within a forest ecosystem, there is a large amount of diversity among members of a warbler species. of the following stages of meiosis illustrated for a typical cell, which contributes most to diversity among the warblers?

Answers

Answer 1

Crossing over occurs between homologous chromosomes, and is closely involved in genetic variation. The stage that most contributes to diversity is stage C, where you can see chromosomes after crossing-over.

----------------------------  

There are different mechanisms involved in producing genetic variation among descendants. These are,

Crossing-over between homologous chromosomes (prophase 1), Random lining of homologous chromosomes (metaphase 1),Random fertilization  

The Crossing-over events occur between two homologous chromosomes in the equatorial plane and make the daughter cells genetically different from the original one.

The Chiasma is the position where two homologous chromatids interchange genetic information, giving a place for new genetic material or information to be provided to descendants.

After crossing over, homologous chromosomes get separated again.  

In the attached imaged there are four different stages of meiosis.

Stage C is the one that contributes the most to diversity.

We can see that crossing over has already occurred between homologous chromosomes, and they have already interchanged segments.

In the image you will see the difference between chromosomes that has gone through the crossing over mechanism, and chromosomes that has not. The difference in color represents segments interchange and variation.

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You can learn more about crossing over at

https://brainly.com/question/12911831?referrer=searchResults

https://brainly.com/question/394891?referrer=searchResults

Within A Forest Ecosystem, There Is A Large Amount Of Diversity Among Members Of A Warbler Species. Of

Related Questions

What is the main cellular structure involved in respiration?

Answers

Answer:

The mitochondria is the main cellular structure involved in respiration

Individuals with a mutation in the gene for apolipoprotein B-100 produce very low levels of this protein, which is a component of LDL. How would accumulation of fat in the liver be affected and would this result in hypercholesterolemia or hypercholesterolemia

Answers

Answer:

Fats would accumulate in the liver and the individual would show hypocholesterolemia

Explanation:

Familial hypercholesterolemia is a genetic disorder caused by a reduction and/or defect in the low-density lipoprotein (LDL) receptor. Moreover, apolipoprotein B is the unique protein component of LDL, which plays a critical role in lipid metabolism by binding the LDL receptor. Familial defective apolipoprotein B-100 refers to an inherited disorder associated with mutations of the apolipoprotein B-100 that leads to moderate or severe cases of hypercholesterolemia. Mutations in apolipoprotein B-100 are associated with a reduction in the binding capacity of LDL to the LDL receptor, thereby leading to hypercholesterolemia.

A researcher found a beautiful plant while traveling in Alaska and collected its seeds. When she came back to Florida, she soaked some of the seeds in pure water and some of these seeds in a water hormone solution. When she put all of the seeds in the soil to grow, only the seeds that had been soaked with the hormone germinated. The hormone most likely was

Answers

Answer:

auxins and cytokinins

Explanation:

the two hormones induce growth for plants

name the fluid which is produced by sebaceous gland​

Answers

Answer:

Sebum

Explanation:

The sebaceous gland produces sebum, an oily, waxy substance. Sebum lubricates the skin and hair of mammals.

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A biochemist discovers several new microorganisms in a sample taken from the bottom of a deep lake in Antarctica. In characterizing one of these organisms, she finds that it cannot survive in an aerobic environment and produces lactic acid as a waste product. What is also likely true about this organism

Answers

Answer:

These organisms can live in anaerobic conditions.

Explanation:

These organisms can live in anaerobic conditions due to death occur in the presence of oxygenated environment or aerobic environment because these organisms are allergic oxygen and open environment. They have to be cultured and colonized in anaerobic condition means without the presence of oxygen so we can say that these organisms lives anaerobically.

Which type of graph could be easily converted into a pie chart?

Answers

Answer:

bar graph can be easily converted to pie chart

Anjuli performed an experiment to determine the respiration rate of yeast. She determined this by measuring the
amount of carbon dioxide (CO2) that was produced. Then, she created the following graph.
Her teacher suggested that she redraw her graph as a line graph. Why should she redraw the graph?
• A line graph looks better in a scientific report.
• She was measuring a rate of change.
• She had graphed the wrong relationship.
• Her experiment had many different variables.

