Write an equation for a line passing through the points (-1, 8) and (0, 5).

Recall the angle sum identity for cosine:

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

cos(x - y) = cos(x) cos(y) + sin(x) sin(y)

==>   sin(x) sin(y) = 1/2 (cos(x - y) - cos(x + y))

Then rewrite the equation as

sin(4x) sin(5x) + sin(4x) sin(3x) - sin(2x) sin(x) = 0

1/2 (cos(-x) - cos(9x)) + 1/2 (cos(x) - cos(7x)) - 1/2 (cos(x) - cos(3x)) = 0

1/2 (cos(9x) - cos(x)) + 1/2 (cos(7x) - cos(3x)) = 0

sin(5x) sin(-4x) + sin(5x) sin(-2x) = 0

-sin(5x) (sin(4x) + sin(2x)) = 0

sin(5x) (sin(4x) + sin(2x)) = 0

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

Rewrite the equation again as

sin(5x) (2 sin(2x) cos(2x) + sin(2x)) = 0

sin(5x) sin(2x) (2 cos(2x) + 1) = 0

sin(5x) = 0   or   sin(2x) = 0   or   2 cos(2x) + 1 = 0

sin(5x) = 0   or   sin(2x) = 0   or   cos(2x) = -1/2

sin(5x) = 0   ==>   5x = arcsin(0) + 2nπ   or   5x = arcsin(0) + π + 2nπ

… … … … …   ==>   5x = 2nπ   or   5x = (2n + 1)π

… … … … …   ==>   x = 2nπ/5   or   x = (2n + 1)π/5

sin(2x) = 0   ==>   2x = arcsin(0) + 2nπ   or   2x = arcsin(0) + π + 2nπ

… … … … …   ==>   2x = 2nπ   or   2x = (2n + 1)π

… … … … …   ==>   x = nπ   or   x = (2n + 1)π/2

cos(2x) = -1/2   ==>   2x = arccos(-1/2) + 2nπ   or   2x = -arccos(-1/2) + 2nπ

… … … … … …    ==>   2x = 2π/3 + 2nπ   or   2x = -2π/3 + 2nπ

… … … … … …    ==>   x = π/3 + nπ   or   x = -π/3 + nπ

(where n is any integer)

Answer:

x = 6; y = -6

Step-by-step explanation:

-4x - 2y = -12

4x + 8y = -24

Add the two equations, so x is eliminated:

6y = -36

6y/6 = -36/6

y = -6

Plug in y, to solve for x

-4x - 2y = -12

-4x - 2(-6) = -12

-4x +12 = -12

-4x = -12 -12

-4x = -24

-4x/-4 = -24/-4

x = 6

Answer from Gauthmath

Answer:

Hence The probability that she is taking a night​ class given that Jane has a​ part-time teacher = P(jane has a part-time teacher and she is taking night class )/P(jane has a part-time teacher)    = 0.6999.

Step-by-step explanation:  

Probability(full-time teacher/ day ) = 0.85  

Probability(part-time teacher/ day ) = 1- 0.85 = 0.15  

Probability(full-time teacher/ night) = 0.30  

Probability(part-time teacher/ night) = 1 - 0.30 = 0.70  

total no of section = 4+2 = 6  

P(jane has part time teacher) = P(jane is from day section)*Probability(part-time teacher/ day )+P(jane is from night section)*Probability(part-time teacher/ night)  

= (4/6)(0.15)+(2/6)(0.70) = 0.33  

P(jane has part time teacher and she is taking night class ) = P(jane is from night section)*Probability(part-time teacher/ night) = (2/6)(0.70) = 0.23  

According to Bayes theorem :    

The probability that she is taking a night​ class given that Jane has a​ part-time teacher = P(jane has a part-time teacher and she is taking night class )/P(jane has a part-time teacher)  

= 0.23/0.33  

= 0.6999

answer:

120°

Step-by-step explanation:

∠OPM=∠ONM=90°

X°＝360°-60°-90°*2＝120°

There would likely be no relationship between first name and height of a person in a random sample.

Hope this helps :)

Answer: it’s B. I answered it right now and it said it was correct.

Step-by-step explanation:

McDonald’s fry’s are better than jack in the box’s fry’s.

