, 5.

You should expect 5 days in July with daily rainfall of more than 11.5 mm.

Answer:

2500 mg

Step-by-step explanation:

Since r(t) is the rate at which the drug is being eliminated, we integrate r(t) with t from 0 to ∞ to find the original dose of drug, m. Since all of the drug will be eliminated at time t = ∞.

Since r(t) =  50 (e^-01t - e^-0.20t)

m = ∫₀⁰⁰50 (e^-01t - e^-0.20t)

= 50∫₀⁰⁰(e^-01t - e^-0.20t)

= 50[∫₀⁰⁰e^-01t - ∫₀⁰⁰e^-0.20t]

= 50([e^-01t/-0.01]₀⁰⁰ - [e^-0.20t/-0.02]₀⁰⁰)

= 50(1/-0.01[e^-01(∞) - e^-01(0)] - {1/-0.02[e^-0.02(∞) - e^-0.02(0)]})

= 50(1/-0.01[e^-(∞) - e^-(0)] - {1/-0.02[e^-(∞) - e^-(0)]})

= 50(1/-0.01[0 - 1] - {1/-0.02[0 - 1]})

= 50(1/-0.01[- 1] - {1/-0.02[- 1]})

= 50(1/0.01 - 1/0.02)

= 50(100 - 50)

= 50(50)

= 2500 mg

Answer:

2√15

Step-by-step explanation:

Use the Pythagorean theorem.

2² + x² = 8²

x² + 4 = 64

x² = 60

x² = 4 * 15

x = 2√15

Answer:

There are four ways to represent an inequality: Equation notation, set notation, interval notation, and solution graph.

Answer:

length= 125

width= 100

Step-by-step explanation:

let width have a length of x m

therefore length= (x+25)m

perimeter=2(length +width)

p=2((x+25)+x)

p=4x+50

but we have perimeter to be 450,, we equate it to 4x+50 above,

450=4x+50

4x=400

x=100 m

length= 125

width= 100

Problem 1

The idea here is to follow PEMDAS in reverse to undo what is happening to the variable b, so we can isolate it.

-11b + 7 = 40

-11b = 40-7

-11b = 33

b = 33/(-11)

b = -3

To check this value, plug it back into the original equation. You should get 40 on each side to help confirm the answer.

=====================================================

Problem 2

There are two ways we can solve. One method is to use the hint your teacher gave you. So we'll distribute first and then follow the same idea as problem 1

9(p-4) = -18

9p-36 = -18

9p = -18+36

9p = 18

p = 18/9

p = 2

Another method you can use is to follow these steps

9(p-4) = -18

p-4 = -18/9

p-4 = -2

p = -2+4

p = 2

Either way, we get the same result. To check the answer, replace every p with 2 in the original equation. You should get -18 on the left side after simplifying.

Answer:

34%

Step-by-step explanation:

Given that the distribution of daily light bulb request replacement is approximately bell shaped with ;

Mean , μ = 45 ; standard deviation, σ = 3

Using the empirical formula where ;

68% of the distribution is within 1 standard deviation from the mean ;

95% of the distribution is within 2 standard deviation from the mean

Lightbulb replacement numbering between ;

42 and 45

Number of standard deviations from the mean /

Z = (x - μ) / σ

(x - μ) / σ < Z < (x - μ) / σ

(42 - 45) / 3 = -1

This lies between - 1 standard deviation a d the mean :

Hence, the approximate percentage is : 68% / 2 = 34%

Answer:

10 2/3 or 32/ 3

Step-by-step explanation:

5 - x^2 - (2 - 2x) =

= -x^2 + 2x + 3

Integral of (-x^2 + 2x + 3)dx from -1 to 3 =

= -x^3/3 + 2x^2/2 + 3x from -1 to 3

= -x^3/3 + x^2 + 3x from -1 to 3

= -27/3 + 9 + 9 - (1/3 + 1 - 3)

= -9 + 9 + 9 - 1/3 - 1 + 3

= 11 - 1/3

= 10 2/3 = 32/3

Answer:

32/3

Step-by-step explanation:

Check the pdf :)

Answer:

340 cars at $ 34 should be rented to produce the maximum income of $ 11,560.

Step-by-step explanation:

Given that a car rental agency rents 480 cars per day at a rate of $ 20 per day, and for each $ 1 increase in rate, 10 fewer cars are rented, to determine at what rate should the cars be rented to produce the maximum income and what is the maximum income, the following calculations must be performed:

480 x 20 = 9600

400 x 28 = 11200

350 x 33 = 11550

300 x 38 = 11400

310 x 37 = 11470

320 x 36 = 11520

330 x 35 = 11550

340 x 34 = 11560

Therefore, 340 cars at $ 34 should be rented to produce the maximum income of $ 11,560.