Answers

The correct answer is B. She was measuring a rate of change.

Explanation

A linear graph is a type of graph that contains a series of data represented by points joined by linear segments, which allow you to quickly check the change in the trend of the data. Therefore, inline graphs quantitative variables are usually used to see their behavior over time. According to the above, Anjuli had to use a linear graph to express the information in the graph more clearly, because the data that he was using in his graph were quantitative variables. Also, she wanted to express the respiration rate of the yeast per minute. According to the above, the correct answer is B. Ella She was measuring a rate of change.

When the flow of water cuts very deep channels through the earth *
2 points

Answers

Answer:

It  carves deep into the rock and soil it flows over. Mountains streams cut narrow V-shaped channels

Explanation:

The active site of an enzyme is _____________. Group of answer choices the region of an enzyme that attaches to the product the region of a product that detaches from the enzyme the region of a substrate that is changed by an enzyme the region of an enzyme that attaches to a substrate the highly changeable portion of an enzyme that adapts to fit the substrates of various reactions

Answers

Answer: The correct option is (the region of an enzyme that attaches to a substrate).

Explanation:

The anabolic and catabolic processes in a cell are directed and regulated by enzymes. An enzyme has the ability to speed up a metabolic reaction by lowering the amount of energy needed to start the reaction. Without enzymes, these processes would be extremely slow. They also arrange the reacting molecules in a manner that will cause the chemical change to take place rapidly. It does so through the following steps:

--> molecules of substrate combine with the enzyme at its active site.

--> the substrate molecules combine with enzyme molecules for a short time, forming an enzyme-substrate complex.

--> New substance ( product) is formed which leaves the active site of the enzyme thereby making it free for another reaction to take place.

In conclusion, the ACTIVE SITE of an enzyme is the region of an enzyme that attaches to a substrate allowing chemical reaction to take place.


In which of the following stages does the DNA replication and protein
synthesis take place?

Answers

G1 is followed by S phase (synthesis), during which DNA replication takes place. The completion of DNA synthesis is followed by the G2 phase (gap 2), during which cell growth continues and proteins are synthesized in preparation for mitosis.

When calcium carbonate is heated, it
decomposes into calcium oxide and carbon
dioxide. If 100 g of calcium carbonate are
decomposed, 56 g of calcium oxide is produced.
What would be the mass of the carbon dioxide
given off by the decomposition?
A. 448
B. 110 g
C. 156 g

Answers

Answer:

A. 44 g

Explanation:

First, you need to write a balanced equation:

CaCO₃ -> CaO + CO₂

Then, you need to find the molar mass of CaCO₃:

Ca = 40.078 amu

C = 12.0107 amu

3O = 47.9982 amu

_________________

100.0869 amu

Then, you calculate the moles of CaCO₃:

100 g ÷ 100.0869 amu = 0.9991 moles

In the balanced equation, we can see that the molar ratio of CaCO₃ and CO₂ is 1 : 1, so moles of CaCO₃ = moles of CO₂.

Now you need to find the molar mass of CO₂:

C = 12.0107 amu

2O = 31.9988 amu

________________

44.0095 amu

Finally, you can calculate the mass of CO₂ produced:

0.9991 moles * 44.0095 amu = 43.9698 g = 44 g

A few individuals of a lizard species from the mainland are transported to a distant island by riding on floating driftwood. These few individuals survive, reproduce, and their descendants make up a population of this species that is distinct from the population on the mainland. This occurrence is an example of

Answers

Answer:

the founder effect, a form of genetic drift

Explanation:

Genetic drift is the change in the frequency of alleles in a population due to random sampling of organisms.

The founder effect is the reduced genetic diversity created when a population is descended from a small number of colonizing ancestors.

Define the word ⇒ Biosphere


THANK YOU!! :)

Answers

The biosphere is a narrow zone of the earth where land, water, air interact with each other to support life.

