Why do scientists listen to ocean around plate boundary?

Answer:

Plant Adaptations is a unique feature a plant has that allows it to live and survive in its own particular habitat (the place that it lives). Desert Plant Adaptations – Plant Adaptation is really a unique have a plant has that enables it to reside and survive in the own particular habitat (the area it lives).

Explanation:

Answer:

Below

Explanation:

The ocean is becoming more acid, which means the pH is decreasing. In that time frame it has decreased by about 0.05

Answer:

car horn preventing accidents

Answer:

d) car horns preventing accidents

Explanation:

the use of car horns represents sound energy in everyday life. batteries use chemical energy that is turned into electrical energy, fireplaces use thermal energy, and lights use electrical energy!

The corresponding change in pressure in atm is 0.285 atm.

To solve the question, we need to know what pressure is.

This is the force per unit area acting on a surface.

The change in pressure in the mercury barometer is given by ΔP = ρgh where

So, ΔP = ρgh

= 13600 kg/m³ × 9.8 m/s² × 0.217 m

= 28921.76 kg/m-s²

= 28921.76 N/m²

= 28921.76 Pa

Since 1 atm = 101325 Pa

28921.76 Pa = 28921.76 Pa × 1 atm/101325 Pa

= 0.285 atm

So, the corresponding change in pressure in atm is 0.285 atm.

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The pH indicators that would be used to determine the unknown substance are :

The pH indicators that can be used to identify the mysterious white powder in the kitchen must be an acid-base indicator such as Litmus or other form of effective pH indicators like methyl orange and Phenol red.

The pH value of the substance as indicated by the acid-base indicators will help to determine what the mysterious white powder is based on the varying pH of the substances resembling the white powder.

Hence we can conclude that The pH indicators that would be used to determine the unknown substance are :Litmus , Methyl orange, Phenol Red.

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A coarse particle has a diameter of 1x10-6m. a nanoparticle has a diameter of 1.6 x 10-9m. Calculate how many times bigger the diameter of the coarse particle is than the diameter of the nanoparticle

Answer:

b.exothermic and entropy is decreasing

The mass of fluorine that were formed is 592 mg

From the question, we are to determine the mass of fluorine formed

First, we will write the balanced chemical equation for the decomposition reaction

The balanced chemical equation for the reaction is

CaF₂ → Ca + F₂

This means

1 mole of calcium fluoride decomposes to give 1 mole of calcium and 1 mole of fluorine

Now, we will determine the number of moles of calcium produced

From the given information,

Mass of calcium produced = 625 mg = 0.625 g

Using the formula,

[tex]Number\ of \ moles =\frac{Mass}{Atomic\ mass}[/tex]

Atomic mass of calcium = 40.078 g/mol

Then,

Number of moles of calcium produced = [tex]\frac{0.625}{40.078}[/tex]

Number of moles of calcium produced = 0.01559 mole

Since

1 mole of calcium fluoride decomposes to give 1 mole of calcium and 1 mole of fluorine

Then,

0.01559 mole of calcium fluoride will decompose to give 0.01559 mole of calcium and 0.01559 mole of fluorine

∴ Number of mole of fluorine formed was 0.01559 mole

Now, for the mass of fluorine formed

Using the formula,

Mass = Number of moles × Molar mass

Molar mass of fluorine = 38 g/mol

Then,

Mass of fluorine formed = 0.01559 × 38

Mass of fluorine formed = 0.59242 g

Mass of fluorine formed = 592.42 mg

Mass of fluorine formed ≅ 592 mg

Hence, the mass of fluorine that were formed is 592 mg.

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Answer:

[tex]5{Fe}^{ + 2} +1{MnO_4}^{ - 1} + 8 {H}^{ + } \rightarrow 5{Fe}^{ + 3} + 1{Mn}^{ + 2} + 4H_2O[/tex]

Explanation:

To balance any redox reaction the primary factor is to identify the species undergoing oxidation and reduction.

Below are the steps to identify species undergoing oxidation and reduction:

let's calculate oxidation number,

given reaction

[tex]{Fe}^{ + 2} +{MnO_4}^{ - 1} \rightarrow {Fe}^{ + 3} + {Mn}^{ + 2}[/tex]

Of reactant,

[tex]Fe = +2, {MnO_4}^{ - 1} \\ Let \: oxidation \: of \: Mn \: is \: x \: and \: Oxygen -2 \\ {MnO_4}^{ - 1} \rightarrow \: x + 4 \times ( - 2) = - 1 \\ {MnO_4}^{ - 1} \rightarrow \: x + - 8 = - 1 \\ {MnO_4}^{ - 1} \rightarrow \: x = + 8 - 1 \\ {MnO_4}^{ - 1} \rightarrow \: x = + 7 \\ \fbox{ Mn \: +7, O \: -2}[/tex]

Of product,

[tex]\fbox{Fe \: +3, \: Mn \: +2}[/tex]

Now calculate the change in oxidation number

[tex]Fe = +3-(+2) = +1 \\ Mn = +2-(+7) = -5[/tex]

now balance the increase in oxidation number and decrease in oxidation number,

thus we require 5 Fe for 1 MnO4-,

Now putting these numbers as their coefficient,

[tex]5{Fe}^{ + 2} +1{MnO_4}^{ - 1} \rightarrow 5{Fe}^{ + 3} + 1{Mn}^{ + 2}[/tex]

now balance oxygen atom on product side by adding water,

since there are 4 oxygen atoms in reactants 4 water molecules will be there on product side.