Answer:  [tex]\frac{3}{2}[/tex]

Step-by-step explanation:

First, we need to open the brackets on either side of the equation.

[tex]\frac{z}3}[/tex] - 4z+4 = 5z-10+1

After opening the brackets, we need to separate the variables from the constants.

[tex]\frac{z}{3}[/tex] -4z-5z = -10+1-4

Then we need to convert the variable fraction into a normal variable by multiplying the variable fraction and also all other terms in the equation.

3([tex]\frac{z}{3}[/tex]) 3(-4z) 3(-5z) = 3(-10) + 3(1) + 3(-4)

z -12z -15z = -30+3-12

Now, we can simplify the equation !

-26z = -39

z = -39÷-26

  =  [tex]\frac{3}{2}[/tex]

Answer:

Option (A)

Step-by-step explanation:

Solution of two functions represented by the graph are the common points or point of intersection of the graphs.

From the graph attached,

Parabola and ellipse are intersecting each other at four points.

Therefore, solutions of the given non linear functions will be FOUR.

Option (A) will be the correct option.

Answer:

I don't know the answer it is to hard.

Answer:

0.0013 = 0.13% probability that a randomly chosen bag will weigh more than 15.6 ounces.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 15.0 ounces and a standard deviation of 0.2 ounces.

This means that [tex]\mu = 15, \sigma = 0.2[/tex]

What is the probability that a randomly chosen bag will weigh more than 15.6 ounces?

This is 1 subtracted by the p-value of Z when X = 15.6. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{15.6 - 15}{0.2}[/tex]

[tex]Z = 3[/tex]

[tex]Z = 3[/tex] has a p-value of 0.9987.

1 - 0.9987 = 0.0013

0.0013 = 0.13% probability that a randomly chosen bag will weigh more than 15.6 ounces.

Answer:

0.127

Step-by-step explanation:

Answer:

Step-by-step explanation:

4

9514 1404 393

Answer:

  2.64 gallons

Step-by-step explanation:

Each gallon costs $3.79, so the number of gallons that can be bought with $10 is ...

  $10/($3.79/gal) = (10/3.79) gal ≈ 2.6385 gal ≈ 2.64 gallons

Answer:

Sixteen million, one hundred and seven thousand, three hundred twenty

Step-by-step explanation:

Answer:

Missing length = 12

Step-by-step explanation:

Let x represent the missing length.

Since the triangles are similar, ∆KLM ~ ∆KRS, therefore, the ratio of their corresponding side lengths would be the same. This implies that:

KL/KR = KM/KS

KL = 65

KR = 65 - 52

KR = 13

KM = 60

KS = x

Plug in the values

65/13 = 60/x

Cross multiply

65*x = 60*13

65x = 780

Divide both sides by 65

65x/65 = 780/65

x = 12

Answer:I just need points

Step-by-step explanation:

Hey

Answer:

3043 (base 6)

Step-by-step explanation:

216      36    6    1

3           0      4  3

216* 3 = 648

6*4 = 24

1*3 = 3

648+24+3 = 675

Answer:

65 degrees

Step-by-step explanation:

Find the range of temperatures by finding the difference between the lowest and highest temperatures:

37 - (-28)

37 + 28

= 65

So, the range of temperatures was 65 degrees

Answer:

$3 profit

Step-by-step explanation:

Since you got a profit of $9 on Saturday and a loss of $6 on Sunday, you have to subtract 9 and 6, which is 3.

Answer:

y=3x+1

Step-by-step explanation:

Determine slope with two coordinates and use it in the formula

Answer:

0.236

Step-by-step explanation:

Given :

x1 = 667 ; n1 = 10 s1 = 20

x2 = 679 ; n2 = 14 s2 = 15

Test statistic :

(x1 - x2) / √[Sp² (1/n1 + 1/n2)]

The pooled Variance, Sp² :

Sp² = [(n1 - 1)s1² + (n2 - 1)s2²] / (n1 + n2 - 2)

Sp² = [(9*20²) + (13*15²)] / (10+14-2)

Sp² = 6525 / 22 = 296.59

T = (667 - 679) / √(296.59*(1/10 + 1/14)

T = -12 / 50.844

T = 0.236

Test statistic = 0.236

========================================================

Explanation:

We have this sequence

(2+1)+(2+1)+(2+1)...