Answered by Gauthmath must click thanks and mark brainliest

An actin-binding protein called cofilin binds preferentially to ADP-containing actin filaments rather than ATP-containing actin filaments. Based on this preference, which is true? Question 7 options: Cofilin binds to the plus ends of treadmilling actin filaments. Cofilin competes with profilin for binding to actin. Cofilin binds to older actin filaments. Cofilin binds to the plus ends of actin filaments.

Answers

Answer:

Cofilin binds to older actin filaments

Explanation:

Microfilaments (also called actin filaments) are a class of protein filament common to all eukaryotic cells, which consist of two strands of subunits of the protein actin. Microfilaments form part of the cell's cytoskeleton and interact with the protein myosin in order to allow the movement of the cell. Within the cell, actin may show two different forms: monomeric G-actin and polymeric F-actin filaments. Microfilaments provide shape to the cell because these filaments can depolymerize (disassemble) and polymerize (assembly) quickly, thereby allowing the cell to change its shape. During the polymerization process, the ATP that is bound to G-actin is hydrolyzed to ADP, which is bound to F-actin. ATP-actin subunits are present at the barbed ends of the filaments, and cleavage of the ATP molecules produces highly stable filaments bound to ADP. In consequence, it is expected that cofilin binds preferentially to highly stable (older) filaments ADP-actin filaments instead of ATP-actin filaments.

Which of the following is an example of a physical change?
O A. A gas is given off when two substances are mixed.
B. A copper rod is hammered into a thin sheet.
C. A solid forms when two clear liquids are mixed.
O D. A matchstick changes color when it burns.

Answers

A gas is given off when two substances are mixed.

physical change: A copper rod is hammered into a thin sheet.

A solid forms when two clear liquids are mixed.

A matchstick changes color when it burns.

explanation

a physicals change vs chemical

physical change is like cutting, changing shape etc, it the molecules that make it and the chemicals of it stay same

chemical change when it chemically changed such as cooking meat

The Answer is B

B. A copper rod is hammered into a thin sheet.

Physical change does not affect the chemical components of the material and the rod was only hammered to change it shape (thus altering a change in the physical aspect)

Sheets composed of two layers of amphipathic molecules arranged with the hydrophilic groups on the surface and the hydrophobic groups buried in the center that form in water are called A) micelles. B) liposomes. C) vacuoles. D) bilayer membranes. E) none of the above

Answers

Answer:

D) bilayer membranes

Explanation:

Two lipidic bilayers compose the cell membrane. There are also proteins and glucans incrusted in between. Lipids are amphipathic molecules with hydrophilic heads -negatively charged phosphate group- and hydrophobic tails. Lipids are arranged with their hydrophilic polar heads facing the exterior and the interior of the cells, while their hydrophobic tails are against each other, constituting the internal part of the membrane. Membranes are fluid, which means that the composing molecules can move through them.

Lipids can easily change places with other neighboring lipids by lateral diffusion in the same layer. This is passive diffusion, which means that it does not need energy to happen.

Lipids can also diffuse transversally to the other layer but not as easily as lateral diffusion. Jumps between monolayers are infrequent as the lipidic polar heads meet the fatty acid barrier.

There are also other lipidic movements as rotational diffusion that imply the rotation of the molecule.  

What are threatened species?Question 1 options: species we do not have enough data for to determine their population numbers only large mammals like elephants, pandas, and whales only species poached for their organs or other parts species at risk for extinction species that have already gone extinct

Answers

Answer:

The correct answer is - species at risk for extinction.

Explanation:

Extinction is a threat to species of any living organism. The death or removal of last individual of a species is the condition of extinction.

It is commonly referred to the species as mostly species extinct from earth. Any size or type of species of living organism can be extinct.

Which process allows a bacterium to take DNA from its environment and add it to its own genome?