[tex]5{Fe}^{ + 2} +1{MnO_4}^{ - 1} \rightarrow 5{Fe}^{ + 3} + 1{Mn}^{ + 2} + 4H_2O[/tex]

now balance Hydrogen atom on reactant side by adding H+ ion, since there are 4 water molecules on product 8 H+ ion will be in reactants!

[tex]5{Fe}^{ + 2} +1{MnO_4}^{ - 1} + 8 {H}^{ + } \rightarrow 5{Fe}^{ + 3} + 1{Mn}^{ + 2} + 4H_2O[/tex]

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

Confirming the balanced reaction, by checking number of atoms and charge on reactant vs Product side.

Total number of Fe on reactant and product = 5

Total number of Mn on reactant and product= 1

Total number of Oxygen on reactant and product = 4

Total number of hydrogen on reactant and product= 8

Total charge on reactant side= 5×(+2)-1+8=17

Total charge on product side = 5×(+3)+1×(+2)=17

━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

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In The RGB color model, colors are described in numerical codes which are written in brackets and separated by commas.

RGB model is a color ( additive ) which enables the addition of  RED, Green and Blue colors  which are the primary colors of light in various ways to produce different colors.

In RGB model the RGB values gets to display different colors when used on different devices hence it can not be described as a reference point for RED, Green and Blue colors.

Hence we can conclude that In The RGB color model, colors are described in numerical codes which are written in brackets and separated by commas.

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Attached below is the GIZMO image

Explanation:

The atomic number of Uranium is 92. The electron configuration is: [U] = [Rn] 5f3; 7s4 where Radon Rn has 86 electrons and a complete period. This result is respecting the Madelung. BUT … U is an exception !!!

On the period 7 are only 6 electron left for Uranium (92–86). The first 2 electrons are on the principal energy level 7 and occupy the 7s-orbital block. The 3rd electron is placed in the 5f-orbital block. The next 3 electrons are place here as well. The last electron has the unique quantum label (n; l; ml; s) = (5; 3; 0; 0)

To understand this: The first electron of the 5f-orbital block has the label (5; 3, -3; 0). The following electrons have the labels (5; 3; -2, 0), (5; 3; -1; 0), (5; 2; 0; 0). You notice, that the HUND’S RULE is satisfied. ( I always use head 0 before tail 1 to represent the spin.) The f-orbital block is made up of 7 orbitals and therefore can be filled up by at most 14 electrons. When the first electron has the spin 0 then the next 6 electrons must also have the spin 0. With the electron 8 you get the label (5; 3; -3, 1) which tells us, that the spin is opposite to 0. It must be 1. The next 6 electrons also will have spin 1 but are placed in the orbitals -2; -1; 0; 1; 2; 3. Their labels are: (5; 3; -2; 1), (5; 3; -1; 1), (5; 3; 0; 1), (5; 3; 1; 1), (5; 3; 2; 1) and (5; 3; 3; 1) Now the f-block is full !!!

ANSWER: The last electron of U has the label (5; 3; 0; 0). BUT … !!!!!

I hope that you can verify now the correctness of the answer by yourself according to the Madelung.

Please, apply the definitions of the 4 quantum numbers correctly by also respecting the MANDELUNG’S RULE, the OCTET RULLE, the HUND’S RULE.

NOTICE: The Madelung has 21 exceptions. (Wikipedia lists only 20 and treats Ni not as an exception)

Cr, Ni, Cu, Nb, Mo, Ru, Rh, (Pd), Ag, Pt, Au and

La, Ce, Gd, Ac, (Th), Pa, U, Np, Cm, Lr.

In the first group listed: 1 electron moves inwards. In the second group listed: 1 electron moves outwards. Pd and Th have 2 moving electron each. YOU CAN SEE, THAT U IS AN EXCEPTION !!!

CORRECT ANSWER: The last electron of U has the label (6; 2; 0; 0). Can you see the moving electron ??? ❮❮(5; 3; 0; 0) becomes (6; 2; 0; 0)❯❯ Can you see the moving outwards ???

The 21 exception were discovered with spectral analysis. The MADELUNG is not a principle !!! It is only a very simple rule to memorise the electron configurations. By respecting the exceptions, you can correct you Madelung answer !!! Learn the 21 exceptions by heart !

Did you get it ??? (6; 2; 0; 0) is the label of the last electron of U.

Notes:-

Electronic configuration

So

Moles of O_2

Now

[tex]\\ \rm\Rrightarrow V=\dfrac{nRT}{P}[/tex]

[tex]\\ \rm\Rrightarrow V=\dfrac{81.25(26)(8.314)}{3}[/tex]

[tex]\\ \rm\Rrightarrow V=5854.4L[/tex]

The volume of the gas in the chamber is equal to 664.36 L.