Answer:

Step-by-step explanation:

(n-1)1.1

Answer:

The critical value is [tex]T_c = 1.7056[/tex]

The 90% confidence interval for the mean repair cost for the refrigerators is ($52.875, $68.165).

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 27 - 1 = 26

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 1.7056, which means that the critical value is [tex]T_c = 1.7056[/tex]

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 1.7056\frac{23.29}{\sqrt{27}} = 7.645[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 60.52 - 7.645 = $52.875.

The upper end of the interval is the sample mean added to M. So it is 60.52 + 7.645 = $68.165.

The 90% confidence interval for the mean repair cost for the refrigerators is ($52.875, $68.165).

The length of arc APD is: [tex]\frac{\pi r}{2}[/tex]

A square when inscribed in a circle will fit the circle such that, the 4 edges of the square touches the sides of the circle. The radius of the circle can be drawn from any of the 4 edges.

Given that ABCD is a square:

This means that:

[tex]AB = BC = CD = DA[/tex] --- equal side lengths

To calculate the length of arc APD, we make use of the following arc length formula

[tex]APD = \frac{\theta}{360} * 2\pi r[/tex]

Where

[tex]\theta = \angle ADO[/tex] and O is circle center

Since ABCD is a square, then:

[tex]\theta = \angle ADO = 90^o[/tex]

So, we have:

[tex]APD = \frac{90}{360} * 2\pi r[/tex]

[tex]APD = \frac{1}{4} * 2\pi r[/tex]

[tex]APD = \frac{\pi r}{2}[/tex]

Read more at:

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Answer:

100

Step-by-step explanation:

We have the sum of first n terms of an AP,

Sn = n/2 [2a+(n−1)d]

Given,

36= 6/2 [2a+(6−1)d]

12=2a+5d ---------(1)

256= 16/2 [2a+(16−1)d]

32=2a+15d ---------(2)

Subtracting, (1) from (2)

32−12=2a+15d−(2a+5d)

20=10d ⟹d=2

Substituting for d in (1),

12=2a+5(2)=2(a+5)

6=a+5 ⟹a=1

∴ The sum of first 10 terms of an AP,

S10 = 10/2 [2(1)+(10−1)2]

S10 =5[2+18]

S10 =100

This is the sum of the first 10 terms.

Hope it will help.

[tex]\sf\underline{\underline{Question:}}[/tex]

If sum of first 6 digits of AP is 36 and that of the first 16 terms is 255,then find the sum of first ten terms.

$\sf\underline{\underline{Solution:}}$

$\space$

$\sf\underline\bold\red{||Step-by-Step||}$

$\sf\bold{Given:}$

$\space$

$\sf\bold{To\:find:}$

$\space$

$\sf\bold{Formula\:we\:are\:using:}$

$\implies$ $\sf{ Sn=}$ $\sf\dfrac{N}{2}$ $\sf\small{[2a+(n-1)d]}$

$\space$

$\sf\bold{Substituting\:the\:values:}$

→ $\sf{S6=}$ $\sf\dfrac{6}{2}$ $\sf\small{[2a+(6-1)d]}$

→ $\sf{36 = 3[2a+(6-1)d]}$

→$\sf{12=[2a+5d]}$ $\sf\bold\purple{(First \: equation)}$

$\space$

$\sf\bold{Again,Substituting \: the\:values:}$

→ $\sf{S16}$ $\sf\dfrac{16}{2}$ $\sf\small{[2a+(16-1)d]}$

→ $\sf{255=8[2a + (16-1)d]}$

:: $\sf\dfrac{255}{8}$ $\sf\small{=31.89=32}$

→ $\sf{32=[2a+15d]}$ $\sf\bold\purple{(Second\:equation)}$

$\space$

$\sf\bold{Now,Solve \: equation \: 1 \:and \:2:}$

→ $\sf{10=20}$

→ $\sf{d=}$ $\sf\dfrac{20}{10}$ $\sf{=2}$

$\space$

$\sf\bold{Putting \: d=2\: in \:equation - 1:}$

→ $\sf{12=2a+5\times 2}$

→ $\sf{a = 1}$

$\space$

$\sf\bold{All\:of\:the\:above\:eq\: In \: S10\:formula:}$

$\mapsto$ $\sf{S10=}$ $\sf\dfrac{10}{2}$ $\sf\small{[2\times1+(10-1)d]}$

$\mapsto$ $\sf{5(2\times1+9\times2)}$

$\mapsto$ $\sf\bold\purple{5(2+18)=100}$

$\space$

$\sf\small\red{||Hence , the \: sum\: of \: the \: first\:10\: terms\: is\:100||}$

_____________________________

Answer:

300

Step-by-step explanation:

A significant figure is the most important (largest) number you can round it to.

As it wants 1 significant figure, you count 1 to the left and round the 4 down.

Hope this helps :)