Answers

Answer:

b transformation

Explanation:

In transformation, a bacterium takes up a piece of DNA floating in its environment. In transduction, DNA is accidentally moved from one bacterium to another by a virus. In conjugation, DNA is transferred between bacteria through a tube between cells.

Traits can also be
, which means they can be masked

Answers

Answer:

is that a question?

Explanation:

Which of the following animals has a fetus ? A.Gobies B.antelope C.Tree frog D. Iguana

Answers

Answer:

the right answer is tree frog

Explanation:

Which of the following is not one of the steps of the water cycle?
A. Condensation of water vapor into clouds.
B. Throughflow of underground water back to the ocean.
C. Respiration of water into the atmosphere.
D. Transpiration of water into the atmosphere.

Answers

The option that is not one of the steps of the water cycle includes options C(Respiration of water into the atmosphere)

and D(Transpiration of water into the atmosphere).

Water cycle can be defined as the constant flow or movement of water through earth, atmosphere and the oceans either in liquid states or vapour.

The four main steps of water cycle includes:

EvaporationCondensationprecipitation and Collection (this leads to formation of underground water which gradually flows back into the oceans).

In nature, water circulates mainly within the abiotic (non-living) environment; only a small proportion recycled through living organisms.

Therefore respiration and transpiration which occurs through living organisms doesn't form the major steps of water cycle, hence the correct option is C (Respiration of water into the atmosphere) and D (Transpiration of water into the atmosphere).

Learn more about water cycle here:

https://brainly.com/question/458815

What are the types of Vitamins and their functions in the body?​

Answers

Hi, here are a few:

Biotin Part of an enzyme needed for energy metabolism

Pyridoxine (vitamin B6) Part of an enzyme needed for protein metabolism; helps make red blood cells

Folic acid Part of an enzyme needed for making DNA and new cells, especially red blood cells

Hope that helps!

Is there any plastid in mango seed?

Answers

there are no plastid in a mango seed because

5. What are hyphae made of?

Answers

Answer:Hyphae are the feathery filaments that make up multicellular fungi. They release enzymes and absorb nutrients from a food source. Hyphae have a firm cell wall made of chitin.

Explanation:

Answer:

They are made of the feathery filaments that make up multicellular fungi

A small size is advantageous for marine organisms because it ________. increases the surface area to volume ratio that in turn reduces frictional resistance to sinking increases the ability to absorb nutrients increases the ability of wastes to diffuse out of the organism All of the above

Answers

Answer:

increases the ability of wastes to diffuse out of the organism

Explanation:

A small size of an organism is advantageous for marine organisms because it increases the ability of wastes to diffuse out of the body of organism. Small size of an organism produces less amount of waste material and these organism does not need a very special and complex excretory system so simple diffusion of waste material occurs from the body in order to clean the body.

Sea urchins belong to the echinoderm phylum. Adult sea urchins have spines that extend outward from their exoskeleton, but as larvae, the sea urchins have only an exoskeleton made from spicules. The spines offer protection against predators. The population size of sea urchins is low in relation to the carrying capacity of the area. As a result, the sea urchins are Multiple choice question. A) r-strategists that allocate much energy toward parental care. By-strategists that allocate energy to producing many young. C) density-independent, because there is plenty of energy. D) irruptive, because their numbers crash quickly.

Answers

Complete question:

Sea urchins belong to the echinoderm phyla. Adult sea urchins have spines that extend outward from their exoskeleton, but as larvae, the sea urchins have only an exoskeleton made from spicules. The spines offer protection against predators. Sea urchins typically spawn near the surface. Males release sperm into floating plankton, then female urchins release between eight and 20 million eggs in the same area. The jelly-like coating on the eggs attracts the sperm, and when the two meet, they create an embryo that starts dividing into new cells within minutes.

Based on the information the population size of sea urchins is low in relation to the carrying capacity of the area. As a result, the sea urchins are

A) r-strategists that allocate much energy toward parental care.

B) r-strategists that allocate energy to producing many young.

C) density-independent because there is plenty of energy.

D) irruptive, because their numbers crash quickly.