The ideal gas law is defined as an equation of the state of an ideal gas. This equation is written as the product of the volume and pressure of 1 mole gas is equal to the product of the gas constant and absolute temperature of the gas.

The mathematical formula of the ideal gas law is as follows:

PV = nRT

Where n is the moles of gas, V is the volume of the gas, R is the gas constant and P is the pressure.

The temperature of the gas in the chamber, T =  26° C = 299 K

The pressure of the gas, P = 3 atm

The value of the gas constant, R = 0.082 atm L/K mol

The number of moles of a given gas, n = 2600/32 = 81.25 mol

Substituting the values n, R, P, and T in the equation, we get:

3 × V = 81.25 × 0.082 × 299.15

V = 664.36 L

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Answer:

The Haber process, also called the Haber–Bosch process, is an artificial nitrogen fixation process and is the main industrial procedure for the production of ammonia today. It is named after its inventors, the German chemists Fritz Haber and Carl Bosch, who developed it in the first decade of the 20th century. 

Answer:

a catalytic process for synthesizing ammonia from nitrogen and hydrogen

Explanation:

Answer:

Have some attraction towards each other

Explanation:

Gases deviate from the ideal gas behavior because their molecules have forces of attraction between them. At high pressure, the molecules of gases are very close to each other so the molecular interactions start operating and these molecules do not strike the walls of the container with full impact.

Hope this helps :-)

Have a great rest of your day or night!

Enjoy your studies and assignments

<3 simplysun

ps. I do not own any of these answers so please don't give full credit to me

If 6 units of AB were reacted with 10 units of CD in the described equation, the limiting reactant would AB

They are reactants that determine how far a reaction can go in terms of yield.

From the equation: 3AB + 4CD --> 2AD + 6CB

The mole ratio of AB to CD is 3:4

Thus, 6 units of AB will require 8 units of CD.

But 10 units of CD were reacted with only 6 units of AB. This means that CD is in excess by 2 units while AB will limit the yield of the reaction.

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Both ionization energy and electron affinity are opposite processes to each other because of their functions.

The main difference between electron affinity and ionization energy is that electron affinity refers to the amount of energy released when an atom gains an electron while on the other hand, ionization energy is the amount of energy required to remove an outermost electron from an atom.

So we can conclude that both ionization energy and electron affinity are opposite processes to each other because of their functions.

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Answer:

contact process, modern industrial method of producing sulfuric acid; it has largely replaced the chamber, or lead-chamber, process. Sulfur dioxide and oxygen, passed over a hot catalyst, unite to form sulfur trioxide, which in turn combines with water to make sulfuric acid.

Answer:The energy of the molecules in the computer decreases.

Explanation:LET ME KNO IM WRONG

Answer: The energy of the molecules decrease in the computer

Explanation:

This is because you turned off the computer cooling it down and slowing the molecules.

Answer:

Explanation:

Pb(NO3)2(aq) + 2NaCl(aq) ==> PbCl2(s) + 2NaNO3(aq)

NO3- mixes with everything at beginning levels.

PbCl2 doesn't mix at all in water. It becomes a ppte, which means it is solid form. Your teacher might prefer using PbCl2(ppte). I think I'd ask to make sure.

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's calculate Equilibrium constant for the following reaction. [tex] \sf{K_c} [/tex]

if we balance the equation, we will get :

[tex] \qquad\sf{C_{(s)}+ CO_2\:{(g)} \leftrightarrow2\: CO_{(g)}} [/tex]

According to question ~

Answer:

There are different ways to write this:

N[tex]a^{+}[/tex] + C[tex]l^{-}[/tex] + H2O

N[tex]a^{+}[/tex](aq) + C[tex]l^{-}[/tex](aq)

Explanation:

(aq) means aqueous in water, which means dissolved in water.

Hope this helps.

- profparis

Answer:

A.

Explanation:

Opposite charged particles attract.

Particles of same charge are repelled.

Answer:

attracts opposites (a)

Explanation:

Answer:

Explanation:

You have the equation. Now change the 3.4 g H2 to moles. moles = grams/molar mass

3.4 g/2.016 = 1.686 moles.

Now using the coefficients in the balanced equation, convert moles H2O2 to moles H2O.

1.686 moles H2 x (2 moles H2O/2 moles H2O2) = 1.686 x (2/2) = 1.686 x (1/1) = 1.686 moles H2O.

Now you know that 1 mole of water is composed of 6.022 x 10^23 molecules. So

1.686 moles H2O x (6.022 x 10^23 molecules H2O/1 mole H2O) = ?? molecules.

The volume, in Liters, that would be required to obtain 0.500 moles of Br ions from 1.40 M FeBr2 will be 0.36 L

Recall that:

Molarity = mole/volume

In this case, molarity = 1.40 M and moles = 0.500 moles

Thus:

Volume = mole/molarity = 0.500/1.40 = 0.36 L

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Explanation:

Wind helps to get out molecules of water from clothes.

In summer Ball is hard b because due to heat kinetic energy of molecules increases

No of molecules

Note that