Effectively, we're repeating "2+1" over and over.

We can see that

Each time we add on another copy of (2+1), we're adding on 3

Dividing 26.2 over 3 gets us (26.2)/3 = 8.733 approximately

If we had 8 copies of (2+1) added together, then we would get

8*(2+1) = 8*3 = 24

This is 26.2-24 = 2.2 miles short of his goal.

He'll need to run 2 more miles, plus walk another 0.2 of a mile

----------------------------------------------------

In summary so far, Joey will run 8+1 = 9 sections (two miles each) and walk 8 sections that are 1 mile each. At the very end, he'll walk 0.2 miles to finish the race. Each running and walking section is alternated of course.

Since he runs 9 sections, each 2 miles, that accounts for 9*2 = 18 miles.

His running pace is 8 minutes per mile, so this means he has run for 8*18 = 144 minutes. This is just the running part and not the walking part.

Let A = 144 so we can use it later.

----------------------------------------------------

He walks 8 sections of 1 mile each. His walking pace is 16 minutes per mile. This must mean he spends 8*16 = 128 minutes on this walking portion.

Then for the last 0.2 mile section he walks, we can solve the proportion below

(1 mile)/(16 min) = (0.2 miles)/(x min)

1/16 = 0.2/x

1*x = 16*0.2

x = 3.2

He spends 3.2 minutes walking the remaining 0.2 of a mile at the end.

So his total walking time is 128+3.2 = 131.2 minutes.

Let B = 131.2

-----------------------------------------------------

To wrap things up, we'll add up the results of each of the previous two sections.

A = total running time = 144 min

B = total walking time = 131.2 min

C = total marathon time

C = A+B

C = 144+131.2

C = 275.2 minutes

This converts to 275 min, 12 sec.

This is also equivalent to 4 hrs, 35 min, 12 sec.

Answer:

[tex]\displaystyle \frac{dy}{dx} = \frac{1}{(x - 2)^2\sqrt{\frac{x}{2 - x}}}[/tex]

General Formulas and Concepts:

Pre-Algebra

Algebra I

Algebra II

Calculus

Differentiation

Derivative Property [Multiplied Constant]:                                                           [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]

Derivative Property [Addition/Subtraction]:                                                         [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Basic Power Rule:

Derivative Rule [Quotient Rule]:                                                                           [tex]\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}[/tex]

Derivative Rule [Chain Rule]:                                                                                 [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Step-by-step explanation:

*Note:

You can simply just use the Quotient and Chain Rule to find the derivative instead of using ln.

Step 1: Define

Identify

[tex]\displaystyle y = \sqrt{\frac{x}{2 - x}}[/tex]

Step 2: Rewrite

Step 3: Differentiate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Book: College Calculus 10e

sine --> cosecant

csc(x) = 1/sin(x)

cosine --> secant

sec(x) = 1/cos(x)

tangent --> cotangent

cot(x) = 1/tan(x)

Correct Answer: A

Hope this helps!

Answer:

Step-by-step explanation:

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

2x + 2y must equal 24. 24 - 2x = 2y and 24 - 2y = 2x. Therefore, 12 - y = x. x could be able to add with y to get 12.

example: x = 4, y = 8. (4 + 4 + 8 + 8 = 16 + 8 = 24)

x = 9, y = 3. (9 + 9 + 3 + 3 = 24)

x = 5, y = 7. (5 + 5 + 7 + 7 = 24)

Answer:

r=24

s=21

Step-by-step explanation:

I use proportion of 2 to 3

I multiply 16 and 3/2 to get r

r=24

I multiply 14 and 3/2 to get s

s=21

Answer:

A∩B ={2;4}

Step-by-step explanation:

Chúc bạn học tốt

Answer:

Can you select multiple answers to this question? then option A, B and C all three applies, if only one the go for option C, since that's the major change happens to the parent function

Answer:

320/3

Step-by-step explanation:

First find the common ratio

20/80 = 1/4

The sum of an infinite geometric series

sum = a1/ (1-r)  where a1 is the first term and r is the common ratio

         =80/ ( 1-1/4)

         = 80/(3/4)

        = 80 *4/3

      = 320/3