Answer:

B) r-strategists that allocate energy to producing many young.

Explanation:

According to the given information, this species expresses survival curve type III, characteristic of r-strategists. Males and females release many gametes into the sea. If these gametes get to meet, they produce the embryo that starts developing. But there are high chances for these new organisms to die. Significant mortality during the early stages of life is expected for the species. The few individuals that manage to reach the later life stages, getting to survive, usually have a long life. These species produce many gametes to release, which results in the production of many offspring simultaneously. However, adult individuals provide no parental care. Their success in reproduction depends on the number of surviving descendants.

Males release sperm into floating plankton, Female urchins release between eight and 20 million eggs in the same area,When they meet, sperm and egg create an embryo that starts dividing into new cells within minutes.

We might also mention that the population size is under the carrying capacity. r-strategist choose to live in areas with only a few individuals, where nitches are hardly occupied.

Which biome does this photograph represent?

Answers

Answer:

There is no photograph .

how many types does the larva of silkworm moult?​

Answers

Answer:

there are 6 lava of silkworm moult.

Answer:

Silkworms will undergo molting up to four times since they grow so much before becoming an adult.

Explanation:

what is the relationship between an enzyme and the substrates it can bind

Answers

Answer:

Enzymes and substrates bind to each other associating through various interactions, including hydrogen bonds, hydrophobic interactions, and covalent bonds.

Indica el período, el grupo y el número atómico de los elementos que se representan con las siguientes configuraciones electrónicas: 1. 1s2 Grupo: ______ Periodo: _______ 2. 1s22s22p63s1 Grupo: ______ Periodo: _______ 3. 1s22s22p63s23p64s2 Grupo: ______ Periodo: _______ 4. 1s22s22p63s23p64s23d1 Grupo: ______ Periodo: _______ 5. 1s22s22p63s23p64s23d104p3 Grupo: ______ Periodo: _______

Answers

Answer:

1. 1s² Grupo: 18  Periodo: 1

2. 1s²2s²2p⁶3s¹ Grupo: 1 Periodo: 3  

3. 1s²2s²2p⁶3s²3p⁶4s² Grupo: 2 Periodo: 4  

4. 1s²2s²2p⁶3s²3p⁶4s²3d¹ (electrones de valencia) Grupo: 3 Periodo: 4

5. 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p³ (electrones de valencia) Grupo: 15 Periodo: 4

Explanation:

La configuración electrónica de los elementos es la disposición de todos los electrones de un elemento en niveles y subniveles de energía (orbitales).

Hay 7 niveles de energía, numerados del 1 al 7, y en los que los electrones se distribuyen, lógicamente, en orden según su nivel de energía. Los electrones con menos energía girarán en el nivel 1. Cada nivel se divide en subniveles. Estos subniveles en los que se divide cada nivel pueden ser hasta 4. Estos 4 subniveles se denominan: s, p, d, f. En el subnivel s solo puede haber un máximo de 2 electrones, en p puede haber un máximo de 6 electrones, en el subnivel d 10 electrones y finalmente en el subnivel f puede haber un máximo de 14 electrones.

Por otro lado, los electrones de valencia son los electrones que se encuentran en la última capa electrónica (denominada orbitales de valencia) y tienen muchas posibilidades de participar en una reacción química.

En la tabla periódica, en cada período aparecen los elementos cuyo último nivel de su configuración electrónica coincide con el número del período, mientras que en cada grupo aparecen los elementos que presentan el mismo número de electrones en el último nivel ocupado o capa de valencia. Entonces:

1. 1s² Grupo: 18  Periodo: 1

2. 1s²2s²2p⁶3s¹ Grupo: 1 Periodo: 3  

3. 1s²2s²2p⁶3s²3p⁶4s² Grupo: 2 Periodo: 4  

4. 1s²2s²2p⁶3s²3p⁶4s²3d¹ (electrones de valencia) Grupo: 3 Periodo: 4

5. 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p³ (electrones de valencia) Grupo: 15 Periodo: 4

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